Toggle variable through a function
this question is pretty straightforward. I want to be able to detect whether a variable is false, and set it to true, commonly known as toggle.
Here is it:
var hello = false
function toggleSt(I, E)
if ((I == "activate") && (!E))
E = !E
alert("activated")
else if ((I == "disable") && (E))
E = !E
alert("disabled")
toggleSt("activate", hello)
alert(hello)
I pasted the code on JSFiddle,
http://jsfiddle.net/kpDSr/
Hello is still false.
javascript variables toggle
edited Nov 13 '18 at 9:19
Cœur
17.5k9104145
asked Aug 10 '11 at 15:31
ImplosionsImplosions
1114
add a comment |
this question is pretty straightforward. I want to be able to detect whether a variable is false, and set it to true, commonly known as toggle.
Here is it:
var hello = false
function toggleSt(I, E)
if ((I == "activate") && (!E))
E = !E
alert("activated")
else if ((I == "disable") && (E))
E = !E
alert("disabled")
toggleSt("activate", hello)
alert(hello)
I pasted the code on JSFiddle,
http://jsfiddle.net/kpDSr/
Hello is still false.
javascript variables toggle
edited Nov 13 '18 at 9:19
Cœur
17.5k9104145
asked Aug 10 '11 at 15:31
ImplosionsImplosions
1114
1
Ewill not be a reference tohello, it will only have the same value. ChangingEwill not changehello.
– Felix Kling
Aug 10 '11 at 15:34
add a comment |
this question is pretty straightforward. I want to be able to detect whether a variable is false, and set it to true, commonly known as toggle.
Here is it:
var hello = false
function toggleSt(I, E)
if ((I == "activate") && (!E))
E = !E
alert("activated")
else if ((I == "disable") && (E))
E = !E
alert("disabled")
toggleSt("activate", hello)
alert(hello)
I pasted the code on JSFiddle,
http://jsfiddle.net/kpDSr/
Hello is still false.
javascript variables toggle
edited Nov 13 '18 at 9:19
Cœur
17.5k9104145
asked Aug 10 '11 at 15:31
ImplosionsImplosions
1114
this question is pretty straightforward. I want to be able to detect whether a variable is false, and set it to true, commonly known as toggle.
Here is it:
var hello = false
function toggleSt(I, E)
if ((I == "activate") && (!E))
E = !E
alert("activated")
else if ((I == "disable") && (E))
E = !E
alert("disabled")
toggleSt("activate", hello)
alert(hello)
I pasted the code on JSFiddle,
http://jsfiddle.net/kpDSr/
Hello is still false.
javascript variables toggle
javascript variables toggle
edited Nov 13 '18 at 9:19
Cœur
17.5k9104145
asked Aug 10 '11 at 15:31
ImplosionsImplosions
1114
edited Nov 13 '18 at 9:19
Cœur
17.5k9104145
asked Aug 10 '11 at 15:31
ImplosionsImplosions
1114
edited Nov 13 '18 at 9:19
Cœur
17.5k9104145
edited Nov 13 '18 at 9:19
Cœur
17.5k9104145
edited Nov 13 '18 at 9:19
Cœur
17.5k9104145
17.5k9104145
asked Aug 10 '11 at 15:31
ImplosionsImplosions
1114
asked Aug 10 '11 at 15:31
ImplosionsImplosions
1114
asked Aug 10 '11 at 15:31
ImplosionsImplosions
1114
1114
1
Ewill not be a reference tohello, it will only have the same value. ChangingEwill not changehello.
– Felix Kling
Aug 10 '11 at 15:34
add a comment |
1
Ewill not be a reference tohello, it will only have the same value. ChangingEwill not changehello.
– Felix Kling
Aug 10 '11 at 15:34
1
1
E will not be a reference to hello, it will only have the same value. Changing E will not change hello.– Felix Kling
Aug 10 '11 at 15:34
E will not be a reference to hello, it will only have the same value. Changing E will not change hello.– Felix Kling
Aug 10 '11 at 15:34
add a comment |
2 Answers
2
active
oldest
votes
Felix is right. Try:
var hello = false
function toggleSt(I)
if ((I == "activate") && (!hello))
hello = !hello;
alert("activated")
else if ((I == "disable") && (hello))
hello = !hello
alert("disabled")
toggleSt("activate");
alert(hello)
answered Aug 10 '11 at 15:38
Gabriel RossGabriel Ross
4,03112127
But that's hardcoding! Any possible alternative?
– Implosions
Aug 10 '11 at 15:47
add a comment |
You assign hello to the new var E when you call the function. So in the function you have the new parameter E that set to true/false. Call the function without a parameter for hello and use hello as a global variable will work as you expected.
var hello = false
function toggleSt(I)
if ((I == "activate") && (!hello))
hello = !hello
alert("activated")
else if ((I == "disable") && (hello))
hello = !hello
alert("disabled")
toggleSt("activate")
alert(hello)
answered Aug 10 '11 at 15:46
Andreas KöberleAndreas Köberle
47.6k39177235
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Felix is right. Try:
var hello = false
function toggleSt(I)
if ((I == "activate") && (!hello))
hello = !hello;
alert("activated")
else if ((I == "disable") && (hello))
hello = !hello
alert("disabled")
toggleSt("activate");
alert(hello)
answered Aug 10 '11 at 15:38
Gabriel RossGabriel Ross
4,03112127
But that's hardcoding! Any possible alternative?
