happening “ java.lang.ExceptionInInitializerError ” Caused by “ Unable to build EntityManagerFactory ” in JPA project









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I want create a web application and use JPA for model layer in MVC for the first time . But I'm having trouble.
The program shows me this error :



Nov 11, 2018 10:56:49 AM org.hibernate.annotations.common.Version <clinit>
INFO: HCANN000001: Hibernate Commons Annotations 4.0.1.Final
Nov 11, 2018 10:56:49 AM org.hibernate.Version logVersion
INFO: HHH000412: Hibernate Core 4.2.0.Final
Nov 11, 2018 10:56:49 AM org.hibernate.cfg.Environment <clinit>
INFO: HHH000205: Loaded properties from resource hibernate.properties: hibernate.connection.driver_class=org.h2.Driver, hibernate.dialect=org.hibernate.dialect.H2Dialect, hibernate.max_fetch_depth=5, hibernate.format_sql=true, hibernate.generate_statistics=true, hibernate.connection.username=sa, hibernate.connection.url=jdbc:h2:mem:db1;DB_CLOSE_DELAY=-1;MVCC=TRUE, hibernate.bytecode.use_reflection_optimizer=false, hibernate.jdbc.batch_versioned_data=true, hibernate.connection.pool_size=5
Nov 11, 2018 10:56:49 AM org.hibernate.cfg.Environment buildBytecodeProvider
INFO: HHH000021: Bytecode provider name : javassist

Exception in thread "main" java.lang.ExceptionInInitializerError
at model.bl.PersonManager.main(PersonManager.java:19)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at com.intellij.rt.execution.application.AppMain.main(AppMain.java:144)

Caused by: javax.persistence.PersistenceException: [PersistenceUnit: MyConnection] Unable to build EntityManagerFactory
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:930)
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:904)
at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:72)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:63)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:47)
at util.JPAProvider.<clinit>(JPAProvider.java:13)
... 6 more

Caused by: org.hibernate.MappingException: Unable to find column with logical name: UID in org.hibernate.mapping.Table(USERS) and its related supertables and secondary tables
at org.hibernate.cfg.Ejb3JoinColumn.checkReferencedColumnsType(Ejb3JoinColumn.java:552)
at org.hibernate.cfg.BinderHelper.createSyntheticPropertyReference(BinderHelper.java:257)
at org.hibernate.cfg.annotations.CollectionBinder.bindCollectionSecondPass(CollectionBinder.java:1331)
at org.hibernate.cfg.annotations.CollectionBinder.bindOneToManySecondPass(CollectionBinder.java:791)
at org.hibernate.cfg.annotations.CollectionBinder.bindStarToManySecondPass(CollectionBinder.java:719)
at org.hibernate.cfg.annotations.CollectionBinder$1.secondPass(CollectionBinder.java:668)
at org.hibernate.cfg.CollectionSecondPass.doSecondPass(CollectionSecondPass.java:66)
at org.hibernate.cfg.Configuration.originalSecondPassCompile(Configuration.java:1593)
at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1350)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1737)
at org.hibernate.ejb.EntityManagerFactoryImpl.<init>(EntityManagerFactoryImpl.java:94)
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:920)
... 11 more


Person class :



package model.entity;
import model.bl.PersonManager;
import javax.persistence.*;
import java.io.Serializable;
import java.util.List;

//mapping class to table
@Entity (name = "person")
@Table(name = "USERS")
@EntityListeners(value = PersonManager.class)

public class Person implements Serializable


@Id // create id and fill auto by sequence in database
@Column(name="UID" ,columnDefinition = "NUMBER" )
@SequenceGenerator(name = "mySeq" , sequenceName = "DB_MYSEQ")
@GeneratedValue(strategy=GenerationType.AUTO ,generator="mySeq")
private long uId;


@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumn(name = "FK_PERSON",referencedColumnName = "UID")
private List<Pictures> picturesList;


@Basic
@Column (name = "USERNAME" , columnDefinition = "NVARCHAR2(30)" , nullable = false , unique = true)
private String username ;

@Basic
@Column (name = "USER_PASSWORD" , columnDefinition = "NVARCHAR2(32)" , nullable = false , unique = true)
private String password ;

@Basic
@Column (name = "EMAIL" , columnDefinition = "NVARCHAR2(40)" , nullable = false)
private String email;


@Basic
@Column (name = "SEX" , columnDefinition = "NVARCHAR2(20)")
private String sex ;

//--------------------------------------------------------

public Person()

public Person(String username, String password, String email, String sex, String userPic)
this.username = username;
this.password = password;
this.email = email;
this.sex = sex;
this.userPic = userPic;

public Person(String username, String password, String email ,String sex, String userPic,List<Pictures> picturesList )
this.picturesList = picturesList;
this.sex = sex;
this.userPic = userPic;
this.email = email;
this.password = password;
this.username = username;


//--------------------------------------------------------

public void setUsername(String username)
this.username = username;


public void setPassword(String password)
this.password = password;


public void setEmail(String email)
this.email = email;


public void setUserPic(String userPic)
this.userPic = userPic;


public void setSex(String sex)
this.sex = sex;


public void setuId(long uId) this.uId = uId;

//--------------------------------------------------------

public String getUsername()
return username;


public String getPassword()
return password;


public String getUserPic()
return userPic;


public String getEmail()
return email;


public String getSex()
return sex;


public long getuId() return uId;


}


Pictures class :



package model.entity;

import javax.persistence.*;
import java.io.Serializable;

@Entity(name = "picture")
@Table(name = "PICTURE")

public class Pictures implements Serializable

@Id // create id and fill auto by sequence in database
@Column(name="PID" ,columnDefinition = "NUMBER" )
@SequenceGenerator(name = "mySeq2" , sequenceName = "DB_MYSEQ2")
@GeneratedValue(strategy=GenerationType.AUTO ,generator="mySeq2")
private long pId;


@Basic
@Column (name = "PICADRESS" , columnDefinition = "NVARCHAR2(50)" , nullable = false)
private String picAdress ;

@Basic
@Column (name = "CAPTION" , columnDefinition = "LONG")
private String caption;

@Basic // user picture for profile
@Column (name = "LIKES" , columnDefinition = "NUMBER")
private int likes;

