Depict supply network structures
I would like to plot a supply network structure. I have tried to use igraph, but until now did not come up with a reasonable result. An example would look like this:
library(igraph)
d <- read.table(text = "V1 V2 weight
s1 p1 88
s3 p1 100
s2 p2 100
s3 p2 43
p1 c1 21
p1 c2 79
p1 c3 88
p2 c1 22
p2 c2 121
", stringsAsFactors = F, header = T)
g <- graph_from_data_frame(d, directed = T)
plot(g, layout=layout.fruchterman.reingold,
edge.width=E(g)$weight/20,
vertex.shape = "none", vertex.label.font = 2,
vertex.label.cex=1.1, edge.color="gray70")
Which gives:
The problem is that the network has an additional structure. A resonable - among others - result would show the "s"-nodes (for suppliers) should be in the left third, the "p"-nodes (plants) should be in the middle and the c-nodes (customers) on the right hand side. Is this even doable with igraph (and how)? Is there another package that could do this?
r plot
asked Nov 14 '18 at 13:09
r.user.05aprr.user.05apr
2,1412723
add a comment |
I would like to plot a supply network structure. I have tried to use igraph, but until now did not come up with a reasonable result. An example would look like this:
library(igraph)
d <- read.table(text = "V1 V2 weight
s1 p1 88
s3 p1 100
s2 p2 100
s3 p2 43
p1 c1 21
p1 c2 79
p1 c3 88
p2 c1 22
p2 c2 121
", stringsAsFactors = F, header = T)
g <- graph_from_data_frame(d, directed = T)
plot(g, layout=layout.fruchterman.reingold,
edge.width=E(g)$weight/20,
vertex.shape = "none", vertex.label.font = 2,
vertex.label.cex=1.1, edge.color="gray70")
Which gives:
The problem is that the network has an additional structure. A resonable - among others - result would show the "s"-nodes (for suppliers) should be in the left third, the "p"-nodes (plants) should be in the middle and the c-nodes (customers) on the right hand side. Is this even doable with igraph (and how)? Is there another package that could do this?
r plot
asked Nov 14 '18 at 13:09
r.user.05aprr.user.05apr
2,1412723
1
I think you are describing a tripartite graph. See e.g. Visualizing graph/network with 3 layeres (tripartite) in R/igraph; how to built tripartite network using .csv file in dataframe?, R is not taking the parameter hgap in layout_with_sugiyama.
– Henrik
Nov 14 '18 at 13:39
add a comment |
I would like to plot a supply network structure. I have tried to use igraph, but until now did not come up with a reasonable result. An example would look like this:
library(igraph)
d <- read.table(text = "V1 V2 weight
s1 p1 88
s3 p1 100
s2 p2 100
s3 p2 43
p1 c1 21
p1 c2 79
p1 c3 88
p2 c1 22
p2 c2 121
", stringsAsFactors = F, header = T)
g <- graph_from_data_frame(d, directed = T)
plot(g, layout=layout.fruchterman.reingold,
edge.width=E(g)$weight/20,
vertex.shape = "none", vertex.label.font = 2,
vertex.label.cex=1.1, edge.color="gray70")
Which gives:
The problem is that the network has an additional structure. A resonable - among others - result would show the "s"-nodes (for suppliers) should be in the left third, the "p"-nodes (plants) should be in the middle and the c-nodes (customers) on the right hand side. Is this even doable with igraph (and how)? Is there another package that could do this?
r plot
asked Nov 14 '18 at 13:09
r.user.05aprr.user.05apr
2,1412723
I would like to plot a supply network structure. I have tried to use igraph, but until now did not come up with a reasonable result. An example would look like this:
library(igraph)
d <- read.table(text = "V1 V2 weight
s1 p1 88
s3 p1 100
s2 p2 100
s3 p2 43
p1 c1 21
p1 c2 79
p1 c3 88
p2 c1 22
p2 c2 121
", stringsAsFactors = F, header = T)
g <- graph_from_data_frame(d, directed = T)
plot(g, layout=layout.fruchterman.reingold,
edge.width=E(g)$weight/20,
vertex.shape = "none", vertex.label.font = 2,
vertex.label.cex=1.1, edge.color="gray70")
Which gives:
The problem is that the network has an additional structure. A resonable - among others - result would show the "s"-nodes (for suppliers) should be in the left third, the "p"-nodes (plants) should be in the middle and the c-nodes (customers) on the right hand side. Is this even doable with igraph (and how)? Is there another package that could do this?
r plot
r plot
asked Nov 14 '18 at 13:09
r.user.05aprr.user.05apr
2,1412723
asked Nov 14 '18 at 13:09
r.user.05aprr.user.05apr
2,1412723
asked Nov 14 '18 at 13:09
r.user.05aprr.user.05apr
2,1412723
asked Nov 14 '18 at 13:09
r.user.05aprr.user.05apr
2,1412723
asked Nov 14 '18 at 13:09
r.user.05aprr.user.05apr
2,1412723
2,1412723
1
I think you are describing a tripartite graph. See e.g. Visualizing graph/network with 3 layeres (tripartite) in R/igraph; how to built tripartite network using .csv file in dataframe?, R is not taking the parameter hgap in layout_with_sugiyama.
