Step wizard form










0















I am making angular application with angular dynamic form where i need to split up the form into two parts.



In which i have input field firstname and lastname at first page and on click the next button the children which has email and dropdown needs to get loaded..



Html:



 <form (ngSubmit)="onSubmit()" [formGroup]="form">

<div *ngFor="let question of questions" class="form-row">
<ng-container *ngIf="question.children">
<div [formArrayName]="question.key">
<div *ngFor="let item of form.get(question.key).controls; let i=index" [formGroupName]="i">
<div *ngFor="let item of question.children">
<app-question [question]="item" [form]="form.get(question.key).at(i)"></app-question>
</div>
</div>
</div>
</ng-container>
<ng-container *ngIf="!question.children">
<app-question [question]="question" [form]="form"></app-question>

</ng-container>
</div>

<button (click)="goBack()"> Previous </button> &nbsp;
<button (click)="addControls('myArray')"> Next </button>

<div class="form-row">
<button type="submit" [disabled]="!form.valid">Save</button>
</div>
</form>


Ts:



 @Input() questions: QuestionBase<any> = ;
form: FormGroup;
payLoad = '';

page: number = 0

constructor(private qcs: QuestionControlService)

ngOnInit()
this.form = this.qcs.toFormGroup(this.questions);


onSubmit()
this.payLoad = JSON.stringify(this.form.value);

addControls(control: string)
let question: any = this.questions.find(q => q.key == control);
let children = question ? question.children : null;
if (children)
(this.form.get(control) as FormArray).push(this.qcs.toFormGroup(children))

removeControls(control: string)
let array=this.form.get(control) as FormArray;
array.removeAt(array.length-1);


goBack()
//Function to move to previous step



Working demo:



https://stackblitz.com/edit/angular-x4a5b6-p4agaq



In this demo with code you can see on every click over add button the children (array) get appended to the below in the same page..



I am also having removeControl function which has,



 removeControls(control: string)
let array=this.form.get(control) as FormArray;
array.removeAt(array.length-1);



To be clear i am not going to use this now and not going to remove anything anywhere.. Only thing is on click next the children via addControl function adds the children to next next page and on previous get back to previous step.



In order to append to the same page given in demo, it should move to next page and again on click the previous it should get to original state on every next click it should give a new email and dropdown and on previous a getback to previous step..



It should get moved like slider with sliding effect while moving forth and back..



Everything needs to be in pure angular and javascript/typescript based and there is no jquery.. As you could able to see in my demo i have not included any library or jquery..



Kindly help me to achieve the result.. Stucked for a long time..










share|improve this question




























    0















    I am making angular application with angular dynamic form where i need to split up the form into two parts.



    In which i have input field firstname and lastname at first page and on click the next button the children which has email and dropdown needs to get loaded..



    Html:



     <form (ngSubmit)="onSubmit()" [formGroup]="form">

    <div *ngFor="let question of questions" class="form-row">
    <ng-container *ngIf="question.children">
    <div [formArrayName]="question.key">
    <div *ngFor="let item of form.get(question.key).controls; let i=index" [formGroupName]="i">
    <div *ngFor="let item of question.children">
    <app-question [question]="item" [form]="form.get(question.key).at(i)"></app-question>
    </div>
    </div>
    </div>
    </ng-container>
    <ng-container *ngIf="!question.children">
    <app-question [question]="question" [form]="form"></app-question>

    </ng-container>
    </div>

    <button (click)="goBack()"> Previous </button> &nbsp;
    <button (click)="addControls('myArray')"> Next </button>

    <div class="form-row">
    <button type="submit" [disabled]="!form.valid">Save</button>
    </div>
    </form>


    Ts:



     @Input() questions: QuestionBase<any> = ;
    form: FormGroup;
    payLoad = '';

    page: number = 0

    constructor(private qcs: QuestionControlService)

    ngOnInit()
    this.form = this.qcs.toFormGroup(this.questions);


    onSubmit()
    this.payLoad = JSON.stringify(this.form.value);

    addControls(control: string)
    let question: any = this.questions.find(q => q.key == control);
    let children = question ? question.children : null;
    if (children)
    (this.form.get(control) as FormArray).push(this.qcs.toFormGroup(children))

    removeControls(control: string)
    let array=this.form.get(control) as FormArray;
    array.removeAt(array.length-1);


    goBack()
    //Function to move to previous step



    Working demo:



    https://stackblitz.com/edit/angular-x4a5b6-p4agaq



    In this demo with code you can see on every click over add button the children (array) get appended to the below in the same page..



    I am also having removeControl function which has,



     removeControls(control: string)
    let array=this.form.get(control) as FormArray;
    array.removeAt(array.length-1);



    To be clear i am not going to use this now and not going to remove anything anywhere.. Only thing is on click next the children via addControl function adds the children to next next page and on previous get back to previous step.



    In order to append to the same page given in demo, it should move to next page and again on click the previous it should get to original state on every next click it should give a new email and dropdown and on previous a getback to previous step..



    It should get moved like slider with sliding effect while moving forth and back..



    Everything needs to be in pure angular and javascript/typescript based and there is no jquery.. As you could able to see in my demo i have not included any library or jquery..



    Kindly help me to achieve the result.. Stucked for a long time..










    share|improve this question


























      0












      0








      0


      0






      I am making angular application with angular dynamic form where i need to split up the form into two parts.



      In which i have input field firstname and lastname at first page and on click the next button the children which has email and dropdown needs to get loaded..



