Is it Necessary to De-Mean my Data before Applying PCA, or does pca(X) do that Automatically?










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I am aware that a first step in performing PCA for dimensionality reduction is de-meaning the data.



I have performed PCA after de-meaning manually with X=X-mean(X) and compared with plainly applying [COEFF,score,latent,~,explained]=pca(X) on my data.



By inspecting the eigenvalues and the percentage of variability described by each PC on both cases (i.e. latent and explained in the above case), I can see that I get two different results. Is manual de-meaning doing too much in this case?










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  • 1





    Did you use pca or princomp? Mathworks have replaced the former by the latter. In the documentation of princomp, one can read the following: princomp centers X by subtracting off column means, but does not rescale the columns of X. Is this perhaps different from what you have done?

    – Floris SA
    Nov 16 '18 at 9:25
















1















I am aware that a first step in performing PCA for dimensionality reduction is de-meaning the data.



I have performed PCA after de-meaning manually with X=X-mean(X) and compared with plainly applying [COEFF,score,latent,~,explained]=pca(X) on my data.



By inspecting the eigenvalues and the percentage of variability described by each PC on both cases (i.e. latent and explained in the above case), I can see that I get two different results. Is manual de-meaning doing too much in this case?










share|improve this question

















  • 1





    Did you use pca or princomp? Mathworks have replaced the former by the latter. In the documentation of princomp, one can read the following: princomp centers X by subtracting off column means, but does not rescale the columns of X. Is this perhaps different from what you have done?

    – Floris SA
    Nov 16 '18 at 9:25














1












1








1








I am aware that a first step in performing PCA for dimensionality reduction is de-meaning the data.



I have performed PCA after de-meaning manually with X=X-mean(X) and compared with plainly applying [COEFF,score,latent,~,explained]=pca(X) on my data.



By inspecting the eigenvalues and the percentage of variability described by each PC on both cases (i.e. latent and explained in the above case), I can see that I get two different results. Is manual de-meaning doing too much in this case?










share|improve this question














I am aware that a first step in performing PCA for dimensionality reduction is de-meaning the data.



I have performed PCA after de-meaning manually with X=X-mean(X) and compared with plainly applying [COEFF,score,latent,~,explained]=pca(X) on my data.



By inspecting the eigenvalues and the percentage of variability described by each PC on both cases (i.e. latent and explained in the above case), I can see that I get two different results. Is manual de-meaning doing too much in this case?







matlab data-analysis pca






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asked Nov 15 '18 at 23:11









John DoeJohn Doe

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  • 1





    Did you use pca or princomp? Mathworks have replaced the former by the latter. In the documentation of princomp, one can read the following: princomp centers X by subtracting off column means, but does not rescale the columns of X. Is this perhaps different from what you have done?

    – Floris SA
    Nov 16 '18 at 9:25













  • 1





    Did you use pca or princomp? Mathworks have replaced the former by the latter. In the documentation of princomp, one can read the following: princomp centers X by subtracting off column means, but does not rescale the columns of X. Is this perhaps different from what you have done?

    – Floris SA
    Nov 16 '18 at 9:25








1




1





Did you use pca or princomp? Mathworks have replaced the former by the latter. In the documentation of princomp, one can read the following: princomp centers X by subtracting off column means, but does not rescale the columns of X. Is this perhaps different from what you have done?

– Floris SA
Nov 16 '18 at 9:25






Did you use pca or princomp? Mathworks have replaced the former by the latter. In the documentation of princomp, one can read the following: princomp centers X by subtracting off column means, but does not rescale the columns of X. Is this perhaps different from what you have done?

– Floris SA
Nov 16 '18 at 9:25













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