Getting a Button to Display Query Results in PHP MYSQL









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I am trying to run a query that will display in my browser when I click the button, but instead the results are just displayed from the beginning. I have the button set to post and my php file as the action but it seems to just run the code from the beginning. Here is what I have:



<?php
$host = "localhost";
$db = "cis475";
$user = "root";
$pw = "";


$conn = new mysqli ($host, $user, $pw, $db);
if($conn->connect_error) die($conn->connect_error);

$readAllQuery = "SELECT * FROM enrollment JOIN course ON enrollment.CourseID
= course.CourseID JOIN student ON enrollment.StudentID = student.StudentID";

$result = $conn->query($readAllQuery);
if (!$result) die($conn->error);

echo "<table border='1'>";
echo "<tr><td>EnrollmentID</td><td>Grade</td><td>EnrollmentSemester</td>
<td>CourseID</td><td>StudentID</td><td>Title</td><td>Credits</td>
<td>LastName</td><td>FirstMidName</td></tr>";
while ($row = mysqli_fetch_assoc($result))
echo "<tr><td>$row['EnrollmentID']</td><td>$row['Grade']</td>
<td>$row['EnrollmentSemester']</td><td>$row['CourseID']</td><td>
$row['StudentID']</td><td>$row['Title']</td><td>$row['Credits']
</td>
<td>$row['LastName']</td><td>$row['FirstMidName']</td></tr>";


echo "</table>";

?>

<form method='post' action='readAll.php'>

<input type='submit' name='submit' value='Show All Enrollments'>

</form>









share|improve this question

























    up vote
    1
    down vote

    favorite












    I am trying to run a query that will display in my browser when I click the button, but instead the results are just displayed from the beginning. I have the button set to post and my php file as the action but it seems to just run the code from the beginning. Here is what I have:



    <?php
    $host = "localhost";
    $db = "cis475";
    $user = "root";
    $pw = "";


    $conn = new mysqli ($host, $user, $pw, $db);
    if($conn->connect_error) die($conn->connect_error);

    $readAllQuery = "SELECT * FROM enrollment JOIN course ON enrollment.CourseID
    = course.CourseID JOIN student ON enrollment.StudentID = student.StudentID";

    $result = $conn->query($readAllQuery);
    if (!$result) die($conn->error);

    echo "<table border='1'>";
    echo "<tr><td>EnrollmentID</td><td>Grade</td><td>EnrollmentSemester</td>
    <td>CourseID</td><td>StudentID</td><td>Title</td><td>Credits</td>
    <td>LastName</td><td>FirstMidName</td></tr>";
    while ($row = mysqli_fetch_assoc($result))
    echo "<tr><td>$row['EnrollmentID']</td><td>$row['Grade']</td>
    <td>$row['EnrollmentSemester']</td><td>$row['CourseID']</td><td>
    $row['StudentID']</td><td>$row['Title']</td><td>$row['Credits']
    </td>
    <td>$row['LastName']</td><td>$row['FirstMidName']</td></tr>";


    echo "</table>";

    ?>

    <form method='post' action='readAll.php'>

    <input type='submit' name='submit' value='Show All Enrollments'>

    </form>









    share|improve this question























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      I am trying to run a query that will display in my browser when I click the button, but instead the results are just displayed from the beginning. I have the button set to post and my php file as the action but it seems to just run the code from the beginning. Here is what I have:



      <?php
      $host = "localhost";
      $db = "cis475";
      $user = "root";
      $pw = "";


      $conn = new mysqli ($host, $user, $pw, $db);
      if($conn->connect_error) die($conn->connect_error);

      $readAllQuery = "SELECT * FROM enrollment JOIN course ON enrollment.CourseID
      = course.CourseID JOIN student ON enrollment.StudentID = student.StudentID";

