lxml (etree) - Pretty Print attributes of root tag










1















Is it possible in python to pretty print the root's attributes?



I used etree to extend the attributes of the child tag and then I had overwritten the existing file with the new content. However during the first generation of the XML, we were using a template where the attributes of the root tag were listed one per line and now with the etree I don't manage to achieve the same result.



I found similar questions but they were all referring to the tutorial of etree, which I find incomplete.



Hopefully someone has found a solution for this using etree.



EDIT: This is for custom XML so HTML Tidy (which was proposed in the comments), doesn't work for this.



Thanks!



generated_descriptors = list_generated_files(generated_descriptors_folder)
counter = 0
for g in generated_descriptors:
if counter % 20 == 0:
print "Extending Descriptor # %s out of %s" % (counter, len(descriptor_attributes))

with open(generated_descriptors_folder + "\" + g, 'r+b') as descriptor:
root = etree.XML(descriptor.read(), parser=parser)

# Go through every ContextObject to check if the block is mandatory
for context_object in root.findall('ContextObject'):
for attribs in descriptor_attributes:
if attribs['descriptor_name'] == g[:-11] and context_object.attrib['name'] in attribs['attributes']['mandatoryobjects']:
context_object.set('allow-null', 'false')
elif attribs['descriptor_name'] == g[:-11] and context_object.attrib['name'] not in attribs['attributes']['mandatoryobjects']:
context_object.set('allow-null', 'true')

# Sort the ContextObjects based on allow-null and their name
context_objects = root.findall('ContextObject')
context_objects_sorted = sorted(context_objects, key=lambda c: (c.attrib['allow-null'], c.attrib['name']))

root[:] = context_objects_sorted

# Remove mandatoryobjects from Descriptor attributes and pretty print
root.attrib.pop("mandatoryobjects", None)
# paste new line here


# Convert to string in order to write the enhanced descriptor
xml = etree.tostring(root, pretty_print=True, encoding="UTF-8", xml_declaration=True)

# Write the enhanced descriptor
descriptor.seek(0) # Set cursor at beginning of the file
descriptor.truncate(0) # Make sure that file is empty
descriptor.write(xml)

descriptor.close()

counter+=1









share|improve this question
























  • I'm using lxml and from that library I'm using etree. The tutorial I'm referring to comes from another thread and the link is lxml.de/tutorial.html

    – Arne Uten
    Nov 14 '18 at 15:44












  • Perhaps this helps: stackoverflow.com/q/40410923/407651

    – mzjn
    Nov 14 '18 at 15:56











  • Thanks @mzjn ! I took a first glance on the 'fix' that was found but as he also mentions after his try-out, it is not an optimal solution and I would like to keep it as clean as possible.

    – Arne Uten
    Nov 14 '18 at 16:14












  • It's tricky. There have been many questions about pretty-printing XML. This one has 19 answers, stackoverflow.com/q/749796/407651, but I'm not sure if they are of any help in this case (arranging attributes).

    – mzjn
    Nov 14 '18 at 16:34











  • You might want to try the Tidy utility (html-tidy.org). It has a indent-attributes option: api.html-tidy.org/tidy/quickref_5.6.0.html#indent-attributes.

    – mzjn
    Nov 14 '18 at 16:42















1















Is it possible in python to pretty print the root's attributes?



I used etree to extend the attributes of the child tag and then I had overwritten the existing file with the new content. However during the first generation of the XML, we were using a template where the attributes of the root tag were listed one per line and now with the etree I don't manage to achieve the same result.



I found similar questions but they were all referring to the tutorial of etree, which I find incomplete.



Hopefully someone has found a solution for this using etree.



EDIT: This is for custom XML so HTML Tidy (which was proposed in the comments), doesn't work for this.



Thanks!



generated_descriptors = list_generated_files(generated_descriptors_folder)
counter = 0
for g in generated_descriptors:
if counter % 20 == 0:
print "Extending Descriptor # %s out of %s" % (counter, len(descriptor_attributes))

with open(generated_descriptors_folder + "\" + g, 'r+b') as descriptor:
root = etree.XML(descriptor.read(), parser=parser)

# Go through every ContextObject to check if the block is mandatory
for context_object in root.findall('ContextObject'):
for attribs in descriptor_attributes:
if attribs['descriptor_name'] == g[:-11] and context_object.attrib['name'] in attribs['attributes']['mandatoryobjects']:
context_object.set('allow-null', 'false')
elif attribs['descriptor_name'] == g[:-11] and context_object.attrib['name'] not in attribs['attributes']['mandatoryobjects']:
context_object.set('allow-null', 'true')

# Sort the ContextObjects based on allow-null and their name
context_objects = root.findall('ContextObject')
context_objects_sorted = sorted(context_objects, key=lambda c: (c.attrib['allow-null'], c.attrib['name']))

root[:] = context_objects_sorted

# Remove mandatoryobjects from Descriptor attributes and pretty print
root.attrib.pop("mandatoryobjects", None)
# paste new line here


