while making a card game how can i make it so you cant draw the same card twice










2















Im trying to figure out how to get the program to recognize what card was drawn and remove it from the deck so it cant be drawn again. I know I could have don't a list of 52 where I have each item be a card name and pull it from that list and put it in a new list but with the way I did this that doesn't seem possible.
so how can I make it so it only draws a card one time?



import random
import time

played = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0]

def loop():
keepLooping = True
while(keepLooping):
global played
print ('The player with the lower card goes first')
print(' ')

# player One draw
draw = input("Player one would you like to draw?(y,n): ")
if draw == 'y':
CardNumber = random.randint(2,14)
Num2 = random.randint(2,4)
Royal = 11: "Jack",12: "Queen",13: "King",14: "Ace"
cardnum1 = Royal.get(CardNumber, CardNumber)
suits = 1: "Spades", 2: "Hearts", 3: "Diamonds", 4: "Clubs"
cardnum2 = suits[Num2]
DrawOne = [cardnum1, cardnum2]
print(DrawOne)
print(' ')
if draw == 'n':
print ('ok')

# player two draw
draw = input("Player Two would you like to draw?(y,n): ")
if draw == 'y':
CardNumber2 = random.randint(2,13)
Num3 = random.randint(2,4)
Royal = 11: "Jack",12: "Queen",13: "King",14: "Ace"
cardnum3 = Royal.get(CardNumber2, CardNumber2)
suits = 1: "Spades", 2: "Hearts", 3: "Diamonds", 4: "Clubs"
cardnum4 = suits[Num3]
DrawTwo = (cardnum3, cardnum4)
print(DrawTwo)
if draw == 'n':
print ('Then you lose')

# Win/lose/tie
if CardNumber == CardNumber2:
time.sleep(1)
print(' ')
print("it was a tie, lets re-draw")
print(' ')
keepLooping = True
else:
if CardNumber < CardNumber2:
keepLooping = False
time.sleep(.5)
print(' ')
print (DrawOne, 'Is the lower card, player 1 youre going first')
if CardNumber > CardNumber2:
keepLooping = False
time.sleep(.5)
print(' ')
print (DrawTwo, 'Is the lower card, player 2 youre going first')

loop()









share|improve this question
























  • Where is your question? What is the problem?

    – BlueSheepToken
    Nov 13 '18 at 22:54











  • title, I don't know how to make it so it only draw a card one time.

    – J WALKAZ
    Nov 13 '18 at 23:10















2















Im trying to figure out how to get the program to recognize what card was drawn and remove it from the deck so it cant be drawn again. I know I could have don't a list of 52 where I have each item be a card name and pull it from that list and put it in a new list but with the way I did this that doesn't seem possible.
so how can I make it so it only draws a card one time?



import random
import time

played = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0]

def loop():
keepLooping = True
while(keepLooping):
global played
print ('The player with the lower card goes first')
print(' ')

# player One draw
draw = input("Player one would you like to draw?(y,n): ")
if draw == 'y':
CardNumber = random.randint(2,14)
Num2 = random.randint(2,4)
Royal = 11: "Jack",12: "Queen",13: "King",14: "Ace"
cardnum1 = Royal.get(CardNumber, CardNumber)
suits = 1: "Spades", 2: "Hearts", 3: "Diamonds", 4: "Clubs"
cardnum2 = suits[Num2]
DrawOne = [cardnum1, cardnum2]
print(DrawOne)
print(' ')
if draw == 'n':
print ('ok')

# player two draw
draw = input("Player Two would you like to draw?(y,n): ")
if draw == 'y':
CardNumber2 = random.randint(2,13)
Num3 = random.randint(2,4)
Royal = 11: "Jack",12: "Queen",13: "King",14: "Ace"
cardnum3 = Royal.get(CardNumber2, CardNumber2)
suits = 1: "Spades", 2: "Hearts", 3: "Diamonds", 4: "Clubs"
cardnum4 = suits[Num3]
DrawTwo = (cardnum3, cardnum4)
print(DrawTwo)
if draw == 'n':
print ('Then you lose')