      Html:



       <form (ngSubmit)="onSubmit()" [formGroup]="form">

      <div *ngFor="let question of questions" class="form-row">
      <ng-container *ngIf="question.children">
      <div [formArrayName]="question.key">
      <div *ngFor="let item of form.get(question.key).controls; let i=index" [formGroupName]="i">
      <div *ngFor="let item of question.children">
      <app-question [question]="item" [form]="form.get(question.key).at(i)"></app-question>
      </div>
      </div>
      </div>
      </ng-container>
      <ng-container *ngIf="!question.children">
      <app-question [question]="question" [form]="form"></app-question>

      </ng-container>
      </div>

      <button (click)="goBack()"> Previous </button> &nbsp;
      <button (click)="addControls('myArray')"> Next </button>

      <div class="form-row">
      <button type="submit" [disabled]="!form.valid">Save</button>
      </div>
      </form>


      Ts:



       @Input() questions: QuestionBase<any> = ;
      form: FormGroup;
      payLoad = '';

      page: number = 0

      constructor(private qcs: QuestionControlService)

      ngOnInit()
      this.form = this.qcs.toFormGroup(this.questions);


      onSubmit()
      this.payLoad = JSON.stringify(this.form.value);

      addControls(control: string)
      let question: any = this.questions.find(q => q.key == control);
      let children = question ? question.children : null;
      if (children)
      (this.form.get(control) as FormArray).push(this.qcs.toFormGroup(children))

      removeControls(control: string)
      let array=this.form.get(control) as FormArray;
      array.removeAt(array.length-1);


      goBack()
      //Function to move to previous step



      Working demo:



      https://stackblitz.com/edit/angular-x4a5b6-p4agaq



      In this demo with code you can see on every click over add button the children (array) get appended to the below in the same page..



      I am also having removeControl function which has,



       removeControls(control: string)
      let array=this.form.get(control) as FormArray;
      array.removeAt(array.length-1);



      To be clear i am not going to use this now and not going to remove anything anywhere.. Only thing is on click next the children via addControl function adds the children to next next page and on previous get back to previous step.



      In order to append to the same page given in demo, it should move to next page and again on click the previous it should get to original state on every next click it should give a new email and dropdown and on previous a getback to previous step..



      It should get moved like slider with sliding effect while moving forth and back..



      Everything needs to be in pure angular and javascript/typescript based and there is no jquery.. As you could able to see in my demo i have not included any library or jquery..



      Kindly help me to achieve the result.. Stucked for a long time..










      share|improve this question
















      I am making angular application with angular dynamic form where i need to split up the form into two parts.



      In which i have input field firstname and lastname at first page and on click the next button the children which has email and dropdown needs to get loaded..



      Html:



       <form (ngSubmit)="onSubmit()" [formGroup]="form">

      <div *ngFor="let question of questions" class="form-row">
      <ng-container *ngIf="question.children">
      <div [formArrayName]="question.key">
      <div *ngFor="let item of form.get(question.key).controls; let i=index" [formGroupName]="i">
      <div *ngFor="let item of question.children">
      <app-question [question]="item" [form]="form.get(question.key).at(i)"></app-question>
      </div>
      </div>
      </div>
      </ng-container>
      <ng-container *ngIf="!question.children">
      <app-question [question]="question" [form]="form"></app-question>

      </ng-container>
      </div>

      <button (click)="goBack()"> Previous </button> &nbsp;
      <button (click)="addControls('myArray')"> Next </button>

      <div class="form-row">
      <button type="submit" [disabled]="!form.valid">Save</button>
      </div>
      </form>


      Ts:



       @Input() questions: QuestionBase<any> = ;
      form: FormGroup;
      payLoad = '';

      page: number = 0

      constructor(private qcs: QuestionControlService)

      ngOnInit()
      this.form = this.qcs.toFormGroup(this.questions);


      onSubmit()
      this.payLoad = JSON.stringify(this.form.value);

      addControls(control: string)
      let question: any = this.questions.find(q => q.key == control);
      let children = question ? question.children : null;
      if (children)
      (this.form.get(control) as FormArray).push(this.qcs.toFormGroup(children))

      removeControls(control: string)
      let array=this.form.get(control) as FormArray;
      array.removeAt(array.length-1);


      goBack()
      //Function to move to previous step



      Working demo:



      https://stackblitz.com/edit/angular-x4a5b6-p4agaq



      In this demo with code you can see on every click over add button the children (array) get appended to the below in the same page..



      I am also having removeControl function which has,



       removeControls(control: string)
      let array=this.form.get(control) as FormArray;
      array.removeAt(array.length-1);



      To be clear i am not going to use this now and not going to remove anything anywhere.. Only thing is on click next the children via addControl function adds the children to next next page and on previous get back to previous step.



      In order to append to the same page given in demo, it should move to next page and again on click the previous it should get to original state on every next click it should give a new email and dropdown and on previous a getback to previous step..



      It should get moved like slider with sliding effect while moving forth and back..



      Everything needs to be in pure angular and javascript/typescript based and there is no jquery.. As you could able to see in my demo i have not included any library or jquery..



      Kindly help me to achieve the result.. Stucked for a long time..







      javascript angular forms typescript angular-reactive-forms






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 15 '18 at 12:29







      Maniraj from Karur

















      asked Nov 15 '18 at 4:42









      Maniraj from KarurManiraj from Karur

      1,0591135




      1,0591135






















          4 Answers
          4






          active

          oldest

          votes


















          1














          If you want to create stepper form you can project the form and use the formcontrol to connect the parentformgroup.