# Convert to string in order to write the enhanced descriptor
xml = etree.tostring(root, pretty_print=True, encoding="UTF-8", xml_declaration=True)

# Write the enhanced descriptor
descriptor.seek(0) # Set cursor at beginning of the file
descriptor.truncate(0) # Make sure that file is empty
descriptor.write(xml)

descriptor.close()

counter+=1









share|improve this question
























  • I'm using lxml and from that library I'm using etree. The tutorial I'm referring to comes from another thread and the link is lxml.de/tutorial.html

    – Arne Uten
    Nov 14 '18 at 15:44












  • Perhaps this helps: stackoverflow.com/q/40410923/407651

    – mzjn
    Nov 14 '18 at 15:56











  • Thanks @mzjn ! I took a first glance on the 'fix' that was found but as he also mentions after his try-out, it is not an optimal solution and I would like to keep it as clean as possible.

    – Arne Uten
    Nov 14 '18 at 16:14












  • It's tricky. There have been many questions about pretty-printing XML. This one has 19 answers, stackoverflow.com/q/749796/407651, but I'm not sure if they are of any help in this case (arranging attributes).

    – mzjn
    Nov 14 '18 at 16:34











  • You might want to try the Tidy utility (html-tidy.org). It has a indent-attributes option: api.html-tidy.org/tidy/quickref_5.6.0.html#indent-attributes.

    – mzjn
    Nov 14 '18 at 16:42













1












1








1








Is it possible in python to pretty print the root's attributes?



I used etree to extend the attributes of the child tag and then I had overwritten the existing file with the new content. However during the first generation of the XML, we were using a template where the attributes of the root tag were listed one per line and now with the etree I don't manage to achieve the same result.



I found similar questions but they were all referring to the tutorial of etree, which I find incomplete.



Hopefully someone has found a solution for this using etree.



EDIT: This is for custom XML so HTML Tidy (which was proposed in the comments), doesn't work for this.



Thanks!



generated_descriptors = list_generated_files(generated_descriptors_folder)
counter = 0
for g in generated_descriptors:
if counter % 20 == 0:
print "Extending Descriptor # %s out of %s" % (counter, len(descriptor_attributes))

with open(generated_descriptors_folder + "\" + g, 'r+b') as descriptor:
root = etree.XML(descriptor.read(), parser=parser)

# Go through every ContextObject to check if the block is mandatory
for context_object in root.findall('ContextObject'):
for attribs in descriptor_attributes:
if attribs['descriptor_name'] == g[:-11] and context_object.attrib['name'] in attribs['attributes']['mandatoryobjects']:
context_object.set('allow-null', 'false')
elif attribs['descriptor_name'] == g[:-11] and context_object.attrib['name'] not in attribs['attributes']['mandatoryobjects']:
context_object.set('allow-null', 'true')

# Sort the ContextObjects based on allow-null and their name
context_objects = root.findall('ContextObject')
context_objects_sorted = sorted(context_objects, key=lambda c: (c.attrib['allow-null'], c.attrib['name']))

root[:] = context_objects_sorted

# Remove mandatoryobjects from Descriptor attributes and pretty print
root.attrib.pop("mandatoryobjects", None)
# paste new line here


# Convert to string in order to write the enhanced descriptor
xml = etree.tostring(root, pretty_print=True, encoding="UTF-8", xml_declaration=True)

# Write the enhanced descriptor
descriptor.seek(0) # Set cursor at beginning of the file
descriptor.truncate(0) # Make sure that file is empty
descriptor.write(xml)

descriptor.close()

counter+=1









share|improve this question
















Is it possible in python to pretty print the root's attributes?



I used etree to extend the attributes of the child tag and then I had overwritten the existing file with the new content. However during the first generation of the XML, we were using a template where the attributes of the root tag were listed one per line and now with the etree I don't manage to achieve the same result.



I found similar questions but they were all referring to the tutorial of etree, which I find incomplete.



Hopefully someone has found a solution for this using etree.



EDIT: This is for custom XML so HTML Tidy (which was proposed in the comments), doesn't work for this.



Thanks!



generated_descriptors = list_generated_files(generated_descriptors_folder)
counter = 0
for g in generated_descriptors:
if counter % 20 == 0:
print "Extending Descriptor # %s out of %s" % (counter, len(descriptor_attributes))

with open(generated_descriptors_folder + "\" + g, 'r+b') as descriptor:
root = etree.XML(descriptor.read(), parser=parser)

# Go through every ContextObject to check if the block is mandatory
for context_object in root.findall('ContextObject'):
for attribs in descriptor_attributes:
if attribs['descriptor_name'] == g[:-11] and context_object.attrib['name'] in attribs['attributes']['mandatoryobjects']:
context_object.set('allow-null', 'false')
elif attribs['descriptor_name'] == g[:-11] and context_object.attrib['name'] not in attribs['attributes']['mandatoryobjects']:
context_object.set('allow-null', 'true')

