how to subsample a fasta file based on the headers if headers contain certain strings?










0














I have a fasta file like this:



>gi|373248686|emb|HE586118.1| Streptomyces albus subsp. albus salinomycin biosynthesis cluster, strain DSM 41398
GGATGCGAAGGACGCGCTGCGCAAGGCGCTGTCGATGGGTGCGGACAAGGGCATCCACGT
CGAGGACGACGATCTGCACGGCACCGACGCCGTGGGTACCTCGCTGGTGCTGGCCAAGGC
>gi|1139489917|gb|KX622588.1| Hyalangium minutum strain DSM 14724 myxochromide D subtype 1 biosynthetic gene cluster and tRNA-Thr gene, complete sequence
ATGCGCAAGCTCGTCATCACGGTGGGGATTCTGGTGGGGTTGGGGCTCGTGGTCCTTTGG
TTCTGGAGCCCGGGAGGCCCAGTCCCCTCCACGGACACGGAGGGGGAAGGGCGGAGTCAG
CGCCGGCAGGCCATGGCCCGGCCCGGCTCCGCGCAGCTGGAGAGTCCCGAGGACATGGGG
>gi|930076459|gb|KR364704.1| Streptomyces sioyaensis strain BCCO10_981 putative annimycin-type biosynthetic gene cluster, partial sequence
GCCGGCAGGTGGGCCGCGGTCAGCTTCAGGACCGTGGCCGTCGCGCCCGCCAGCACCACG
GAGGCCCCCACGGCCAGCGCCGGGCCCGTGCCCGTGCCGTACGCGAGGTCCGTGCTGAAC


and I have a text file containing a list of numbers:



373248686
930076459
296280703
......


I want to do the following:



if the header in the fasta file contains the numbers in the text file:
write all the matches(header+sequence) to a new output.fasta file.


How to do this in python? It seems easy, just some for loops may do the job, but somehow I cannot make that happen, and if my files are really big, loop in another loop may take a long time. Here's what I have tried:



from Bio import SeqIO 
import sys

wanted =
for line in open(sys.argv[2]):
titles = line.strip()
wanted.append(titles)


seqiter = SeqIO.parse(open(sys.argv[1]), 'fasta')
sys.stdout = open('output.fasta', 'w')

new_seq =

for seq in seqiter:
new_seq.append(seq if i in seq.id for i in wanted)


SeqIO.write(new_seq, sys.stdout, "fasta")
sys.stdout.close()


Got this error:



new_seq.append(seq if i in seq.id for i in wanted)
^
SyntaxError: invalid syntax


Is there a better way to do this?



Thank you!










share|improve this question




























    0














    I have a fasta file like this:



    >gi|373248686|emb|HE586118.1| Streptomyces albus subsp. albus salinomycin biosynthesis cluster, strain DSM 41398
    GGATGCGAAGGACGCGCTGCGCAAGGCGCTGTCGATGGGTGCGGACAAGGGCATCCACGT
    CGAGGACGACGATCTGCACGGCACCGACGCCGTGGGTACCTCGCTGGTGCTGGCCAAGGC
    >gi|1139489917|gb|KX622588.1| Hyalangium minutum strain DSM 14724 myxochromide D subtype 1 biosynthetic gene cluster and tRNA-Thr gene, complete sequence
    ATGCGCAAGCTCGTCATCACGGTGGGGATTCTGGTGGGGTTGGGGCTCGTGGTCCTTTGG
    TTCTGGAGCCCGGGAGGCCCAGTCCCCTCCACGGACACGGAGGGGGAAGGGCGGAGTCAG
    CGCCGGCAGGCCATGGCCCGGCCCGGCTCCGCGCAGCTGGAGAGTCCCGAGGACATGGGG
    >gi|930076459|gb|KR364704.1| Streptomyces sioyaensis strain BCCO10_981 putative annimycin-type biosynthetic gene cluster, partial sequence
    GCCGGCAGGTGGGCCGCGGTCAGCTTCAGGACCGTGGCCGTCGCGCCCGCCAGCACCACG
    GAGGCCCCCACGGCCAGCGCCGGGCCCGTGCCCGTGCCGTACGCGAGGTCCGTGCTGAAC


    and I have a text file containing a list of numbers:



    373248686
    930076459
    296280703
    ......


