Angular 6:services with providedIn: 'root' returns empty object in component
0
My service located in src/core/services/api.service.ts
import Injectable from '@angular/core';
@Injectable(
providedIn: 'root'
)
export class ApiService
constructor()
test()
console.log('hello from services');
I am trying to invoke this service from a component which in another module.
home.component.ts
import Component, OnInit from '@angular/core';
import ApiService from './core/services/api.service';
@Component(
selector: 'app-home',
templateUrl: './home.component.html',
styleUrls: ['./home.component.css']
)
export class HomeComponent implements OnInit
constructor(private api: ApiService)
ngOnInit()
console.log(this.api);
But I am getting an empty object like this ApiService
javascript angular service dependency-injection
asked Nov 14 '18 at 9:31
iam batmaniam batman
2,11532450
add a comment |
0
My service located in src/core/services/api.service.ts
import Injectable from '@angular/core';
@Injectable(
providedIn: 'root'
)
export class ApiService
constructor()
test()
console.log('hello from services');
I am trying to invoke this service from a component which in another module.
home.component.ts
import Component, OnInit from '@angular/core';
import ApiService from './core/services/api.service';
@Component(
selector: 'app-home',
templateUrl: './home.component.html',
styleUrls: ['./home.component.css']
)
export class HomeComponent implements OnInit
constructor(private api: ApiService)
ngOnInit()
console.log(this.api);
But I am getting an empty object like this ApiService
javascript angular service dependency-injection
asked Nov 14 '18 at 9:31
iam batmaniam batman
2,11532450
1
if it's loggingApiService, then that's an ApiService instance, exactly as intended. You can find thetestmethod under the object's prototype. Are you 100% sure this is not working or did you just guess it?
– briosheje
Nov 14 '18 at 9:40
yeah, right! Check this, this stackblitz.com/edit/angular-aizqtqApiServiceworks fine
– qiAlex
Nov 14 '18 at 9:41
Your code is looking and working perfectly fine. No change is needed.
– Sunil Singh
Nov 14 '18 at 9:43
Additionaly, if you don't want to do any sort of call, just do:console.log(this.api instanceof ApiService);, if it logs true, it just works.
– briosheje
Nov 14 '18 at 10:14
add a comment |
0
0
0
My service located in src/core/services/api.service.ts
import Injectable from '@angular/core';
@Injectable(
providedIn: 'root'
)
export class ApiService
constructor()
test()
console.log('hello from services');
I am trying to invoke this service from a component which in another module.
home.component.ts
import Component, OnInit from '@angular/core';
import ApiService from './core/services/api.service';
@Component(
selector: 'app-home',
templateUrl: './home.component.html',
styleUrls: ['./home.component.css']
)
export class HomeComponent implements OnInit
constructor(private api: ApiService)
ngOnInit()
console.log(this.api);
But I am getting an empty object like this ApiService
javascript angular service dependency-injection
asked Nov 14 '18 at 9:31
iam batmaniam batman
2,11532450
My service located in src/core/services/api.service.ts
import Injectable from '@angular/core';
@Injectable(
providedIn: 'root'
)
export class ApiService
constructor()
test()
console.log('hello from services');
I am trying to invoke this service from a component which in another module.
home.component.ts
import Component, OnInit from '@angular/core';
import ApiService from './core/services/api.service';
@Component(
selector: 'app-home',
templateUrl: './home.component.html',
styleUrls: ['./home.component.css']
)
export class HomeComponent implements OnInit
constructor(private api: ApiService)
ngOnInit()
console.log(this.api);
But I am getting an empty object like this ApiService
javascript angular service dependency-injection
javascript angular service dependency-injection
asked Nov 14 '18 at 9:31
iam batmaniam batman
2,11532450
asked Nov 14 '18 at 9:31
iam batmaniam batman
2,11532450
asked Nov 14 '18 at 9:31
iam batmaniam batman
2,11532450
asked Nov 14 '18 at 9:31
iam batmaniam batman
2,11532450
asked Nov 14 '18 at 9:31
iam batmaniam batman
2,11532450
2,11532450
1
if it's loggingApiService, then that's an ApiService instance, exactly as intended. You can find thetestmethod under the object's prototype. Are you 100% sure this is not working or did you just guess it?
– briosheje
Nov 14 '18 at 9:40
yeah, right! Check this, this stackblitz.com/edit/angular-aizqtqApiServiceworks fine
– qiAlex
Nov 14 '18 at 9:41
Your code is looking and working perfectly fine. No change is needed.
