How to avoid calling function in base class?










1















I have two classes A and B like below, B have to inherit from A. The classType() function of class B is not provided, If call B::classType(), will get the class type of A. I would like to get a compiler error here instead of calling into the classType() function of class A. How do I do it?



In general, the sub classes of A should provide the function classType(), in case the author forgets to write the classType() function, it's best to report a compiler error. This is the purpose. Maybe, I can use static_assert in TypeOf() function.



class A

public:
static const char* classType()

static const char* s_classType = "A";
return s_classType;

;

class B : public A

;

template <class T>
const char* TypeOf()

return T::classType();


int main()

const char* type = TypeOf<B>(); // I would like to get compiler error here, not get "A".










share|improve this question
























  • Prefer std::string to const char*.

    – Ron
    Nov 15 '18 at 16:09











  • void main?? -

    – Quentin
    Nov 15 '18 at 16:11











  • Solution: replace class B : public A with class B.

    – Evg
    Nov 15 '18 at 16:12











  • @Evg, B needs to inherits form A in the case.

    – ldlchina
    Nov 15 '18 at 16:14






  • 1





    See edited answer.

    – Evg
    Nov 15 '18 at 16:39















1















I have two classes A and B like below, B have to inherit from A. The classType() function of class B is not provided, If call B::classType(), will get the class type of A. I would like to get a compiler error here instead of calling into the classType() function of class A. How do I do it?



In general, the sub classes of A should provide the function classType(), in case the author forgets to write the classType() function, it's best to report a compiler error. This is the purpose. Maybe, I can use static_assert in TypeOf() function.



class A

public:
static const char* classType()

static const char* s_classType = "A";
return s_classType;

;

class B : public A

;

template <class T>
const char* TypeOf()

return T::classType();


int main()

const char* type = TypeOf<B>(); // I would like to get compiler error here, not get "A".










share|improve this question
























  • Prefer std::string to const char*.

    – Ron
    Nov 15 '18 at 16:09











  • void main?? -

    – Quentin
    Nov 15 '18 at 16:11











  • Solution: replace class B : public A with class B.

    – Evg
    Nov 15 '18 at 16:12











  • @Evg, B needs to inherits form A in the case.

    – ldlchina
    Nov 15 '18 at 16:14






  • 1





    See edited answer.

    – Evg
    Nov 15 '18 at 16:39













1












1








1








I have two classes A and B like below, B have to inherit from A. The classType() function of class B is not provided, If call B::classType(), will get the class type of A. I would like to get a compiler error here instead of calling into the classType() function of class A. How do I do it?



In general, the sub classes of A should provide the function classType(), in case the author forgets to write the classType() function, it's best to report a compiler error. This is the purpose. Maybe, I can use static_assert in TypeOf() function.



class A

public:
static const char* classType()

static const char* s_classType = "A";
return s_classType;

;

class B : public A

;

template <class T>
const char* TypeOf()

return T::classType();


int main()

const char* type = TypeOf<B>(); // I would like to get compiler error here, not get "A".










share|improve this question
















I have two classes A and B like below, B have to inherit from A. The classType() function of class B is not provided, If call B::classType(), will get the class type of A. I would like to get a compiler error here instead of calling into the classType() function of class A. How do I do it?



In general, the sub classes of A should provide the function classType(), in case the author forgets to write the classType() function, it's best to report a compiler error. This is the purpose. Maybe, I can use static_assert in TypeOf() function.



class A

public:
static const char* classType()

static const char* s_classType = "A";
return s_classType;

;

class B : public A

;

template <class T>
const char* TypeOf()

return T::classType();


int main()

const char* type = TypeOf<B>(); // I would like to get compiler error here, not get "A".







c++






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 15 '18 at 19:41









Evg

4,01221436




4,01221436










asked Nov 15 '18 at 16:08









ldlchinaldlchina

4161823




4161823












  • Prefer std::string to const char*.

    – Ron
    Nov 15 '18 at 16:09











  • void main?? -

    – Quentin
    Nov 15 '18 at 16:11











  • Solution: replace class B : public A with class B.