//--------------------------------------------------------
public Pictures()

public Pictures( String picAdress, String caption, int likes)
this.picAdress = picAdress;
this.caption = caption;
this.likes = likes;

//--------------------------------------------------------

public void setPid(long pid)
this.pId = pid;


public void setLikes(int likes)
this.likes = likes;


public void setPicAdress(String picAdress)
this.picAdress = picAdress;


public void setCaption(String caption)
this.caption = caption;


//--------------------------------------------------------

public int getLikes()
return likes;


public String getCaption()
return caption;


public String getPicAdress()
return picAdress;


public long getPid()
return pId;




my JPA Provider is :



public class JPAProvider 

private static final EntityManagerFactory entityManagerFactory;//instate of session for connect to database
static
entityManagerFactory = Persistence.createEntityManagerFactory("MyConnection");


public static EntityManagerFactory getEntityManagerFactory()
return entityManagerFactory;




PersonManager class is :



public class PersonManager 

public static void main(String args)

EntityManager entityManager = JPAProvider.getEntityManagerFactory().createEntityManager();
EntityTransaction entityTransaction = entityManager.getTransaction();
entityTransaction.begin();

Person person = new Person("midas" , "midas123" , "aaaaa@gmail.com", "female" ,"female-user.png" );
Pictures pictures = new Pictures("aaa" , "akflkkglhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh" ,2);
Pictures pictures2 = new Pictures("nnbnbn" , "affddAlllllllllllllllllllllllllllllllllllll" ,5);
List<Pictures> picturesList =new ArrayList<Pictures>();
picturesList.add(pictures);
picturesList.add(pictures2);
person.setPicturesList(picturesList);

entityManager.persist(person);
entityTransaction.commit();
entityManager.close();




and persistence.xml :



<persistence-unit name="MyConnection" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.Oracle10gDialect"/>
<property name="hibernate.connection.driver_class" value="oracle.jdbc.driver.OracleDriver"/>
<property name="hibernate.connection.username" value="midas"/>
<property name="hibernate.connection.password" value="midas123"/>
<property name="hibernate.connection.url" value="jdbc:oracle:thin:@localhost:1521:orcl"/>
<property name="hibernate.hbm2ddl.auto" value="create-drop"/>
<property name="show_sql" value="true"></property>
<property name="hibernate.globally_quoted_identifiers" value="true"/>
</properties>
</persistence-unit>


I used the following libraries :



1)hibernate-enverc-4.2.0.final



2)hibernate-jpa-2.0-api-1.0.1-final.jar



3)tomcat library



my JDK version = 1.8.0-172



my IDE = IntellyJ Idea



I use Oracle 11g .



I tried to solve the problem by solving similar questions, but I could not .
for example I checked the following topics that were more similar to my problem :



[Error creating bean with name 'entityManagerFactory' defined in class path resource : Invocation of init method failed



[Getting Exception in thread "main" java.lang.ExceptionInInitializerError Exception



Additional explanation: No tables have been created in the database so far.










share|improve this question









New contributor




farzane is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.



















  • Is the schema already created on the database?
    – Michael Wiles
    yesterday










  • @MichaelWiles No ، Not made.
    – farzane
    yesterday











  • In passing, I think you should not build the EntityManagerFactory in a static initializer. Its initialization is very susceptible to fail, so putting it here guarantees that you cannot deal with its failing should it happen. The initialization belongs some place else.
    – Arthur Noseda
    yesterday










  • @ArthurNoseda I tested the same program in the same way and it runs correctly. Of course, that program was just a training example for the JPA.
    – farzane
    yesterday










  • looks like column UID is not present can you change hm2ddl property to <property name="hibernate.hbm2ddl.auto" value="create"/> and try
    – Nawnit Sen
    yesterday














up vote
0
down vote

favorite












I want create a web application and use JPA for model layer in MVC for the first time . But I'm having trouble.
The program shows me this error :



Nov 11, 2018 10:56:49 AM org.hibernate.annotations.common.Version <clinit>
INFO: HCANN000001: Hibernate Commons Annotations 4.0.1.Final
Nov 11, 2018 10:56:49 AM org.hibernate.Version logVersion
INFO: HHH000412: Hibernate Core 4.2.0.Final
Nov 11, 2018 10:56:49 AM org.hibernate.cfg.Environment <clinit>
INFO: HHH000205: Loaded properties from resource hibernate.properties: hibernate.connection.driver_class=org.h2.Driver, hibernate.dialect=org.hibernate.dialect.H2Dialect, hibernate.max_fetch_depth=5, hibernate.format_sql=true, hibernate.generate_statistics=true, hibernate.connection.username=sa, hibernate.connection.url=jdbc:h2:mem:db1;DB_CLOSE_DELAY=-1;MVCC=TRUE, hibernate.bytecode.use_reflection_optimizer=false, hibernate.jdbc.batch_versioned_data=true, hibernate.connection.pool_size=5
Nov 11, 2018 10:56:49 AM org.hibernate.cfg.Environment buildBytecodeProvider
INFO: HHH000021: Bytecode provider name : javassist

Exception in thread "main" java.lang.ExceptionInInitializerError
at model.bl.PersonManager.main(PersonManager.java:19)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at com.intellij.rt.execution.application.AppMain.main(AppMain.java:144)

Caused by: javax.persistence.PersistenceException: [PersistenceUnit: MyConnection] Unable to build EntityManagerFactory
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:930)
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:904)
at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:72)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:63)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:47)
at util.JPAProvider.<clinit>(JPAProvider.java:13)
... 6 more

Caused by: org.hibernate.MappingException: Unable to find column with logical name: UID in org.hibernate.mapping.Table(USERS) and its related supertables and secondary tables
at org.hibernate.cfg.Ejb3JoinColumn.checkReferencedColumnsType(Ejb3JoinColumn.java:552)
at org.hibernate.cfg.BinderHelper.createSyntheticPropertyReference(BinderHelper.java:257)
at org.hibernate.cfg.annotations.CollectionBinder.bindCollectionSecondPass(CollectionBinder.java:1331)
at org.hibernate.cfg.annotations.CollectionBinder.bindOneToManySecondPass(CollectionBinder.java:791)
at org.hibernate.cfg.annotations.CollectionBinder.bindStarToManySecondPass(CollectionBinder.java:719)
at org.hibernate.cfg.annotations.CollectionBinder$1.secondPass(CollectionBinder.java:668)
at org.hibernate.cfg.CollectionSecondPass.doSecondPass(CollectionSecondPass.java:66)
at org.hibernate.cfg.Configuration.originalSecondPassCompile(Configuration.java:1593)
at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1350)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1737)
at org.hibernate.ejb.EntityManagerFactoryImpl.<init>(EntityManagerFactoryImpl.java:94)
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:920)
... 11 more