    I want to do the following:



    if the header in the fasta file contains the numbers in the text file:
    write all the matches(header+sequence) to a new output.fasta file.


    How to do this in python? It seems easy, just some for loops may do the job, but somehow I cannot make that happen, and if my files are really big, loop in another loop may take a long time. Here's what I have tried:



    from Bio import SeqIO 
    import sys

    wanted =
    for line in open(sys.argv[2]):
    titles = line.strip()
    wanted.append(titles)


    seqiter = SeqIO.parse(open(sys.argv[1]), 'fasta')
    sys.stdout = open('output.fasta', 'w')

    new_seq =

    for seq in seqiter:
    new_seq.append(seq if i in seq.id for i in wanted)


    SeqIO.write(new_seq, sys.stdout, "fasta")
    sys.stdout.close()


    Got this error:



    new_seq.append(seq if i in seq.id for i in wanted)
    ^
    SyntaxError: invalid syntax


    Is there a better way to do this?



    Thank you!










    share|improve this question


























      0












      0








      0







      I have a fasta file like this:



      >gi|373248686|emb|HE586118.1| Streptomyces albus subsp. albus salinomycin biosynthesis cluster, strain DSM 41398
      GGATGCGAAGGACGCGCTGCGCAAGGCGCTGTCGATGGGTGCGGACAAGGGCATCCACGT
      CGAGGACGACGATCTGCACGGCACCGACGCCGTGGGTACCTCGCTGGTGCTGGCCAAGGC
      >gi|1139489917|gb|KX622588.1| Hyalangium minutum strain DSM 14724 myxochromide D subtype 1 biosynthetic gene cluster and tRNA-Thr gene, complete sequence
      ATGCGCAAGCTCGTCATCACGGTGGGGATTCTGGTGGGGTTGGGGCTCGTGGTCCTTTGG
      TTCTGGAGCCCGGGAGGCCCAGTCCCCTCCACGGACACGGAGGGGGAAGGGCGGAGTCAG
      CGCCGGCAGGCCATGGCCCGGCCCGGCTCCGCGCAGCTGGAGAGTCCCGAGGACATGGGG
      >gi|930076459|gb|KR364704.1| Streptomyces sioyaensis strain BCCO10_981 putative annimycin-type biosynthetic gene cluster, partial sequence
      GCCGGCAGGTGGGCCGCGGTCAGCTTCAGGACCGTGGCCGTCGCGCCCGCCAGCACCACG
      GAGGCCCCCACGGCCAGCGCCGGGCCCGTGCCCGTGCCGTACGCGAGGTCCGTGCTGAAC


      and I have a text file containing a list of numbers:



      373248686
      930076459
      296280703
      ......


      I want to do the following:



      if the header in the fasta file contains the numbers in the text file:
      write all the matches(header+sequence) to a new output.fasta file.


      How to do this in python? It seems easy, just some for loops may do the job, but somehow I cannot make that happen, and if my files are really big, loop in another loop may take a long time. Here's what I have tried:



      from Bio import SeqIO 
      import sys

      wanted =
      for line in open(sys.argv[2]):
      titles = line.strip()
      wanted.append(titles)


      seqiter = SeqIO.parse(open(sys.argv[1]), 'fasta')
      sys.stdout = open('output.fasta', 'w')

      new_seq =

      for seq in seqiter:
      new_seq.append(seq if i in seq.id for i in wanted)


      SeqIO.write(new_seq, sys.stdout, "fasta")
      sys.stdout.close()


      Got this error:



      new_seq.append(seq if i in seq.id for i in wanted)
      ^
      SyntaxError: invalid syntax


      Is there a better way to do this?