          ParentComponent.ts








          Next


          <div class="step container" *ngIf="form.valid && nextForm" >
          <form [formGroup]="step2">
          <app-step2 (control)="enableSave($event)"></app-step2>
          <button class="btn btn-primary" (click)="moveToPrevious()" >Previous</button>
          </form>
          </div>
          <hr>
          <button
          [disabled]="eSave"
          class="btn btn-primary" (click)="save()">Save</button>
          </app-stepper-wrapper>


          ParentComponent.ts



          name = 'Angular';
          eSave = true;
          form = new FormGroup();
          step2 = new FormGroup();
          nextForm = false;

          ngOnInit()
          this.form.statusChanges.subscribe(s => this.eSave = true);

          moveToNext()
          if (this.form.valid)
          this.nextForm = true;


          moveToPrevious()
          this.nextForm = false;

          save()
          console.log(this.form);
          console.log(this.step2);

          enableSave($event)
          if ($event == 'VALID' && this.form.valid)

          this.eSave = false;




          Example:https://stackblitz.com/edit/angular-nynvvr






          share|improve this answer























          • Chellappan, I couldn't able to find anything on click next button in your solution..

            – Maniraj from Karur
            Nov 15 '18 at 7:50






          • 1





            @ManiRaj Nantri!!!!

            – Chellappan
            Nov 15 '18 at 9:17












          • Chellappan, Can you help me here, stucked for past two days, stackoverflow.com/questions/53316581/…

            – Maniraj from Karur
            Nov 15 '18 at 9:48











          • I will try to help later

            – Chellappan
            Nov 15 '18 at 9:55











          • Okay please help me to achieve the result..

            – Maniraj from Karur
            Nov 15 '18 at 9:57


















          1














          Pass array in the goBack method which you want to remove



           <button (click)="goBack('myArray')"> Previous </button> &nbsp; 


          Put this method in the component ts file



           goBack(control: string) 
          let question: any = this.questions.find(q => q.key == control);
          let children = question ? question.children : null;
          if (children)

          (this.form.get(control) as FormArray).removeAt(children.length-1)







          share|improve this answer




















          • 1





            I am in the need of the children in the next page and not in same page..

            – Maniraj from Karur
            Nov 15 '18 at 5:49


















          0














          Have try to reach your requirements : Except UI part. I hope you can handle you UI as your requirement.



          TS :



           import Component, Input, OnInit from '@angular/core';
          import FormGroup, FormArray from '@angular/forms';

          import QuestionBase from './question-base';
          import QuestionControlService from './question-control.service';

          @Component(
          selector: 'app-dynamic-form',
          templateUrl: './dynamic-form.component.html',
          providers: [QuestionControlService]
          )
          export class DynamicFormComponent implements OnInit

          @Input() questions: QuestionBase<any> = ;
          form: FormGroup;
          payLoad = '';

          page: number = 0;

          constructor(private qcs: QuestionControlService)

          ngOnInit()
          this.form = this.qcs.toFormGroup(this.questions);


          onSubmit()
          this.payLoad = JSON.stringify(this.form.value);

          addControls(control: string, index: any)
          let array = this.form.get('myArray') as FormArray;
          if (array.length > this.page)
          this.page = this.page + 1;
          else
          let question: any = this.questions.find(q => q.key == control);
          let children = question ? question.children : null;
          if (children)
          (this.form.get(control) as FormArray).push(this.qcs.toFormGroup(children))
          this.page = this.page + 1;


          removeControls(control: string)
          let array = this.form.get(control) as FormArray;
          array.removeAt(array.length - 1);


          goBack()
          if (this.page > 0)
          this.page = this.page - 1;

          //let array = this.form.get('myArray') as FormArray;
          //array.removeAt(array.length - 1);
          //Function to move to previous step




          HTML :

          <div>
          <form (ngSubmit)="onSubmit()" [formGroup]="form">

          <div *ngFor="let question of questions" class="form-row">
          <ng-container *ngIf="question.children">
          <div [formArrayName]="question.key">
          <div *ngFor="let item of form.get(question.key).controls; let i=index" [formGroupName]="i">
          <ng-template [ngIf]="i + 1 == page">
          <div *ngFor="let item of question.children">
          <app-question [question]="item" [form]="form.get(question.key).at(i)"></app-question>
          </div>
          </ng-template>
          </div>
          </div>
          </ng-container>
          <ng-container *ngIf="!question.children">
          <app-question [question]="question" [form]="form"></app-question>

          </ng-container>
          </div>

          <button (click)="goBack()"> Previous </button> &nbsp;
          <button (click)="addControls('myArray',i)"> Next </button>

          <div class="form-row">
          <button type="submit" [disabled]="!form.valid">Save</button>
          </div>
          </form> <br>

          <pre>
          json
          </pre>
          </div>


          This will help you showing one page at a time. It will create new one if no next form exists. And on clicking previous it will navigate to old form.






          share|improve this answer























          • I am in the need of the children in the next view and not in same view. If it moves to next view then provide stackblitz moving to next

            – Maniraj from Karur
            Nov 15 '18 at 5:51


















          0














          So, you want to remove lastly added control email and dropdown control from the form group array.



          I have added the code into goBack() function to remove child form group controls.




          Component:




           goBack() 
          //Function to move to previous step
          if(this.form.controls['myArray'])
          const arr = <FormArray>this.form.controls.myArray;
          arr.removeAt(arr.length - 1);




          Working demo: https://angular-x4a5b6-cc4kyr.stackblitz.io






          share|improve this answer























          • For this i already have removeControl function, you can see in example.. The thing is on click next button, the first name and last name needs to get hidden and the email and dropdown needs to come.. On click the previous button the firstname and lastname come.. This alone my requirement.. And no need of remove function now.. On each next click the dropdown and email needs to get show in next next screen.. The question is mainly to handle the thing in the different views and not on same page..

            – Maniraj from Karur
            Nov 15 '18 at 5:23












          • Okay, I will suggest you make a new route in this case for email and dropdown. Because things become complex if you do manual hide and show.