Person class :



package model.entity;
import model.bl.PersonManager;
import javax.persistence.*;
import java.io.Serializable;
import java.util.List;

//mapping class to table
@Entity (name = "person")
@Table(name = "USERS")
@EntityListeners(value = PersonManager.class)

public class Person implements Serializable


@Id // create id and fill auto by sequence in database
@Column(name="UID" ,columnDefinition = "NUMBER" )
@SequenceGenerator(name = "mySeq" , sequenceName = "DB_MYSEQ")
@GeneratedValue(strategy=GenerationType.AUTO ,generator="mySeq")
private long uId;


@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumn(name = "FK_PERSON",referencedColumnName = "UID")
private List<Pictures> picturesList;


@Basic
@Column (name = "USERNAME" , columnDefinition = "NVARCHAR2(30)" , nullable = false , unique = true)
private String username ;

@Basic
@Column (name = "USER_PASSWORD" , columnDefinition = "NVARCHAR2(32)" , nullable = false , unique = true)
private String password ;

@Basic
@Column (name = "EMAIL" , columnDefinition = "NVARCHAR2(40)" , nullable = false)
private String email;


@Basic
@Column (name = "SEX" , columnDefinition = "NVARCHAR2(20)")
private String sex ;

//--------------------------------------------------------

public Person()

public Person(String username, String password, String email, String sex, String userPic)
this.username = username;
this.password = password;
this.email = email;
this.sex = sex;
this.userPic = userPic;

public Person(String username, String password, String email ,String sex, String userPic,List<Pictures> picturesList )
this.picturesList = picturesList;
this.sex = sex;
this.userPic = userPic;
this.email = email;
this.password = password;
this.username = username;


//--------------------------------------------------------

public void setUsername(String username)
this.username = username;


public void setPassword(String password)
this.password = password;


public void setEmail(String email)
this.email = email;


public void setUserPic(String userPic)
this.userPic = userPic;


public void setSex(String sex)
this.sex = sex;


public void setuId(long uId) this.uId = uId;

//--------------------------------------------------------

public String getUsername()
return username;


public String getPassword()
return password;


public String getUserPic()
return userPic;


public String getEmail()
return email;


public String getSex()
return sex;


public long getuId() return uId;


}


Pictures class :



package model.entity;

import javax.persistence.*;
import java.io.Serializable;

@Entity(name = "picture")
@Table(name = "PICTURE")

public class Pictures implements Serializable

@Id // create id and fill auto by sequence in database
@Column(name="PID" ,columnDefinition = "NUMBER" )
@SequenceGenerator(name = "mySeq2" , sequenceName = "DB_MYSEQ2")
@GeneratedValue(strategy=GenerationType.AUTO ,generator="mySeq2")
private long pId;


@Basic
@Column (name = "PICADRESS" , columnDefinition = "NVARCHAR2(50)" , nullable = false)
private String picAdress ;

@Basic
@Column (name = "CAPTION" , columnDefinition = "LONG")
private String caption;

@Basic // user picture for profile
@Column (name = "LIKES" , columnDefinition = "NUMBER")
private int likes;

//--------------------------------------------------------
public Pictures()

public Pictures( String picAdress, String caption, int likes)
this.picAdress = picAdress;
this.caption = caption;
this.likes = likes;

//--------------------------------------------------------

public void setPid(long pid)
this.pId = pid;


public void setLikes(int likes)
this.likes = likes;


public void setPicAdress(String picAdress)
this.picAdress = picAdress;


public void setCaption(String caption)
this.caption = caption;


//--------------------------------------------------------

public int getLikes()
return likes;


public String getCaption()
return caption;


public String getPicAdress()
return picAdress;


public long getPid()
return pId;




my JPA Provider is :



public class JPAProvider 

private static final EntityManagerFactory entityManagerFactory;//instate of session for connect to database
static
entityManagerFactory = Persistence.createEntityManagerFactory("MyConnection");


public static EntityManagerFactory getEntityManagerFactory()
return entityManagerFactory;




PersonManager class is :



public class PersonManager 

public static void main(String args)

EntityManager entityManager = JPAProvider.getEntityManagerFactory().createEntityManager();
EntityTransaction entityTransaction = entityManager.getTransaction();
entityTransaction.begin();

Person person = new Person("midas" , "midas123" , "aaaaa@gmail.com", "female" ,"female-user.png" );
Pictures pictures = new Pictures("aaa" , "akflkkglhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh" ,2);
Pictures pictures2 = new Pictures("nnbnbn" , "affddAlllllllllllllllllllllllllllllllllllll" ,5);
List<Pictures> picturesList =new ArrayList<Pictures>();
picturesList.add(pictures);
picturesList.add(pictures2);
person.setPicturesList(picturesList);

entityManager.persist(person);
entityTransaction.commit();
entityManager.close();




and persistence.xml :



<persistence-unit name="MyConnection" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.Oracle10gDialect"/>
<property name="hibernate.connection.driver_class" value="oracle.jdbc.driver.OracleDriver"/>
<property name="hibernate.connection.username" value="midas"/>
<property name="hibernate.connection.password" value="midas123"/>
<property name="hibernate.connection.url" value="jdbc:oracle:thin:@localhost:1521:orcl"/>
<property name="hibernate.hbm2ddl.auto" value="create-drop"/>
<property name="show_sql" value="true"></property>
<property name="hibernate.globally_quoted_identifiers" value="true"/>
</properties>
</persistence-unit>


I used the following libraries :



1)hibernate-enverc-4.2.0.final



2)hibernate-jpa-2.0-api-1.0.1-final.jar



3)tomcat library



my JDK version = 1.8.0-172



my IDE = IntellyJ Idea



I use Oracle 11g .



