Transition Action and Condition Action in Stateflow
In the below two state charts , the first one has an action to perform when it moves from StateA to StateD , ie. /z=5;
and the second one has to perform the action z=5;
I understand that this is a Transition Action , but i am unable to understand what is the different between the two transition
matlab charts simulink statechart stateflow
add a comment |
In the below two state charts , the first one has an action to perform when it moves from StateA to StateD , ie. /z=5;
and the second one has to perform the action z=5;
I understand that this is a Transition Action , but i am unable to understand what is the different between the two transition
matlab charts simulink statechart stateflow
See uk.mathworks.com/help/stateflow/ug/transition-action-types.html
– am304
Nov 16 '18 at 9:08
add a comment |
In the below two state charts , the first one has an action to perform when it moves from StateA to StateD , ie. /z=5;
and the second one has to perform the action z=5;
I understand that this is a Transition Action , but i am unable to understand what is the different between the two transition
matlab charts simulink statechart stateflow
In the below two state charts , the first one has an action to perform when it moves from StateA to StateD , ie. /z=5;
and the second one has to perform the action z=5;
I understand that this is a Transition Action , but i am unable to understand what is the different between the two transition
matlab charts simulink statechart stateflow
matlab charts simulink statechart stateflow
edited Nov 17 '18 at 0:35
Phil Goddard
9,2161925
9,2161925
asked Nov 16 '18 at 8:14
beastboybeastboy
73128
73128
See uk.mathworks.com/help/stateflow/ug/transition-action-types.html
– am304
Nov 16 '18 at 9:08
add a comment |
See uk.mathworks.com/help/stateflow/ug/transition-action-types.html
– am304
Nov 16 '18 at 9:08
See uk.mathworks.com/help/stateflow/ug/transition-action-types.html
– am304
Nov 16 '18 at 9:08
See uk.mathworks.com/help/stateflow/ug/transition-action-types.html
– am304
Nov 16 '18 at 9:08
add a comment |
2 Answers
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See the link given by @am304 for specific information, but in brief,
in your first image you have a
Transition Action
, which executes when the transition occurs (and after any state exit actions - if you had any forState A
),in your second image you have a
Condition Action
, which executes when any condition associated with the transition is determined to be true. You do not have any explicit conditions (i.e. nothing likee1[cond1]z = 5
) so the condition is considered to be true when any event occurs. This will execute even if the transition is not made (i.e. it is only dependent on the condition.) This means that it would occur before any state exit action (if you had any forState A
.)
Given the above, in your specific case (i.e. no exit actions for State A
and no conditions on the transition), the two will give the same result.
Thanks Phil for you answer... i understood the concept
– beastboy
Nov 27 '18 at 11:37
add a comment |
The "transition action" /z=5;
is equal to an "entry action" of a destination state entry: z=5;
. It might look like an "elegant" solution if you have multiple destination states but want to set a value based on the previous state and lots of additional logics (not in your example).
In the model reviews our people spent too much time figuring out what exctly happened in the charts using "transition actions". The generated code was also difficult to read. In our company-wide modeling guidelines we evntually prohibited using the "transition actions" because they make the models difficult to review.
The "condition actions" z=5;
in combination with the "state actions" entry: z=5;
are sufficient for any logics we needed to implement.
It would be a good move for MathWorks to discontinue the transition action semantics in the future releases.
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
See the link given by @am304 for specific information, but in brief,
in your first image you have a
Transition Action
, which executes when the transition occurs (and after any state exit actions - if you had any forState A
),in your second image you have a
Condition Action
, which executes when any condition associated with the transition is determined to be true. You do not have any explicit conditions (i.e. nothing likee1[cond1]z = 5
) so the condition is considered to be true when any event occurs. This will execute even if the transition is not made (i.e. it is only dependent on the condition.) This means that it would occur before any state exit action (if you had any forState A
.)
Given the above, in your specific case (i.e. no exit actions for State A
and no conditions on the transition), the two will give the same result.
Thanks Phil for you answer... i understood the concept
– beastboy
Nov 27 '18 at 11:37
add a comment |
See the link given by @am304 for specific information, but in brief,
in your first image you have a
Transition Action
, which executes when the transition occurs (and after any state exit actions - if you had any forState A
),in your second image you have a
Condition Action
, which executes when any condition associated with the transition is determined to be true. You do not have any explicit conditions (i.e. nothing likee1[cond1]z = 5
) so the condition is considered to be true when any event occurs. This will execute even if the transition is not made (i.e. it is only dependent on the condition.) This means that it would occur before any state exit action (if you had any forState A
.)
Given the above, in your specific case (i.e. no exit actions for State A
and no conditions on the transition), the two will give the same result.