      Thank you!










      share|improve this question















      I have a fasta file like this:



      >gi|373248686|emb|HE586118.1| Streptomyces albus subsp. albus salinomycin biosynthesis cluster, strain DSM 41398
      GGATGCGAAGGACGCGCTGCGCAAGGCGCTGTCGATGGGTGCGGACAAGGGCATCCACGT
      CGAGGACGACGATCTGCACGGCACCGACGCCGTGGGTACCTCGCTGGTGCTGGCCAAGGC
      >gi|1139489917|gb|KX622588.1| Hyalangium minutum strain DSM 14724 myxochromide D subtype 1 biosynthetic gene cluster and tRNA-Thr gene, complete sequence
      ATGCGCAAGCTCGTCATCACGGTGGGGATTCTGGTGGGGTTGGGGCTCGTGGTCCTTTGG
      TTCTGGAGCCCGGGAGGCCCAGTCCCCTCCACGGACACGGAGGGGGAAGGGCGGAGTCAG
      CGCCGGCAGGCCATGGCCCGGCCCGGCTCCGCGCAGCTGGAGAGTCCCGAGGACATGGGG
      >gi|930076459|gb|KR364704.1| Streptomyces sioyaensis strain BCCO10_981 putative annimycin-type biosynthetic gene cluster, partial sequence
      GCCGGCAGGTGGGCCGCGGTCAGCTTCAGGACCGTGGCCGTCGCGCCCGCCAGCACCACG
      GAGGCCCCCACGGCCAGCGCCGGGCCCGTGCCCGTGCCGTACGCGAGGTCCGTGCTGAAC


      and I have a text file containing a list of numbers:



      373248686
      930076459
      296280703
      ......


      I want to do the following:



      if the header in the fasta file contains the numbers in the text file:
      write all the matches(header+sequence) to a new output.fasta file.


      How to do this in python? It seems easy, just some for loops may do the job, but somehow I cannot make that happen, and if my files are really big, loop in another loop may take a long time. Here's what I have tried:



      from Bio import SeqIO 
      import sys

      wanted =
      for line in open(sys.argv[2]):
      titles = line.strip()
      wanted.append(titles)


      seqiter = SeqIO.parse(open(sys.argv[1]), 'fasta')
      sys.stdout = open('output.fasta', 'w')

      new_seq =

      for seq in seqiter:
      new_seq.append(seq if i in seq.id for i in wanted)


      SeqIO.write(new_seq, sys.stdout, "fasta")
      sys.stdout.close()


      Got this error:



      new_seq.append(seq if i in seq.id for i in wanted)
      ^
      SyntaxError: invalid syntax


      Is there a better way to do this?



      Thank you!







      python bioinformatics






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 13 at 1:08









      quant

      1,58411526




      1,58411526










      asked Nov 12 at 20:26









      stevex

      275




      275






















          2 Answers
          2






          active

          oldest

          votes


















          0














          Use a program like this



          from Bio import SeqIO
          import sys

          # read in the text file
          numbersInTxtFile = set()
          # hint: use with, then you don't need to
          # program file closing. Furhtermore error
          # handling is comming along with this too
          with open(sys.argv[2], "r") as inF:
          for line in inF:
          line = line.strip()
          if line == "": continue
          numbersInTxtFile.add(int(line))

          # read in the fasta file
          with open(sys.argv[1], "r") as inF:
          for record in SeqIO.parse(inF, "fasta"):
          # now check if this record in the fasta file
          # has an id we are searching for
          name = record.description
          id = int(name.split("|")[1])
          print(id, numbersInTxtFile, id in numbersInTxtFile)
          if id in numbersInTxtFile:
          # we need to output
          print(">%s" % name)
          print(record.seq)


          which you can then call like so from the commandline



          python3 nameOfProg.py inputFastaFile.fa idsToSearch.txt > outputFastaFile.fa





          share|improve this answer




















          • Thank you! It works!
            – stevex
            Nov 12 at 22:18


















          0














          Import your "keeper" IDs into a dictionary rather than a list, this will be much faster as the list doesn't have to be searched thousands of times.



          keepers = 
          with open("ids.txt", "r") as id_handle:
          for curr_id in id_handle:
          keepers[curr_id] = True


          A list comprehension generates a list, so you don't need to append to another list.



          keeper_seqs = [x for x in seqiter if x.id in keepers]


          With larger files you will want to loop over seqiter and write the entries one at a time to avoid memory issues.