I tried to solve the problem by solving similar questions, but I could not .
for example I checked the following topics that were more similar to my problem :



[Error creating bean with name 'entityManagerFactory' defined in class path resource : Invocation of init method failed



[Getting Exception in thread "main" java.lang.ExceptionInInitializerError Exception



Additional explanation: No tables have been created in the database so far.










share|improve this question









New contributor




farzane is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.



















  • Is the schema already created on the database?
    – Michael Wiles
    yesterday










  • @MichaelWiles No ، Not made.
    – farzane
    yesterday











  • In passing, I think you should not build the EntityManagerFactory in a static initializer. Its initialization is very susceptible to fail, so putting it here guarantees that you cannot deal with its failing should it happen. The initialization belongs some place else.
    – Arthur Noseda
    yesterday










  • @ArthurNoseda I tested the same program in the same way and it runs correctly. Of course, that program was just a training example for the JPA.
    – farzane
    yesterday










  • looks like column UID is not present can you change hm2ddl property to <property name="hibernate.hbm2ddl.auto" value="create"/> and try
    – Nawnit Sen
    yesterday












up vote
0
down vote

favorite









up vote
0
down vote

favorite











I want create a web application and use JPA for model layer in MVC for the first time . But I'm having trouble.
The program shows me this error :



Nov 11, 2018 10:56:49 AM org.hibernate.annotations.common.Version <clinit>
INFO: HCANN000001: Hibernate Commons Annotations 4.0.1.Final
Nov 11, 2018 10:56:49 AM org.hibernate.Version logVersion
INFO: HHH000412: Hibernate Core 4.2.0.Final
Nov 11, 2018 10:56:49 AM org.hibernate.cfg.Environment <clinit>
INFO: HHH000205: Loaded properties from resource hibernate.properties: hibernate.connection.driver_class=org.h2.Driver, hibernate.dialect=org.hibernate.dialect.H2Dialect, hibernate.max_fetch_depth=5, hibernate.format_sql=true, hibernate.generate_statistics=true, hibernate.connection.username=sa, hibernate.connection.url=jdbc:h2:mem:db1;DB_CLOSE_DELAY=-1;MVCC=TRUE, hibernate.bytecode.use_reflection_optimizer=false, hibernate.jdbc.batch_versioned_data=true, hibernate.connection.pool_size=5
Nov 11, 2018 10:56:49 AM org.hibernate.cfg.Environment buildBytecodeProvider
INFO: HHH000021: Bytecode provider name : javassist

Exception in thread "main" java.lang.ExceptionInInitializerError
at model.bl.PersonManager.main(PersonManager.java:19)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at com.intellij.rt.execution.application.AppMain.main(AppMain.java:144)

Caused by: javax.persistence.PersistenceException: [PersistenceUnit: MyConnection] Unable to build EntityManagerFactory
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:930)
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:904)
at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:72)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:63)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:47)
at util.JPAProvider.<clinit>(JPAProvider.java:13)
... 6 more

Caused by: org.hibernate.MappingException: Unable to find column with logical name: UID in org.hibernate.mapping.Table(USERS) and its related supertables and secondary tables
at org.hibernate.cfg.Ejb3JoinColumn.checkReferencedColumnsType(Ejb3JoinColumn.java:552)
at org.hibernate.cfg.BinderHelper.createSyntheticPropertyReference(BinderHelper.java:257)
at org.hibernate.cfg.annotations.CollectionBinder.bindCollectionSecondPass(CollectionBinder.java:1331)
at org.hibernate.cfg.annotations.CollectionBinder.bindOneToManySecondPass(CollectionBinder.java:791)
at org.hibernate.cfg.annotations.CollectionBinder.bindStarToManySecondPass(CollectionBinder.java:719)
at org.hibernate.cfg.annotations.CollectionBinder$1.secondPass(CollectionBinder.java:668)
at org.hibernate.cfg.CollectionSecondPass.doSecondPass(CollectionSecondPass.java:66)
at org.hibernate.cfg.Configuration.originalSecondPassCompile(Configuration.java:1593)
at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1350)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1737)
at org.hibernate.ejb.EntityManagerFactoryImpl.<init>(EntityManagerFactoryImpl.java:94)
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:920)
... 11 more


Person class :



package model.entity;
import model.bl.PersonManager;
import javax.persistence.*;
import java.io.Serializable;
import java.util.List;

//mapping class to table
@Entity (name = "person")
@Table(name = "USERS")
@EntityListeners(value = PersonManager.class)

public class Person implements Serializable


@Id // create id and fill auto by sequence in database
@Column(name="UID" ,columnDefinition = "NUMBER" )
@SequenceGenerator(name = "mySeq" , sequenceName = "DB_MYSEQ")
@GeneratedValue(strategy=GenerationType.AUTO ,generator="mySeq")
private long uId;


@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumn(name = "FK_PERSON",referencedColumnName = "UID")
private List<Pictures> picturesList;


@Basic
@Column (name = "USERNAME" , columnDefinition = "NVARCHAR2(30)" , nullable = false , unique = true)
private String username ;

@Basic
@Column (name = "USER_PASSWORD" , columnDefinition = "NVARCHAR2(32)" , nullable = false , unique = true)
private String password ;

@Basic
@Column (name = "EMAIL" , columnDefinition = "NVARCHAR2(40)" , nullable = false)
private String email;


@Basic
@Column (name = "SEX" , columnDefinition = "NVARCHAR2(20)")
private String sex ;

//--------------------------------------------------------

public Person()

public Person(String username, String password, String email, String sex, String userPic)
this.username = username;
this.password = password;
this.email = email;
this.sex = sex;
this.userPic = userPic;

public Person(String username, String password, String email ,String sex, String userPic,List<Pictures> picturesList )
this.picturesList = picturesList;
this.sex = sex;
this.userPic = userPic;
this.email = email;
this.password = password;
this.username = username;


//--------------------------------------------------------

public void setUsername(String username)
this.username = username;


public void setPassword(String password)
this.password = password;


public void setEmail(String email)
this.email = email;


public void setUserPic(String userPic)
this.userPic = userPic;


public void setSex(String sex)
this.sex = sex;


public void setuId(long uId) this.uId = uId;