            – Surjeet Bhadauriya
            Nov 15 '18 at 5:26










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          4 Answers
          4






          active

          oldest

          votes








          4 Answers
          4






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          If you want to create stepper form you can project the form and use the formcontrol to connect the parentformgroup.



          ParentComponent.ts








          Next


          <div class="step container" *ngIf="form.valid && nextForm" >
          <form [formGroup]="step2">
          <app-step2 (control)="enableSave($event)"></app-step2>
          <button class="btn btn-primary" (click)="moveToPrevious()" >Previous</button>
          </form>
          </div>
          <hr>
          <button
          [disabled]="eSave"
          class="btn btn-primary" (click)="save()">Save</button>
          </app-stepper-wrapper>


          ParentComponent.ts



          name = 'Angular';
          eSave = true;
          form = new FormGroup();
          step2 = new FormGroup();
          nextForm = false;

          ngOnInit()
          this.form.statusChanges.subscribe(s => this.eSave = true);

          moveToNext()
          if (this.form.valid)
          this.nextForm = true;


          moveToPrevious()
          this.nextForm = false;

          save()
          console.log(this.form);
          console.log(this.step2);

          enableSave($event)
          if ($event == 'VALID' && this.form.valid)

          this.eSave = false;




          Example:https://stackblitz.com/edit/angular-nynvvr






          share|improve this answer























          • Chellappan, I couldn't able to find anything on click next button in your solution..

            – Maniraj from Karur
            Nov 15 '18 at 7:50






          • 1





            @ManiRaj Nantri!!!!

            – Chellappan
            Nov 15 '18 at 9:17












          • Chellappan, Can you help me here, stucked for past two days, stackoverflow.com/questions/53316581/…

            – Maniraj from Karur
            Nov 15 '18 at 9:48











          • I will try to help later

            – Chellappan
            Nov 15 '18 at 9:55











          • Okay please help me to achieve the result..

            – Maniraj from Karur
            Nov 15 '18 at 9:57















          1














          If you want to create stepper form you can project the form and use the formcontrol to connect the parentformgroup.



          ParentComponent.ts








          Next


          <div class="step container" *ngIf="form.valid && nextForm" >
          <form [formGroup]="step2">
          <app-step2 (control)="enableSave($event)"></app-step2>
          <button class="btn btn-primary" (click)="moveToPrevious()" >Previous</button>
          </form>
          </div>
          <hr>
          <button
          [disabled]="eSave"
          class="btn btn-primary" (click)="save()">Save</button>
          </app-stepper-wrapper>


          ParentComponent.ts



          name = 'Angular';
          eSave = true;
          form = new FormGroup();
          step2 = new FormGroup();
          nextForm = false;

          ngOnInit()
          this.form.statusChanges.subscribe(s => this.eSave = true);

          moveToNext()
          if (this.form.valid)
          this.nextForm = true;


          moveToPrevious()
          this.nextForm = false;

          save()
          console.log(this.form);
          console.log(this.step2);

          enableSave($event)
          if ($event == 'VALID' && this.form.valid)

          this.eSave = false;




          Example:https://stackblitz.com/edit/angular-nynvvr






          share|improve this answer























          • Chellappan, I couldn't able to find anything on click next button in your solution..

            – Maniraj from Karur
            Nov 15 '18 at 7:50






          • 1





            @ManiRaj Nantri!!!!

            – Chellappan
            Nov 15 '18 at 9:17












          • Chellappan, Can you help me here, stucked for past two days, stackoverflow.com/questions/53316581/…

            – Maniraj from Karur
            Nov 15 '18 at 9:48











          • I will try to help later

            – Chellappan
            Nov 15 '18 at 9:55











          • Okay please help me to achieve the result..

            – Maniraj from Karur
            Nov 15 '18 at 9:57













          1












          1








          1







          If you want to create stepper form you can project the form and use the formcontrol to connect the parentformgroup.



          ParentComponent.ts








          Next


          <div class="step container" *ngIf="form.valid && nextForm" >
          <form [formGroup]="step2">
          <app-step2 (control)="enableSave($event)"></app-step2>
          <button class="btn btn-primary" (click)="moveToPrevious()" >Previous</button>
          </form>
          </div>
          <hr>
          <button
          [disabled]="eSave"
          class="btn btn-primary" (click)="save()">Save</button>
          </app-stepper-wrapper>


          ParentComponent.ts



          name = 'Angular';
          eSave = true;
          form = new FormGroup();
          step2 = new FormGroup();
          nextForm = false;

          ngOnInit()
          this.form.statusChanges.subscribe(s => this.eSave = true);

          moveToNext()
          if (this.form.valid)
          this.nextForm = true;


          moveToPrevious()
          this.nextForm = false;

          save()
          console.log(this.form);
          console.log(this.step2);

          enableSave($event)
          if ($event == 'VALID' && this.form.valid)

          this.eSave = false;




          Example:https://stackblitz.com/edit/angular-nynvvr






          share|improve this answer













          If you want to create stepper form you can project the form and use the formcontrol to connect the parentformgroup.



          ParentComponent.ts








          Next


          <div class="step container" *ngIf="form.valid && nextForm" >
          <form [formGroup]="step2">
          <app-step2 (control)="enableSave($event)"></app-step2>
          <button class="btn btn-primary" (click)="moveToPrevious()" >Previous</button>
          </form>
          </div>
          <hr>
          <button
          [disabled]="eSave"
          class="btn btn-primary" (click)="save()">Save</button>
          </app-stepper-wrapper>


          ParentComponent.ts



          name = 'Angular';
          eSave = true;
          form = new FormGroup();
          step2 = new FormGroup();
          nextForm = false;

          ngOnInit()
          this.form.statusChanges.subscribe(s => this.eSave = true);

          moveToNext()
          if (this.form.valid)
          this.nextForm = true;


          moveToPrevious()
          this.nextForm = false;

          save()
          console.log(this.form);
          console.log(this.step2);

          enableSave($event)
          if ($event == 'VALID' && this.form.valid)

          this.eSave = false;




          Example:https://stackblitz.com/edit/angular-nynvvr







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 15 '18 at 7:43









          ChellappanChellappan

          5,4262419




          5,4262419












          • Chellappan, I couldn't able to find anything on click next button in your solution..

