Display warnning only once using python multiprocessing









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Is there a way to display a warning only once when using Pythons multiprocessing.Pool?



Simple example that illustrates the problem



import multiprocessing
import warnings


def func_with_warning(data):
warnings.warn("Warning message ".format(data))

if __name__ == '__main__':
data = [0, 1, 2]
pool = multiprocessing.Pool(2)
pool.map(func_with_warning, data)


Result:



>> /home/user/script.py:10: UserWarning: Warning message 0
warnings.warn("Warning message ".format(data))
/home/user/script.py:10: UserWarning: Warning message 1
warnings.warn("Warning message ".format(data))
/home/user/script.py:10: UserWarning: Warning message 2
warnings.warn("Warning message ".format(data))
>>


I understand that each spawned process is like separate Python world, but maybe someone knows any trick how to display warnings in such cases only once?



Someone suggested it is duplicate of question: Python 3: Catching warnings during multiprocessing. In my opinion:



  • it is similar, but not the same.

  • solutions there may, but do not have to answer my question,

  • it is much more detailed and focused on some narrower scope problem of catching warnings during objects instantiations









share|improve this question























  • Use a shared flag or a queue.
    – stovfl
    Nov 8 at 16:03










  • You should surround the work with the pool in if __name__ == '__main__': clause. See this for detail
    – Artemiy
    Nov 8 at 18:51










  • @stovfl So in shared memory I need to keep track of every possible warning I am displaying and check before warning? Sounds like a lot of work and additional code, it is some solution, but only for warnings I raise myself. For warnings raised by libraries I use I think it won't work.
    – dankal444
    Nov 9 at 20:36










  • @Artemly I guess you tried to run the example while being on Windows, I am using Linux and when I wrote this simple example I forgot about this fork-problem you encountered. I will edit post
    – dankal444
    Nov 9 at 20:40











  • Possible duplicate of Python 3: Catching warnings during multiprocessing
    – stovfl
    Nov 9 at 21:11














up vote
0
down vote

favorite












Is there a way to display a warning only once when using Pythons multiprocessing.Pool?



Simple example that illustrates the problem



import multiprocessing
import warnings


def func_with_warning(data):
warnings.warn("Warning message ".format(data))

if __name__ == '__main__':
data = [0, 1, 2]
pool = multiprocessing.Pool(2)
pool.map(func_with_warning, data)


Result:



>> /home/user/script.py:10: UserWarning: Warning message 0
warnings.warn("Warning message ".format(data))
/home/user/script.py:10: UserWarning: Warning message 1
warnings.warn("Warning message ".format(data))
/home/user/script.py:10: UserWarning: Warning message 2
warnings.warn("Warning message ".format(data))
>>


I understand that each spawned process is like separate Python world, but maybe someone knows any trick how to display warnings in such cases only once?



Someone suggested it is duplicate of question: Python 3: Catching warnings during multiprocessing. In my opinion:



  • it is similar, but not the same.

  • solutions there may, but do not have to answer my question,

  • it is much more detailed and focused on some narrower scope problem of catching warnings during objects instantiations









share|improve this question























  • Use a shared flag or a queue.
    – stovfl
    Nov 8 at 16:03










  • You should surround the work with the pool in if __name__ == '__main__': clause. See this for detail
    – Artemiy
    Nov 8 at 18:51










  • @stovfl So in shared memory I need to keep track of every possible warning I am displaying and check before warning? Sounds like a lot of work and additional code, it is some solution, but only for warnings I raise myself. For warnings raised by libraries I use I think it won't work.
    – dankal444
    Nov 9 at 20:36










  • @Artemly I guess you tried to run the example while being on Windows, I am using Linux and when I wrote this simple example I forgot about this fork-problem you encountered. I will edit post
    – dankal444
    Nov 9 at 20:40











  • Possible duplicate of Python 3: Catching warnings during multiprocessing
    – stovfl
    Nov 9 at 21:11












up vote
0
down vote

favorite









up vote
0
down vote

favorite











Is there a way to display a warning only once when using Pythons multiprocessing.Pool?



Simple example that illustrates the problem



import multiprocessing
import warnings


def func_with_warning(data):
warnings.warn("Warning message ".format(data))

if __name__ == '__main__':
data = [0, 1, 2]
pool = multiprocessing.Pool(2)
pool.map(func_with_warning, data)


Result:



>> /home/user/script.py:10: UserWarning: Warning message 0
warnings.warn("Warning message ".format(data))
/home/user/script.py:10: UserWarning: Warning message 1
warnings.warn("Warning message ".format(data))
/home/user/script.py:10: UserWarning: Warning message 2
warnings.warn("Warning message ".format(data))
>>


I understand that each spawned process is like separate Python world, but maybe someone knows any trick how to display warnings in such cases only once?