# Win/lose/tie
if CardNumber == CardNumber2:
time.sleep(1)
print(' ')
print("it was a tie, lets re-draw")
print(' ')
keepLooping = True
else:
if CardNumber < CardNumber2:
keepLooping = False
time.sleep(.5)
print(' ')
print (DrawOne, 'Is the lower card, player 1 youre going first')
if CardNumber > CardNumber2:
keepLooping = False
time.sleep(.5)
print(' ')
print (DrawTwo, 'Is the lower card, player 2 youre going first')

loop()









share|improve this question
























  • Where is your question? What is the problem?

    – BlueSheepToken
    Nov 13 '18 at 22:54











  • title, I don't know how to make it so it only draw a card one time.

    – J WALKAZ
    Nov 13 '18 at 23:10













2












2








2








Im trying to figure out how to get the program to recognize what card was drawn and remove it from the deck so it cant be drawn again. I know I could have don't a list of 52 where I have each item be a card name and pull it from that list and put it in a new list but with the way I did this that doesn't seem possible.
so how can I make it so it only draws a card one time?



import random
import time

played = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0]

def loop():
keepLooping = True
while(keepLooping):
global played
print ('The player with the lower card goes first')
print(' ')

# player One draw
draw = input("Player one would you like to draw?(y,n): ")
if draw == 'y':
CardNumber = random.randint(2,14)
Num2 = random.randint(2,4)
Royal = 11: "Jack",12: "Queen",13: "King",14: "Ace"
cardnum1 = Royal.get(CardNumber, CardNumber)
suits = 1: "Spades", 2: "Hearts", 3: "Diamonds", 4: "Clubs"
cardnum2 = suits[Num2]
DrawOne = [cardnum1, cardnum2]
print(DrawOne)
print(' ')
if draw == 'n':
print ('ok')

# player two draw
draw = input("Player Two would you like to draw?(y,n): ")
if draw == 'y':
CardNumber2 = random.randint(2,13)
Num3 = random.randint(2,4)
Royal = 11: "Jack",12: "Queen",13: "King",14: "Ace"
cardnum3 = Royal.get(CardNumber2, CardNumber2)
suits = 1: "Spades", 2: "Hearts", 3: "Diamonds", 4: "Clubs"
cardnum4 = suits[Num3]
DrawTwo = (cardnum3, cardnum4)
print(DrawTwo)
if draw == 'n':
print ('Then you lose')

# Win/lose/tie
if CardNumber == CardNumber2:
time.sleep(1)
print(' ')
print("it was a tie, lets re-draw")
print(' ')
keepLooping = True
else:
if CardNumber < CardNumber2:
keepLooping = False
time.sleep(.5)
print(' ')
print (DrawOne, 'Is the lower card, player 1 youre going first')
if CardNumber > CardNumber2:
keepLooping = False
time.sleep(.5)
print(' ')
print (DrawTwo, 'Is the lower card, player 2 youre going first')

loop()









share|improve this question
















Im trying to figure out how to get the program to recognize what card was drawn and remove it from the deck so it cant be drawn again. I know I could have don't a list of 52 where I have each item be a card name and pull it from that list and put it in a new list but with the way I did this that doesn't seem possible.
so how can I make it so it only draws a card one time?



import random
import time

played = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,
0,0,0,0,0,0,0]

def loop():
keepLooping = True
while(keepLooping):
global played
print ('The player with the lower card goes first')
print(' ')