            – Maniraj from Karur
            Nov 15 '18 at 7:50






          • 1





            @ManiRaj Nantri!!!!

            – Chellappan
            Nov 15 '18 at 9:17












          • Chellappan, Can you help me here, stucked for past two days, stackoverflow.com/questions/53316581/…

            – Maniraj from Karur
            Nov 15 '18 at 9:48











          • I will try to help later

            – Chellappan
            Nov 15 '18 at 9:55











          • Okay please help me to achieve the result..

            – Maniraj from Karur
            Nov 15 '18 at 9:57

















          • Chellappan, I couldn't able to find anything on click next button in your solution..

            – Maniraj from Karur
            Nov 15 '18 at 7:50






          • 1





            @ManiRaj Nantri!!!!

            – Chellappan
            Nov 15 '18 at 9:17












          • Chellappan, Can you help me here, stucked for past two days, stackoverflow.com/questions/53316581/…

            – Maniraj from Karur
            Nov 15 '18 at 9:48











          • I will try to help later

            – Chellappan
            Nov 15 '18 at 9:55











          • Okay please help me to achieve the result..

            – Maniraj from Karur
            Nov 15 '18 at 9:57
















          Chellappan, I couldn't able to find anything on click next button in your solution..

          – Maniraj from Karur
          Nov 15 '18 at 7:50





          Chellappan, I couldn't able to find anything on click next button in your solution..

          – Maniraj from Karur
          Nov 15 '18 at 7:50




          1




          1





          @ManiRaj Nantri!!!!

          – Chellappan
          Nov 15 '18 at 9:17






          @ManiRaj Nantri!!!!

          – Chellappan
          Nov 15 '18 at 9:17














          Chellappan, Can you help me here, stucked for past two days, stackoverflow.com/questions/53316581/…

          – Maniraj from Karur
          Nov 15 '18 at 9:48





          Chellappan, Can you help me here, stucked for past two days, stackoverflow.com/questions/53316581/…

          – Maniraj from Karur
          Nov 15 '18 at 9:48













          I will try to help later

          – Chellappan
          Nov 15 '18 at 9:55





          I will try to help later

          – Chellappan
          Nov 15 '18 at 9:55













          Okay please help me to achieve the result..

          – Maniraj from Karur
          Nov 15 '18 at 9:57





          Okay please help me to achieve the result..

          – Maniraj from Karur
          Nov 15 '18 at 9:57













          1














          Pass array in the goBack method which you want to remove



           <button (click)="goBack('myArray')"> Previous </button> &nbsp; 


          Put this method in the component ts file



           goBack(control: string) 
          let question: any = this.questions.find(q => q.key == control);
          let children = question ? question.children : null;
          if (children)

          (this.form.get(control) as FormArray).removeAt(children.length-1)







          share|improve this answer




















          • 1





            I am in the need of the children in the next page and not in same page..

            – Maniraj from Karur
            Nov 15 '18 at 5:49















          1














          Pass array in the goBack method which you want to remove



           <button (click)="goBack('myArray')"> Previous </button> &nbsp; 


          Put this method in the component ts file



           goBack(control: string) 
          let question: any = this.questions.find(q => q.key == control);
          let children = question ? question.children : null;
          if (children)

          (this.form.get(control) as FormArray).removeAt(children.length-1)







          share|improve this answer




















          • 1





            I am in the need of the children in the next page and not in same page..

            – Maniraj from Karur
            Nov 15 '18 at 5:49













          1












          1








          1







          Pass array in the goBack method which you want to remove



           <button (click)="goBack('myArray')"> Previous </button> &nbsp; 


          Put this method in the component ts file



           goBack(control: string) 
          let question: any = this.questions.find(q => q.key == control);
          let children = question ? question.children : null;
          if (children)

          (this.form.get(control) as FormArray).removeAt(children.length-1)







          share|improve this answer















          Pass array in the goBack method which you want to remove



           <button (click)="goBack('myArray')"> Previous </button> &nbsp; 


          Put this method in the component ts file



           goBack(control: string) 
          let question: any = this.questions.find(q => q.key == control);
          let children = question ? question.children : null;
          if (children)

          (this.form.get(control) as FormArray).removeAt(children.length-1)








          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 15 '18 at 5:51

























          answered Nov 15 '18 at 5:46









          Ushmi DaveUshmi Dave

          713




          713







          • 1





            I am in the need of the children in the next page and not in same page..

            – Maniraj from Karur
            Nov 15 '18 at 5:49












          • 1





            I am in the need of the children in the next page and not in same page..

            – Maniraj from Karur
            Nov 15 '18 at 5:49







          1




          1





          I am in the need of the children in the next page and not in same page..

          – Maniraj from Karur
          Nov 15 '18 at 5:49





          I am in the need of the children in the next page and not in same page..

          – Maniraj from Karur
          Nov 15 '18 at 5:49











          0














          Have try to reach your requirements : Except UI part. I hope you can handle you UI as your requirement.



