Query subselect at least one









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I have a table named movement_history (that represenents movements of cars (register, sell, suspended, repaired, destroyed)). I want to get the information of a company
that has sold each cars and to who.



This is my table (select *)



code_car date_movement type_movement current_company_code
6000 01/01/2010 NEW 5
6000 01/01/2012 REPARATION 5
6000 01/11/2015 SOLD 8
6000 01/01/2017 DESTROYED 8
4444 01/05/2000 NEW 10
4444 01/05/2000 SUSPENDED 10
4444 01/05/2015 SOLD 5
4444 01/07/2015 RENOVATION 5
4444 09/12/2015 SOLD 18
.... ... ... ...


So if i want all the sales of cars from the company 5 in a determinated time (01-01-2015 to 31-02-2015) this would be the result:



 code_car date_movement type_movement current_company_code
6000 01/11/2015 SOLD 8
4444 09/12/2015 SOLD 18


That's my query. First I obtain all the cars that someday have been from the company 5. Then I obtain all the 'SOLD' movements and I want to obtain for each car sold if some day has been part of the company 5.



select 
code_car,date_movement,type_movement,current_company_code
from
movement_history where code_car in (
(select code_car from movement_history where current_company_code = 5)) and
code_car IN
(select code_car from movement_history where type_movement =
'SOLD' and code_car <> 5 and date_movement > to_Date('01-01-2015','dd/mm/yyyy') and date_movement < to_Date('31-12-2015','dd/mm/yyyy'));


I guess am doing badly the part to obtain if each car sold some day has been part of the company 5 al least one time.



Any suggestion? Thanks a lot.










share|improve this question



















  • 1




    What date is "31-02-2015" supposed to represent?
    – Gordon Linoff
    Nov 10 at 17:24














up vote
0
down vote

favorite












I have a table named movement_history (that represenents movements of cars (register, sell, suspended, repaired, destroyed)). I want to get the information of a company
that has sold each cars and to who.



This is my table (select *)



code_car date_movement type_movement current_company_code
6000 01/01/2010 NEW 5
6000 01/01/2012 REPARATION 5
6000 01/11/2015 SOLD 8
6000 01/01/2017 DESTROYED 8
4444 01/05/2000 NEW 10
4444 01/05/2000 SUSPENDED 10
4444 01/05/2015 SOLD 5
4444 01/07/2015 RENOVATION 5
4444 09/12/2015 SOLD 18
.... ... ... ...


So if i want all the sales of cars from the company 5 in a determinated time (01-01-2015 to 31-02-2015) this would be the result:



 code_car date_movement type_movement current_company_code
6000 01/11/2015 SOLD 8
4444 09/12/2015 SOLD 18


That's my query. First I obtain all the cars that someday have been from the company 5. Then I obtain all the 'SOLD' movements and I want to obtain for each car sold if some day has been part of the company 5.



select 
code_car,date_movement,type_movement,current_company_code
from
movement_history where code_car in (
(select code_car from movement_history where current_company_code = 5)) and
code_car IN
(select code_car from movement_history where type_movement =
'SOLD' and code_car <> 5 and date_movement > to_Date('01-01-2015','dd/mm/yyyy') and date_movement < to_Date('31-12-2015','dd/mm/yyyy'));


I guess am doing badly the part to obtain if each car sold some day has been part of the company 5 al least one time.



Any suggestion? Thanks a lot.










share|improve this question



















  • 1




    What date is "31-02-2015" supposed to represent?
    – Gordon Linoff
    Nov 10 at 17:24












up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have a table named movement_history (that represenents movements of cars (register, sell, suspended, repaired, destroyed)). I want to get the information of a company
that has sold each cars and to who.