      $result = $conn->query($readAllQuery);
      if (!$result) die($conn->error);

      echo "<table border='1'>";
      echo "<tr><td>EnrollmentID</td><td>Grade</td><td>EnrollmentSemester</td>
      <td>CourseID</td><td>StudentID</td><td>Title</td><td>Credits</td>
      <td>LastName</td><td>FirstMidName</td></tr>";
      while ($row = mysqli_fetch_assoc($result))
      echo "<tr><td>$row['EnrollmentID']</td><td>$row['Grade']</td>
      <td>$row['EnrollmentSemester']</td><td>$row['CourseID']</td><td>
      $row['StudentID']</td><td>$row['Title']</td><td>$row['Credits']
      </td>
      <td>$row['LastName']</td><td>$row['FirstMidName']</td></tr>";


      echo "</table>";

      ?>

      <form method='post' action='readAll.php'>

      <input type='submit' name='submit' value='Show All Enrollments'>

      </form>









      share|improve this question













      I am trying to run a query that will display in my browser when I click the button, but instead the results are just displayed from the beginning. I have the button set to post and my php file as the action but it seems to just run the code from the beginning. Here is what I have:



      <?php
      $host = "localhost";
      $db = "cis475";
      $user = "root";
      $pw = "";


      $conn = new mysqli ($host, $user, $pw, $db);
      if($conn->connect_error) die($conn->connect_error);

      $readAllQuery = "SELECT * FROM enrollment JOIN course ON enrollment.CourseID
      = course.CourseID JOIN student ON enrollment.StudentID = student.StudentID";

      $result = $conn->query($readAllQuery);
      if (!$result) die($conn->error);

      echo "<table border='1'>";
      echo "<tr><td>EnrollmentID</td><td>Grade</td><td>EnrollmentSemester</td>
      <td>CourseID</td><td>StudentID</td><td>Title</td><td>Credits</td>
      <td>LastName</td><td>FirstMidName</td></tr>";
      while ($row = mysqli_fetch_assoc($result))
      echo "<tr><td>$row['EnrollmentID']</td><td>$row['Grade']</td>
      <td>$row['EnrollmentSemester']</td><td>$row['CourseID']</td><td>
      $row['StudentID']</td><td>$row['Title']</td><td>$row['Credits']
      </td>
      <td>$row['LastName']</td><td>$row['FirstMidName']</td></tr>";


      echo "</table>";

      ?>

      <form method='post' action='readAll.php'>

      <input type='submit' name='submit' value='Show All Enrollments'>

      </form>






      php mysql forms






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      share|improve this question











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      share|improve this question










      asked Nov 11 at 16:25









      Mason Cox

      265




      265






















          2 Answers
          2






          active

          oldest

          votes

















          up vote
          0
          down vote



          accepted










          Any code present in inside the program file will run upon execution, this is true for all languages, unless it is wrapped inside an if or any other conditional statements; in which case the code enclosed in the conditional statement will only be executed if the condition is true.



          And thus to solve your issue, you'll need a conditional statement that checks if the form was submitted or not and if it was then execute the code that follows-



          if(isset($_POST['submit']))
          $host = "localhost";
          $db = "cis475";
          $user = "root";
          $pw = "";

          $conn = new mysqli ($host, $user, $pw, $db);
          if($conn->connect_error) die($conn->connect_error);

          $readAllQuery = "SELECT * FROM enrollment JOIN course ON enrollment.CourseID = course.CourseID JOIN student ON enrollment.StudentID = student.StudentID";

          $result = $conn->query($readAllQuery);
          if (!$result) die($conn->error);

          echo "<table border='1'>";
          echo "<tr><td>EnrollmentID</td><td>Grade</td><td>EnrollmentSemester</td>
          <td>CourseID</td><td>StudentID</td><td>Title</td><td>Credits</td>
          <td>LastName</td><td>FirstMidName</td></tr>";
          while ($row = mysqli_fetch_assoc($result))
          echo "<tr><td>$row['EnrollmentID']</td><td>$row['Grade']</td>
          <td>$row['EnrollmentSemester']</td><td>$row['CourseID']</td><td>
          $row['StudentID']</td><td>$row['Title']</td><td>$row['Credits']
          </td><td>$row['LastName']</td><td>$row['FirstMidName']</td></tr>";

          echo "</table>";



          In this snippet, we use if statement to check if variable $_POST['submit'] exists.
          Here submit with is the name of your form's submit button
          Note: a $_POST variable will only exist if the form was submitted, calling isset() will return false if the form wasn't submitted and as such your code inside will not be executed on first load but will run upon submit.






          share|improve this answer





























            up vote
            1
            down vote













            You need to see if 'something' is there (in this case, all you have is the submit) and then do the display....



