How can I serve static content (Javascript, CSS and HTML files) from AppEngine Flexible without x-google-allow: all OpenApi extension?









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Issue:



I am trying to serve few static HTML files from a Google AppEngine Flexible service (not the default service) but I get the below error:




"code": 5,
"message": "Method does not exist.",
"details": [

"@type": "type.googleapis.com/google.rpc.DebugInfo",
"stackEntries": ,
"detail": "service_control"

]



The OpenApi is defined to allow only requests that are configured, i.e. x-google-allow is not specified in the OpenApi configuration file and defaults to "configured".



How do I allow access to the static resources in a particular folder without having to define each url to a file in OpenApi?



Additional information:



The service hosts Jersey 1.x which is configured to serve requests matching /*. I have configured requests to /static/* to be served by the default servlet. I have not configured any handlers in app.yaml and don't think this is required for AppEngine Flexible.



web.xml



 <servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>/static/*</url-pattern>
</servlet-mapping>

<servlet-mapping>
<servlet-name>jersey-serlvet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>









share|improve this question



























    up vote
    0
    down vote

    favorite












    Issue:



    I am trying to serve few static HTML files from a Google AppEngine Flexible service (not the default service) but I get the below error:




    "code": 5,
    "message": "Method does not exist.",
    "details": [

    "@type": "type.googleapis.com/google.rpc.DebugInfo",
    "stackEntries": ,
    "detail": "service_control"

    ]



    The OpenApi is defined to allow only requests that are configured, i.e. x-google-allow is not specified in the OpenApi configuration file and defaults to "configured".



    How do I allow access to the static resources in a particular folder without having to define each url to a file in OpenApi?



    Additional information:



    The service hosts Jersey 1.x which is configured to serve requests matching /*. I have configured requests to /static/* to be served by the default servlet. I have not configured any handlers in app.yaml and don't think this is required for AppEngine Flexible.



    web.xml



     <servlet-mapping>
    <servlet-name>default</servlet-name>
    <url-pattern>/static/*</url-pattern>
    </servlet-mapping>

    <servlet-mapping>
    <servlet-name>jersey-serlvet</servlet-name>
    <url-pattern>/*</url-pattern>
    </servlet-mapping>









    share|improve this question

























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      Issue:



      I am trying to serve few static HTML files from a Google AppEngine Flexible service (not the default service) but I get the below error:




      "code": 5,
      "message": "Method does not exist.",
      "details": [

      "@type": "type.googleapis.com/google.rpc.DebugInfo",
      "stackEntries": ,
      "detail": "service_control"

      ]



      The OpenApi is defined to allow only requests that are configured, i.e. x-google-allow is not specified in the OpenApi configuration file and defaults to "configured".



      How do I allow access to the static resources in a particular folder without having to define each url to a file in OpenApi?



      Additional information:



      The service hosts Jersey 1.x which is configured to serve requests matching /*. I have configured requests to /static/* to be served by the default servlet. I have not configured any handlers in app.yaml and don't think this is required for AppEngine Flexible.



      web.xml



       <servlet-mapping>
      <servlet-name>default</servlet-name>
      <url-pattern>/static/*</url-pattern>
      </servlet-mapping>

      <servlet-mapping>
      <servlet-name>jersey-serlvet</servlet-name>
      <url-pattern>/*</url-pattern>
      </servlet-mapping>









      share|improve this question















      Issue:



      I am trying to serve few static HTML files from a Google AppEngine Flexible service (not the default service) but I get the below error:




      "code": 5,
      "message": "Method does not exist.",
      "details": [

      "@type": "type.googleapis.com/google.rpc.DebugInfo",
      "stackEntries": ,
      "detail": "service_control"

      ]



      The OpenApi is defined to allow only requests that are configured, i.e. x-google-allow is not specified in the OpenApi configuration file and defaults to "configured".



      How do I allow access to the static resources in a particular folder without having to define each url to a file in OpenApi?



      Additional information:



      The service hosts Jersey 1.x which is configured to serve requests matching /*. I have configured requests to /static/* to be served by the default servlet. I have not configured any handlers in app.yaml and don't think this is required for AppEngine Flexible.



      web.xml



       <servlet-mapping>
      <servlet-name>default</servlet-name>
      <url-pattern>/static/*</url-pattern>
      </servlet-mapping>

      <servlet-mapping>
      <servlet-name>jersey-serlvet</servlet-name>
      <url-pattern>/*</url-pattern>
      </servlet-mapping>






      google-app-engine static-content






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      edited Nov 11 at 10:56

























      asked Nov 10 at 18:42









      Kenneth Mascarenhas

      208




      208



























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