    – Evg
    Nov 15 '18 at 16:12











  • @Evg, B needs to inherits form A in the case.

    – ldlchina
    Nov 15 '18 at 16:14






  • 1





    See edited answer.

    – Evg
    Nov 15 '18 at 16:39

















  • Prefer std::string to const char*.

    – Ron
    Nov 15 '18 at 16:09











  • void main?? -

    – Quentin
    Nov 15 '18 at 16:11











  • Solution: replace class B : public A with class B.

    – Evg
    Nov 15 '18 at 16:12











  • @Evg, B needs to inherits form A in the case.

    – ldlchina
    Nov 15 '18 at 16:14






  • 1





    See edited answer.

    – Evg
    Nov 15 '18 at 16:39
















Prefer std::string to const char*.

– Ron
Nov 15 '18 at 16:09





Prefer std::string to const char*.

– Ron
Nov 15 '18 at 16:09













void main?? -

– Quentin
Nov 15 '18 at 16:11





void main?? -

– Quentin
Nov 15 '18 at 16:11













Solution: replace class B : public A with class B.

– Evg
Nov 15 '18 at 16:12





Solution: replace class B : public A with class B.

– Evg
Nov 15 '18 at 16:12













@Evg, B needs to inherits form A in the case.

– ldlchina
Nov 15 '18 at 16:14





@Evg, B needs to inherits form A in the case.

– ldlchina
Nov 15 '18 at 16:14




1




1





See edited answer.

– Evg
Nov 15 '18 at 16:39





See edited answer.

– Evg
Nov 15 '18 at 16:39












4 Answers
4






active

oldest

votes


















4














Alternatively, make A::classType() private in B:



class B : public A 
private:
using A::classType;



Edit. After the question has been clarified, I suggest that you use type traits technique instead of static member functions.



template<class>
struct Traits;

template<>
struct Traits<A>
static const char* classType()
return "A";

;

template<class T>
const char* TypeOf()
return Traits<T>::classType();



Now the user has to define his own type trait for B, otherwise



const char* type = TypeOf<B>(); 


will not compile.






share|improve this answer

























  • Explicitly deleting the function in class B seems more expressive to me. Both approaches work with classes inheriting from B.

    – Paul Sanders
    Nov 15 '18 at 16:19












  • @PaulSanders, agree. I upvoted your answer. But there is an alternative solution, nevertheless.

    – Evg
    Nov 15 '18 at 16:20


















3














Apart from a couple of typos in your code ... add the following to the definition of class B



static const char* classType() = delete;


Live Demo






share|improve this answer























  • It's not my purpose. My purpose is that when the author forgets to write the classType() function in the sub classes of class A, the author should get a reminder.

    – ldlchina
    Nov 15 '18 at 16:30


















1














I got the idea from @Evg, thanks Evg.
Use template like below:



class A

public:
template <class T>
static const char* classType() static_assert(false, "classType not implemented");
template <>
static const char* classType<A>()

static const char* s_classType = "A";
return s_classType;

;

template <class T>
const char* TypeOf()

return T::classType<T>();






share|improve this answer
































    0














    Declare the function as pure virtual.



    class A

    public:
    virtual static const char* classType() =0;
    ;


    Then all instantiated classes inheriting from A have to implement this.






    share|improve this answer






















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      4 Answers
      4






      active

      oldest

      votes








      4 Answers
      4






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      4














      Alternatively, make A::classType() private in B:



      class B : public A 
      private:
      using A::classType;



      Edit. After the question has been clarified, I suggest that you use type traits technique instead of static member functions.



      template<class>
      struct Traits;

      template<>
      struct Traits<A>
      static const char* classType()
      return "A";

      ;

      template<class T>
      const char* TypeOf()
      return Traits<T>::classType();



      Now the user has to define his own type trait for B, otherwise



      const char* type = TypeOf<B>(); 


      will not compile.






      share|improve this answer

























      • Explicitly deleting the function in class B seems more expressive to me. Both approaches work with classes inheriting from B.

