how i can apply which.min function conditionally










-2















I want to create a column in dataframe and populate minimum value in the data frame in column A condition is met :



**Sample data** 
Variable value
A 10
A 20
A 30
B 5
B 60
B 70


Expected Result :



Variable value NewColumn
A 10 min
A 20 between min to 20
A 30 between 21 to 30
B 5 min
B 60 between 50 to 60


Is there any easy way to achieve this ?










share|improve this question
























  • what is between 20 to 30?

    – Sotos
    Nov 15 '18 at 12:40






  • 1





    It will be easy to spot and flag the min per group, but I'm not sure I get the philosophy you apply to the rest of the values. Can you explain a bit more?

    – AntoniosK
    Nov 15 '18 at 12:40











  • I am trying to create a new column and distinguish it in dataframe based on following criterias : a. if value is min based b. if value is between 20 and min, if value between 20 to 30 and so on

    – gurtej
    Nov 15 '18 at 12:42












  • So, you want to get min if it is the min value of a factor, and between which two Tens is the value. Is it that ?

    – Santiago I. Hurtado
    Nov 15 '18 at 13:07











  • yes thats correct

    – gurtej
    Nov 15 '18 at 13:13















-2















I want to create a column in dataframe and populate minimum value in the data frame in column A condition is met :



**Sample data** 
Variable value
A 10
A 20
A 30
B 5
B 60
B 70


Expected Result :



Variable value NewColumn
A 10 min
A 20 between min to 20
A 30 between 21 to 30
B 5 min
B 60 between 50 to 60


Is there any easy way to achieve this ?










share|improve this question
























  • what is between 20 to 30?

    – Sotos
    Nov 15 '18 at 12:40






  • 1





    It will be easy to spot and flag the min per group, but I'm not sure I get the philosophy you apply to the rest of the values. Can you explain a bit more?

    – AntoniosK
    Nov 15 '18 at 12:40











  • I am trying to create a new column and distinguish it in dataframe based on following criterias : a. if value is min based b. if value is between 20 and min, if value between 20 to 30 and so on

    – gurtej
    Nov 15 '18 at 12:42












  • So, you want to get min if it is the min value of a factor, and between which two Tens is the value. Is it that ?

    – Santiago I. Hurtado
    Nov 15 '18 at 13:07











  • yes thats correct

    – gurtej
    Nov 15 '18 at 13:13













-2












-2








-2


0






I want to create a column in dataframe and populate minimum value in the data frame in column A condition is met :



**Sample data** 
Variable value
A 10
A 20
A 30
B 5
B 60
B 70


Expected Result :



Variable value NewColumn
A 10 min
A 20 between min to 20
A 30 between 21 to 30
B 5 min
B 60 between 50 to 60


Is there any easy way to achieve this ?










share|improve this question
















I want to create a column in dataframe and populate minimum value in the data frame in column A condition is met :



**Sample data** 
Variable value
A 10
A 20
A 30
B 5
B 60
B 70


Expected Result :



Variable value NewColumn
A 10 min
A 20 between min to 20
A 30 between 21 to 30
B 5 min
B 60 between 50 to 60


Is there any easy way to achieve this ?







r






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 15 '18 at 12:46







gurtej

















asked Nov 15 '18 at 12:37









gurtejgurtej

84




84












  • what is between 20 to 30?

    – Sotos
    Nov 15 '18 at 12:40






  • 1





    It will be easy to spot and flag the min per group, but I'm not sure I get the philosophy you apply to the rest of the values. Can you explain a bit more?

    – AntoniosK
    Nov 15 '18 at 12:40











  • I am trying to create a new column and distinguish it in dataframe based on following criterias : a. if value is min based b. if value is between 20 and min, if value between 20 to 30 and so on

    – gurtej
    Nov 15 '18 at 12:42












  • So, you want to get min if it is the min value of a factor, and between which two Tens is the value. Is it that ?

    – Santiago I. Hurtado
    Nov 15 '18 at 13:07











  • yes thats correct

    – gurtej
    Nov 15 '18 at 13:13

















  • what is between 20 to 30?

    – Sotos
    Nov 15 '18 at 12:40






  • 1





    It will be easy to spot and flag the min per group, but I'm not sure I get the philosophy you apply to the rest of the values. Can you explain a bit more?

    – AntoniosK
    Nov 15 '18 at 12:40











  • I am trying to create a new column and distinguish it in dataframe based on following criterias : a. if value is min based b. if value is between 20 and min, if value between 20 to 30 and so on

    – gurtej
    Nov 15 '18 at 12:42












  • So, you want to get min if it is the min value of a factor, and between which two Tens is the value. Is it that ?

    – Santiago I. Hurtado
    Nov 15 '18 at 13:07











  • yes thats correct

    – gurtej
    Nov 15 '18 at 13:13
















what is between 20 to 30?

– Sotos
Nov 15 '18 at 12:40





what is between 20 to 30?

– Sotos
Nov 15 '18 at 12:40




1




1





It will be easy to spot and flag the min per group, but I'm not sure I get the philosophy you apply to the rest of the values. Can you explain a bit more?

– AntoniosK
Nov 15 '18 at 12:40





It will be easy to spot and flag the min per group, but I'm not sure I get the philosophy you apply to the rest of the values. Can you explain a bit more?

– AntoniosK
Nov 15 '18 at 12:40













I am trying to create a new column and distinguish it in dataframe based on following criterias : a. if value is min based b. if value is between 20 and min, if value between 20 to 30 and so on

– gurtej
Nov 15 '18 at 12:42






I am trying to create a new column and distinguish it in dataframe based on following criterias : a. if value is min based b. if value is between 20 and min, if value between 20 to 30 and so on

– gurtej
Nov 15 '18 at 12:42














So, you want to get min if it is the min value of a factor, and between which two Tens is the value. Is it that ?

