Min/Max of dates in an array

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0
down vote

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var expenseDates = ["2018-02-06","2018-11-08","2018-11-10","2017-05-02","2017-05-02","2018-11-01"];

var sorted = expenseDates.slice()
.sort(function(a, b) 
 return new Date(a) - new Date(b);
);
 
console.log(sorted.pop()+ '--max');
console.log(sorted.shift()+ '--min');

edited Nov 10 at 14:42

asked Nov 10 at 14:04

Mr world wide

1,44021339

2

Posting an image of your code or data is kind-of annoying because it's not possible to copy-paste in order to test it. Stackoverflow has ample facilities for rendering code directly in the question.
– Pointy
Nov 10 at 14:09

1

You're sorting your dates in ascending order, so pop() will retrieve the max one, not the min one (other way around for shift()).
– Jeto
Nov 10 at 14:11

@Pointy updated and found solution thanks,
– Mr world wide
Nov 10 at 14:13

Thank you @Jeto
– Mr world wide
Nov 10 at 14:14

add a comment |

up vote
0
down vote

favorite

var expenseDates = ["2018-02-06","2018-11-08","2018-11-10","2017-05-02","2017-05-02","2018-11-01"];

var sorted = expenseDates.slice()
.sort(function(a, b) 
 return new Date(a) - new Date(b);
);
 
console.log(sorted.pop()+ '--max');
console.log(sorted.shift()+ '--min');

edited Nov 10 at 14:42

asked Nov 10 at 14:04

Mr world wide

1,44021339

2

Posting an image of your code or data is kind-of annoying because it's not possible to copy-paste in order to test it. Stackoverflow has ample facilities for rendering code directly in the question.
– Pointy
Nov 10 at 14:09

1

You're sorting your dates in ascending order, so pop() will retrieve the max one, not the min one (other way around for shift()).
– Jeto
Nov 10 at 14:11

@Pointy updated and found solution thanks,
– Mr world wide
Nov 10 at 14:13

Thank you @Jeto
– Mr world wide
Nov 10 at 14:14

add a comment |

up vote
0
down vote

favorite

var expenseDates = ["2018-02-06","2018-11-08","2018-11-10","2017-05-02","2017-05-02","2018-11-01"];

var sorted = expenseDates.slice()
.sort(function(a, b) 
 return new Date(a) - new Date(b);
);
 
console.log(sorted.pop()+ '--max');
console.log(sorted.shift()+ '--min');

edited Nov 10 at 14:42

asked Nov 10 at 14:04

Mr world wide

1,44021339

var expenseDates = ["2018-02-06","2018-11-08","2018-11-10","2017-05-02","2017-05-02","2018-11-01"];

var sorted = expenseDates.slice()
.sort(function(a, b) 
 return new Date(a) - new Date(b);
);
 
console.log(sorted.pop()+ '--max');
console.log(sorted.shift()+ '--min');

var expenseDates = ["2018-02-06","2018-11-08","2018-11-10","2017-05-02","2017-05-02","2018-11-01"];

var sorted = expenseDates.slice()
.sort(function(a, b) 
 return new Date(a) - new Date(b);
);
 
console.log(sorted.pop()+ '--max');
console.log(sorted.shift()+ '--min');

var expenseDates = ["2018-02-06","2018-11-08","2018-11-10","2017-05-02","2017-05-02","2018-11-01"];

var sorted = expenseDates.slice()
.sort(function(a, b) 
 return new Date(a) - new Date(b);
);
 
console.log(sorted.pop()+ '--max');
console.log(sorted.shift()+ '--min');

javascript arrays date

edited Nov 10 at 14:42

asked Nov 10 at 14:04

Mr world wide

1,44021339

edited Nov 10 at 14:42

asked Nov 10 at 14:04

Mr world wide

1,44021339

edited Nov 10 at 14:42

asked Nov 10 at 14:04

Mr world wide

1,44021339

asked Nov 10 at 14:04

Mr world wide

1,44021339

asked Nov 10 at 14:04

Mr world wide

1,44021339

2

Posting an image of your code or data is kind-of annoying because it's not possible to copy-paste in order to test it. Stackoverflow has ample facilities for rendering code directly in the question.
– Pointy
Nov 10 at 14:09

1

You're sorting your dates in ascending order, so pop() will retrieve the max one, not the min one (other way around for shift()).
– Jeto
Nov 10 at 14:11