          TS :



           import Component, Input, OnInit from '@angular/core';
          import FormGroup, FormArray from '@angular/forms';

          import QuestionBase from './question-base';
          import QuestionControlService from './question-control.service';

          @Component(
          selector: 'app-dynamic-form',
          templateUrl: './dynamic-form.component.html',
          providers: [QuestionControlService]
          )
          export class DynamicFormComponent implements OnInit

          @Input() questions: QuestionBase<any> = ;
          form: FormGroup;
          payLoad = '';

          page: number = 0;

          constructor(private qcs: QuestionControlService)

          ngOnInit()
          this.form = this.qcs.toFormGroup(this.questions);


          onSubmit()
          this.payLoad = JSON.stringify(this.form.value);

          addControls(control: string, index: any)
          let array = this.form.get('myArray') as FormArray;
          if (array.length > this.page)
          this.page = this.page + 1;
          else
          let question: any = this.questions.find(q => q.key == control);
          let children = question ? question.children : null;
          if (children)
          (this.form.get(control) as FormArray).push(this.qcs.toFormGroup(children))
          this.page = this.page + 1;


          removeControls(control: string)
          let array = this.form.get(control) as FormArray;
          array.removeAt(array.length - 1);


          goBack()
          if (this.page > 0)
          this.page = this.page - 1;

          //let array = this.form.get('myArray') as FormArray;
          //array.removeAt(array.length - 1);
          //Function to move to previous step




          HTML :

          <div>
          <form (ngSubmit)="onSubmit()" [formGroup]="form">

          <div *ngFor="let question of questions" class="form-row">
          <ng-container *ngIf="question.children">
          <div [formArrayName]="question.key">
          <div *ngFor="let item of form.get(question.key).controls; let i=index" [formGroupName]="i">
          <ng-template [ngIf]="i + 1 == page">
          <div *ngFor="let item of question.children">
          <app-question [question]="item" [form]="form.get(question.key).at(i)"></app-question>
          </div>
          </ng-template>
          </div>
          </div>
          </ng-container>
          <ng-container *ngIf="!question.children">
          <app-question [question]="question" [form]="form"></app-question>

          </ng-container>
          </div>

          <button (click)="goBack()"> Previous </button> &nbsp;
          <button (click)="addControls('myArray',i)"> Next </button>

          <div class="form-row">
          <button type="submit" [disabled]="!form.valid">Save</button>
          </div>
          </form> <br>

          <pre>
          json
          </pre>
          </div>


          This will help you showing one page at a time. It will create new one if no next form exists. And on clicking previous it will navigate to old form.






          share|improve this answer























          • I am in the need of the children in the next view and not in same view. If it moves to next view then provide stackblitz moving to next

            – Maniraj from Karur
            Nov 15 '18 at 5:51















          0














          Have try to reach your requirements : Except UI part. I hope you can handle you UI as your requirement.



          TS :



           import Component, Input, OnInit from '@angular/core';
          import FormGroup, FormArray from '@angular/forms';

          import QuestionBase from './question-base';
          import QuestionControlService from './question-control.service';

          @Component(
          selector: 'app-dynamic-form',
          templateUrl: './dynamic-form.component.html',
          providers: [QuestionControlService]
          )
          export class DynamicFormComponent implements OnInit

          @Input() questions: QuestionBase<any> = ;
          form: FormGroup;
          payLoad = '';

          page: number = 0;

          constructor(private qcs: QuestionControlService)

          ngOnInit()
          this.form = this.qcs.toFormGroup(this.questions);


          onSubmit()
          this.payLoad = JSON.stringify(this.form.value);

          addControls(control: string, index: any)
          let array = this.form.get('myArray') as FormArray;
          if (array.length > this.page)
          this.page = this.page + 1;
          else
          let question: any = this.questions.find(q => q.key == control);
          let children = question ? question.children : null;
          if (children)
          (this.form.get(control) as FormArray).push(this.qcs.toFormGroup(children))
          this.page = this.page + 1;


          removeControls(control: string)
          let array = this.form.get(control) as FormArray;
          array.removeAt(array.length - 1);


          goBack()
          if (this.page > 0)
          this.page = this.page - 1;

          //let array = this.form.get('myArray') as FormArray;
          //array.removeAt(array.length - 1);
          //Function to move to previous step




          HTML :

          <div>
          <form (ngSubmit)="onSubmit()" [formGroup]="form">

          <div *ngFor="let question of questions" class="form-row">
          <ng-container *ngIf="question.children">
          <div [formArrayName]="question.key">
          <div *ngFor="let item of form.get(question.key).controls; let i=index" [formGroupName]="i">
          <ng-template [ngIf]="i + 1 == page">
          <div *ngFor="let item of question.children">
          <app-question [question]="item" [form]="form.get(question.key).at(i)"></app-question>
          </div>
          </ng-template>
          </div>
          </div>
          </ng-container>
          <ng-container *ngIf="!question.children">
          <app-question [question]="question" [form]="form"></app-question>

          </ng-container>
          </div>

          <button (click)="goBack()"> Previous </button> &nbsp;
          <button (click)="addControls('myArray',i)"> Next </button>

          <div class="form-row">
          <button type="submit" [disabled]="!form.valid">Save</button>
          </div>
          </form> <br>

          <pre>
          json
          </pre>
          </div>


          This will help you showing one page at a time. It will create new one if no next form exists. And on clicking previous it will navigate to old form.






          share|improve this answer























          • I am in the need of the children in the next view and not in same view. If it moves to next view then provide stackblitz moving to next

            – Maniraj from Karur
            Nov 15 '18 at 5:51













          0












          0








          0







          Have try to reach your requirements : Except UI part. I hope you can handle you UI as your requirement.



