rails 5 active record model setup help two user types










0















I am trying to work out the best DB structure to power this setup:



I have two types of user: sales and market.
Each user can have a number of clients.
Each client can have a number of transactions.Transactions will be assigned a transaction type: 'sales' or 'market'. Each client can have only one sales user and one market user.



I need to be able to retrieve a list of transactions for each user, so for a 'sales' user, user.transactions returns all transactions with a 'sales' type for all clients where the client's 'sales' user is that user



I have started out with the following setup but can't get all the queries I need, for example:



u = User.find(5)
Transaction.all.where(sales_ee: u)
# This is returning nothing


This is the setup so far:



class User < ApplicationRecord
has_many :sales_clients, :class_name => "Client", :foreign_key => "sales_ee_id"
has_many :market_traders, :class_name => "Client", :foreign_key => "market_ee_id"
has_many :clients, dependent: :destroy
has_many :transactions, :through => :traders
end

class Client < ApplicationRecord
belongs_to :sales_ee, :class_name => 'User', optional: true
belongs_to :market_ee, :class_name => 'User', optional: true
has_many :transactions, dependent: :destroy
belongs_to :user
end

class Transaction < ApplicationRecord
belongs_to :client
has_one :user, :through => :client
has_one :sales_ee, :through => :client
has_one :market_ee, :through => :client, required: false
end


I'm not sure if having two classes of user may be a more appropriate setup - any help would be much appreciated.










share|improve this question


























    0















    I am trying to work out the best DB structure to power this setup:



    I have two types of user: sales and market.
    Each user can have a number of clients.
    Each client can have a number of transactions.Transactions will be assigned a transaction type: 'sales' or 'market'. Each client can have only one sales user and one market user.



    I need to be able to retrieve a list of transactions for each user, so for a 'sales' user, user.transactions returns all transactions with a 'sales' type for all clients where the client's 'sales' user is that user



    I have started out with the following setup but can't get all the queries I need, for example:



    u = User.find(5)
    Transaction.all.where(sales_ee: u)
    # This is returning nothing


    This is the setup so far:



    class User < ApplicationRecord
    has_many :sales_clients, :class_name => "Client", :foreign_key => "sales_ee_id"
    has_many :market_traders, :class_name => "Client", :foreign_key => "market_ee_id"
    has_many :clients, dependent: :destroy
    has_many :transactions, :through => :traders
    end

    class Client < ApplicationRecord
    belongs_to :sales_ee, :class_name => 'User', optional: true
    belongs_to :market_ee, :class_name => 'User', optional: true
    has_many :transactions, dependent: :destroy
    belongs_to :user
    end

    class Transaction < ApplicationRecord
    belongs_to :client
    has_one :user, :through => :client
    has_one :sales_ee, :through => :client
    has_one :market_ee, :through => :client, required: false
    end


    I'm not sure if having two classes of user may be a more appropriate setup - any help would be much appreciated.










    share|improve this question
























      0












      0








      0








      I am trying to work out the best DB structure to power this setup:



      I have two types of user: sales and market.
      Each user can have a number of clients.
      Each client can have a number of transactions.Transactions will be assigned a transaction type: 'sales' or 'market'. Each client can have only one sales user and one market user.



      I need to be able to retrieve a list of transactions for each user, so for a 'sales' user, user.transactions returns all transactions with a 'sales' type for all clients where the client's 'sales' user is that user



      I have started out with the following setup but can't get all the queries I need, for example:



      u = User.find(5)
      Transaction.all.where(sales_ee: u)
      # This is returning nothing


      This is the setup so far:



      class User < ApplicationRecord
      has_many :sales_clients, :class_name => "Client", :foreign_key => "sales_ee_id"
      has_many :market_traders, :class_name => "Client", :foreign_key => "market_ee_id"
      has_many :clients, dependent: :destroy
      has_many :transactions, :through => :traders
      end

      class Client < ApplicationRecord
      belongs_to :sales_ee, :class_name => 'User', optional: true
      belongs_to :market_ee, :class_name => 'User', optional: true
      has_many :transactions, dependent: :destroy
      belongs_to :user
      end

      class Transaction < ApplicationRecord
      belongs_to :client
      has_one :user, :through => :client
      has_one :sales_ee, :through => :client
      has_one :market_ee, :through => :client, required: false
      end


      I'm not sure if having two classes of user may be a more appropriate setup - any help would be much appreciated.










      share|improve this question














      I am trying to work out the best DB structure to power this setup:



      I have two types of user: sales and market.
      Each user can have a number of clients.
      Each client can have a number of transactions.Transactions will be assigned a transaction type: 'sales' or 'market'. Each client can have only one sales user and one market user.



