How to check if a number in a list is greater than the number before it - python










-2















I have 3 sets of data zipped together (date,somenumber,price). I want to iterated through the table and whenever somenumber is less than somenumber before it in the list I want to pull the date,somenumber,price for when that happens. Currently I just have:



for a,b,c in zip(date,somenumber,price):
print(a,b,c)


and it prints something like:



2018-01-30 18:42:00 859235 6.95
2018-02-01 09:08:00 323405 7.43
2018-02-02 15:16:00 528963 6.4
2018-02-05 18:48:00 808739 7.91
2018-02-07 14:42:00 462541 7.33
2018-02-10 18:48:00 598001 6.21
2018-02-11 03:32:00 650558 7.31
2018-02-11 11:28:00 670392 6.21


When somenumber went from 808739 to 462541 I want to return the data for that lower number:
2018-02-07 14:42:00 462541 7.33



Thanks!










share|improve this question






















  • 323405 is less than 859235. Do you want to report it, too? If not, why?

    – DYZ
    Nov 15 '18 at 4:38















-2















I have 3 sets of data zipped together (date,somenumber,price). I want to iterated through the table and whenever somenumber is less than somenumber before it in the list I want to pull the date,somenumber,price for when that happens. Currently I just have:



for a,b,c in zip(date,somenumber,price):
print(a,b,c)


and it prints something like:



2018-01-30 18:42:00 859235 6.95
2018-02-01 09:08:00 323405 7.43
2018-02-02 15:16:00 528963 6.4
2018-02-05 18:48:00 808739 7.91
2018-02-07 14:42:00 462541 7.33
2018-02-10 18:48:00 598001 6.21
2018-02-11 03:32:00 650558 7.31
2018-02-11 11:28:00 670392 6.21


When somenumber went from 808739 to 462541 I want to return the data for that lower number:
2018-02-07 14:42:00 462541 7.33



Thanks!










share|improve this question






















  • 323405 is less than 859235. Do you want to report it, too? If not, why?

    – DYZ
    Nov 15 '18 at 4:38













-2












-2








-2








I have 3 sets of data zipped together (date,somenumber,price). I want to iterated through the table and whenever somenumber is less than somenumber before it in the list I want to pull the date,somenumber,price for when that happens. Currently I just have:



for a,b,c in zip(date,somenumber,price):
print(a,b,c)


and it prints something like:



2018-01-30 18:42:00 859235 6.95
2018-02-01 09:08:00 323405 7.43
2018-02-02 15:16:00 528963 6.4
2018-02-05 18:48:00 808739 7.91
2018-02-07 14:42:00 462541 7.33
2018-02-10 18:48:00 598001 6.21
2018-02-11 03:32:00 650558 7.31
2018-02-11 11:28:00 670392 6.21


When somenumber went from 808739 to 462541 I want to return the data for that lower number:
2018-02-07 14:42:00 462541 7.33



Thanks!










share|improve this question














I have 3 sets of data zipped together (date,somenumber,price). I want to iterated through the table and whenever somenumber is less than somenumber before it in the list I want to pull the date,somenumber,price for when that happens. Currently I just have:



for a,b,c in zip(date,somenumber,price):
print(a,b,c)


and it prints something like:



2018-01-30 18:42:00 859235 6.95
2018-02-01 09:08:00 323405 7.43
2018-02-02 15:16:00 528963 6.4
2018-02-05 18:48:00 808739 7.91
2018-02-07 14:42:00 462541 7.33
2018-02-10 18:48:00 598001 6.21
2018-02-11 03:32:00 650558 7.31
2018-02-11 11:28:00 670392 6.21


When somenumber went from 808739 to 462541 I want to return the data for that lower number:
2018-02-07 14:42:00 462541 7.33



Thanks!







python






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 15 '18 at 4:35









ZakZak

81




81












  • 323405 is less than 859235. Do you want to report it, too? If not, why?

    – DYZ
    Nov 15 '18 at 4:38

















  • 323405 is less than 859235. Do you want to report it, too? If not, why?

    – DYZ
    Nov 15 '18 at 4:38
















323405 is less than 859235. Do you want to report it, too? If not, why?

– DYZ
Nov 15 '18 at 4:38





323405 is less than 859235. Do you want to report it, too? If not, why?

