Is it possible to disable bool operator<(float,int)










0















Can I, in C++, disable or force an explicit cast in operator< when comparing integer and floating types? Using operator< between integer and float types can easily lead to bugs in quantitative code. I tried bool operator<(double, int) = delete; but it expects one of the types to be a class or enum. How do I make the below fail to compile with a type error?



int main()

if (3.0 < 4)

std::cout << "X" << std::endl;

else

std::cout << "Y" << std::endl;

return 0;










share|improve this question






















  • It cannot be done natively. But you can look into various external tests.

    – Mooing Duck
    Nov 13 '18 at 21:43











  • Nuts. Do you mean taking a static analysis approach?

    – Carbon
    Nov 13 '18 at 21:43











  • I don't see the applicability of being able to do this. It's really a contract between the programmer and the compiler to not do stupid things. The end-client can't touch this.

    – DeiDei
    Nov 13 '18 at 21:59











  • In quant finance it's very common to have business users doing dev. I clean up.

    – Carbon
    Nov 13 '18 at 22:37















0















Can I, in C++, disable or force an explicit cast in operator< when comparing integer and floating types? Using operator< between integer and float types can easily lead to bugs in quantitative code. I tried bool operator<(double, int) = delete; but it expects one of the types to be a class or enum. How do I make the below fail to compile with a type error?



int main()

if (3.0 < 4)

std::cout << "X" << std::endl;

else

std::cout << "Y" << std::endl;

return 0;










share|improve this question






















  • It cannot be done natively. But you can look into various external tests.

    – Mooing Duck
    Nov 13 '18 at 21:43











  • Nuts. Do you mean taking a static analysis approach?

    – Carbon
    Nov 13 '18 at 21:43











  • I don't see the applicability of being able to do this. It's really a contract between the programmer and the compiler to not do stupid things. The end-client can't touch this.

    – DeiDei
    Nov 13 '18 at 21:59











  • In quant finance it's very common to have business users doing dev. I clean up.

    – Carbon
    Nov 13 '18 at 22:37













0












0








0








Can I, in C++, disable or force an explicit cast in operator< when comparing integer and floating types? Using operator< between integer and float types can easily lead to bugs in quantitative code. I tried bool operator<(double, int) = delete; but it expects one of the types to be a class or enum. How do I make the below fail to compile with a type error?



int main()

if (3.0 < 4)

std::cout << "X" << std::endl;

else

std::cout << "Y" << std::endl;

return 0;










share|improve this question














Can I, in C++, disable or force an explicit cast in operator< when comparing integer and floating types? Using operator< between integer and float types can easily lead to bugs in quantitative code. I tried bool operator<(double, int) = delete; but it expects one of the types to be a class or enum. How do I make the below fail to compile with a type error?



int main()

if (3.0 < 4)

std::cout << "X" << std::endl;

else

std::cout << "Y" << std::endl;

return 0;







c++






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 13 '18 at 21:41









CarbonCarbon

1,4211926




1,4211926












  • It cannot be done natively. But you can look into various external tests.

    – Mooing Duck
    Nov 13 '18 at 21:43











  • Nuts. Do you mean taking a static analysis approach?

    – Carbon
    Nov 13 '18 at 21:43











  • I don't see the applicability of being able to do this. It's really a contract between the programmer and the compiler to not do stupid things. The end-client can't touch this.

    – DeiDei
    Nov 13 '18 at 21:59











  • In quant finance it's very common to have business users doing dev. I clean up.

    – Carbon
    Nov 13 '18 at 22:37

















  • It cannot be done natively. But you can look into various external tests.

    – Mooing Duck
    Nov 13 '18 at 21:43











  • Nuts. Do you mean taking a static analysis approach?

    – Carbon
    Nov 13 '18 at 21:43











  • I don't see the applicability of being able to do this. It's really a contract between the programmer and the compiler to not do stupid things. The end-client can't touch this.

    – DeiDei
    Nov 13 '18 at 21:59











  • In quant finance it's very common to have business users doing dev. I clean up.

    – Carbon
    Nov 13 '18 at 22:37
















It cannot be done natively. But you can look into various external tests.

– Mooing Duck
Nov 13 '18 at 21:43





It cannot be done natively. But you can look into various external tests.

– Mooing Duck
Nov 13 '18 at 21:43













Nuts. Do you mean taking a static analysis approach?

– Carbon
Nov 13 '18 at 21:43





Nuts. Do you mean taking a static analysis approach?

– Carbon
Nov 13 '18 at 21:43













I don't see the applicability of being able to do this. It's really a contract between the programmer and the compiler to not do stupid things. The end-client can't touch this.

– DeiDei
Nov 13 '18 at 21:59





I don't see the applicability of being able to do this. It's really a contract between the programmer and the compiler to not do stupid things. The end-client can't touch this.

– DeiDei
Nov 13 '18 at 21:59













In quant finance it's very common to have business users doing dev. I clean up.

– Carbon
Nov 13 '18 at 22:37





In quant finance it's very common to have business users doing dev. I clean up.

– Carbon
Nov 13 '18 at 22:37












1 Answer
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It's not possible to change the behaviour of built-in operators. You will have to detect this situation via compiler warnings or other code analysis tools.






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    1 Answer
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    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

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    5














    It's not possible to change the behaviour of built-in operators. You will have to detect this situation via compiler warnings or other code analysis tools.






    share|improve this answer



























      5














      It's not possible to change the behaviour of built-in operators. You will have to detect this situation via compiler warnings or other code analysis tools.






      share|improve this answer

























        5












        5








        5







        It's not possible to change the behaviour of built-in operators. You will have to detect this situation via compiler warnings or other code analysis tools.






        share|improve this answer













        It's not possible to change the behaviour of built-in operators. You will have to detect this situation via compiler warnings or other code analysis tools.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 13 '18 at 21:44









        M.MM.M

        105k11116237




        105k11116237



























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