Why the regular expression is not working properly










-1















I have a validation for first name and while I'm running the "Start*" it will not pass through the code while I pass the "Start$" then it will pass the string. below is the program:-



package main

import (
"fmt"
"regexp"
)

func main()
FirstName := "Star*"
var validName = regexp.MustCompile("^[\pL0-9-_&$.,’'x60()!/ ]*$")
if !validName.MatchString(FirstName)
fmt.Println("--------------", FirstName)
else
fmt.Println(FirstName)

FirstName2 := "Star$"
if !validName.MatchString(FirstName2)
fmt.Println("--------------", FirstName2)
else
fmt.Println(FirstName2)




Play ground link










share|improve this question




























    -1















    I have a validation for first name and while I'm running the "Start*" it will not pass through the code while I pass the "Start$" then it will pass the string. below is the program:-



    package main

    import (
    "fmt"
    "regexp"
    )

    func main()
    FirstName := "Star*"
    var validName = regexp.MustCompile("^[\pL0-9-_&$.,’'x60()!/ ]*$")
    if !validName.MatchString(FirstName)
    fmt.Println("--------------", FirstName)
    else
    fmt.Println(FirstName)

    FirstName2 := "Star$"
    if !validName.MatchString(FirstName2)
    fmt.Println("--------------", FirstName2)
    else
    fmt.Println(FirstName2)




    Play ground link










    share|improve this question


























      -1












      -1








      -1








      I have a validation for first name and while I'm running the "Start*" it will not pass through the code while I pass the "Start$" then it will pass the string. below is the program:-



      package main

      import (
      "fmt"
      "regexp"
      )

      func main()
      FirstName := "Star*"
      var validName = regexp.MustCompile("^[\pL0-9-_&$.,’'x60()!/ ]*$")
      if !validName.MatchString(FirstName)
      fmt.Println("--------------", FirstName)
      else
      fmt.Println(FirstName)

      FirstName2 := "Star$"
      if !validName.MatchString(FirstName2)
      fmt.Println("--------------", FirstName2)
      else
      fmt.Println(FirstName2)




      Play ground link










      share|improve this question
















      I have a validation for first name and while I'm running the "Start*" it will not pass through the code while I pass the "Start$" then it will pass the string. below is the program:-



      package main

      import (
      "fmt"
      "regexp"
      )

      func main()
      FirstName := "Star*"
      var validName = regexp.MustCompile("^[\pL0-9-_&$.,’'x60()!/ ]*$")
      if !validName.MatchString(FirstName)
      fmt.Println("--------------", FirstName)
      else
      fmt.Println(FirstName)

      FirstName2 := "Star$"
      if !validName.MatchString(FirstName2)
      fmt.Println("--------------", FirstName2)
      else
      fmt.Println(FirstName2)




      Play ground link







      regex go






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 16 '18 at 8:30









      Vorsprung

      23.4k32246




      23.4k32246










      asked Nov 16 '18 at 7:41









      stackstack

      165




      165






















          1 Answer
          1






          active

          oldest

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          2














          Delete the use $ inside of the
          ^[\pL0-9-_&$.,’'x60()!/ ]*$ so it would be ^[\pL0-9-_&.,’'x60()!/ ]*$.






          share|improve this answer




















          • 1





            $ is a normal character inside the braces of a character class, so that's not it

            – Vorsprung
            Nov 16 '18 at 8:09











          • @vorsprung you are correct. I've edited my answer.

            – Vizjerei
            Nov 16 '18 at 8:20











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          1 Answer
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          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2














          Delete the use $ inside of the
          ^[\pL0-9-_&$.,’'x60()!/ ]*$ so it would be ^[\pL0-9-_&.,’'x60()!/ ]*$.






          share|improve this answer




















          • 1





            $ is a normal character inside the braces of a character class, so that's not it

            – Vorsprung
            Nov 16 '18 at 8:09











          • @vorsprung you are correct. I've edited my answer.

            – Vizjerei
            Nov 16 '18 at 8:20















          2














          Delete the use $ inside of the
          ^[\pL0-9-_&$.,’'x60()!/ ]*$ so it would be ^[\pL0-9-_&.,’'x60()!/ ]*$.






          share|improve this answer




















          • 1





            $ is a normal character inside the braces of a character class, so that's not it

            – Vorsprung
            Nov 16 '18 at 8:09











          • @vorsprung you are correct. I've edited my answer.

            – Vizjerei
            Nov 16 '18 at 8:20













          2












          2








          2







          Delete the use $ inside of the
          ^[\pL0-9-_&$.,’'x60()!/ ]*$ so it would be ^[\pL0-9-_&.,’'x60()!/ ]*$.






          share|improve this answer















          Delete the use $ inside of the
          ^[\pL0-9-_&$.,’'x60()!/ ]*$ so it would be ^[\pL0-9-_&.,’'x60()!/ ]*$.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 16 '18 at 8:19

























          answered Nov 16 '18 at 7:57









          VizjereiVizjerei

          629312




          629312







          • 1





            $ is a normal character inside the braces of a character class, so that's not it

            – Vorsprung
            Nov 16 '18 at 8:09











          • @vorsprung you are correct. I've edited my answer.

            – Vizjerei
            Nov 16 '18 at 8:20












          • 1





            $ is a normal character inside the braces of a character class, so that's not it

            – Vorsprung
            Nov 16 '18 at 8:09











          • @vorsprung you are correct. I've edited my answer.

            – Vizjerei
            Nov 16 '18 at 8:20







          1




          1





          $ is a normal character inside the braces of a character class, so that's not it

          – Vorsprung
          Nov 16 '18 at 8:09





          $ is a normal character inside the braces of a character class, so that's not it

          – Vorsprung
          Nov 16 '18 at 8:09













          @vorsprung you are correct. I've edited my answer.

          – Vizjerei
          Nov 16 '18 at 8:20





          @vorsprung you are correct. I've edited my answer.

          – Vizjerei
          Nov 16 '18 at 8:20



















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