– Sunil Singh
Nov 14 '18 at 9:43
Additionaly, if you don't want to do any sort of call, just do:console.log(this.api instanceof ApiService);, if it logs true, it just works.
– briosheje
Nov 14 '18 at 10:14
add a comment |
1
if it's loggingApiService, then that's an ApiService instance, exactly as intended. You can find thetestmethod under the object's prototype. Are you 100% sure this is not working or did you just guess it?
– briosheje
Nov 14 '18 at 9:40
yeah, right! Check this, this stackblitz.com/edit/angular-aizqtqApiServiceworks fine
– qiAlex
Nov 14 '18 at 9:41
Your code is looking and working perfectly fine. No change is needed.
– Sunil Singh
Nov 14 '18 at 9:43
Additionaly, if you don't want to do any sort of call, just do:console.log(this.api instanceof ApiService);, if it logs true, it just works.
– briosheje
Nov 14 '18 at 10:14
1
1
if it's logging
ApiService , then that's an ApiService instance, exactly as intended. You can find the test method under the object's prototype. Are you 100% sure this is not working or did you just guess it?– briosheje
Nov 14 '18 at 9:40
if it's logging
ApiService , then that's an ApiService instance, exactly as intended. You can find the test method under the object's prototype. Are you 100% sure this is not working or did you just guess it?– briosheje
Nov 14 '18 at 9:40
yeah, right! Check this, this stackblitz.com/edit/angular-aizqtq
ApiService works fine– qiAlex
Nov 14 '18 at 9:41
yeah, right! Check this, this stackblitz.com/edit/angular-aizqtq
ApiService works fine– qiAlex
Nov 14 '18 at 9:41
Your code is looking and working perfectly fine. No change is needed.
– Sunil Singh
Nov 14 '18 at 9:43
Your code is looking and working perfectly fine. No change is needed.
– Sunil Singh
Nov 14 '18 at 9:43
Additionaly, if you don't want to do any sort of call, just do:
console.log(this.api instanceof ApiService);, if it logs true, it just works.– briosheje
Nov 14 '18 at 10:14
Additionaly, if you don't want to do any sort of call, just do:
console.log(this.api instanceof ApiService);, if it logs true, it just works.– briosheje
Nov 14 '18 at 10:14
add a comment |
1 Answer
1
active
oldest
votes
1
So it is returning an object and that means that the service is initialized correctly, instead of console.log(this.api); try this.api.test(), you should see hello from services in the console.
answered Nov 14 '18 at 9:41
Mac_WMac_W
845515
add a comment |
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1
So it is returning an object and that means that the service is initialized correctly, instead of console.log(this.api); try this.api.test(), you should see hello from services in the console.
answered Nov 14 '18 at 9:41
Mac_WMac_W
845515
add a comment |
1
So it is returning an object and that means that the service is initialized correctly, instead of console.log(this.api); try this.api.test(), you should see hello from services in the console.
answered Nov 14 '18 at 9:41
Mac_WMac_W
845515
add a comment |
1
1
1
So it is returning an object and that means that the service is initialized correctly, instead of console.log(this.api); try this.api.test(), you should see hello from services in the console.
answered Nov 14 '18 at 9:41
Mac_WMac_W
845515
So it is returning an object and that means that the service is initialized correctly, instead of console.log(this.api); try this.api.test(), you should see hello from services in the console.
answered Nov 14 '18 at 9:41
Mac_WMac_W
845515
answered Nov 14 '18 at 9:41
Mac_WMac_W
845515
answered Nov 14 '18 at 9:41
Mac_WMac_W
845515
answered Nov 14 '18 at 9:41
Mac_WMac_W
845515
845515
add a comment |
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1
if it's logging
ApiService, then that's an ApiService instance, exactly as intended. You can find thetestmethod under the object's prototype. Are you 100% sure this is not working or did you just guess it?– briosheje
Nov 14 '18 at 9:40
yeah, right! Check this, this stackblitz.com/edit/angular-aizqtq
ApiServiceworks fine– qiAlex
Nov 14 '18 at 9:41
Your code is looking and working perfectly fine. No change is needed.
– Sunil Singh
Nov 14 '18 at 9:43
Additionaly, if you don't want to do any sort of call, just do:
console.log(this.api instanceof ApiService);, if it logs true, it just works.– briosheje
Nov 14 '18 at 10:14