@Pointy updated and found solution thanks,
– Mr world wide
Nov 10 at 14:13

Thank you @Jeto
– Mr world wide
Nov 10 at 14:14

add a comment |

2

Posting an image of your code or data is kind-of annoying because it's not possible to copy-paste in order to test it. Stackoverflow has ample facilities for rendering code directly in the question.
– Pointy
Nov 10 at 14:09

1

You're sorting your dates in ascending order, so pop() will retrieve the max one, not the min one (other way around for shift()).
– Jeto
Nov 10 at 14:11

@Pointy updated and found solution thanks,
– Mr world wide
Nov 10 at 14:13

Thank you @Jeto
– Mr world wide
Nov 10 at 14:14

Posting an image of your code or data is kind-of annoying because it's not possible to copy-paste in order to test it. Stackoverflow has ample facilities for rendering code directly in the question.
– Pointy
Nov 10 at 14:09

You're sorting your dates in ascending order, so pop() will retrieve the max one, not the min one (other way around for shift()).
– Jeto
Nov 10 at 14:11

@Pointy updated and found solution thanks,
– Mr world wide
Nov 10 at 14:13

Thank you @Jeto
– Mr world wide
Nov 10 at 14:14

add a comment |

1 Answer
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up vote
2
down vote

accepted

You don't have convert it into date object as the date are in YYYY-MM-DD format which itself is in sorted order by year => month => day. So you just have to compare the input string as localCompare. First index is minimum date while the last index is maximum date

var expenseDates = ["2018-02-06","2018-11-08","2018-11-10","2017-05-02","2017-05-02","2018-11-01"];

 expenseDates = expenseDates.sort(function(a, b) 
 return a.localeCompare(b);
 );

 console.log('--min => ',expenseDates[0]);
 console.log('--max => ', expenseDates[expenseDates.length -1]);

Working jsFiddle demo - https://jsfiddle.net/rpdon5cm/1/

edited Nov 11 at 5:09

answered Nov 10 at 14:19

front_end_dev

1,310411

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1 Answer
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active

oldest

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1 Answer
1

active

oldest

votes

up vote
2
down vote

accepted

var expenseDates = ["2018-02-06","2018-11-08","2018-11-10","2017-05-02","2017-05-02","2018-11-01"];

 expenseDates = expenseDates.sort(function(a, b) 
 return a.localeCompare(b);
 );

 console.log('--min => ',expenseDates[0]);
 console.log('--max => ', expenseDates[expenseDates.length -1]);

Working jsFiddle demo - https://jsfiddle.net/rpdon5cm/1/

edited Nov 11 at 5:09

answered Nov 10 at 14:19

front_end_dev

1,310411

add a comment |

up vote
2
down vote

accepted

var expenseDates = ["2018-02-06","2018-11-08","2018-11-10","2017-05-02","2017-05-02","2018-11-01"];

 expenseDates = expenseDates.sort(function(a, b) 
 return a.localeCompare(b);
 );

 console.log('--min => ',expenseDates[0]);
 console.log('--max => ', expenseDates[expenseDates.length -1]);

Working jsFiddle demo - https://jsfiddle.net/rpdon5cm/1/

edited Nov 11 at 5:09

answered Nov 10 at 14:19

front_end_dev

1,310411

add a comment |

up vote
2
down vote

accepted

var expenseDates = ["2018-02-06","2018-11-08","2018-11-10","2017-05-02","2017-05-02","2018-11-01"];

 expenseDates = expenseDates.sort(function(a, b) 
 return a.localeCompare(b);
 );

 console.log('--min => ',expenseDates[0]);
 console.log('--max => ', expenseDates[expenseDates.length -1]);

Working jsFiddle demo - https://jsfiddle.net/rpdon5cm/1/

edited Nov 11 at 5:09

answered Nov 10 at 14:19

front_end_dev

1,310411

var expenseDates = ["2018-02-06","2018-11-08","2018-11-10","2017-05-02","2017-05-02","2018-11-01"];

 expenseDates = expenseDates.sort(function(a, b) 
 return a.localeCompare(b);
 );

 console.log('--min => ',expenseDates[0]);
 console.log('--max => ', expenseDates[expenseDates.length -1]);

Working jsFiddle demo - https://jsfiddle.net/rpdon5cm/1/

edited Nov 11 at 5:09

answered Nov 10 at 14:19

front_end_dev

1,310411

edited Nov 11 at 5:09

answered Nov 10 at 14:19

front_end_dev

1,310411

answered Nov 10 at 14:19

front_end_dev

1,310411

answered Nov 10 at 14:19

front_end_dev

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