Someone suggested it is duplicate of question: Python 3: Catching warnings during multiprocessing. In my opinion:



  • it is similar, but not the same.

  • solutions there may, but do not have to answer my question,

  • it is much more detailed and focused on some narrower scope problem of catching warnings during objects instantiations









share|improve this question















Is there a way to display a warning only once when using Pythons multiprocessing.Pool?



Simple example that illustrates the problem



import multiprocessing
import warnings


def func_with_warning(data):
warnings.warn("Warning message ".format(data))

if __name__ == '__main__':
data = [0, 1, 2]
pool = multiprocessing.Pool(2)
pool.map(func_with_warning, data)


Result:



>> /home/user/script.py:10: UserWarning: Warning message 0
warnings.warn("Warning message ".format(data))
/home/user/script.py:10: UserWarning: Warning message 1
warnings.warn("Warning message ".format(data))
/home/user/script.py:10: UserWarning: Warning message 2
warnings.warn("Warning message ".format(data))
>>


I understand that each spawned process is like separate Python world, but maybe someone knows any trick how to display warnings in such cases only once?



Someone suggested it is duplicate of question: Python 3: Catching warnings during multiprocessing. In my opinion:



  • it is similar, but not the same.

  • solutions there may, but do not have to answer my question,

  • it is much more detailed and focused on some narrower scope problem of catching warnings during objects instantiations






python python-3.x warnings python-multiprocessing






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 11 at 15:38

























asked Nov 8 at 11:11









dankal444

145113




145113











  • Use a shared flag or a queue.
    – stovfl
    Nov 8 at 16:03










  • You should surround the work with the pool in if __name__ == '__main__': clause. See this for detail
    – Artemiy
    Nov 8 at 18:51










  • @stovfl So in shared memory I need to keep track of every possible warning I am displaying and check before warning? Sounds like a lot of work and additional code, it is some solution, but only for warnings I raise myself. For warnings raised by libraries I use I think it won't work.
    – dankal444
    Nov 9 at 20:36










  • @Artemly I guess you tried to run the example while being on Windows, I am using Linux and when I wrote this simple example I forgot about this fork-problem you encountered. I will edit post
    – dankal444
    Nov 9 at 20:40











  • Possible duplicate of Python 3: Catching warnings during multiprocessing
    – stovfl
    Nov 9 at 21:11
















  • Use a shared flag or a queue.
    – stovfl
    Nov 8 at 16:03










  • You should surround the work with the pool in if __name__ == '__main__': clause. See this for detail
    – Artemiy
    Nov 8 at 18:51










  • @stovfl So in shared memory I need to keep track of every possible warning I am displaying and check before warning? Sounds like a lot of work and additional code, it is some solution, but only for warnings I raise myself. For warnings raised by libraries I use I think it won't work.
    – dankal444
    Nov 9 at 20:36










  • @Artemly I guess you tried to run the example while being on Windows, I am using Linux and when I wrote this simple example I forgot about this fork-problem you encountered. I will edit post
    – dankal444
    Nov 9 at 20:40











  • Possible duplicate of Python 3: Catching warnings during multiprocessing
    – stovfl
    Nov 9 at 21:11















Use a shared flag or a queue.
– stovfl
Nov 8 at 16:03




Use a shared flag or a queue.
– stovfl
Nov 8 at 16:03












You should surround the work with the pool in if __name__ == '__main__': clause. See this for detail
– Artemiy
Nov 8 at 18:51




You should surround the work with the pool in if __name__ == '__main__': clause. See this for detail
– Artemiy
Nov 8 at 18:51












@stovfl So in shared memory I need to keep track of every possible warning I am displaying and check before warning? Sounds like a lot of work and additional code, it is some solution, but only for warnings I raise myself. For warnings raised by libraries I use I think it won't work.
– dankal444
Nov 9 at 20:36




@stovfl So in shared memory I need to keep track of every possible warning I am displaying and check before warning? Sounds like a lot of work and additional code, it is some solution, but only for warnings I raise myself. For warnings raised by libraries I use I think it won't work.
– dankal444
Nov 9 at 20:36












@Artemly I guess you tried to run the example while being on Windows, I am using Linux and when I wrote this simple example I forgot about this fork-problem you encountered. I will edit post
– dankal444
Nov 9 at 20:40





@Artemly I guess you tried to run the example while being on Windows, I am using Linux and when I wrote this simple example I forgot about this fork-problem you encountered. I will edit post
– dankal444
Nov 9 at 20:40













Possible duplicate of Python 3: Catching warnings during multiprocessing
– stovfl
Nov 9 at 21:11




Possible duplicate of Python 3: Catching warnings during multiprocessing
– stovfl
Nov 9 at 21:11

















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