# player One draw
draw = input("Player one would you like to draw?(y,n): ")
if draw == 'y':
CardNumber = random.randint(2,14)
Num2 = random.randint(2,4)
Royal = 11: "Jack",12: "Queen",13: "King",14: "Ace"
cardnum1 = Royal.get(CardNumber, CardNumber)
suits = 1: "Spades", 2: "Hearts", 3: "Diamonds", 4: "Clubs"
cardnum2 = suits[Num2]
DrawOne = [cardnum1, cardnum2]
print(DrawOne)
print(' ')
if draw == 'n':
print ('ok')

# player two draw
draw = input("Player Two would you like to draw?(y,n): ")
if draw == 'y':
CardNumber2 = random.randint(2,13)
Num3 = random.randint(2,4)
Royal = 11: "Jack",12: "Queen",13: "King",14: "Ace"
cardnum3 = Royal.get(CardNumber2, CardNumber2)
suits = 1: "Spades", 2: "Hearts", 3: "Diamonds", 4: "Clubs"
cardnum4 = suits[Num3]
DrawTwo = (cardnum3, cardnum4)
print(DrawTwo)
if draw == 'n':
print ('Then you lose')

# Win/lose/tie
if CardNumber == CardNumber2:
time.sleep(1)
print(' ')
print("it was a tie, lets re-draw")
print(' ')
keepLooping = True
else:
if CardNumber < CardNumber2:
keepLooping = False
time.sleep(.5)
print(' ')
print (DrawOne, 'Is the lower card, player 1 youre going first')
if CardNumber > CardNumber2:
keepLooping = False
time.sleep(.5)
print(' ')
print (DrawTwo, 'Is the lower card, player 2 youre going first')

loop()






python-3.x






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 13 '18 at 23:11







J WALKAZ

















asked Nov 13 '18 at 22:46









J WALKAZJ WALKAZ

113




113












  • Where is your question? What is the problem?

    – BlueSheepToken
    Nov 13 '18 at 22:54











  • title, I don't know how to make it so it only draw a card one time.

    – J WALKAZ
    Nov 13 '18 at 23:10

















  • Where is your question? What is the problem?

    – BlueSheepToken
    Nov 13 '18 at 22:54











  • title, I don't know how to make it so it only draw a card one time.

    – J WALKAZ
    Nov 13 '18 at 23:10
















Where is your question? What is the problem?

– BlueSheepToken
Nov 13 '18 at 22:54





Where is your question? What is the problem?

– BlueSheepToken
Nov 13 '18 at 22:54













title, I don't know how to make it so it only draw a card one time.

– J WALKAZ
Nov 13 '18 at 23:10





title, I don't know how to make it so it only draw a card one time.

– J WALKAZ
Nov 13 '18 at 23:10












1 Answer
1






active

oldest

votes


















1














Easy way conceptually (and not using numpy):



>>> cards = list(range(52))
>>> random.shuffle(cards)
>>> cards
[7, 28, 1, 49, 27, 36, 26, 16, 32, 23, 45, 19, 31, 13, 44, 5, 37, 3, 39, 29, 42, 11, 46, 6, 2, 0, 15, 14, 48, 38, 9, 51, 10, 20, 43, 25, 18, 12, 8, 21, 47, 4, 33, 24, 41, 50, 35, 17, 40, 22, 34, 30]


Now everytime you draw, you can pop one from the list.



>>> card = cards.pop()
>>> card
30


Then to get the suit and the number, you can do this:



suit = card % 4 # e.g. 0 is hearts, etc. (arbitrary)
number = card % 13 + 1 # so that 1 is 1, and 11 is Jack


In case modulo (%) is not familiar, please have a look here: How does % work in Python?






share|improve this answer

























  • to make sure I understand are you saying replace this? CardNumber = random.randint(2,14) Num2 = random.randint(2,4) Royal = 11: "Jack",12: "Queen",13: "King",14: "Ace" cardnum1 = Royal.get(CardNumber, CardNumber) suits = 1: "Spades", 2: "Hearts", 3: "Diamonds", 4: "Clubs"

    – J WALKAZ
    Nov 13 '18 at 23:31












  • I'm sure you can figure it out using this. Final clue: suit will be a number, so you still need to convert it indeed using your "suits" dictionary, these parts didn't change.