# Sort the ContextObjects based on allow-null and their name
context_objects = root.findall('ContextObject')
context_objects_sorted = sorted(context_objects, key=lambda c: (c.attrib['allow-null'], c.attrib['name']))

root[:] = context_objects_sorted

# Remove mandatoryobjects from Descriptor attributes and pretty print
root.attrib.pop("mandatoryobjects", None)
# paste new line here


# Convert to string in order to write the enhanced descriptor
xml = etree.tostring(root, pretty_print=True, encoding="UTF-8", xml_declaration=True)

# Write the enhanced descriptor
descriptor.seek(0) # Set cursor at beginning of the file
descriptor.truncate(0) # Make sure that file is empty
descriptor.write(xml)

descriptor.close()

counter+=1






python lxml pretty-print






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 19 '18 at 10:46







Arne Uten

















asked Nov 14 '18 at 15:33









Arne UtenArne Uten

64




64












  • I'm using lxml and from that library I'm using etree. The tutorial I'm referring to comes from another thread and the link is lxml.de/tutorial.html

    – Arne Uten
    Nov 14 '18 at 15:44












  • Perhaps this helps: stackoverflow.com/q/40410923/407651

    – mzjn
    Nov 14 '18 at 15:56











  • Thanks @mzjn ! I took a first glance on the 'fix' that was found but as he also mentions after his try-out, it is not an optimal solution and I would like to keep it as clean as possible.

    – Arne Uten
    Nov 14 '18 at 16:14












  • It's tricky. There have been many questions about pretty-printing XML. This one has 19 answers, stackoverflow.com/q/749796/407651, but I'm not sure if they are of any help in this case (arranging attributes).

    – mzjn
    Nov 14 '18 at 16:34











  • You might want to try the Tidy utility (html-tidy.org). It has a indent-attributes option: api.html-tidy.org/tidy/quickref_5.6.0.html#indent-attributes.

    – mzjn
    Nov 14 '18 at 16:42

















  • I'm using lxml and from that library I'm using etree. The tutorial I'm referring to comes from another thread and the link is lxml.de/tutorial.html

    – Arne Uten
    Nov 14 '18 at 15:44












  • Perhaps this helps: stackoverflow.com/q/40410923/407651

    – mzjn
    Nov 14 '18 at 15:56











  • Thanks @mzjn ! I took a first glance on the 'fix' that was found but as he also mentions after his try-out, it is not an optimal solution and I would like to keep it as clean as possible.

    – Arne Uten
    Nov 14 '18 at 16:14












  • It's tricky. There have been many questions about pretty-printing XML. This one has 19 answers, stackoverflow.com/q/749796/407651, but I'm not sure if they are of any help in this case (arranging attributes).

    – mzjn
    Nov 14 '18 at 16:34











  • You might want to try the Tidy utility (html-tidy.org). It has a indent-attributes option: api.html-tidy.org/tidy/quickref_5.6.0.html#indent-attributes.

    – mzjn
    Nov 14 '18 at 16:42
















I'm using lxml and from that library I'm using etree. The tutorial I'm referring to comes from another thread and the link is lxml.de/tutorial.html

– Arne Uten
Nov 14 '18 at 15:44






I'm using lxml and from that library I'm using etree. The tutorial I'm referring to comes from another thread and the link is lxml.de/tutorial.html

– Arne Uten
Nov 14 '18 at 15:44














Perhaps this helps: stackoverflow.com/q/40410923/407651

– mzjn
Nov 14 '18 at 15:56





Perhaps this helps: stackoverflow.com/q/40410923/407651

– mzjn
Nov 14 '18 at 15:56













Thanks @mzjn ! I took a first glance on the 'fix' that was found but as he also mentions after his try-out, it is not an optimal solution and I would like to keep it as clean as possible.

– Arne Uten
Nov 14 '18 at 16:14






Thanks @mzjn ! I took a first glance on the 'fix' that was found but as he also mentions after his try-out, it is not an optimal solution and I would like to keep it as clean as possible.

– Arne Uten
Nov 14 '18 at 16:14














It's tricky. There have been many questions about pretty-printing XML. This one has 19 answers, stackoverflow.com/q/749796/407651, but I'm not sure if they are of any help in this case (arranging attributes).

– mzjn
Nov 14 '18 at 16:34





It's tricky. There have been many questions about pretty-printing XML. This one has 19 answers, stackoverflow.com/q/749796/407651, but I'm not sure if they are of any help in this case (arranging attributes).

– mzjn
Nov 14 '18 at 16:34













You might want to try the Tidy utility (html-tidy.org). It has a indent-attributes option: api.html-tidy.org/tidy/quickref_5.6.0.html#indent-attributes.

– mzjn
Nov 14 '18 at 16:42





You might want to try the Tidy utility (html-tidy.org). It has a indent-attributes option: api.html-tidy.org/tidy/quickref_5.6.0.html#indent-attributes.

– mzjn
Nov 14 '18 at 16:42












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