          You should also never assign to sys.stdout without a good reason, if you want to output to STDOUT just use print or sys.stdout.write().






          share|improve this answer




















          • Thank you very much!
            – stevex
            Nov 12 at 22:18










          Your Answer






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          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          Use a program like this



          from Bio import SeqIO
          import sys

          # read in the text file
          numbersInTxtFile = set()
          # hint: use with, then you don't need to
          # program file closing. Furhtermore error
          # handling is comming along with this too
          with open(sys.argv[2], "r") as inF:
          for line in inF:
          line = line.strip()
          if line == "": continue
          numbersInTxtFile.add(int(line))

          # read in the fasta file
          with open(sys.argv[1], "r") as inF:
          for record in SeqIO.parse(inF, "fasta"):
          # now check if this record in the fasta file
          # has an id we are searching for
          name = record.description
          id = int(name.split("|")[1])
          print(id, numbersInTxtFile, id in numbersInTxtFile)
          if id in numbersInTxtFile:
          # we need to output
          print(">%s" % name)
          print(record.seq)


          which you can then call like so from the commandline



          python3 nameOfProg.py inputFastaFile.fa idsToSearch.txt > outputFastaFile.fa





          share|improve this answer




















          • Thank you! It works!
            – stevex
            Nov 12 at 22:18















          0














          Use a program like this



          from Bio import SeqIO
          import sys

          # read in the text file
          numbersInTxtFile = set()
          # hint: use with, then you don't need to
          # program file closing. Furhtermore error
          # handling is comming along with this too
          with open(sys.argv[2], "r") as inF:
          for line in inF:
          line = line.strip()
          if line == "": continue
          numbersInTxtFile.add(int(line))

          # read in the fasta file
          with open(sys.argv[1], "r") as inF:
          for record in SeqIO.parse(inF, "fasta"):
          # now check if this record in the fasta file
          # has an id we are searching for
          name = record.description
          id = int(name.split("|")[1])
          print(id, numbersInTxtFile, id in numbersInTxtFile)
          if id in numbersInTxtFile:
          # we need to output
          print(">%s" % name)
          print(record.seq)


          which you can then call like so from the commandline



          python3 nameOfProg.py inputFastaFile.fa idsToSearch.txt > outputFastaFile.fa





          share|improve this answer




















          • Thank you! It works!
            – stevex
            Nov 12 at 22:18













          0












          0








          0






          Use a program like this



          from Bio import SeqIO
          import sys

          # read in the text file
          numbersInTxtFile = set()
          # hint: use with, then you don't need to
          # program file closing. Furhtermore error
          # handling is comming along with this too
          with open(sys.argv[2], "r") as inF:
          for line in inF:
          line = line.strip()
          if line == "": continue
          numbersInTxtFile.add(int(line))

          # read in the fasta file
          with open(sys.argv[1], "r") as inF:
          for record in SeqIO.parse(inF, "fasta"):
          # now check if this record in the fasta file
          # has an id we are searching for
          name = record.description
          id = int(name.split("|")[1])
          print(id, numbersInTxtFile, id in numbersInTxtFile)
          if id in numbersInTxtFile:
          # we need to output
          print(">%s" % name)
          print(record.seq)


          which you can then call like so from the commandline



          python3 nameOfProg.py inputFastaFile.fa idsToSearch.txt > outputFastaFile.fa





          share|improve this answer












          Use a program like this



          from Bio import SeqIO
          import sys

          # read in the text file
          numbersInTxtFile = set()
          # hint: use with, then you don't need to
          # program file closing. Furhtermore error
          # handling is comming along with this too
          with open(sys.argv[2], "r") as inF:
          for line in inF:
          line = line.strip()
          if line == "": continue
          numbersInTxtFile.add(int(line))