    – PascalVKooten
    Nov 13 '18 at 23:33











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














Easy way conceptually (and not using numpy):



>>> cards = list(range(52))
>>> random.shuffle(cards)
>>> cards
[7, 28, 1, 49, 27, 36, 26, 16, 32, 23, 45, 19, 31, 13, 44, 5, 37, 3, 39, 29, 42, 11, 46, 6, 2, 0, 15, 14, 48, 38, 9, 51, 10, 20, 43, 25, 18, 12, 8, 21, 47, 4, 33, 24, 41, 50, 35, 17, 40, 22, 34, 30]


Now everytime you draw, you can pop one from the list.



>>> card = cards.pop()
>>> card
30


Then to get the suit and the number, you can do this:



suit = card % 4 # e.g. 0 is hearts, etc. (arbitrary)
number = card % 13 + 1 # so that 1 is 1, and 11 is Jack


In case modulo (%) is not familiar, please have a look here: How does % work in Python?






share|improve this answer

























  • to make sure I understand are you saying replace this? CardNumber = random.randint(2,14) Num2 = random.randint(2,4) Royal = 11: "Jack",12: "Queen",13: "King",14: "Ace" cardnum1 = Royal.get(CardNumber, CardNumber) suits = 1: "Spades", 2: "Hearts", 3: "Diamonds", 4: "Clubs"

    – J WALKAZ
    Nov 13 '18 at 23:31












  • I'm sure you can figure it out using this. Final clue: suit will be a number, so you still need to convert it indeed using your "suits" dictionary, these parts didn't change.

    – PascalVKooten
    Nov 13 '18 at 23:33
















1














Easy way conceptually (and not using numpy):



>>> cards = list(range(52))
>>> random.shuffle(cards)
>>> cards
[7, 28, 1, 49, 27, 36, 26, 16, 32, 23, 45, 19, 31, 13, 44, 5, 37, 3, 39, 29, 42, 11, 46, 6, 2, 0, 15, 14, 48, 38, 9, 51, 10, 20, 43, 25, 18, 12, 8, 21, 47, 4, 33, 24, 41, 50, 35, 17, 40, 22, 34, 30]


Now everytime you draw, you can pop one from the list.



>>> card = cards.pop()
>>> card
30


Then to get the suit and the number, you can do this:



suit = card % 4 # e.g. 0 is hearts, etc. (arbitrary)
number = card % 13 + 1 # so that 1 is 1, and 11 is Jack


In case modulo (%) is not familiar, please have a look here: How does % work in Python?






share|improve this answer

























  • to make sure I understand are you saying replace this? CardNumber = random.randint(2,14) Num2 = random.randint(2,4) Royal = 11: "Jack",12: "Queen",13: "King",14: "Ace" cardnum1 = Royal.get(CardNumber, CardNumber) suits = 1: "Spades", 2: "Hearts", 3: "Diamonds", 4: "Clubs"

    – J WALKAZ
    Nov 13 '18 at 23:31












  • I'm sure you can figure it out using this. Final clue: suit will be a number, so you still need to convert it indeed using your "suits" dictionary, these parts didn't change.

    – PascalVKooten
    Nov 13 '18 at 23:33














1












1








1







Easy way conceptually (and not using numpy):



>>> cards = list(range(52))
>>> random.shuffle(cards)
>>> cards
[7, 28, 1, 49, 27, 36, 26, 16, 32, 23, 45, 19, 31, 13, 44, 5, 37, 3, 39, 29, 42, 11, 46, 6, 2, 0, 15, 14, 48, 38, 9, 51, 10, 20, 43, 25, 18, 12, 8, 21, 47, 4, 33, 24, 41, 50, 35, 17, 40, 22, 34, 30]


Now everytime you draw, you can pop one from the list.