– DYZ
Nov 15 '18 at 4:38












2 Answers
2






active

oldest

votes


















6














This will compare somenumber+1 to somenumber, and if somenumber + 1 (the next number in the sequence is less than the current) it will print all data for that row. If it is not less it will not print anything.



for a,b,c,d in zip(date, somenumber, somenumber[1:], price):
if c < b:
print(a, b, c, d)





share|improve this answer
































    2














    What I understood from the question is every time, the value of somenumber decreases in the next row, it should print the row. It's very easy to implement. Just store the previous value in another variable (prev_number). For the first row, though, we need to initialize prev_number to the minimum number possible. Following is the solution:



    import sys
    prev_number = -sys.maxint - 1 #initialize prev_number to lowest possible number in python
    for a,b,c in zip(date,somenumber,price):
    if b < prev_number:
    print(a,b,c)
    prev_number = d


    Let me know if it works for you.






    share|improve this answer






















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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      6














      This will compare somenumber+1 to somenumber, and if somenumber + 1 (the next number in the sequence is less than the current) it will print all data for that row. If it is not less it will not print anything.



      for a,b,c,d in zip(date, somenumber, somenumber[1:], price):
      if c < b:
      print(a, b, c, d)





      share|improve this answer





























        6














        This will compare somenumber+1 to somenumber, and if somenumber + 1 (the next number in the sequence is less than the current) it will print all data for that row. If it is not less it will not print anything.



        for a,b,c,d in zip(date, somenumber, somenumber[1:], price):
        if c < b:
        print(a, b, c, d)





        share|improve this answer



























          6












          6








          6







          This will compare somenumber+1 to somenumber, and if somenumber + 1 (the next number in the sequence is less than the current) it will print all data for that row. If it is not less it will not print anything.



          for a,b,c,d in zip(date, somenumber, somenumber[1:], price):
          if c < b:
          print(a, b, c, d)





          share|improve this answer















          This will compare somenumber+1 to somenumber, and if somenumber + 1 (the next number in the sequence is less than the current) it will print all data for that row. If it is not less it will not print anything.



          for a,b,c,d in zip(date, somenumber, somenumber[1:], price):
          if c < b:
          print(a, b, c, d)






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 15 '18 at 4:47

























          answered Nov 15 '18 at 4:41









          d_kennetzd_kennetz

          2,1853721




          2,1853721























              2














              What I understood from the question is every time, the value of somenumber decreases in the next row, it should print the row. It's very easy to implement. Just store the previous value in another variable (prev_number). For the first row, though, we need to initialize prev_number to the minimum number possible. Following is the solution:



              import sys
              prev_number = -sys.maxint - 1 #initialize prev_number to lowest possible number in python
              for a,b,c in zip(date,somenumber,price):
              if b < prev_number:
              print(a,b,c)
              prev_number = d


              Let me know if it works for you.






              share|improve this answer



























                2














                What I understood from the question is every time, the value of somenumber decreases in the next row, it should print the row. It's very easy to implement. Just store the previous value in another variable (prev_number). For the first row, though, we need to initialize prev_number to the minimum number possible. Following is the solution:



                import sys
                prev_number = -sys.maxint - 1 #initialize prev_number to lowest possible number in python
                for a,b,c in zip(date,somenumber,price):
                if b < prev_number:
                print(a,b,c)
                prev_number = d


                Let me know if it works for you.






                share|improve this answer

























                  2












                  2








                  2







                  What I understood from the question is every time, the value of somenumber decreases in the next row, it should print the row. It's very easy to implement. Just store the previous value in another variable (prev_number). For the first row, though, we need to initialize prev_number to the minimum number possible. Following is the solution:



                  import sys
                  prev_number = -sys.maxint - 1 #initialize prev_number to lowest possible number in python
                  for a,b,c in zip(date,somenumber,price):
                  if b < prev_number:
                  print(a,b,c)
                  prev_number = d


                  Let me know if it works for you.






                  share|improve this answer













                  What I understood from the question is every time, the value of somenumber decreases in the next row, it should print the row. It's very easy to implement. Just store the previous value in another variable (prev_number). For the first row, though, we need to initialize prev_number to the minimum number possible. Following is the solution:



                  import sys
                  prev_number = -sys.maxint - 1 #initialize prev_number to lowest possible number in python
                  for a,b,c in zip(date,somenumber,price):
                  if b < prev_number:
                  print(a,b,c)
                  prev_number = d


                  Let me know if it works for you.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 15 '18 at 4:48









                  amulya349amulya349

                  678918




                  678918



























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