– Santiago I. Hurtado
Nov 15 '18 at 13:07





So, you want to get min if it is the min value of a factor, and between which two Tens is the value. Is it that ?

– Santiago I. Hurtado
Nov 15 '18 at 13:07













yes thats correct

– gurtej
Nov 15 '18 at 13:13





yes thats correct

– gurtej
Nov 15 '18 at 13:13












1 Answer
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The output in the question seems inconsistent since sometimes the lower bound is 10 less than the upper bound and other times is 9 less. We have defined it to be 9 less and if min is 9 or 10 below the upper bound write min instead of the lower bound.



Now, define a function which inputs a vector x and categorizes it using ave to apply it separately to each group. No packages are used.



categorize <- function(x) upper-10 == min(x), "min", upper-9)
ifelse(x == min(x), "min", paste("between", lower, "to", upper))


transform(DF, New = ave(value, Variable, FUN = categorize))


giving:



 Variable value New
1 A 10 min
2 A 20 between min to 20
3 A 30 between 21 to 30
4 B 5 min
5 B 60 between 51 to 60
6 B 70 between 61 to 70


Note



The input DF used, in reproducible form is:



Lines <- "
Variable value
A 10
A 20
A 30
B 5
B 60
B 70"
DF <- read.table(text = Lines, header = TRUE, strip.white = TRUE)





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    The output in the question seems inconsistent since sometimes the lower bound is 10 less than the upper bound and other times is 9 less. We have defined it to be 9 less and if min is 9 or 10 below the upper bound write min instead of the lower bound.



    Now, define a function which inputs a vector x and categorizes it using ave to apply it separately to each group. No packages are used.



    categorize <- function(x) upper-10 == min(x), "min", upper-9)
    ifelse(x == min(x), "min", paste("between", lower, "to", upper))


    transform(DF, New = ave(value, Variable, FUN = categorize))


    giving:



     Variable value New
    1 A 10 min
    2 A 20 between min to 20
    3 A 30 between 21 to 30
    4 B 5 min
    5 B 60 between 51 to 60
    6 B 70 between 61 to 70


    Note



    The input DF used, in reproducible form is:



    Lines <- "
    Variable value
    A 10
    A 20
    A 30
    B 5
    B 60
    B 70"
    DF <- read.table(text = Lines, header = TRUE, strip.white = TRUE)





    share|improve this answer



























      1














      The output in the question seems inconsistent since sometimes the lower bound is 10 less than the upper bound and other times is 9 less. We have defined it to be 9 less and if min is 9 or 10 below the upper bound write min instead of the lower bound.



      Now, define a function which inputs a vector x and categorizes it using ave to apply it separately to each group. No packages are used.



      categorize <- function(x) upper-10 == min(x), "min", upper-9)
      ifelse(x == min(x), "min", paste("between", lower, "to", upper))


      transform(DF, New = ave(value, Variable, FUN = categorize))


      giving:



       Variable value New
      1 A 10 min
      2 A 20 between min to 20
      3 A 30 between 21 to 30
      4 B 5 min
      5 B 60 between 51 to 60
      6 B 70 between 61 to 70


      Note



      The input DF used, in reproducible form is:



      Lines <- "
      Variable value
      A 10
      A 20
      A 30
      B 5
      B 60
      B 70"
      DF <- read.table(text = Lines, header = TRUE, strip.white = TRUE)





      share|improve this answer

























        1












        1








        1







        The output in the question seems inconsistent since sometimes the lower bound is 10 less than the upper bound and other times is 9 less. We have defined it to be 9 less and if min is 9 or 10 below the upper bound write min instead of the lower bound.



        Now, define a function which inputs a vector x and categorizes it using ave to apply it separately to each group. No packages are used.



        categorize <- function(x) upper-10 == min(x), "min", upper-9)
        ifelse(x == min(x), "min", paste("between", lower, "to", upper))


        transform(DF, New = ave(value, Variable, FUN = categorize))


        giving:



         Variable value New
        1 A 10 min
        2 A 20 between min to 20
        3 A 30 between 21 to 30
        4 B 5 min
        5 B 60 between 51 to 60
        6 B 70 between 61 to 70


        Note



        The input DF used, in reproducible form is:



        Lines <- "
        Variable value
        A 10
        A 20
        A 30
        B 5
        B 60
        B 70"
        DF <- read.table(text = Lines, header = TRUE, strip.white = TRUE)





        share|improve this answer













        The output in the question seems inconsistent since sometimes the lower bound is 10 less than the upper bound and other times is 9 less. We have defined it to be 9 less and if min is 9 or 10 below the upper bound write min instead of the lower bound.



        Now, define a function which inputs a vector x and categorizes it using ave to apply it separately to each group. No packages are used.



        categorize <- function(x) upper-10 == min(x), "min", upper-9)
        ifelse(x == min(x), "min", paste("between", lower, "to", upper))


        transform(DF, New = ave(value, Variable, FUN = categorize))


        giving:



         Variable value New
        1 A 10 min
        2 A 20 between min to 20
        3 A 30 between 21 to 30
        4 B 5 min
        5 B 60 between 51 to 60
        6 B 70 between 61 to 70


        Note



        The input DF used, in reproducible form is:



        Lines <- "
        Variable value
        A 10
        A 20
        A 30
        B 5
        B 60
        B 70"
        DF <- read.table(text = Lines, header = TRUE, strip.white = TRUE)






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 15 '18 at 13:06









        G. GrothendieckG. Grothendieck

        150k10133238




        150k10133238





























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