Adding Column and column names dynamically in R
up vote
0
down vote
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I have an R data.table like this:
id
1: 1
2: 29
3: 26
4: 6
5: 1
6: 14`
And I would like to add columns dynamically by presence of this Id in a row.
Result:
id is_present_1 ... is_present_6....
1: 1 1 0
2: 2 0 0
3: 3 0 0
4: 4 0 1
5: 5 0 0
6: 6 0 1
I tried to write a function, or using mutate and paste:
ids <- c(1, 2, 3, 4, 5, 6)
for (i in length(ids))
df %>% mutate(paste("is_present",id[i]) = ifelse(id == ids[i],1,0))
I get an error:Error: unexpected '=' in:
"for (i in length(ids)) {
df %>% mutate(paste("is_present",id[i]) ="
Can someone help with this?
dynamic dplyr data.table
add a comment |
up vote
0
down vote
favorite
I have an R data.table like this:
id
1: 1
2: 29
3: 26
4: 6
5: 1
6: 14`
And I would like to add columns dynamically by presence of this Id in a row.
Result:
id is_present_1 ... is_present_6....
1: 1 1 0
2: 2 0 0
3: 3 0 0
4: 4 0 1
5: 5 0 0
6: 6 0 1
I tried to write a function, or using mutate and paste:
ids <- c(1, 2, 3, 4, 5, 6)
for (i in length(ids))
df %>% mutate(paste("is_present",id[i]) = ifelse(id == ids[i],1,0))
I get an error:Error: unexpected '=' in:
"for (i in length(ids)) {
df %>% mutate(paste("is_present",id[i]) ="
Can someone help with this?
dynamic dplyr data.table
You need to use tidy evaluation to create dynamic names withindplyr
verbs. See some examples here: stackoverflow.com/q/49700912/786542 & maraaverick.rbind.io/2017/08/tidyeval-resource-roundup
– Tung
Nov 12 at 7:47
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have an R data.table like this:
id
1: 1
2: 29
3: 26
4: 6
5: 1
6: 14`
And I would like to add columns dynamically by presence of this Id in a row.
Result:
id is_present_1 ... is_present_6....
1: 1 1 0
2: 2 0 0
3: 3 0 0
4: 4 0 1
5: 5 0 0
6: 6 0 1
I tried to write a function, or using mutate and paste:
ids <- c(1, 2, 3, 4, 5, 6)
for (i in length(ids))
df %>% mutate(paste("is_present",id[i]) = ifelse(id == ids[i],1,0))
I get an error:Error: unexpected '=' in:
"for (i in length(ids)) {
df %>% mutate(paste("is_present",id[i]) ="
Can someone help with this?
dynamic dplyr data.table
I have an R data.table like this:
id
1: 1
2: 29
3: 26
4: 6
5: 1
6: 14`
And I would like to add columns dynamically by presence of this Id in a row.
Result:
id is_present_1 ... is_present_6....
1: 1 1 0
2: 2 0 0
3: 3 0 0
4: 4 0 1
5: 5 0 0
6: 6 0 1
I tried to write a function, or using mutate and paste:
ids <- c(1, 2, 3, 4, 5, 6)
for (i in length(ids))
df %>% mutate(paste("is_present",id[i]) = ifelse(id == ids[i],1,0))
I get an error:Error: unexpected '=' in:
"for (i in length(ids)) {
df %>% mutate(paste("is_present",id[i]) ="
Can someone help with this?
dynamic dplyr data.table
dynamic dplyr data.table
asked Nov 11 at 19:31
Jenny
103
103
You need to use tidy evaluation to create dynamic names withindplyr
verbs. See some examples here: stackoverflow.com/q/49700912/786542 & maraaverick.rbind.io/2017/08/tidyeval-resource-roundup
– Tung
Nov 12 at 7:47
add a comment |
You need to use tidy evaluation to create dynamic names withindplyr
verbs. See some examples here: stackoverflow.com/q/49700912/786542 & maraaverick.rbind.io/2017/08/tidyeval-resource-roundup
– Tung
Nov 12 at 7:47
You need to use tidy evaluation to create dynamic names within
dplyr
verbs. See some examples here: stackoverflow.com/q/49700912/786542 & maraaverick.rbind.io/2017/08/tidyeval-resource-roundup– Tung
Nov 12 at 7:47
You need to use tidy evaluation to create dynamic names within
dplyr
verbs. See some examples here: stackoverflow.com/q/49700912/786542 & maraaverick.rbind.io/2017/08/tidyeval-resource-roundup– Tung
Nov 12 at 7:47
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
accepted
Not sure if I understand the question. But i think you are looking for a map function from purr with dynamic columns names. If the logic is wrong you can just adjust inside the function.