      I need to be able to retrieve a list of transactions for each user, so for a 'sales' user, user.transactions returns all transactions with a 'sales' type for all clients where the client's 'sales' user is that user



      I have started out with the following setup but can't get all the queries I need, for example:



      u = User.find(5)
      Transaction.all.where(sales_ee: u)
      # This is returning nothing


      This is the setup so far:



      class User < ApplicationRecord
      has_many :sales_clients, :class_name => "Client", :foreign_key => "sales_ee_id"
      has_many :market_traders, :class_name => "Client", :foreign_key => "market_ee_id"
      has_many :clients, dependent: :destroy
      has_many :transactions, :through => :traders
      end

      class Client < ApplicationRecord
      belongs_to :sales_ee, :class_name => 'User', optional: true
      belongs_to :market_ee, :class_name => 'User', optional: true
      has_many :transactions, dependent: :destroy
      belongs_to :user
      end

      class Transaction < ApplicationRecord
      belongs_to :client
      has_one :user, :through => :client
      has_one :sales_ee, :through => :client
      has_one :market_ee, :through => :client, required: false
      end


      I'm not sure if having two classes of user may be a more appropriate setup - any help would be much appreciated.







      activerecord ruby-on-rails-5 rails-activerecord






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      asked Nov 13 '18 at 19:17









      rhosynrhosyn

      12




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          1 Answer
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          Changes



           class Client < ApplicationRecord
          - belongs_to :sales_ee, :class_name => 'User', optional: true
          + belongs_to :sales_ee, :class_name => 'User', :foreign_key => "sales_ee_id", optional: true
          - belongs_to :market_ee, :class_name => 'User', optional: true
          + belongs_to :market_ee, :class_name => 'User', :foreign_key => "market_ee_id", optional: true
          has_many :transactions, dependent: :destroy
          belongs_to :user
          end





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            Changes



             class Client < ApplicationRecord
            - belongs_to :sales_ee, :class_name => 'User', optional: true
            + belongs_to :sales_ee, :class_name => 'User', :foreign_key => "sales_ee_id", optional: true
            - belongs_to :market_ee, :class_name => 'User', optional: true
            + belongs_to :market_ee, :class_name => 'User', :foreign_key => "market_ee_id", optional: true
            has_many :transactions, dependent: :destroy
            belongs_to :user
            end





            share|improve this answer



























              0














              Changes



               class Client < ApplicationRecord
              - belongs_to :sales_ee, :class_name => 'User', optional: true
              + belongs_to :sales_ee, :class_name => 'User', :foreign_key => "sales_ee_id", optional: true
              - belongs_to :market_ee, :class_name => 'User', optional: true
              + belongs_to :market_ee, :class_name => 'User', :foreign_key => "market_ee_id", optional: true
              has_many :transactions, dependent: :destroy
              belongs_to :user
              end





              share|improve this answer

























                0












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                0







                Changes



                 class Client < ApplicationRecord
                - belongs_to :sales_ee, :class_name => 'User', optional: true
                + belongs_to :sales_ee, :class_name => 'User', :foreign_key => "sales_ee_id", optional: true
                - belongs_to :market_ee, :class_name => 'User', optional: true
                + belongs_to :market_ee, :class_name => 'User', :foreign_key => "market_ee_id", optional: true
                has_many :transactions, dependent: :destroy
                belongs_to :user
                end





                share|improve this answer













                Changes



                 class Client < ApplicationRecord
                - belongs_to :sales_ee, :class_name => 'User', optional: true
                + belongs_to :sales_ee, :class_name => 'User', :foreign_key => "sales_ee_id", optional: true
                - belongs_to :market_ee, :class_name => 'User', optional: true
                + belongs_to :market_ee, :class_name => 'User', :foreign_key => "market_ee_id", optional: true
                has_many :transactions, dependent: :destroy
                belongs_to :user
                end






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 26 '18 at 8:15









                rayray

                1,8141319




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