          # read in the fasta file
          with open(sys.argv[1], "r") as inF:
          for record in SeqIO.parse(inF, "fasta"):
          # now check if this record in the fasta file
          # has an id we are searching for
          name = record.description
          id = int(name.split("|")[1])
          print(id, numbersInTxtFile, id in numbersInTxtFile)
          if id in numbersInTxtFile:
          # we need to output
          print(">%s" % name)
          print(record.seq)


          which you can then call like so from the commandline



          python3 nameOfProg.py inputFastaFile.fa idsToSearch.txt > outputFastaFile.fa






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 12 at 20:44









          quant

          1,58411526




          1,58411526











          • Thank you! It works!
            – stevex
            Nov 12 at 22:18
















          • Thank you! It works!
            – stevex
            Nov 12 at 22:18















          Thank you! It works!
          – stevex
          Nov 12 at 22:18




          Thank you! It works!
          – stevex
          Nov 12 at 22:18













          0














          Import your "keeper" IDs into a dictionary rather than a list, this will be much faster as the list doesn't have to be searched thousands of times.



          keepers = 
          with open("ids.txt", "r") as id_handle:
          for curr_id in id_handle:
          keepers[curr_id] = True


          A list comprehension generates a list, so you don't need to append to another list.



          keeper_seqs = [x for x in seqiter if x.id in keepers]


          With larger files you will want to loop over seqiter and write the entries one at a time to avoid memory issues.



          You should also never assign to sys.stdout without a good reason, if you want to output to STDOUT just use print or sys.stdout.write().






          share|improve this answer




















          • Thank you very much!
            – stevex
            Nov 12 at 22:18















          0














          Import your "keeper" IDs into a dictionary rather than a list, this will be much faster as the list doesn't have to be searched thousands of times.



          keepers = 
          with open("ids.txt", "r") as id_handle:
          for curr_id in id_handle:
          keepers[curr_id] = True


          A list comprehension generates a list, so you don't need to append to another list.



          keeper_seqs = [x for x in seqiter if x.id in keepers]


          With larger files you will want to loop over seqiter and write the entries one at a time to avoid memory issues.



          You should also never assign to sys.stdout without a good reason, if you want to output to STDOUT just use print or sys.stdout.write().






          share|improve this answer




















          • Thank you very much!
            – stevex
            Nov 12 at 22:18













          0












          0








          0






          Import your "keeper" IDs into a dictionary rather than a list, this will be much faster as the list doesn't have to be searched thousands of times.



          keepers = 
          with open("ids.txt", "r") as id_handle:
          for curr_id in id_handle:
          keepers[curr_id] = True


          A list comprehension generates a list, so you don't need to append to another list.



          keeper_seqs = [x for x in seqiter if x.id in keepers]


          With larger files you will want to loop over seqiter and write the entries one at a time to avoid memory issues.



          You should also never assign to sys.stdout without a good reason, if you want to output to STDOUT just use print or sys.stdout.write().






          share|improve this answer












          Import your "keeper" IDs into a dictionary rather than a list, this will be much faster as the list doesn't have to be searched thousands of times.



          keepers = 
          with open("ids.txt", "r") as id_handle:
          for curr_id in id_handle:
          keepers[curr_id] = True


          A list comprehension generates a list, so you don't need to append to another list.



          keeper_seqs = [x for x in seqiter if x.id in keepers]


          With larger files you will want to loop over seqiter and write the entries one at a time to avoid memory issues.



          You should also never assign to sys.stdout without a good reason, if you want to output to STDOUT just use print or sys.stdout.write().







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 12 at 20:45









          hurfdurf

          20228




          20228











          • Thank you very much!
            – stevex
            Nov 12 at 22:18
















          • Thank you very much!
            – stevex
            Nov 12 at 22:18















          Thank you very much!
          – stevex
          Nov 12 at 22:18




          Thank you very much!
          – stevex
          Nov 12 at 22:18

















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