– Implosions
Aug 10 '11 at 15:47
add a comment |
Felix is right. Try:
var hello = false
function toggleSt(I)
if ((I == "activate") && (!hello))
hello = !hello;
alert("activated")
else if ((I == "disable") && (hello))
hello = !hello
alert("disabled")
toggleSt("activate");
alert(hello)
answered Aug 10 '11 at 15:38
Gabriel RossGabriel Ross
4,03112127
But that's hardcoding! Any possible alternative?
– Implosions
Aug 10 '11 at 15:47
add a comment |
Felix is right. Try:
var hello = false
function toggleSt(I)
if ((I == "activate") && (!hello))
hello = !hello;
alert("activated")
else if ((I == "disable") && (hello))
hello = !hello
alert("disabled")
toggleSt("activate");
alert(hello)
answered Aug 10 '11 at 15:38
Gabriel RossGabriel Ross
4,03112127
Felix is right. Try:
var hello = false
function toggleSt(I)
if ((I == "activate") && (!hello))
hello = !hello;
alert("activated")
else if ((I == "disable") && (hello))
hello = !hello
alert("disabled")
toggleSt("activate");
alert(hello)
answered Aug 10 '11 at 15:38
Gabriel RossGabriel Ross
4,03112127
edited Aug 10 '11 at 15:45
answered Aug 10 '11 at 15:38
Gabriel RossGabriel Ross
4,03112127
answered Aug 10 '11 at 15:38
Gabriel RossGabriel Ross
4,03112127
answered Aug 10 '11 at 15:38
Gabriel RossGabriel Ross
4,03112127
4,03112127
But that's hardcoding! Any possible alternative?
– Implosions
Aug 10 '11 at 15:47
add a comment |
But that's hardcoding! Any possible alternative?
– Implosions
Aug 10 '11 at 15:47
But that's hardcoding! Any possible alternative?
– Implosions
Aug 10 '11 at 15:47
But that's hardcoding! Any possible alternative?
– Implosions
Aug 10 '11 at 15:47
add a comment |
You assign hello to the new var E when you call the function. So in the function you have the new parameter E that set to true/false. Call the function without a parameter for hello and use hello as a global variable will work as you expected.
var hello = false
function toggleSt(I)
if ((I == "activate") && (!hello))
hello = !hello
alert("activated")
else if ((I == "disable") && (hello))
hello = !hello
alert("disabled")
toggleSt("activate")
alert(hello)
answered Aug 10 '11 at 15:46
Andreas KöberleAndreas Köberle
47.6k39177235
add a comment |
You assign hello to the new var E when you call the function. So in the function you have the new parameter E that set to true/false. Call the function without a parameter for hello and use hello as a global variable will work as you expected.
var hello = false
function toggleSt(I)
if ((I == "activate") && (!hello))
hello = !hello
alert("activated")
else if ((I == "disable") && (hello))
hello = !hello
alert("disabled")
toggleSt("activate")
alert(hello)
answered Aug 10 '11 at 15:46
Andreas KöberleAndreas Köberle
47.6k39177235
add a comment |
You assign hello to the new var E when you call the function. So in the function you have the new parameter E that set to true/false. Call the function without a parameter for hello and use hello as a global variable will work as you expected.
var hello = false
function toggleSt(I)
if ((I == "activate") && (!hello))
hello = !hello
alert("activated")
else if ((I == "disable") && (hello))
hello = !hello
alert("disabled")
toggleSt("activate")
alert(hello)
answered Aug 10 '11 at 15:46
Andreas KöberleAndreas Köberle
47.6k39177235
You assign hello to the new var E when you call the function. So in the function you have the new parameter E that set to true/false. Call the function without a parameter for hello and use hello as a global variable will work as you expected.
var hello = false
function toggleSt(I)
if ((I == "activate") && (!hello))
hello = !hello
alert("activated")
else if ((I == "disable") && (hello))
hello = !hello
alert("disabled")
toggleSt("activate")
alert(hello)
answered Aug 10 '11 at 15:46
Andreas KöberleAndreas Köberle
47.6k39177235
answered Aug 10 '11 at 15:46
Andreas KöberleAndreas Köberle
47.6k39177235
answered Aug 10 '11 at 15:46
Andreas KöberleAndreas Köberle
47.6k39177235
answered Aug 10 '11 at 15:46
Andreas KöberleAndreas Köberle
47.6k39177235
47.6k39177235
add a comment |
add a comment |
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Ewill not be a reference tohello, it will only have the same value. ChangingEwill not changehello.– Felix Kling
Aug 10 '11 at 15:34