//--------------------------------------------------------

public String getUsername()
return username;


public String getPassword()
return password;


public String getUserPic()
return userPic;


public String getEmail()
return email;


public String getSex()
return sex;


public long getuId() return uId;


}


Pictures class :



package model.entity;

import javax.persistence.*;
import java.io.Serializable;

@Entity(name = "picture")
@Table(name = "PICTURE")

public class Pictures implements Serializable

@Id // create id and fill auto by sequence in database
@Column(name="PID" ,columnDefinition = "NUMBER" )
@SequenceGenerator(name = "mySeq2" , sequenceName = "DB_MYSEQ2")
@GeneratedValue(strategy=GenerationType.AUTO ,generator="mySeq2")
private long pId;


@Basic
@Column (name = "PICADRESS" , columnDefinition = "NVARCHAR2(50)" , nullable = false)
private String picAdress ;

@Basic
@Column (name = "CAPTION" , columnDefinition = "LONG")
private String caption;

@Basic // user picture for profile
@Column (name = "LIKES" , columnDefinition = "NUMBER")
private int likes;

//--------------------------------------------------------
public Pictures()

public Pictures( String picAdress, String caption, int likes)
this.picAdress = picAdress;
this.caption = caption;
this.likes = likes;

//--------------------------------------------------------

public void setPid(long pid)
this.pId = pid;


public void setLikes(int likes)
this.likes = likes;


public void setPicAdress(String picAdress)
this.picAdress = picAdress;


public void setCaption(String caption)
this.caption = caption;


//--------------------------------------------------------

public int getLikes()
return likes;


public String getCaption()
return caption;


public String getPicAdress()
return picAdress;


public long getPid()
return pId;




my JPA Provider is :



public class JPAProvider 

private static final EntityManagerFactory entityManagerFactory;//instate of session for connect to database
static
entityManagerFactory = Persistence.createEntityManagerFactory("MyConnection");


public static EntityManagerFactory getEntityManagerFactory()
return entityManagerFactory;




PersonManager class is :



public class PersonManager 

public static void main(String args)

EntityManager entityManager = JPAProvider.getEntityManagerFactory().createEntityManager();
EntityTransaction entityTransaction = entityManager.getTransaction();
entityTransaction.begin();

Person person = new Person("midas" , "midas123" , "aaaaa@gmail.com", "female" ,"female-user.png" );
Pictures pictures = new Pictures("aaa" , "akflkkglhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh" ,2);
Pictures pictures2 = new Pictures("nnbnbn" , "affddAlllllllllllllllllllllllllllllllllllll" ,5);
List<Pictures> picturesList =new ArrayList<Pictures>();
picturesList.add(pictures);
picturesList.add(pictures2);
person.setPicturesList(picturesList);

entityManager.persist(person);
entityTransaction.commit();
entityManager.close();




and persistence.xml :



<persistence-unit name="MyConnection" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.Oracle10gDialect"/>
<property name="hibernate.connection.driver_class" value="oracle.jdbc.driver.OracleDriver"/>
<property name="hibernate.connection.username" value="midas"/>
<property name="hibernate.connection.password" value="midas123"/>
<property name="hibernate.connection.url" value="jdbc:oracle:thin:@localhost:1521:orcl"/>
<property name="hibernate.hbm2ddl.auto" value="create-drop"/>
<property name="show_sql" value="true"></property>
<property name="hibernate.globally_quoted_identifiers" value="true"/>
</properties>
</persistence-unit>


I used the following libraries :



1)hibernate-enverc-4.2.0.final



2)hibernate-jpa-2.0-api-1.0.1-final.jar



3)tomcat library



my JDK version = 1.8.0-172



my IDE = IntellyJ Idea



I use Oracle 11g .



I tried to solve the problem by solving similar questions, but I could not .
for example I checked the following topics that were more similar to my problem :



[Error creating bean with name 'entityManagerFactory' defined in class path resource : Invocation of init method failed



[Getting Exception in thread "main" java.lang.ExceptionInInitializerError Exception



Additional explanation: No tables have been created in the database so far.










share|improve this question









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Check out our Code of Conduct.











I want create a web application and use JPA for model layer in MVC for the first time . But I'm having trouble.
The program shows me this error :



Nov 11, 2018 10:56:49 AM org.hibernate.annotations.common.Version <clinit>
INFO: HCANN000001: Hibernate Commons Annotations 4.0.1.Final
Nov 11, 2018 10:56:49 AM org.hibernate.Version logVersion
INFO: HHH000412: Hibernate Core 4.2.0.Final
Nov 11, 2018 10:56:49 AM org.hibernate.cfg.Environment <clinit>
INFO: HHH000205: Loaded properties from resource hibernate.properties: hibernate.connection.driver_class=org.h2.Driver, hibernate.dialect=org.hibernate.dialect.H2Dialect, hibernate.max_fetch_depth=5, hibernate.format_sql=true, hibernate.generate_statistics=true, hibernate.connection.username=sa, hibernate.connection.url=jdbc:h2:mem:db1;DB_CLOSE_DELAY=-1;MVCC=TRUE, hibernate.bytecode.use_reflection_optimizer=false, hibernate.jdbc.batch_versioned_data=true, hibernate.connection.pool_size=5
Nov 11, 2018 10:56:49 AM org.hibernate.cfg.Environment buildBytecodeProvider
INFO: HHH000021: Bytecode provider name : javassist

Exception in thread "main" java.lang.ExceptionInInitializerError
at model.bl.PersonManager.main(PersonManager.java:19)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at com.intellij.rt.execution.application.AppMain.main(AppMain.java:144)

Caused by: javax.persistence.PersistenceException: [PersistenceUnit: MyConnection] Unable to build EntityManagerFactory
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:930)
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:904)
at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:72)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:63)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:47)
at util.JPAProvider.<clinit>(JPAProvider.java:13)
... 6 more