library(tidyverse)
library(data.table)
map_dfc(df$row, function(x)
nm <- paste("is_present_", x, sep = "")
df %>%
mutate(!!nm := ifelse(id == x, 1, 0))) %>%
select(contains("is_present_"))
results in:
is_present_1 is_present_2 is_present_3 is_present_4 is_present_5 is_present_6
1 1 0 0 0 0 0
2 0 0 0 0 0 0
3 0 0 0 0 0 0
4 0 0 0 0 0 1
5 1 0 0 0 0 0
6 0 0 0 0 0 0
Sample data:
df <- fread("
id
1: 1
2: 29
3: 26
4: 6
5: 1
6: 14") %>%
select(2) %>%
rownames_to_column("row")
Thank you for your help :)
– Jenny
Nov 13 at 10:41
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
Not sure if I understand the question. But i think you are looking for a map function from purr with dynamic columns names. If the logic is wrong you can just adjust inside the function.
library(tidyverse)
library(data.table)
map_dfc(df$row, function(x)
nm <- paste("is_present_", x, sep = "")
df %>%
mutate(!!nm := ifelse(id == x, 1, 0))) %>%
select(contains("is_present_"))
results in:
is_present_1 is_present_2 is_present_3 is_present_4 is_present_5 is_present_6
1 1 0 0 0 0 0
2 0 0 0 0 0 0
3 0 0 0 0 0 0
4 0 0 0 0 0 1
5 1 0 0 0 0 0
6 0 0 0 0 0 0
Sample data:
df <- fread("
id
1: 1
2: 29
3: 26
4: 6
5: 1
6: 14") %>%
select(2) %>%
rownames_to_column("row")
Thank you for your help :)
– Jenny
Nov 13 at 10:41
add a comment |
up vote
0
down vote
accepted
Not sure if I understand the question. But i think you are looking for a map function from purr with dynamic columns names. If the logic is wrong you can just adjust inside the function.
library(tidyverse)
library(data.table)
map_dfc(df$row, function(x)
nm <- paste("is_present_", x, sep = "")
df %>%
mutate(!!nm := ifelse(id == x, 1, 0))) %>%
select(contains("is_present_"))
results in:
is_present_1 is_present_2 is_present_3 is_present_4 is_present_5 is_present_6
1 1 0 0 0 0 0
2 0 0 0 0 0 0
3 0 0 0 0 0 0
4 0 0 0 0 0 1
5 1 0 0 0 0 0
6 0 0 0 0 0 0
Sample data:
df <- fread("
id
1: 1
2: 29
3: 26
4: 6
5: 1
6: 14") %>%
select(2) %>%
rownames_to_column("row")
Thank you for your help :)
– Jenny
Nov 13 at 10:41
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
Not sure if I understand the question. But i think you are looking for a map function from purr with dynamic columns names. If the logic is wrong you can just adjust inside the function.
library(tidyverse)
library(data.table)
map_dfc(df$row, function(x)
nm <- paste("is_present_", x, sep = "")
df %>%
mutate(!!nm := ifelse(id == x, 1, 0))) %>%
select(contains("is_present_"))
results in:
is_present_1 is_present_2 is_present_3 is_present_4 is_present_5 is_present_6
1 1 0 0 0 0 0
2 0 0 0 0 0 0
3 0 0 0 0 0 0
4 0 0 0 0 0 1
5 1 0 0 0 0 0
6 0 0 0 0 0 0
Sample data:
df <- fread("
id
1: 1
2: 29
3: 26
4: 6
5: 1
6: 14") %>%
select(2) %>%
rownames_to_column("row")
Not sure if I understand the question. But i think you are looking for a map function from purr with dynamic columns names. If the logic is wrong you can just adjust inside the function.
library(tidyverse)
library(data.table)
map_dfc(df$row, function(x)
nm <- paste("is_present_", x, sep = "")
df %>%
mutate(!!nm := ifelse(id == x, 1, 0))) %>%
select(contains("is_present_"))
results in:
is_present_1 is_present_2 is_present_3 is_present_4 is_present_5 is_present_6
1 1 0 0 0 0 0
2 0 0 0 0 0 0
3 0 0 0 0 0 0
4 0 0 0 0 0 1
5 1 0 0 0 0 0
6 0 0 0 0 0 0
Sample data:
df <- fread("
id
1: 1
2: 29
3: 26
4: 6
5: 1
6: 14") %>%
select(2) %>%
rownames_to_column("row")
answered Nov 12 at 18:59
davsjob
49726
49726
Thank you for your help :)
– Jenny
Nov 13 at 10:41
add a comment |
Thank you for your help :)
– Jenny
Nov 13 at 10:41
Thank you for your help :)
– Jenny
Nov 13 at 10:41
Thank you for your help :)
– Jenny
Nov 13 at 10:41
add a comment |
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You need to use tidy evaluation to create dynamic names within
dplyr
verbs. See some examples here: stackoverflow.com/q/49700912/786542 & maraaverick.rbind.io/2017/08/tidyeval-resource-roundup– Tung
Nov 12 at 7:47