          TS :



           import Component, Input, OnInit from '@angular/core';
          import FormGroup, FormArray from '@angular/forms';

          import QuestionBase from './question-base';
          import QuestionControlService from './question-control.service';

          @Component(
          selector: 'app-dynamic-form',
          templateUrl: './dynamic-form.component.html',
          providers: [QuestionControlService]
          )
          export class DynamicFormComponent implements OnInit

          @Input() questions: QuestionBase<any> = ;
          form: FormGroup;
          payLoad = '';

          page: number = 0;

          constructor(private qcs: QuestionControlService)

          ngOnInit()
          this.form = this.qcs.toFormGroup(this.questions);


          onSubmit()
          this.payLoad = JSON.stringify(this.form.value);

          addControls(control: string, index: any)
          let array = this.form.get('myArray') as FormArray;
          if (array.length > this.page)
          this.page = this.page + 1;
          else
          let question: any = this.questions.find(q => q.key == control);
          let children = question ? question.children : null;
          if (children)
          (this.form.get(control) as FormArray).push(this.qcs.toFormGroup(children))
          this.page = this.page + 1;


          removeControls(control: string)
          let array = this.form.get(control) as FormArray;
          array.removeAt(array.length - 1);


          goBack()
          if (this.page > 0)
          this.page = this.page - 1;

          //let array = this.form.get('myArray') as FormArray;
          //array.removeAt(array.length - 1);
          //Function to move to previous step




          HTML :

          <div>
          <form (ngSubmit)="onSubmit()" [formGroup]="form">

          <div *ngFor="let question of questions" class="form-row">
          <ng-container *ngIf="question.children">
          <div [formArrayName]="question.key">
          <div *ngFor="let item of form.get(question.key).controls; let i=index" [formGroupName]="i">
          <ng-template [ngIf]="i + 1 == page">
          <div *ngFor="let item of question.children">
          <app-question [question]="item" [form]="form.get(question.key).at(i)"></app-question>
          </div>
          </ng-template>
          </div>
          </div>
          </ng-container>
          <ng-container *ngIf="!question.children">
          <app-question [question]="question" [form]="form"></app-question>

          </ng-container>
          </div>

          <button (click)="goBack()"> Previous </button> &nbsp;
          <button (click)="addControls('myArray',i)"> Next </button>

          <div class="form-row">
          <button type="submit" [disabled]="!form.valid">Save</button>
          </div>
          </form> <br>

          <pre>
          json
          </pre>
          </div>


          This will help you showing one page at a time. It will create new one if no next form exists. And on clicking previous it will navigate to old form.






          share|improve this answer













          Have try to reach your requirements : Except UI part. I hope you can handle you UI as your requirement.



          TS :



           import Component, Input, OnInit from '@angular/core';
          import FormGroup, FormArray from '@angular/forms';

          import QuestionBase from './question-base';
          import QuestionControlService from './question-control.service';

          @Component(
          selector: 'app-dynamic-form',
          templateUrl: './dynamic-form.component.html',
          providers: [QuestionControlService]
          )
          export class DynamicFormComponent implements OnInit

          @Input() questions: QuestionBase<any> = ;
          form: FormGroup;
          payLoad = '';

          page: number = 0;

          constructor(private qcs: QuestionControlService)

          ngOnInit()
          this.form = this.qcs.toFormGroup(this.questions);


          onSubmit()
          this.payLoad = JSON.stringify(this.form.value);

          addControls(control: string, index: any)
          let array = this.form.get('myArray') as FormArray;
          if (array.length > this.page)
          this.page = this.page + 1;
          else
          let question: any = this.questions.find(q => q.key == control);
          let children = question ? question.children : null;
          if (children)
          (this.form.get(control) as FormArray).push(this.qcs.toFormGroup(children))
          this.page = this.page + 1;


          removeControls(control: string)
          let array = this.form.get(control) as FormArray;
          array.removeAt(array.length - 1);


          goBack()
          if (this.page > 0)
          this.page = this.page - 1;

          //let array = this.form.get('myArray') as FormArray;
          //array.removeAt(array.length - 1);
          //Function to move to previous step




          HTML :

          <div>
          <form (ngSubmit)="onSubmit()" [formGroup]="form">

          <div *ngFor="let question of questions" class="form-row">
          <ng-container *ngIf="question.children">
          <div [formArrayName]="question.key">
          <div *ngFor="let item of form.get(question.key).controls; let i=index" [formGroupName]="i">
          <ng-template [ngIf]="i + 1 == page">
          <div *ngFor="let item of question.children">
          <app-question [question]="item" [form]="form.get(question.key).at(i)"></app-question>
          </div>
          </ng-template>
          </div>
          </div>
          </ng-container>
          <ng-container *ngIf="!question.children">
          <app-question [question]="question" [form]="form"></app-question>

          </ng-container>
          </div>

          <button (click)="goBack()"> Previous </button> &nbsp;
          <button (click)="addControls('myArray',i)"> Next </button>

          <div class="form-row">
          <button type="submit" [disabled]="!form.valid">Save</button>
          </div>
          </form> <br>

          <pre>
          json
          </pre>
          </div>


          This will help you showing one page at a time. It will create new one if no next form exists. And on clicking previous it will navigate to old form.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 15 '18 at 5:17









          Vishw PatelVishw Patel

          37119




          37119












          • I am in the need of the children in the next view and not in same view. If it moves to next view then provide stackblitz moving to next

            – Maniraj from Karur
            Nov 15 '18 at 5:51

















          • I am in the need of the children in the next view and not in same view. If it moves to next view then provide stackblitz moving to next

            – Maniraj from Karur
            Nov 15 '18 at 5:51
















          I am in the need of the children in the next view and not in same view. If it moves to next view then provide stackblitz moving to next

          – Maniraj from Karur
          Nov 15 '18 at 5:51





          I am in the need of the children in the next view and not in same view. If it moves to next view then provide stackblitz moving to next

          – Maniraj from Karur
          Nov 15 '18 at 5:51











          0














          So, you want to remove lastly added control email and dropdown control from the form group array.