>>> card = cards.pop()
>>> card
30


Then to get the suit and the number, you can do this:



suit = card % 4 # e.g. 0 is hearts, etc. (arbitrary)
number = card % 13 + 1 # so that 1 is 1, and 11 is Jack


In case modulo (%) is not familiar, please have a look here: How does % work in Python?






share|improve this answer















Easy way conceptually (and not using numpy):



>>> cards = list(range(52))
>>> random.shuffle(cards)
>>> cards
[7, 28, 1, 49, 27, 36, 26, 16, 32, 23, 45, 19, 31, 13, 44, 5, 37, 3, 39, 29, 42, 11, 46, 6, 2, 0, 15, 14, 48, 38, 9, 51, 10, 20, 43, 25, 18, 12, 8, 21, 47, 4, 33, 24, 41, 50, 35, 17, 40, 22, 34, 30]


Now everytime you draw, you can pop one from the list.



>>> card = cards.pop()
>>> card
30


Then to get the suit and the number, you can do this:



suit = card % 4 # e.g. 0 is hearts, etc. (arbitrary)
number = card % 13 + 1 # so that 1 is 1, and 11 is Jack


In case modulo (%) is not familiar, please have a look here: How does % work in Python?







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 13 '18 at 23:28

























answered Nov 13 '18 at 23:21









PascalVKootenPascalVKooten

9,977958110




9,977958110












  • to make sure I understand are you saying replace this? CardNumber = random.randint(2,14) Num2 = random.randint(2,4) Royal = 11: "Jack",12: "Queen",13: "King",14: "Ace" cardnum1 = Royal.get(CardNumber, CardNumber) suits = 1: "Spades", 2: "Hearts", 3: "Diamonds", 4: "Clubs"

    – J WALKAZ
    Nov 13 '18 at 23:31












  • I'm sure you can figure it out using this. Final clue: suit will be a number, so you still need to convert it indeed using your "suits" dictionary, these parts didn't change.

    – PascalVKooten
    Nov 13 '18 at 23:33


















  • to make sure I understand are you saying replace this? CardNumber = random.randint(2,14) Num2 = random.randint(2,4) Royal = 11: "Jack",12: "Queen",13: "King",14: "Ace" cardnum1 = Royal.get(CardNumber, CardNumber) suits = 1: "Spades", 2: "Hearts", 3: "Diamonds", 4: "Clubs"

    – J WALKAZ
    Nov 13 '18 at 23:31












  • I'm sure you can figure it out using this. Final clue: suit will be a number, so you still need to convert it indeed using your "suits" dictionary, these parts didn't change.

    – PascalVKooten
    Nov 13 '18 at 23:33

















to make sure I understand are you saying replace this? CardNumber = random.randint(2,14) Num2 = random.randint(2,4) Royal = 11: "Jack",12: "Queen",13: "King",14: "Ace" cardnum1 = Royal.get(CardNumber, CardNumber) suits = 1: "Spades", 2: "Hearts", 3: "Diamonds", 4: "Clubs"

– J WALKAZ
Nov 13 '18 at 23:31






to make sure I understand are you saying replace this? CardNumber = random.randint(2,14) Num2 = random.randint(2,4) Royal = 11: "Jack",12: "Queen",13: "King",14: "Ace" cardnum1 = Royal.get(CardNumber, CardNumber) suits = 1: "Spades", 2: "Hearts", 3: "Diamonds", 4: "Clubs"

– J WALKAZ
Nov 13 '18 at 23:31














I'm sure you can figure it out using this. Final clue: suit will be a number, so you still need to convert it indeed using your "suits" dictionary, these parts didn't change.

– PascalVKooten
Nov 13 '18 at 23:33






I'm sure you can figure it out using this. Final clue: suit will be a number, so you still need to convert it indeed using your "suits" dictionary, these parts didn't change.

– PascalVKooten
Nov 13 '18 at 23:33


















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