Caused by: org.hibernate.MappingException: Unable to find column with logical name: UID in org.hibernate.mapping.Table(USERS) and its related supertables and secondary tables
at org.hibernate.cfg.Ejb3JoinColumn.checkReferencedColumnsType(Ejb3JoinColumn.java:552)
at org.hibernate.cfg.BinderHelper.createSyntheticPropertyReference(BinderHelper.java:257)
at org.hibernate.cfg.annotations.CollectionBinder.bindCollectionSecondPass(CollectionBinder.java:1331)
at org.hibernate.cfg.annotations.CollectionBinder.bindOneToManySecondPass(CollectionBinder.java:791)
at org.hibernate.cfg.annotations.CollectionBinder.bindStarToManySecondPass(CollectionBinder.java:719)
at org.hibernate.cfg.annotations.CollectionBinder$1.secondPass(CollectionBinder.java:668)
at org.hibernate.cfg.CollectionSecondPass.doSecondPass(CollectionSecondPass.java:66)
at org.hibernate.cfg.Configuration.originalSecondPassCompile(Configuration.java:1593)
at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1350)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1737)
at org.hibernate.ejb.EntityManagerFactoryImpl.<init>(EntityManagerFactoryImpl.java:94)
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:920)
... 11 more


Person class :



package model.entity;
import model.bl.PersonManager;
import javax.persistence.*;
import java.io.Serializable;
import java.util.List;

//mapping class to table
@Entity (name = "person")
@Table(name = "USERS")
@EntityListeners(value = PersonManager.class)

public class Person implements Serializable


@Id // create id and fill auto by sequence in database
@Column(name="UID" ,columnDefinition = "NUMBER" )
@SequenceGenerator(name = "mySeq" , sequenceName = "DB_MYSEQ")
@GeneratedValue(strategy=GenerationType.AUTO ,generator="mySeq")
private long uId;


@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumn(name = "FK_PERSON",referencedColumnName = "UID")
private List<Pictures> picturesList;


@Basic
@Column (name = "USERNAME" , columnDefinition = "NVARCHAR2(30)" , nullable = false , unique = true)
private String username ;

@Basic
@Column (name = "USER_PASSWORD" , columnDefinition = "NVARCHAR2(32)" , nullable = false , unique = true)
private String password ;

@Basic
@Column (name = "EMAIL" , columnDefinition = "NVARCHAR2(40)" , nullable = false)
private String email;


@Basic
@Column (name = "SEX" , columnDefinition = "NVARCHAR2(20)")
private String sex ;

//--------------------------------------------------------

public Person()

public Person(String username, String password, String email, String sex, String userPic)
this.username = username;
this.password = password;
this.email = email;
this.sex = sex;
this.userPic = userPic;

public Person(String username, String password, String email ,String sex, String userPic,List<Pictures> picturesList )
this.picturesList = picturesList;
this.sex = sex;
this.userPic = userPic;
this.email = email;
this.password = password;
this.username = username;


//--------------------------------------------------------

public void setUsername(String username)
this.username = username;


public void setPassword(String password)
this.password = password;


public void setEmail(String email)
this.email = email;


public void setUserPic(String userPic)
this.userPic = userPic;


public void setSex(String sex)
this.sex = sex;


public void setuId(long uId) this.uId = uId;

//--------------------------------------------------------

public String getUsername()
return username;


public String getPassword()
return password;


public String getUserPic()
return userPic;


public String getEmail()
return email;


public String getSex()
return sex;


public long getuId() return uId;


}


Pictures class :



package model.entity;

import javax.persistence.*;
import java.io.Serializable;

@Entity(name = "picture")
@Table(name = "PICTURE")

public class Pictures implements Serializable

@Id // create id and fill auto by sequence in database
@Column(name="PID" ,columnDefinition = "NUMBER" )
@SequenceGenerator(name = "mySeq2" , sequenceName = "DB_MYSEQ2")
@GeneratedValue(strategy=GenerationType.AUTO ,generator="mySeq2")
private long pId;


@Basic
@Column (name = "PICADRESS" , columnDefinition = "NVARCHAR2(50)" , nullable = false)
private String picAdress ;

@Basic
@Column (name = "CAPTION" , columnDefinition = "LONG")
private String caption;

@Basic // user picture for profile
@Column (name = "LIKES" , columnDefinition = "NUMBER")
private int likes;

//--------------------------------------------------------
public Pictures()

public Pictures( String picAdress, String caption, int likes)
this.picAdress = picAdress;
this.caption = caption;
this.likes = likes;

//--------------------------------------------------------

public void setPid(long pid)
this.pId = pid;


public void setLikes(int likes)
this.likes = likes;


public void setPicAdress(String picAdress)
this.picAdress = picAdress;


public void setCaption(String caption)
this.caption = caption;


//--------------------------------------------------------

public int getLikes()
return likes;


public String getCaption()
return caption;


public String getPicAdress()
return picAdress;


public long getPid()
return pId;




my JPA Provider is :



public class JPAProvider 

private static final EntityManagerFactory entityManagerFactory;//instate of session for connect to database
static
entityManagerFactory = Persistence.createEntityManagerFactory("MyConnection");


public static EntityManagerFactory getEntityManagerFactory()
return entityManagerFactory;




PersonManager class is :



public class PersonManager 

public static void main(String args)

EntityManager entityManager = JPAProvider.getEntityManagerFactory().createEntityManager();
EntityTransaction entityTransaction = entityManager.getTransaction();
entityTransaction.begin();

Person person = new Person("midas" , "midas123" , "aaaaa@gmail.com", "female" ,"female-user.png" );
Pictures pictures = new Pictures("aaa" , "akflkkglhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh" ,2);
Pictures pictures2 = new Pictures("nnbnbn" , "affddAlllllllllllllllllllllllllllllllllllll" ,5);
List<Pictures> picturesList =new ArrayList<Pictures>();
picturesList.add(pictures);
picturesList.add(pictures2);
person.setPicturesList(picturesList);

entityManager.persist(person);
entityTransaction.commit();
entityManager.close();




and persistence.xml :



<persistence-unit name="MyConnection" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.Oracle10gDialect"/>
<property name="hibernate.connection.driver_class" value="oracle.jdbc.driver.OracleDriver"/>
<property name="hibernate.connection.username" value="midas"/>
<property name="hibernate.connection.password" value="midas123"/>
<property name="hibernate.connection.url" value="jdbc:oracle:thin:@localhost:1521:orcl"/>
<property name="hibernate.hbm2ddl.auto" value="create-drop"/>
<property name="show_sql" value="true"></property>
<property name="hibernate.globally_quoted_identifiers" value="true"/>
</properties>
</persistence-unit>


I used the following libraries :



1)hibernate-enverc-4.2.0.final



2)hibernate-jpa-2.0-api-1.0.1-final.jar



3)tomcat library



my JDK version = 1.8.0-172



my IDE = IntellyJ Idea



I use Oracle 11g .



