Moment.js cannot parse string to date
0
i have a string in javascript. The string is in this format: 14. November 2018
Now I want to create a Javascript date object. I tried this with moment.js
moment('14. November 2018').format('DD. MMM YYYY');
The browser shows this error:
Invalid date
What is wrong with my code?
javascript momentjs
edited Nov 12 at 17:37
Matt Johnson
135k41274397
asked Nov 12 at 17:30
Markus
7310
add a comment |
0
i have a string in javascript. The string is in this format: 14. November 2018
Now I want to create a Javascript date object. I tried this with moment.js
moment('14. November 2018').format('DD. MMM YYYY');
The browser shows this error:
Invalid date
What is wrong with my code?
javascript momentjs
edited Nov 12 at 17:37
Matt Johnson
135k41274397
asked Nov 12 at 17:30
Markus
7310
add a comment |
0
0
0
i have a string in javascript. The string is in this format: 14. November 2018
Now I want to create a Javascript date object. I tried this with moment.js
moment('14. November 2018').format('DD. MMM YYYY');
The browser shows this error:
Invalid date
What is wrong with my code?
javascript momentjs
edited Nov 12 at 17:37
Matt Johnson
135k41274397
asked Nov 12 at 17:30
Markus
7310
i have a string in javascript. The string is in this format: 14. November 2018
Now I want to create a Javascript date object. I tried this with moment.js
moment('14. November 2018').format('DD. MMM YYYY');
The browser shows this error:
Invalid date
What is wrong with my code?
javascript momentjs
javascript momentjs
edited Nov 12 at 17:37
Matt Johnson
135k41274397
asked Nov 12 at 17:30
Markus
7310
edited Nov 12 at 17:37
Matt Johnson
135k41274397
asked Nov 12 at 17:30
Markus
7310
edited Nov 12 at 17:37
Matt Johnson
135k41274397
edited Nov 12 at 17:37
Matt Johnson
135k41274397
edited Nov 12 at 17:37
Matt Johnson
135k41274397
135k41274397
asked Nov 12 at 17:30
Markus
7310
asked Nov 12 at 17:30
Markus
7310
asked Nov 12 at 17:30
Markus
7310
7310
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
0
I solved the problem by reading the docs again. The right way is:
moment('14. November 2018', 'DD. MMMM YYYY');
answered Nov 12 at 17:35
Markus
7310
2
Close, but you should useMMMMif you have the full name of the month.MMMis the abbreviation form. It may still work for parsing, but will give different output for formatting later. Also, how will you be passing single digit days? If it will be like'01. November 2018', then continue to useDD. But if instead it would be like'1. November 2018'then you should just useD. It will still parse both single and two digit days, but will omit the leading zero if used for formatting.
– Matt Johnson
Nov 12 at 17:41
add a comment |
0
try this
moment(str, 'DD. MMMM YYYY').toDate();
answered Nov 12 at 17:50
Asim Khan
462
Please add a little detail of how you think this will help the OP
– Black Mamba
Nov 12 at 18:24
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
I solved the problem by reading the docs again. The right way is:
moment('14. November 2018', 'DD. MMMM YYYY');
answered Nov 12 at 17:35
Markus
7310
2
Close, but you should useMMMMif you have the full name of the month.MMMis the abbreviation form. It may still work for parsing, but will give different output for formatting later. Also, how will you be passing single digit days? If it will be like'01. November 2018', then continue to useDD. But if instead it would be like'1. November 2018'then you should just useD. It will still parse both single and two digit days, but will omit the leading zero if used for formatting.
– Matt Johnson
Nov 12 at 17:41
add a comment |
0
I solved the problem by reading the docs again. The right way is:
moment('14. November 2018', 'DD. MMMM YYYY');
answered Nov 12 at 17:35
Markus
7310
2
Close, but you should useMMMMif you have the full name of the month.MMMis the abbreviation form. It may still work for parsing, but will give different output for formatting later. Also, how will you be passing single digit days? If it will be like'01. November 2018', then continue to useDD. But if instead it would be like'1. November 2018'then you should just useD. It will still parse both single and two digit days, but will omit the leading zero if used for formatting.