            <?php
            if($_POST['submit'])
            $host = "localhost";
            $db = "cis475";
            $user = "root";
            $pw = "";

            $conn = new mysqli ($host, $user, $pw, $db);
            if($conn->connect_error) die($conn->connect_error);

            $readAllQuery = "SELECT * FROM enrollment JOIN course ON enrollment.CourseID = course.CourseID JOIN student ON enrollment.StudentID = student.StudentID";

            $result = $conn->query($readAllQuery);
            if (!$result) die($conn->error);

            echo "<table border='1'>";
            echo "<tr><td>EnrollmentID</td><td>Grade</td><td>EnrollmentSemester</td>
            <td>CourseID</td><td>StudentID</td><td>Title</td><td>Credits</td>
            <td>LastName</td><td>FirstMidName</td></tr>";
            while ($row = mysqli_fetch_assoc($result))
            echo "<tr><td>$row['EnrollmentID']</td><td>$row['Grade']</td>
            <td>$row['EnrollmentSemester']</td><td>$row['CourseID']</td><td>
            $row['StudentID']</td><td>$row['Title']</td><td>$row['Credits']
            </td><td>$row['LastName']</td><td>$row['FirstMidName']</td></tr>";

            echo "</table>";

            ?>

            <form method='post' action='readAll.php'>

            <input type='submit' name='submit' value='Show All Enrollments'>

            </form>





            share|improve this answer




















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              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes








              up vote
              0
              down vote



              accepted










              Any code present in inside the program file will run upon execution, this is true for all languages, unless it is wrapped inside an if or any other conditional statements; in which case the code enclosed in the conditional statement will only be executed if the condition is true.



              And thus to solve your issue, you'll need a conditional statement that checks if the form was submitted or not and if it was then execute the code that follows-



              if(isset($_POST['submit']))
              $host = "localhost";
              $db = "cis475";
              $user = "root";
              $pw = "";

              $conn = new mysqli ($host, $user, $pw, $db);
              if($conn->connect_error) die($conn->connect_error);

              $readAllQuery = "SELECT * FROM enrollment JOIN course ON enrollment.CourseID = course.CourseID JOIN student ON enrollment.StudentID = student.StudentID";

              $result = $conn->query($readAllQuery);
              if (!$result) die($conn->error);

              echo "<table border='1'>";
              echo "<tr><td>EnrollmentID</td><td>Grade</td><td>EnrollmentSemester</td>
              <td>CourseID</td><td>StudentID</td><td>Title</td><td>Credits</td>
              <td>LastName</td><td>FirstMidName</td></tr>";
              while ($row = mysqli_fetch_assoc($result))
              echo "<tr><td>$row['EnrollmentID']</td><td>$row['Grade']</td>
              <td>$row['EnrollmentSemester']</td><td>$row['CourseID']</td><td>
              $row['StudentID']</td><td>$row['Title']</td><td>$row['Credits']
              </td><td>$row['LastName']</td><td>$row['FirstMidName']</td></tr>";

              echo "</table>";



              In this snippet, we use if statement to check if variable $_POST['submit'] exists.
              Here submit with is the name of your form's submit button
              Note: a $_POST variable will only exist if the form was submitted, calling isset() will return false if the form wasn't submitted and as such your code inside will not be executed on first load but will run upon submit.






              share|improve this answer


























                up vote
                0
                down vote



                accepted










                Any code present in inside the program file will run upon execution, this is true for all languages, unless it is wrapped inside an if or any other conditional statements; in which case the code enclosed in the conditional statement will only be executed if the condition is true.