I tried to solve the problem by solving similar questions, but I could not .
for example I checked the following topics that were more similar to my problem :



[Error creating bean with name 'entityManagerFactory' defined in class path resource : Invocation of init method failed



[Getting Exception in thread "main" java.lang.ExceptionInInitializerError Exception



Additional explanation: No tables have been created in the database so far.







java hibernate jpa model-view-controller






share|improve this question









New contributor




farzane is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




farzane is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 19 hours ago





















New contributor




farzane is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked yesterday









farzane

53




53




New contributor




farzane is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





farzane is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






farzane is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











  • Is the schema already created on the database?
    – Michael Wiles
    yesterday










  • @MichaelWiles No ، Not made.
    – farzane
    yesterday











  • In passing, I think you should not build the EntityManagerFactory in a static initializer. Its initialization is very susceptible to fail, so putting it here guarantees that you cannot deal with its failing should it happen. The initialization belongs some place else.
    – Arthur Noseda
    yesterday










  • @ArthurNoseda I tested the same program in the same way and it runs correctly. Of course, that program was just a training example for the JPA.
    – farzane
    yesterday










  • looks like column UID is not present can you change hm2ddl property to <property name="hibernate.hbm2ddl.auto" value="create"/> and try
    – Nawnit Sen
    yesterday
















  • Is the schema already created on the database?
    – Michael Wiles
    yesterday










  • @MichaelWiles No ، Not made.
    – farzane
    yesterday











  • In passing, I think you should not build the EntityManagerFactory in a static initializer. Its initialization is very susceptible to fail, so putting it here guarantees that you cannot deal with its failing should it happen. The initialization belongs some place else.
    – Arthur Noseda
    yesterday










  • @ArthurNoseda I tested the same program in the same way and it runs correctly. Of course, that program was just a training example for the JPA.
    – farzane
    yesterday










  • looks like column UID is not present can you change hm2ddl property to <property name="hibernate.hbm2ddl.auto" value="create"/> and try
    – Nawnit Sen
    yesterday















Is the schema already created on the database?
– Michael Wiles
yesterday




Is the schema already created on the database?
– Michael Wiles
yesterday












@MichaelWiles No ، Not made.
– farzane
yesterday





@MichaelWiles No ، Not made.
– farzane
yesterday













In passing, I think you should not build the EntityManagerFactory in a static initializer. Its initialization is very susceptible to fail, so putting it here guarantees that you cannot deal with its failing should it happen. The initialization belongs some place else.
– Arthur Noseda
yesterday




In passing, I think you should not build the EntityManagerFactory in a static initializer. Its initialization is very susceptible to fail, so putting it here guarantees that you cannot deal with its failing should it happen. The initialization belongs some place else.
– Arthur Noseda
yesterday












@ArthurNoseda I tested the same program in the same way and it runs correctly. Of course, that program was just a training example for the JPA.
– farzane
yesterday




@ArthurNoseda I tested the same program in the same way and it runs correctly. Of course, that program was just a training example for the JPA.
– farzane
yesterday












looks like column UID is not present can you change hm2ddl property to <property name="hibernate.hbm2ddl.auto" value="create"/> and try
– Nawnit Sen
yesterday




looks like column UID is not present can you change hm2ddl property to <property name="hibernate.hbm2ddl.auto" value="create"/> and try
– Nawnit Sen
yesterday












1 Answer
1






active

oldest

votes

















up vote
0
down vote



accepted










Looks like problem is with @JoinColumn(name = "FK_PERSON",referencedColumnName = "UID")
referencedColumnName attribute points to the related column in asociated/referenced entity, i.e. column name of the primary key. By default it is primary key of associated entity. You are not required to fill the referencedColumnName if the referenced entity has single column as PK, because there is no doubt what column it references (i.e. primary key column of associated entity).
change that line to @JoinColumn(name = "FK_PERSON") it should work.



For more info about referencedColumnName refer to "What is referencedColumnName used for in JPA?"






share|improve this answer




















  • Thanks so much for your follow up and help . This error seems to be fixed , but I encountered another error :(
    – farzane
    16 hours ago











  • if you find my answer helpful please mark it is accepted.:) BTW what is another error that you are getting?
    – Nawnit Sen
    16 hours ago










  • javax.persistence.RollbackException: Error while committing the transaction--->Caused by:javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute statement--->Caused by: org.hibernate.exception.SQLGrammarException: could not execute statement--->Caused by: java.sql.SQLSyntaxErrorException: ORA-00942: table or view does not exist
    – farzane
    16 hours ago











  • it says table doesnt exist...just check in the db if that particular table exist or not
    – Nawnit Sen
    16 hours ago






  • 1




    I created my table by sql plus and run program . program was run correctly. tank you Nawinit Sen :)
    – farzane
    15 hours ago










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
0
down vote



accepted










Looks like problem is with @JoinColumn(name = "FK_PERSON",referencedColumnName = "UID")
referencedColumnName attribute points to the related column in asociated/referenced entity, i.e. column name of the primary key. By default it is primary key of associated entity. You are not required to fill the referencedColumnName if the referenced entity has single column as PK, because there is no doubt what column it references (i.e. primary key column of associated entity).
change that line to @JoinColumn(name = "FK_PERSON") it should work.