This is my table (select *)



code_car date_movement type_movement current_company_code
6000 01/01/2010 NEW 5
6000 01/01/2012 REPARATION 5
6000 01/11/2015 SOLD 8
6000 01/01/2017 DESTROYED 8
4444 01/05/2000 NEW 10
4444 01/05/2000 SUSPENDED 10
4444 01/05/2015 SOLD 5
4444 01/07/2015 RENOVATION 5
4444 09/12/2015 SOLD 18
.... ... ... ...


So if i want all the sales of cars from the company 5 in a determinated time (01-01-2015 to 31-02-2015) this would be the result:



 code_car date_movement type_movement current_company_code
6000 01/11/2015 SOLD 8
4444 09/12/2015 SOLD 18


That's my query. First I obtain all the cars that someday have been from the company 5. Then I obtain all the 'SOLD' movements and I want to obtain for each car sold if some day has been part of the company 5.



select 
code_car,date_movement,type_movement,current_company_code
from
movement_history where code_car in (
(select code_car from movement_history where current_company_code = 5)) and
code_car IN
(select code_car from movement_history where type_movement =
'SOLD' and code_car <> 5 and date_movement > to_Date('01-01-2015','dd/mm/yyyy') and date_movement < to_Date('31-12-2015','dd/mm/yyyy'));


I guess am doing badly the part to obtain if each car sold some day has been part of the company 5 al least one time.



Any suggestion? Thanks a lot.










share|improve this question















I have a table named movement_history (that represenents movements of cars (register, sell, suspended, repaired, destroyed)). I want to get the information of a company
that has sold each cars and to who.



This is my table (select *)



code_car date_movement type_movement current_company_code
6000 01/01/2010 NEW 5
6000 01/01/2012 REPARATION 5
6000 01/11/2015 SOLD 8
6000 01/01/2017 DESTROYED 8
4444 01/05/2000 NEW 10
4444 01/05/2000 SUSPENDED 10
4444 01/05/2015 SOLD 5
4444 01/07/2015 RENOVATION 5
4444 09/12/2015 SOLD 18
.... ... ... ...


So if i want all the sales of cars from the company 5 in a determinated time (01-01-2015 to 31-02-2015) this would be the result:



 code_car date_movement type_movement current_company_code
6000 01/11/2015 SOLD 8
4444 09/12/2015 SOLD 18


That's my query. First I obtain all the cars that someday have been from the company 5. Then I obtain all the 'SOLD' movements and I want to obtain for each car sold if some day has been part of the company 5.



select 
code_car,date_movement,type_movement,current_company_code
from
movement_history where code_car in (
(select code_car from movement_history where current_company_code = 5)) and
code_car IN
(select code_car from movement_history where type_movement =
'SOLD' and code_car <> 5 and date_movement > to_Date('01-01-2015','dd/mm/yyyy') and date_movement < to_Date('31-12-2015','dd/mm/yyyy'));


I guess am doing badly the part to obtain if each car sold some day has been part of the company 5 al least one time.



Any suggestion? Thanks a lot.







sql oracle subquery






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edited Nov 10 at 18:20









a_horse_with_no_name

286k45429526




286k45429526










asked Nov 10 at 17:22









artyui berwaf

1




1







  • 1




    What date is "31-02-2015" supposed to represent?
    – Gordon Linoff
    Nov 10 at 17:24












  • 1




    What date is "31-02-2015" supposed to represent?
    – Gordon Linoff
    Nov 10 at 17:24







1




1




What date is "31-02-2015" supposed to represent?
– Gordon Linoff
Nov 10 at 17:24




What date is "31-02-2015" supposed to represent?
– Gordon Linoff
Nov 10 at 17:24












1 Answer
1






active

oldest

votes

















up vote
1
down vote













I see. The current_company_code is the company that got the car. So, you want to use LAG():



select mh.*
from (select mh.*,
lag(mh.current_company_code) over (partition by mh.code_car order by date_movement) as prev_ccc
from movement_history mh
) mh
where mh.type_movement = 'SOLD' and
mh.date_movement >= date '2015-01-01' and
mh.date_movement < date '2016-01-01' and
mh.prev_ccc = 5;





share|improve this answer




















  • Without using lag is ther any possibility?
    – artyui berwaf
    Nov 10 at 17:29