        – Paul Sanders
        Nov 15 '18 at 16:19












      • @PaulSanders, agree. I upvoted your answer. But there is an alternative solution, nevertheless.

        – Evg
        Nov 15 '18 at 16:20















      4














      Alternatively, make A::classType() private in B:



      class B : public A 
      private:
      using A::classType;



      Edit. After the question has been clarified, I suggest that you use type traits technique instead of static member functions.



      template<class>
      struct Traits;

      template<>
      struct Traits<A>
      static const char* classType()
      return "A";

      ;

      template<class T>
      const char* TypeOf()
      return Traits<T>::classType();



      Now the user has to define his own type trait for B, otherwise



      const char* type = TypeOf<B>(); 


      will not compile.






      share|improve this answer

























      • Explicitly deleting the function in class B seems more expressive to me. Both approaches work with classes inheriting from B.

        – Paul Sanders
        Nov 15 '18 at 16:19












      • @PaulSanders, agree. I upvoted your answer. But there is an alternative solution, nevertheless.

        – Evg
        Nov 15 '18 at 16:20













      4












      4








      4







      Alternatively, make A::classType() private in B:



      class B : public A 
      private:
      using A::classType;



      Edit. After the question has been clarified, I suggest that you use type traits technique instead of static member functions.



      template<class>
      struct Traits;

      template<>
      struct Traits<A>
      static const char* classType()
      return "A";

      ;

      template<class T>
      const char* TypeOf()
      return Traits<T>::classType();



      Now the user has to define his own type trait for B, otherwise



      const char* type = TypeOf<B>(); 


      will not compile.






      share|improve this answer















      Alternatively, make A::classType() private in B:



      class B : public A 
      private:
      using A::classType;



      Edit. After the question has been clarified, I suggest that you use type traits technique instead of static member functions.



      template<class>
      struct Traits;

      template<>
      struct Traits<A>
      static const char* classType()
      return "A";

      ;

      template<class T>
      const char* TypeOf()
      return Traits<T>::classType();



      Now the user has to define his own type trait for B, otherwise



      const char* type = TypeOf<B>(); 


      will not compile.







      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Nov 15 '18 at 16:39

























      answered Nov 15 '18 at 16:15









      EvgEvg

      4,01221436




      4,01221436












      • Explicitly deleting the function in class B seems more expressive to me. Both approaches work with classes inheriting from B.

        – Paul Sanders
        Nov 15 '18 at 16:19












      • @PaulSanders, agree. I upvoted your answer. But there is an alternative solution, nevertheless.

        – Evg
        Nov 15 '18 at 16:20

















      • Explicitly deleting the function in class B seems more expressive to me. Both approaches work with classes inheriting from B.

        – Paul Sanders
        Nov 15 '18 at 16:19












      • @PaulSanders, agree. I upvoted your answer. But there is an alternative solution, nevertheless.

        – Evg
        Nov 15 '18 at 16:20
















      Explicitly deleting the function in class B seems more expressive to me. Both approaches work with classes inheriting from B.

      – Paul Sanders
      Nov 15 '18 at 16:19






      Explicitly deleting the function in class B seems more expressive to me. Both approaches work with classes inheriting from B.

      – Paul Sanders
      Nov 15 '18 at 16:19














      @PaulSanders, agree. I upvoted your answer. But there is an alternative solution, nevertheless.

      – Evg
      Nov 15 '18 at 16:20





      @PaulSanders, agree. I upvoted your answer. But there is an alternative solution, nevertheless.

      – Evg
      Nov 15 '18 at 16:20













      3














      Apart from a couple of typos in your code ... add the following to the definition of class B



      static const char* classType() = delete;


      Live Demo






      share|improve this answer























      • It's not my purpose. My purpose is that when the author forgets to write the classType() function in the sub classes of class A, the author should get a reminder.