For more info about referencedColumnName refer to "What is referencedColumnName used for in JPA?"






share|improve this answer




















  • Thanks so much for your follow up and help . This error seems to be fixed , but I encountered another error :(
    – farzane
    16 hours ago











  • if you find my answer helpful please mark it is accepted.:) BTW what is another error that you are getting?
    – Nawnit Sen
    16 hours ago










  • javax.persistence.RollbackException: Error while committing the transaction--->Caused by:javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute statement--->Caused by: org.hibernate.exception.SQLGrammarException: could not execute statement--->Caused by: java.sql.SQLSyntaxErrorException: ORA-00942: table or view does not exist
    – farzane
    16 hours ago











  • it says table doesnt exist...just check in the db if that particular table exist or not
    – Nawnit Sen
    16 hours ago






  • 1




    I created my table by sql plus and run program . program was run correctly. tank you Nawinit Sen :)
    – farzane
    15 hours ago














up vote
0
down vote



accepted










Looks like problem is with @JoinColumn(name = "FK_PERSON",referencedColumnName = "UID")
referencedColumnName attribute points to the related column in asociated/referenced entity, i.e. column name of the primary key. By default it is primary key of associated entity. You are not required to fill the referencedColumnName if the referenced entity has single column as PK, because there is no doubt what column it references (i.e. primary key column of associated entity).
change that line to @JoinColumn(name = "FK_PERSON") it should work.



For more info about referencedColumnName refer to "What is referencedColumnName used for in JPA?"






share|improve this answer




















  • Thanks so much for your follow up and help . This error seems to be fixed , but I encountered another error :(
    – farzane
    16 hours ago











  • if you find my answer helpful please mark it is accepted.:) BTW what is another error that you are getting?
    – Nawnit Sen
    16 hours ago










  • javax.persistence.RollbackException: Error while committing the transaction--->Caused by:javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute statement--->Caused by: org.hibernate.exception.SQLGrammarException: could not execute statement--->Caused by: java.sql.SQLSyntaxErrorException: ORA-00942: table or view does not exist
    – farzane
    16 hours ago











  • it says table doesnt exist...just check in the db if that particular table exist or not
    – Nawnit Sen
    16 hours ago






  • 1




    I created my table by sql plus and run program . program was run correctly. tank you Nawinit Sen :)
    – farzane
    15 hours ago












up vote
0
down vote



accepted







up vote
0
down vote



accepted






Looks like problem is with @JoinColumn(name = "FK_PERSON",referencedColumnName = "UID")
referencedColumnName attribute points to the related column in asociated/referenced entity, i.e. column name of the primary key. By default it is primary key of associated entity. You are not required to fill the referencedColumnName if the referenced entity has single column as PK, because there is no doubt what column it references (i.e. primary key column of associated entity).
change that line to @JoinColumn(name = "FK_PERSON") it should work.



For more info about referencedColumnName refer to "What is referencedColumnName used for in JPA?"






share|improve this answer












Looks like problem is with @JoinColumn(name = "FK_PERSON",referencedColumnName = "UID")
referencedColumnName attribute points to the related column in asociated/referenced entity, i.e. column name of the primary key. By default it is primary key of associated entity. You are not required to fill the referencedColumnName if the referenced entity has single column as PK, because there is no doubt what column it references (i.e. primary key column of associated entity).
change that line to @JoinColumn(name = "FK_PERSON") it should work.



For more info about referencedColumnName refer to "What is referencedColumnName used for in JPA?"







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answered 17 hours ago









Nawnit Sen

31225




31225











  • Thanks so much for your follow up and help . This error seems to be fixed , but I encountered another error :(
    – farzane
    16 hours ago











  • if you find my answer helpful please mark it is accepted.:) BTW what is another error that you are getting?
    – Nawnit Sen
    16 hours ago










  • javax.persistence.RollbackException: Error while committing the transaction--->Caused by:javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute statement--->Caused by: org.hibernate.exception.SQLGrammarException: could not execute statement--->Caused by: java.sql.SQLSyntaxErrorException: ORA-00942: table or view does not exist
    – farzane
    16 hours ago











  • it says table doesnt exist...just check in the db if that particular table exist or not
    – Nawnit Sen
    16 hours ago






  • 1




    I created my table by sql plus and run program . program was run correctly. tank you Nawinit Sen :)
    – farzane
    15 hours ago
















  • Thanks so much for your follow up and help . This error seems to be fixed , but I encountered another error :(
    – farzane
    16 hours ago











  • if you find my answer helpful please mark it is accepted.:) BTW what is another error that you are getting?
    – Nawnit Sen
    16 hours ago










  • javax.persistence.RollbackException: Error while committing the transaction--->Caused by:javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute statement--->Caused by: org.hibernate.exception.SQLGrammarException: could not execute statement--->Caused by: java.sql.SQLSyntaxErrorException: ORA-00942: table or view does not exist
    – farzane
    16 hours ago











  • it says table doesnt exist...just check in the db if that particular table exist or not
    – Nawnit Sen
    16 hours ago






  • 1




    I created my table by sql plus and run program . program was run correctly. tank you Nawinit Sen :)
    – farzane
    15 hours ago















Thanks so much for your follow up and help . This error seems to be fixed , but I encountered another error :(
– farzane
16 hours ago





Thanks so much for your follow up and help . This error seems to be fixed , but I encountered another error :(
– farzane
16 hours ago













if you find my answer helpful please mark it is accepted.:) BTW what is another error that you are getting?
– Nawnit Sen
16 hours ago




if you find my answer helpful please mark it is accepted.:) BTW what is another error that you are getting?
– Nawnit Sen
16 hours ago












javax.persistence.RollbackException: Error while committing the transaction--->Caused by:javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute statement--->Caused by: org.hibernate.exception.SQLGrammarException: could not execute statement--->Caused by: java.sql.SQLSyntaxErrorException: ORA-00942: table or view does not exist
– farzane
16 hours ago





javax.persistence.RollbackException: Error while committing the transaction--->Caused by:javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not execute statement--->Caused by: org.hibernate.exception.SQLGrammarException: could not execute statement--->Caused by: java.sql.SQLSyntaxErrorException: ORA-00942: table or view does not exist
– farzane
16 hours ago













it says table doesnt exist...just check in the db if that particular table exist or not
– Nawnit Sen
16 hours ago




it says table doesnt exist...just check in the db if that particular table exist or not
– Nawnit Sen
16 hours ago




1




1




I created my table by sql plus and run program . program was run correctly. tank you Nawinit Sen :)
– farzane
15 hours ago




I created my table by sql plus and run program . program was run correctly. tank you Nawinit Sen :)
– farzane
15 hours ago










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