  • 1




    @artyuiberwaf . . . lag() is the simplest solution and should have the best performance. I see no reason not to use it.
    – Gordon Linoff
    Nov 10 at 17:38










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1 Answer
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active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote













I see. The current_company_code is the company that got the car. So, you want to use LAG():



select mh.*
from (select mh.*,
lag(mh.current_company_code) over (partition by mh.code_car order by date_movement) as prev_ccc
from movement_history mh
) mh
where mh.type_movement = 'SOLD' and
mh.date_movement >= date '2015-01-01' and
mh.date_movement < date '2016-01-01' and
mh.prev_ccc = 5;





share|improve this answer




















  • Without using lag is ther any possibility?
    – artyui berwaf
    Nov 10 at 17:29







  • 1




    @artyuiberwaf . . . lag() is the simplest solution and should have the best performance. I see no reason not to use it.
    – Gordon Linoff
    Nov 10 at 17:38














up vote
1
down vote













I see. The current_company_code is the company that got the car. So, you want to use LAG():



select mh.*
from (select mh.*,
lag(mh.current_company_code) over (partition by mh.code_car order by date_movement) as prev_ccc
from movement_history mh
) mh
where mh.type_movement = 'SOLD' and
mh.date_movement >= date '2015-01-01' and
mh.date_movement < date '2016-01-01' and
mh.prev_ccc = 5;





share|improve this answer




















  • Without using lag is ther any possibility?
    – artyui berwaf
    Nov 10 at 17:29







  • 1




    @artyuiberwaf . . . lag() is the simplest solution and should have the best performance. I see no reason not to use it.
    – Gordon Linoff
    Nov 10 at 17:38












up vote
1
down vote










up vote
1
down vote









I see. The current_company_code is the company that got the car. So, you want to use LAG():



select mh.*
from (select mh.*,
lag(mh.current_company_code) over (partition by mh.code_car order by date_movement) as prev_ccc
from movement_history mh
) mh
where mh.type_movement = 'SOLD' and
mh.date_movement >= date '2015-01-01' and
mh.date_movement < date '2016-01-01' and
mh.prev_ccc = 5;





share|improve this answer












I see. The current_company_code is the company that got the car. So, you want to use LAG():



select mh.*
from (select mh.*,
lag(mh.current_company_code) over (partition by mh.code_car order by date_movement) as prev_ccc
from movement_history mh
) mh
where mh.type_movement = 'SOLD' and
mh.date_movement >= date '2015-01-01' and
mh.date_movement < date '2016-01-01' and
mh.prev_ccc = 5;






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 10 at 17:25









Gordon Linoff

744k32285390




744k32285390











  • Without using lag is ther any possibility?
    – artyui berwaf
    Nov 10 at 17:29







  • 1




    @artyuiberwaf . . . lag() is the simplest solution and should have the best performance. I see no reason not to use it.
    – Gordon Linoff
    Nov 10 at 17:38
















  • Without using lag is ther any possibility?
    – artyui berwaf
    Nov 10 at 17:29







  • 1




    @artyuiberwaf . . . lag() is the simplest solution and should have the best performance. I see no reason not to use it.
    – Gordon Linoff
    Nov 10 at 17:38















Without using lag is ther any possibility?
– artyui berwaf
Nov 10 at 17:29





Without using lag is ther any possibility?
– artyui berwaf
Nov 10 at 17:29





1




1




@artyuiberwaf . . . lag() is the simplest solution and should have the best performance. I see no reason not to use it.
– Gordon Linoff
Nov 10 at 17:38




@artyuiberwaf . . . lag() is the simplest solution and should have the best performance. I see no reason not to use it.
– Gordon Linoff
Nov 10 at 17:38

















 

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