Function declarations and how they create variables in the current scope









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I was reading this article about js functions.
https://dmitripavlutin.com/6-ways-to-declare-javascript-functions/



and it says "The function declaration creates a variable in the current scope with the identifier equal to function name. This variable holds the function object."



So I did some experiments to learn more.



function a () 
return 1;

console.log(typeof a === "function")
console.log(typeof a === "number")


This outputs

True

False



Which isn't surprising, then when I run this.



var a = 1;
function a ()
return 1;

console.log(typeof a === "function")
console.log(typeof a === "number")


The output is

False

True



So although a is allocated to a number and then later allocated to a function, it ends up being a number in the end.



Is there some kind of rule that says variable declarations override function declarations or is there more to it?










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  • 1




    Maybe this is due to hoisting. I am not sure but that can be a reason. I am on phone so can't check. Please try replacing var with const. Let us know.
    – Akhil Gautam
    Nov 11 at 1:35














up vote
1
down vote

favorite












I was reading this article about js functions.
https://dmitripavlutin.com/6-ways-to-declare-javascript-functions/



and it says "The function declaration creates a variable in the current scope with the identifier equal to function name. This variable holds the function object."



So I did some experiments to learn more.



function a () 
return 1;

console.log(typeof a === "function")
console.log(typeof a === "number")


This outputs

True

False



Which isn't surprising, then when I run this.



var a = 1;
function a ()
return 1;

console.log(typeof a === "function")
console.log(typeof a === "number")


The output is

False

True



So although a is allocated to a number and then later allocated to a function, it ends up being a number in the end.



Is there some kind of rule that says variable declarations override function declarations or is there more to it?










share|improve this question

















  • 1




    Maybe this is due to hoisting. I am not sure but that can be a reason. I am on phone so can't check. Please try replacing var with const. Let us know.
    – Akhil Gautam
    Nov 11 at 1:35












up vote
1
down vote

favorite









up vote
1
down vote

favorite











I was reading this article about js functions.
https://dmitripavlutin.com/6-ways-to-declare-javascript-functions/



and it says "The function declaration creates a variable in the current scope with the identifier equal to function name. This variable holds the function object."



So I did some experiments to learn more.



function a () 
return 1;

console.log(typeof a === "function")
console.log(typeof a === "number")


This outputs

True

False



Which isn't surprising, then when I run this.



var a = 1;
function a ()
return 1;

console.log(typeof a === "function")
console.log(typeof a === "number")


The output is

False

True



So although a is allocated to a number and then later allocated to a function, it ends up being a number in the end.



Is there some kind of rule that says variable declarations override function declarations or is there more to it?










share|improve this question













I was reading this article about js functions.
https://dmitripavlutin.com/6-ways-to-declare-javascript-functions/



and it says "The function declaration creates a variable in the current scope with the identifier equal to function name. This variable holds the function object."



So I did some experiments to learn more.



function a () 
return 1;

console.log(typeof a === "function")
console.log(typeof a === "number")


This outputs

True

False



Which isn't surprising, then when I run this.



var a = 1;
function a ()
return 1;

console.log(typeof a === "function")
console.log(typeof a === "number")


The output is

False

True



So although a is allocated to a number and then later allocated to a function, it ends up being a number in the end.



Is there some kind of rule that says variable declarations override function declarations or is there more to it?







javascript






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asked Nov 11 at 1:31









h33

1968




1968







  • 1




    Maybe this is due to hoisting. I am not sure but that can be a reason. I am on phone so can't check. Please try replacing var with const. Let us know.
    – Akhil Gautam
    Nov 11 at 1:35












  • 1




    Maybe this is due to hoisting. I am not sure but that can be a reason. I am on phone so can't check. Please try replacing var with const. Let us know.
    – Akhil Gautam
    Nov 11 at 1:35







1




1




Maybe this is due to hoisting. I am not sure but that can be a reason. I am on phone so can't check. Please try replacing var with const. Let us know.
– Akhil Gautam
Nov 11 at 1:35




Maybe this is due to hoisting. I am not sure but that can be a reason. I am on phone so can't check. Please try replacing var with const. Let us know.
– Akhil Gautam
Nov 11 at 1:35












1 Answer
1






active

oldest

votes

















up vote
2
down vote













Function declarations are hoisted to the top of their containing function (or the outermost block). a will start out as contain



Your lower code is equivalent to the following:






var a = function a () 
return 1;

// next line reassigns `a` to number:
a = 1;
console.log(typeof a === "function")
console.log(typeof a === "number")





If you log a before the line a = 1, you'll see that it is indeed a function before it gets reassigned:






console.log(typeof a);
var a = 1;
console.log(typeof a);
function a ()
return 1;








share|improve this answer




















  • aren't variable hoisted as well? I guess function are just hoisted higher?
    – h33
    Nov 11 at 1:38










  • Variable creation is hoisted (eg var a;, doesn't make a difference here though), but variable assignment is not hoisted (eg a = 10;, assignment will always occur on the same line as you expect it to occur).
    – CertainPerformance
    Nov 11 at 1:39