                And thus to solve your issue, you'll need a conditional statement that checks if the form was submitted or not and if it was then execute the code that follows-



                if(isset($_POST['submit']))
                $host = "localhost";
                $db = "cis475";
                $user = "root";
                $pw = "";

                $conn = new mysqli ($host, $user, $pw, $db);
                if($conn->connect_error) die($conn->connect_error);

                $readAllQuery = "SELECT * FROM enrollment JOIN course ON enrollment.CourseID = course.CourseID JOIN student ON enrollment.StudentID = student.StudentID";

                $result = $conn->query($readAllQuery);
                if (!$result) die($conn->error);

                echo "<table border='1'>";
                echo "<tr><td>EnrollmentID</td><td>Grade</td><td>EnrollmentSemester</td>
                <td>CourseID</td><td>StudentID</td><td>Title</td><td>Credits</td>
                <td>LastName</td><td>FirstMidName</td></tr>";
                while ($row = mysqli_fetch_assoc($result))
                echo "<tr><td>$row['EnrollmentID']</td><td>$row['Grade']</td>
                <td>$row['EnrollmentSemester']</td><td>$row['CourseID']</td><td>
                $row['StudentID']</td><td>$row['Title']</td><td>$row['Credits']
                </td><td>$row['LastName']</td><td>$row['FirstMidName']</td></tr>";

                echo "</table>";



                In this snippet, we use if statement to check if variable $_POST['submit'] exists.
                Here submit with is the name of your form's submit button
                Note: a $_POST variable will only exist if the form was submitted, calling isset() will return false if the form wasn't submitted and as such your code inside will not be executed on first load but will run upon submit.






                share|improve this answer
























                  up vote
                  0
                  down vote



                  accepted







                  up vote
                  0
                  down vote



                  accepted






                  Any code present in inside the program file will run upon execution, this is true for all languages, unless it is wrapped inside an if or any other conditional statements; in which case the code enclosed in the conditional statement will only be executed if the condition is true.



                  And thus to solve your issue, you'll need a conditional statement that checks if the form was submitted or not and if it was then execute the code that follows-



                  if(isset($_POST['submit']))
                  $host = "localhost";
                  $db = "cis475";
                  $user = "root";
                  $pw = "";

                  $conn = new mysqli ($host, $user, $pw, $db);
                  if($conn->connect_error) die($conn->connect_error);

                  $readAllQuery = "SELECT * FROM enrollment JOIN course ON enrollment.CourseID = course.CourseID JOIN student ON enrollment.StudentID = student.StudentID";

                  $result = $conn->query($readAllQuery);
                  if (!$result) die($conn->error);

                  echo "<table border='1'>";
                  echo "<tr><td>EnrollmentID</td><td>Grade</td><td>EnrollmentSemester</td>
                  <td>CourseID</td><td>StudentID</td><td>Title</td><td>Credits</td>
                  <td>LastName</td><td>FirstMidName</td></tr>";
                  while ($row = mysqli_fetch_assoc($result))
                  echo "<tr><td>$row['EnrollmentID']</td><td>$row['Grade']</td>
                  <td>$row['EnrollmentSemester']</td><td>$row['CourseID']</td><td>
                  $row['StudentID']</td><td>$row['Title']</td><td>$row['Credits']
                  </td><td>$row['LastName']</td><td>$row['FirstMidName']</td></tr>";

                  echo "</table>";



                  In this snippet, we use if statement to check if variable $_POST['submit'] exists.
                  Here submit with is the name of your form's submit button
                  Note: a $_POST variable will only exist if the form was submitted, calling isset() will return false if the form wasn't submitted and as such your code inside will not be executed on first load but will run upon submit.






                  share|improve this answer














                  Any code present in inside the program file will run upon execution, this is true for all languages, unless it is wrapped inside an if or any other conditional statements; in which case the code enclosed in the conditional statement will only be executed if the condition is true.