          I have added the code into goBack() function to remove child form group controls.




          Component:




           goBack() 
          //Function to move to previous step
          if(this.form.controls['myArray'])
          const arr = <FormArray>this.form.controls.myArray;
          arr.removeAt(arr.length - 1);




          Working demo: https://angular-x4a5b6-cc4kyr.stackblitz.io






          share|improve this answer























          • For this i already have removeControl function, you can see in example.. The thing is on click next button, the first name and last name needs to get hidden and the email and dropdown needs to come.. On click the previous button the firstname and lastname come.. This alone my requirement.. And no need of remove function now.. On each next click the dropdown and email needs to get show in next next screen.. The question is mainly to handle the thing in the different views and not on same page..

            – Maniraj from Karur
            Nov 15 '18 at 5:23












          • Okay, I will suggest you make a new route in this case for email and dropdown. Because things become complex if you do manual hide and show.

            – Surjeet Bhadauriya
            Nov 15 '18 at 5:26















          0














          So, you want to remove lastly added control email and dropdown control from the form group array.



          I have added the code into goBack() function to remove child form group controls.




          Component:




           goBack() 
          //Function to move to previous step
          if(this.form.controls['myArray'])
          const arr = <FormArray>this.form.controls.myArray;
          arr.removeAt(arr.length - 1);




          Working demo: https://angular-x4a5b6-cc4kyr.stackblitz.io






          share|improve this answer























          • For this i already have removeControl function, you can see in example.. The thing is on click next button, the first name and last name needs to get hidden and the email and dropdown needs to come.. On click the previous button the firstname and lastname come.. This alone my requirement.. And no need of remove function now.. On each next click the dropdown and email needs to get show in next next screen.. The question is mainly to handle the thing in the different views and not on same page..

            – Maniraj from Karur
            Nov 15 '18 at 5:23












          • Okay, I will suggest you make a new route in this case for email and dropdown. Because things become complex if you do manual hide and show.

            – Surjeet Bhadauriya
            Nov 15 '18 at 5:26













          0












          0








          0







          So, you want to remove lastly added control email and dropdown control from the form group array.



          I have added the code into goBack() function to remove child form group controls.




          Component:




           goBack() 
          //Function to move to previous step
          if(this.form.controls['myArray'])
          const arr = <FormArray>this.form.controls.myArray;
          arr.removeAt(arr.length - 1);




          Working demo: https://angular-x4a5b6-cc4kyr.stackblitz.io






          share|improve this answer













          So, you want to remove lastly added control email and dropdown control from the form group array.



          I have added the code into goBack() function to remove child form group controls.




          Component:




           goBack() 
          //Function to move to previous step
          if(this.form.controls['myArray'])
          const arr = <FormArray>this.form.controls.myArray;
          arr.removeAt(arr.length - 1);




          Working demo: https://angular-x4a5b6-cc4kyr.stackblitz.io







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 15 '18 at 5:18









          Surjeet BhadauriyaSurjeet Bhadauriya

          1,98211326




          1,98211326












          • For this i already have removeControl function, you can see in example.. The thing is on click next button, the first name and last name needs to get hidden and the email and dropdown needs to come.. On click the previous button the firstname and lastname come.. This alone my requirement.. And no need of remove function now.. On each next click the dropdown and email needs to get show in next next screen.. The question is mainly to handle the thing in the different views and not on same page..

            – Maniraj from Karur
            Nov 15 '18 at 5:23












          • Okay, I will suggest you make a new route in this case for email and dropdown. Because things become complex if you do manual hide and show.

            – Surjeet Bhadauriya
            Nov 15 '18 at 5:26

















          • For this i already have removeControl function, you can see in example.. The thing is on click next button, the first name and last name needs to get hidden and the email and dropdown needs to come.. On click the previous button the firstname and lastname come.. This alone my requirement.. And no need of remove function now.. On each next click the dropdown and email needs to get show in next next screen.. The question is mainly to handle the thing in the different views and not on same page..

            – Maniraj from Karur
            Nov 15 '18 at 5:23












          • Okay, I will suggest you make a new route in this case for email and dropdown. Because things become complex if you do manual hide and show.

            – Surjeet Bhadauriya
            Nov 15 '18 at 5:26
















          For this i already have removeControl function, you can see in example.. The thing is on click next button, the first name and last name needs to get hidden and the email and dropdown needs to come.. On click the previous button the firstname and lastname come.. This alone my requirement.. And no need of remove function now.. On each next click the dropdown and email needs to get show in next next screen.. The question is mainly to handle the thing in the different views and not on same page..

          – Maniraj from Karur
          Nov 15 '18 at 5:23






          For this i already have removeControl function, you can see in example.. The thing is on click next button, the first name and last name needs to get hidden and the email and dropdown needs to come.. On click the previous button the firstname and lastname come.. This alone my requirement.. And no need of remove function now.. On each next click the dropdown and email needs to get show in next next screen.. The question is mainly to handle the thing in the different views and not on same page..

          – Maniraj from Karur
          Nov 15 '18 at 5:23














          Okay, I will suggest you make a new route in this case for email and dropdown. Because things become complex if you do manual hide and show.

          – Surjeet Bhadauriya
          Nov 15 '18 at 5:26





          Okay, I will suggest you make a new route in this case for email and dropdown. Because things become complex if you do manual hide and show.

          – Surjeet Bhadauriya
          Nov 15 '18 at 5:26

















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