Thanks Phil for you answer... i understood the concept
– beastboy
Nov 27 '18 at 11:37
add a comment |
See the link given by @am304 for specific information, but in brief,
in your first image you have a
Transition Action
, which executes when the transition occurs (and after any state exit actions - if you had any forState A
),in your second image you have a
Condition Action
, which executes when any condition associated with the transition is determined to be true. You do not have any explicit conditions (i.e. nothing likee1[cond1]z = 5
) so the condition is considered to be true when any event occurs. This will execute even if the transition is not made (i.e. it is only dependent on the condition.) This means that it would occur before any state exit action (if you had any forState A
.)
Given the above, in your specific case (i.e. no exit actions for State A
and no conditions on the transition), the two will give the same result.
See the link given by @am304 for specific information, but in brief,
in your first image you have a
Transition Action
, which executes when the transition occurs (and after any state exit actions - if you had any forState A
),in your second image you have a
Condition Action
, which executes when any condition associated with the transition is determined to be true. You do not have any explicit conditions (i.e. nothing likee1[cond1]z = 5
) so the condition is considered to be true when any event occurs. This will execute even if the transition is not made (i.e. it is only dependent on the condition.) This means that it would occur before any state exit action (if you had any forState A
.)
Given the above, in your specific case (i.e. no exit actions for State A
and no conditions on the transition), the two will give the same result.
edited Nov 17 '18 at 14:52
answered Nov 17 '18 at 0:45
Phil GoddardPhil Goddard
9,2161925
9,2161925
Thanks Phil for you answer... i understood the concept
– beastboy
Nov 27 '18 at 11:37
add a comment |
Thanks Phil for you answer... i understood the concept
– beastboy
Nov 27 '18 at 11:37
Thanks Phil for you answer... i understood the concept
– beastboy
Nov 27 '18 at 11:37
Thanks Phil for you answer... i understood the concept
– beastboy
Nov 27 '18 at 11:37
add a comment |
The "transition action" /z=5;
is equal to an "entry action" of a destination state entry: z=5;
. It might look like an "elegant" solution if you have multiple destination states but want to set a value based on the previous state and lots of additional logics (not in your example).
In the model reviews our people spent too much time figuring out what exctly happened in the charts using "transition actions". The generated code was also difficult to read. In our company-wide modeling guidelines we evntually prohibited using the "transition actions" because they make the models difficult to review.
The "condition actions" z=5;
in combination with the "state actions" entry: z=5;
are sufficient for any logics we needed to implement.
It would be a good move for MathWorks to discontinue the transition action semantics in the future releases.
add a comment |
The "transition action" /z=5;
is equal to an "entry action" of a destination state entry: z=5;
. It might look like an "elegant" solution if you have multiple destination states but want to set a value based on the previous state and lots of additional logics (not in your example).
In the model reviews our people spent too much time figuring out what exctly happened in the charts using "transition actions". The generated code was also difficult to read. In our company-wide modeling guidelines we evntually prohibited using the "transition actions" because they make the models difficult to review.
The "condition actions" z=5;
in combination with the "state actions" entry: z=5;
are sufficient for any logics we needed to implement.
It would be a good move for MathWorks to discontinue the transition action semantics in the future releases.
add a comment |
The "transition action" /z=5;
is equal to an "entry action" of a destination state entry: z=5;
. It might look like an "elegant" solution if you have multiple destination states but want to set a value based on the previous state and lots of additional logics (not in your example).
In the model reviews our people spent too much time figuring out what exctly happened in the charts using "transition actions". The generated code was also difficult to read. In our company-wide modeling guidelines we evntually prohibited using the "transition actions" because they make the models difficult to review.
The "condition actions" z=5;
in combination with the "state actions" entry: z=5;
are sufficient for any logics we needed to implement.
It would be a good move for MathWorks to discontinue the transition action semantics in the future releases.
The "transition action" /z=5;
is equal to an "entry action" of a destination state entry: z=5;
. It might look like an "elegant" solution if you have multiple destination states but want to set a value based on the previous state and lots of additional logics (not in your example).
In the model reviews our people spent too much time figuring out what exctly happened in the charts using "transition actions". The generated code was also difficult to read. In our company-wide modeling guidelines we evntually prohibited using the "transition actions" because they make the models difficult to review.
The "condition actions" z=5;
in combination with the "state actions" entry: z=5;
are sufficient for any logics we needed to implement.
It would be a good move for MathWorks to discontinue the transition action semantics in the future releases.
answered Feb 24 at 15:58
Evgeni VerbitskiEvgeni Verbitski
212
212
add a comment |
add a comment |
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See uk.mathworks.com/help/stateflow/ug/transition-action-types.html
– am304
Nov 16 '18 at 9:08