                  And thus to solve your issue, you'll need a conditional statement that checks if the form was submitted or not and if it was then execute the code that follows-



                  if(isset($_POST['submit']))
                  $host = "localhost";
                  $db = "cis475";
                  $user = "root";
                  $pw = "";

                  $conn = new mysqli ($host, $user, $pw, $db);
                  if($conn->connect_error) die($conn->connect_error);

                  $readAllQuery = "SELECT * FROM enrollment JOIN course ON enrollment.CourseID = course.CourseID JOIN student ON enrollment.StudentID = student.StudentID";

                  $result = $conn->query($readAllQuery);
                  if (!$result) die($conn->error);

                  echo "<table border='1'>";
                  echo "<tr><td>EnrollmentID</td><td>Grade</td><td>EnrollmentSemester</td>
                  <td>CourseID</td><td>StudentID</td><td>Title</td><td>Credits</td>
                  <td>LastName</td><td>FirstMidName</td></tr>";
                  while ($row = mysqli_fetch_assoc($result))
                  echo "<tr><td>$row['EnrollmentID']</td><td>$row['Grade']</td>
                  <td>$row['EnrollmentSemester']</td><td>$row['CourseID']</td><td>
                  $row['StudentID']</td><td>$row['Title']</td><td>$row['Credits']
                  </td><td>$row['LastName']</td><td>$row['FirstMidName']</td></tr>";

                  echo "</table>";



                  In this snippet, we use if statement to check if variable $_POST['submit'] exists.
                  Here submit with is the name of your form's submit button
                  Note: a $_POST variable will only exist if the form was submitted, calling isset() will return false if the form wasn't submitted and as such your code inside will not be executed on first load but will run upon submit.







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 13 at 11:31

























                  answered Nov 11 at 16:49









                  Jaswinder Singh

                  301210




                  301210






















                      up vote
                      1
                      down vote













                      You need to see if 'something' is there (in this case, all you have is the submit) and then do the display....



                      <?php
                      if($_POST['submit'])
                      $host = "localhost";
                      $db = "cis475";
                      $user = "root";
                      $pw = "";

                      $conn = new mysqli ($host, $user, $pw, $db);
                      if($conn->connect_error) die($conn->connect_error);

                      $readAllQuery = "SELECT * FROM enrollment JOIN course ON enrollment.CourseID = course.CourseID JOIN student ON enrollment.StudentID = student.StudentID";

                      $result = $conn->query($readAllQuery);
                      if (!$result) die($conn->error);

                      echo "<table border='1'>";
                      echo "<tr><td>EnrollmentID</td><td>Grade</td><td>EnrollmentSemester</td>
                      <td>CourseID</td><td>StudentID</td><td>Title</td><td>Credits</td>
                      <td>LastName</td><td>FirstMidName</td></tr>";
                      while ($row = mysqli_fetch_assoc($result))
                      echo "<tr><td>$row['EnrollmentID']</td><td>$row['Grade']</td>
                      <td>$row['EnrollmentSemester']</td><td>$row['CourseID']</td><td>
                      $row['StudentID']</td><td>$row['Title']</td><td>$row['Credits']
                      </td><td>$row['LastName']</td><td>$row['FirstMidName']</td></tr>";

                      echo "</table>";

                      ?>

                      <form method='post' action='readAll.php'>

                      <input type='submit' name='submit' value='Show All Enrollments'>

                      </form>





                      share|improve this answer
























                        up vote
                        1
                        down vote













                        You need to see if 'something' is there (in this case, all you have is the submit) and then do the display....



                        <?php
                        if($_POST['submit'])
                        $host = "localhost";
                        $db = "cis475";
                        $user = "root";
                        $pw = "";

                        $conn = new mysqli ($host, $user, $pw, $db);
                        if($conn->connect_error) die($conn->connect_error);

                        $readAllQuery = "SELECT * FROM enrollment JOIN course ON enrollment.CourseID = course.CourseID JOIN student ON enrollment.StudentID = student.StudentID";

                        $result = $conn->query($readAllQuery);
                        if (!$result) die($conn->error);