  • ahh that makes sense. Thanks.
    – h33
    Nov 11 at 1:42










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1 Answer
1






active

oldest

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1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes








up vote
2
down vote













Function declarations are hoisted to the top of their containing function (or the outermost block). a will start out as contain



Your lower code is equivalent to the following:






var a = function a () 
return 1;

// next line reassigns `a` to number:
a = 1;
console.log(typeof a === "function")
console.log(typeof a === "number")





If you log a before the line a = 1, you'll see that it is indeed a function before it gets reassigned:






console.log(typeof a);
var a = 1;
console.log(typeof a);
function a ()
return 1;








share|improve this answer




















  • aren't variable hoisted as well? I guess function are just hoisted higher?
    – h33
    Nov 11 at 1:38










  • Variable creation is hoisted (eg var a;, doesn't make a difference here though), but variable assignment is not hoisted (eg a = 10;, assignment will always occur on the same line as you expect it to occur).
    – CertainPerformance
    Nov 11 at 1:39











  • ahh that makes sense. Thanks.
    – h33
    Nov 11 at 1:42














up vote
2
down vote













Function declarations are hoisted to the top of their containing function (or the outermost block). a will start out as contain



Your lower code is equivalent to the following:






var a = function a () 
return 1;

// next line reassigns `a` to number:
a = 1;
console.log(typeof a === "function")
console.log(typeof a === "number")





If you log a before the line a = 1, you'll see that it is indeed a function before it gets reassigned:






console.log(typeof a);
var a = 1;
console.log(typeof a);
function a ()
return 1;








share|improve this answer




















  • aren't variable hoisted as well? I guess function are just hoisted higher?
    – h33
    Nov 11 at 1:38










  • Variable creation is hoisted (eg var a;, doesn't make a difference here though), but variable assignment is not hoisted (eg a = 10;, assignment will always occur on the same line as you expect it to occur).
    – CertainPerformance
    Nov 11 at 1:39











  • ahh that makes sense. Thanks.
    – h33
    Nov 11 at 1:42












up vote
2
down vote










up vote
2
down vote









Function declarations are hoisted to the top of their containing function (or the outermost block). a will start out as contain



Your lower code is equivalent to the following:






var a = function a () 
return 1;

// next line reassigns `a` to number:
a = 1;
console.log(typeof a === "function")
console.log(typeof a === "number")





If you log a before the line a = 1, you'll see that it is indeed a function before it gets reassigned:






console.log(typeof a);
var a = 1;
console.log(typeof a);
function a ()
return 1;








share|improve this answer












Function declarations are hoisted to the top of their containing function (or the outermost block). a will start out as contain



Your lower code is equivalent to the following:






var a = function a () 
return 1;

// next line reassigns `a` to number:
a = 1;
console.log(typeof a === "function")
console.log(typeof a === "number")





If you log a before the line a = 1, you'll see that it is indeed a function before it gets reassigned:






console.log(typeof a);
var a = 1;
console.log(typeof a);
function a ()
return 1;








var a = function a () 
return 1;

// next line reassigns `a` to number:
a = 1;
console.log(typeof a === "function")
console.log(typeof a === "number")





var a = function a () 
return 1;

// next line reassigns `a` to number:
a = 1;
console.log(typeof a === "function")
console.log(typeof a === "number")





console.log(typeof a);
var a = 1;
console.log(typeof a);
function a ()
return 1;





console.log(typeof a);
var a = 1;
console.log(typeof a);
function a ()
return 1;






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 11 at 1:33









CertainPerformance

67.1k143252




67.1k143252











  • aren't variable hoisted as well? I guess function are just hoisted higher?
    – h33
    Nov 11 at 1:38










  • Variable creation is hoisted (eg var a;, doesn't make a difference here though), but variable assignment is not hoisted (eg a = 10;, assignment will always occur on the same line as you expect it to occur).
    – CertainPerformance
    Nov 11 at 1:39











  • ahh that makes sense. Thanks.
    – h33
    Nov 11 at 1:42
















  • aren't variable hoisted as well? I guess function are just hoisted higher?
    – h33
    Nov 11 at 1:38










  • Variable creation is hoisted (eg var a;, doesn't make a difference here though), but variable assignment is not hoisted (eg a = 10;, assignment will always occur on the same line as you expect it to occur).
    – CertainPerformance
    Nov 11 at 1:39











  • ahh that makes sense. Thanks.
    – h33
    Nov 11 at 1:42















aren't variable hoisted as well? I guess function are just hoisted higher?
– h33
Nov 11 at 1:38




aren't variable hoisted as well? I guess function are just hoisted higher?
– h33
Nov 11 at 1:38












Variable creation is hoisted (eg var a;, doesn't make a difference here though), but variable assignment is not hoisted (eg a = 10;, assignment will always occur on the same line as you expect it to occur).
– CertainPerformance
Nov 11 at 1:39





Variable creation is hoisted (eg var a;, doesn't make a difference here though), but variable assignment is not hoisted (eg a = 10;, assignment will always occur on the same line as you expect it to occur).
– CertainPerformance
Nov 11 at 1:39













ahh that makes sense. Thanks.
– h33
Nov 11 at 1:42




ahh that makes sense. Thanks.
– h33
Nov 11 at 1:42

















 

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