– Henrik
Nov 14 '18 at 13:39
add a comment |
1
I think you are describing a tripartite graph. See e.g. Visualizing graph/network with 3 layeres (tripartite) in R/igraph; how to built tripartite network using .csv file in dataframe?, R is not taking the parameter hgap in layout_with_sugiyama.
– Henrik
Nov 14 '18 at 13:39
1
1
I think you are describing a tripartite graph. See e.g. Visualizing graph/network with 3 layeres (tripartite) in R/igraph; how to built tripartite network using .csv file in dataframe?, R is not taking the parameter hgap in layout_with_sugiyama.
– Henrik
Nov 14 '18 at 13:39
I think you are describing a tripartite graph. See e.g. Visualizing graph/network with 3 layeres (tripartite) in R/igraph; how to built tripartite network using .csv file in dataframe?, R is not taking the parameter hgap in layout_with_sugiyama.
– Henrik
Nov 14 '18 at 13:39
add a comment |
1 Answer
1
active
oldest
votes
Yes, this is doable with igraph. One way to make your own layout. A simple way to do this is to place all "s" nodes at x=1, "p" nodes at x=2 and "c" nodes at x=3. Each distinct node of each type (s,p,c) should get a unique y value so that they do not overlap. Using your example graph:
LO = matrix(0, nrow=vcount(g), ncol=2)
LO[grep("s", V(g)$name), 1] = 1
LO[grep("p", V(g)$name), 1] = 2
LO[grep("c", V(g)$name), 1] = 3
LO[,2] = ave(rep(1, vcount(g)), LO[,1], FUN = seq_along)
plot(g, layout=LO, edge.width=E(g)$weight/20,
vertex.shape = "none", vertex.label.font = 2,
vertex.label.cex=1.1, edge.color="gray70")
Also, following up on the comment of @Henrik, you can use layout_with_sugiyama. You still need to define the (s,p,c)-layers. Also, sugiyama arranges the layers vertically. You need to swap the x and y coordinates to get a horizontal layout.
Layers = rep(0,vcount(g))
Layers[grep("s", V(g)$name)] = 3
Layers[grep("p", V(g)$name)] = 2
Layers[grep("c", V(g)$name)] = 1
LO2 = layout_with_sugiyama(g, layers=Layers)$layout
LO2 = LO2[,2:1]
plot(g, layout=LO2, edge.width=E(g)$weight/20,
vertex.shape = "none", vertex.label.font = 2,
vertex.label.cex=1.1, edge.color="gray70")
answered Nov 14 '18 at 14:11
G5WG5W
22.1k82041
You even did the rotation. Thx.
– r.user.05apr
Nov 14 '18 at 14:33
add a comment |
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Yes, this is doable with igraph. One way to make your own layout. A simple way to do this is to place all "s" nodes at x=1, "p" nodes at x=2 and "c" nodes at x=3. Each distinct node of each type (s,p,c) should get a unique y value so that they do not overlap. Using your example graph:
LO = matrix(0, nrow=vcount(g), ncol=2)
LO[grep("s", V(g)$name), 1] = 1
LO[grep("p", V(g)$name), 1] = 2
LO[grep("c", V(g)$name), 1] = 3
LO[,2] = ave(rep(1, vcount(g)), LO[,1], FUN = seq_along)
plot(g, layout=LO, edge.width=E(g)$weight/20,
vertex.shape = "none", vertex.label.font = 2,
vertex.label.cex=1.1, edge.color="gray70")
Also, following up on the comment of @Henrik, you can use layout_with_sugiyama. You still need to define the (s,p,c)-layers. Also, sugiyama arranges the layers vertically. You need to swap the x and y coordinates to get a horizontal layout.
Layers = rep(0,vcount(g))
Layers[grep("s", V(g)$name)] = 3
Layers[grep("p", V(g)$name)] = 2
Layers[grep("c", V(g)$name)] = 1
LO2 = layout_with_sugiyama(g, layers=Layers)$layout
LO2 = LO2[,2:1]
plot(g, layout=LO2, edge.width=E(g)$weight/20,
vertex.shape = "none", vertex.label.font = 2,
vertex.label.cex=1.1, edge.color="gray70")
answered Nov 14 '18 at 14:11
G5WG5W
22.1k82041
You even did the rotation. Thx.
– r.user.05apr
Nov 14 '18 at 14:33
add a comment |
Yes, this is doable with igraph. One way to make your own layout. A simple way to do this is to place all "s" nodes at x=1, "p" nodes at x=2 and "c" nodes at x=3. Each distinct node of each type (s,p,c) should get a unique y value so that they do not overlap. Using your example graph:
LO = matrix(0, nrow=vcount(g), ncol=2)
LO[grep("s", V(g)$name), 1] = 1
LO[grep("p", V(g)$name), 1] = 2
LO[grep("c", V(g)$name), 1] = 3
LO[,2] = ave(rep(1, vcount(g)), LO[,1], FUN = seq_along)
plot(g, layout=LO, edge.width=E(g)$weight/20,
vertex.shape = "none", vertex.label.font = 2,
vertex.label.cex=1.1, edge.color="gray70")
Also, following up on the comment of @Henrik, you can use layout_with_sugiyama. You still need to define the (s,p,c)-layers. Also, sugiyama arranges the layers vertically. You need to swap the x and y coordinates to get a horizontal layout.