– Matt Johnson
Nov 12 at 17:41
add a comment |
0
0
0
I solved the problem by reading the docs again. The right way is:
moment('14. November 2018', 'DD. MMMM YYYY');
answered Nov 12 at 17:35
Markus
7310
I solved the problem by reading the docs again. The right way is:
moment('14. November 2018', 'DD. MMMM YYYY');
answered Nov 12 at 17:35
Markus
7310
edited Nov 12 at 17:43
answered Nov 12 at 17:35
Markus
7310
answered Nov 12 at 17:35
Markus
7310
answered Nov 12 at 17:35
Markus
7310
7310
2
Close, but you should useMMMMif you have the full name of the month.MMMis the abbreviation form. It may still work for parsing, but will give different output for formatting later. Also, how will you be passing single digit days? If it will be like'01. November 2018', then continue to useDD. But if instead it would be like'1. November 2018'then you should just useD. It will still parse both single and two digit days, but will omit the leading zero if used for formatting.
– Matt Johnson
Nov 12 at 17:41
add a comment |
2
Close, but you should useMMMMif you have the full name of the month.MMMis the abbreviation form. It may still work for parsing, but will give different output for formatting later. Also, how will you be passing single digit days? If it will be like'01. November 2018', then continue to useDD. But if instead it would be like'1. November 2018'then you should just useD. It will still parse both single and two digit days, but will omit the leading zero if used for formatting.
– Matt Johnson
Nov 12 at 17:41
2
2
Close, but you should use
MMMM if you have the full name of the month. MMM is the abbreviation form. It may still work for parsing, but will give different output for formatting later. Also, how will you be passing single digit days? If it will be like '01. November 2018', then continue to use DD. But if instead it would be like '1. November 2018' then you should just use D. It will still parse both single and two digit days, but will omit the leading zero if used for formatting.– Matt Johnson
Nov 12 at 17:41
Close, but you should use
MMMM if you have the full name of the month. MMM is the abbreviation form. It may still work for parsing, but will give different output for formatting later. Also, how will you be passing single digit days? If it will be like '01. November 2018', then continue to use DD. But if instead it would be like '1. November 2018' then you should just use D. It will still parse both single and two digit days, but will omit the leading zero if used for formatting.– Matt Johnson
Nov 12 at 17:41
add a comment |
0
try this
moment(str, 'DD. MMMM YYYY').toDate();
answered Nov 12 at 17:50
Asim Khan
462
Please add a little detail of how you think this will help the OP
– Black Mamba
Nov 12 at 18:24
add a comment |
0
try this
moment(str, 'DD. MMMM YYYY').toDate();
answered Nov 12 at 17:50
Asim Khan
462
Please add a little detail of how you think this will help the OP
– Black Mamba
Nov 12 at 18:24
add a comment |
0
0
0
try this
moment(str, 'DD. MMMM YYYY').toDate();
answered Nov 12 at 17:50
Asim Khan
462
try this
moment(str, 'DD. MMMM YYYY').toDate();
answered Nov 12 at 17:50
Asim Khan
462
answered Nov 12 at 17:50
Asim Khan
462
answered Nov 12 at 17:50
Asim Khan
462
answered Nov 12 at 17:50
Asim Khan
462
462
Please add a little detail of how you think this will help the OP
– Black Mamba
Nov 12 at 18:24
add a comment |
Please add a little detail of how you think this will help the OP
– Black Mamba
Nov 12 at 18:24
Please add a little detail of how you think this will help the OP
– Black Mamba
Nov 12 at 18:24
Please add a little detail of how you think this will help the OP
– Black Mamba
Nov 12 at 18:24
add a comment |
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