        – ldlchina
        Nov 15 '18 at 16:30















      3














      Apart from a couple of typos in your code ... add the following to the definition of class B



      static const char* classType() = delete;


      Live Demo






      share|improve this answer























      • It's not my purpose. My purpose is that when the author forgets to write the classType() function in the sub classes of class A, the author should get a reminder.

        – ldlchina
        Nov 15 '18 at 16:30













      3












      3








      3







      Apart from a couple of typos in your code ... add the following to the definition of class B



      static const char* classType() = delete;


      Live Demo






      share|improve this answer













      Apart from a couple of typos in your code ... add the following to the definition of class B



      static const char* classType() = delete;


      Live Demo







      share|improve this answer












      share|improve this answer



      share|improve this answer










      answered Nov 15 '18 at 16:13









      Paul SandersPaul Sanders

      5,2762621




      5,2762621












      • It's not my purpose. My purpose is that when the author forgets to write the classType() function in the sub classes of class A, the author should get a reminder.

        – ldlchina
        Nov 15 '18 at 16:30

















      • It's not my purpose. My purpose is that when the author forgets to write the classType() function in the sub classes of class A, the author should get a reminder.

        – ldlchina
        Nov 15 '18 at 16:30
















      It's not my purpose. My purpose is that when the author forgets to write the classType() function in the sub classes of class A, the author should get a reminder.

      – ldlchina
      Nov 15 '18 at 16:30





      It's not my purpose. My purpose is that when the author forgets to write the classType() function in the sub classes of class A, the author should get a reminder.

      – ldlchina
      Nov 15 '18 at 16:30











      1














      I got the idea from @Evg, thanks Evg.
      Use template like below:



      class A

      public:
      template <class T>
      static const char* classType() static_assert(false, "classType not implemented");
      template <>
      static const char* classType<A>()

      static const char* s_classType = "A";
      return s_classType;

      ;

      template <class T>
      const char* TypeOf()

      return T::classType<T>();






      share|improve this answer





























        1














        I got the idea from @Evg, thanks Evg.
        Use template like below:



        class A

        public:
        template <class T>
        static const char* classType() static_assert(false, "classType not implemented");
        template <>
        static const char* classType<A>()

        static const char* s_classType = "A";
        return s_classType;

        ;

        template <class T>
        const char* TypeOf()

        return T::classType<T>();






        share|improve this answer



























          1












          1








          1







          I got the idea from @Evg, thanks Evg.
          Use template like below:



          class A

          public:
          template <class T>
          static const char* classType() static_assert(false, "classType not implemented");
          template <>
          static const char* classType<A>()

          static const char* s_classType = "A";
          return s_classType;

          ;

          template <class T>
          const char* TypeOf()

          return T::classType<T>();






          share|improve this answer















          I got the idea from @Evg, thanks Evg.
          Use template like below:



          class A

          public:
          template <class T>
          static const char* classType() static_assert(false, "classType not implemented");
          template <>
          static const char* classType<A>()

          static const char* s_classType = "A";
          return s_classType;

          ;

          template <class T>
          const char* TypeOf()

          return T::classType<T>();







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 16 '18 at 5:31

























          answered Nov 15 '18 at 17:34









          ldlchinaldlchina

          4161823




          4161823





















              0














              Declare the function as pure virtual.



              class A

              public:
              virtual static const char* classType() =0;
              ;


              Then all instantiated classes inheriting from A have to implement this.






              share|improve this answer



























                0














                Declare the function as pure virtual.



                class A

                public:
                virtual static const char* classType() =0;
                ;


                Then all instantiated classes inheriting from A have to implement this.






                share|improve this answer

























                  0












                  0








                  0







                  Declare the function as pure virtual.



                  class A

                  public:
                  virtual static const char* classType() =0;
                  ;


                  Then all instantiated classes inheriting from A have to implement this.






                  share|improve this answer













                  Declare the function as pure virtual.



                  class A

                  public:
                  virtual static const char* classType() =0;
                  ;


                  Then all instantiated classes inheriting from A have to implement this.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 15 '18 at 16:56









                  Robert AndrzejukRobert Andrzejuk

                  2,99621425




                  2,99621425



























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