Layers = rep(0,vcount(g))
Layers[grep("s", V(g)$name)] = 3
Layers[grep("p", V(g)$name)] = 2
Layers[grep("c", V(g)$name)] = 1
LO2 = layout_with_sugiyama(g, layers=Layers)$layout
LO2 = LO2[,2:1]
plot(g, layout=LO2, edge.width=E(g)$weight/20,
vertex.shape = "none", vertex.label.font = 2,
vertex.label.cex=1.1, edge.color="gray70")
answered Nov 14 '18 at 14:11
G5WG5W
22.1k82041
You even did the rotation. Thx.
– r.user.05apr
Nov 14 '18 at 14:33
add a comment |
Yes, this is doable with igraph. One way to make your own layout. A simple way to do this is to place all "s" nodes at x=1, "p" nodes at x=2 and "c" nodes at x=3. Each distinct node of each type (s,p,c) should get a unique y value so that they do not overlap. Using your example graph:
LO = matrix(0, nrow=vcount(g), ncol=2)
LO[grep("s", V(g)$name), 1] = 1
LO[grep("p", V(g)$name), 1] = 2
LO[grep("c", V(g)$name), 1] = 3
LO[,2] = ave(rep(1, vcount(g)), LO[,1], FUN = seq_along)
plot(g, layout=LO, edge.width=E(g)$weight/20,
vertex.shape = "none", vertex.label.font = 2,
vertex.label.cex=1.1, edge.color="gray70")
Also, following up on the comment of @Henrik, you can use layout_with_sugiyama. You still need to define the (s,p,c)-layers. Also, sugiyama arranges the layers vertically. You need to swap the x and y coordinates to get a horizontal layout.
Layers = rep(0,vcount(g))
Layers[grep("s", V(g)$name)] = 3
Layers[grep("p", V(g)$name)] = 2
Layers[grep("c", V(g)$name)] = 1
LO2 = layout_with_sugiyama(g, layers=Layers)$layout
LO2 = LO2[,2:1]
plot(g, layout=LO2, edge.width=E(g)$weight/20,
vertex.shape = "none", vertex.label.font = 2,
vertex.label.cex=1.1, edge.color="gray70")
answered Nov 14 '18 at 14:11
G5WG5W
22.1k82041
Yes, this is doable with igraph. One way to make your own layout. A simple way to do this is to place all "s" nodes at x=1, "p" nodes at x=2 and "c" nodes at x=3. Each distinct node of each type (s,p,c) should get a unique y value so that they do not overlap. Using your example graph:
LO = matrix(0, nrow=vcount(g), ncol=2)
LO[grep("s", V(g)$name), 1] = 1
LO[grep("p", V(g)$name), 1] = 2
LO[grep("c", V(g)$name), 1] = 3
LO[,2] = ave(rep(1, vcount(g)), LO[,1], FUN = seq_along)
plot(g, layout=LO, edge.width=E(g)$weight/20,
vertex.shape = "none", vertex.label.font = 2,
vertex.label.cex=1.1, edge.color="gray70")
Also, following up on the comment of @Henrik, you can use layout_with_sugiyama. You still need to define the (s,p,c)-layers. Also, sugiyama arranges the layers vertically. You need to swap the x and y coordinates to get a horizontal layout.
Layers = rep(0,vcount(g))
Layers[grep("s", V(g)$name)] = 3
Layers[grep("p", V(g)$name)] = 2
Layers[grep("c", V(g)$name)] = 1
LO2 = layout_with_sugiyama(g, layers=Layers)$layout
LO2 = LO2[,2:1]
plot(g, layout=LO2, edge.width=E(g)$weight/20,
vertex.shape = "none", vertex.label.font = 2,
vertex.label.cex=1.1, edge.color="gray70")
answered Nov 14 '18 at 14:11
G5WG5W
22.1k82041
edited Nov 14 '18 at 14:24
answered Nov 14 '18 at 14:11
G5WG5W
22.1k82041
answered Nov 14 '18 at 14:11
G5WG5W
22.1k82041
answered Nov 14 '18 at 14:11
G5WG5W
22.1k82041
22.1k82041
You even did the rotation. Thx.
– r.user.05apr
Nov 14 '18 at 14:33
add a comment |
You even did the rotation. Thx.
– r.user.05apr
Nov 14 '18 at 14:33
You even did the rotation. Thx.
– r.user.05apr
Nov 14 '18 at 14:33
You even did the rotation. Thx.
– r.user.05apr
Nov 14 '18 at 14:33
add a comment |
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1
I think you are describing a tripartite graph. See e.g. Visualizing graph/network with 3 layeres (tripartite) in R/igraph; how to built tripartite network using .csv file in dataframe?, R is not taking the parameter hgap in layout_with_sugiyama.
– Henrik
Nov 14 '18 at 13:39