                        echo "<table border='1'>";
                        echo "<tr><td>EnrollmentID</td><td>Grade</td><td>EnrollmentSemester</td>
                        <td>CourseID</td><td>StudentID</td><td>Title</td><td>Credits</td>
                        <td>LastName</td><td>FirstMidName</td></tr>";
                        while ($row = mysqli_fetch_assoc($result))
                        echo "<tr><td>$row['EnrollmentID']</td><td>$row['Grade']</td>
                        <td>$row['EnrollmentSemester']</td><td>$row['CourseID']</td><td>
                        $row['StudentID']</td><td>$row['Title']</td><td>$row['Credits']
                        </td><td>$row['LastName']</td><td>$row['FirstMidName']</td></tr>";

                        echo "</table>";

                        ?>

                        <form method='post' action='readAll.php'>

                        <input type='submit' name='submit' value='Show All Enrollments'>

                        </form>





                        share|improve this answer






















                          up vote
                          1
                          down vote










                          up vote
                          1
                          down vote









                          You need to see if 'something' is there (in this case, all you have is the submit) and then do the display....



                          <?php
                          if($_POST['submit'])
                          $host = "localhost";
                          $db = "cis475";
                          $user = "root";
                          $pw = "";

                          $conn = new mysqli ($host, $user, $pw, $db);
                          if($conn->connect_error) die($conn->connect_error);

                          $readAllQuery = "SELECT * FROM enrollment JOIN course ON enrollment.CourseID = course.CourseID JOIN student ON enrollment.StudentID = student.StudentID";

                          $result = $conn->query($readAllQuery);
                          if (!$result) die($conn->error);

                          echo "<table border='1'>";
                          echo "<tr><td>EnrollmentID</td><td>Grade</td><td>EnrollmentSemester</td>
                          <td>CourseID</td><td>StudentID</td><td>Title</td><td>Credits</td>
                          <td>LastName</td><td>FirstMidName</td></tr>";
                          while ($row = mysqli_fetch_assoc($result))
                          echo "<tr><td>$row['EnrollmentID']</td><td>$row['Grade']</td>
                          <td>$row['EnrollmentSemester']</td><td>$row['CourseID']</td><td>
                          $row['StudentID']</td><td>$row['Title']</td><td>$row['Credits']
                          </td><td>$row['LastName']</td><td>$row['FirstMidName']</td></tr>";

                          echo "</table>";

                          ?>

                          <form method='post' action='readAll.php'>

                          <input type='submit' name='submit' value='Show All Enrollments'>

                          </form>





                          share|improve this answer












                          You need to see if 'something' is there (in this case, all you have is the submit) and then do the display....



                          <?php
                          if($_POST['submit'])
                          $host = "localhost";
                          $db = "cis475";
                          $user = "root";
                          $pw = "";

                          $conn = new mysqli ($host, $user, $pw, $db);
                          if($conn->connect_error) die($conn->connect_error);

                          $readAllQuery = "SELECT * FROM enrollment JOIN course ON enrollment.CourseID = course.CourseID JOIN student ON enrollment.StudentID = student.StudentID";

                          $result = $conn->query($readAllQuery);
                          if (!$result) die($conn->error);

                          echo "<table border='1'>";
                          echo "<tr><td>EnrollmentID</td><td>Grade</td><td>EnrollmentSemester</td>
                          <td>CourseID</td><td>StudentID</td><td>Title</td><td>Credits</td>
                          <td>LastName</td><td>FirstMidName</td></tr>";
                          while ($row = mysqli_fetch_assoc($result))
                          echo "<tr><td>$row['EnrollmentID']</td><td>$row['Grade']</td>
                          <td>$row['EnrollmentSemester']</td><td>$row['CourseID']</td><td>
                          $row['StudentID']</td><td>$row['Title']</td><td>$row['Credits']
                          </td><td>$row['LastName']</td><td>$row['FirstMidName']</td></tr>";

                          echo "</table>";

                          ?>

                          <form method='post' action='readAll.php'>

                          <input type='submit' name='submit' value='Show All Enrollments'>

                          </form>






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                          answered Nov 11 at 16:39









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