Creating a multidimensional array from a string with delimiter
I have an comma separated string like this:
string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#";
This is basically the data from an csv file where I am using reader to read from file.
In the above string ',' represents the data delimeter while '#' represents EOL of the file.
myString = myString.TrimEnd('#'); //Removing extra # in the end.
//Result of above 1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,
I want to convert the above into multidimentional array, loop through it reading value of each row data and create my own json.
So I started with the below code. This would result me with row and column count.
int rowCount = result.TrimEnd('#').Split('#').Count();
int colCount = result.TrimEnd('#').Split('#')[0].TrimEnd(',').Split(',').Length;
//Defining my object which I want to fill.
JObject myObject = new JObject();
Below I want to loop through row and column getting data value from each row and column
for (int row = o ; row <= rowCount; row++)
for (int col = 0; col <= colCount; col++)
//So here I want to do something like:
var rowValue = multiArray[row][col];
//After getting the row value below is the logic to add to my object
if(col == 0)
myObject.Add("first", rowValue);
else if(col == colCount)
myObject.Add("last", rowValue);
else
myObject.Add(col, rowValue);
So my question is how can I create the multidimentional array "multiArray" in my code.
Example of my json:
"first": 1
"1": a,
"2": b,
"last": C1
,
"first": 2
"1": c,
"2": d,
"last": C2
c#
add a comment |
I have an comma separated string like this:
string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#";
This is basically the data from an csv file where I am using reader to read from file.
In the above string ',' represents the data delimeter while '#' represents EOL of the file.
myString = myString.TrimEnd('#'); //Removing extra # in the end.
//Result of above 1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,
I want to convert the above into multidimentional array, loop through it reading value of each row data and create my own json.
So I started with the below code. This would result me with row and column count.
int rowCount = result.TrimEnd('#').Split('#').Count();
int colCount = result.TrimEnd('#').Split('#')[0].TrimEnd(',').Split(',').Length;
//Defining my object which I want to fill.
JObject myObject = new JObject();
Below I want to loop through row and column getting data value from each row and column
for (int row = o ; row <= rowCount; row++)
for (int col = 0; col <= colCount; col++)
//So here I want to do something like:
var rowValue = multiArray[row][col];
//After getting the row value below is the logic to add to my object
if(col == 0)
myObject.Add("first", rowValue);
else if(col == colCount)
myObject.Add("last", rowValue);
else
myObject.Add(col, rowValue);
So my question is how can I create the multidimentional array "multiArray" in my code.
Example of my json:
"first": 1
"1": a,
"2": b,
"last": C1
,
"first": 2
"1": c,
"2": d,
"last": C2
c#
It would be helpful if you included what you want your final JSON to look like given the starting string"1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#"
– Matt Burland
Nov 15 '18 at 19:12
So where are you stuck?
– Ole EH Dufour
Nov 15 '18 at 19:15
@MattBurland my final json would depend upon the rows and columns of the file ie the string. I would take care of creating the json its just that I dont know to create the multi array "multiArray" in my code above from which I can loop through. I have updated my post with json.
– user1563677
Nov 15 '18 at 19:19
@OleEHDufour as mentioned in my post, I dont know how to create the "multiarray" so that I can loop through it.
– user1563677
Nov 15 '18 at 19:20
@user1563677 - you have an example input, what's the example output for that?
– Matt Burland
Nov 15 '18 at 21:10
add a comment |
I have an comma separated string like this:
string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#";
This is basically the data from an csv file where I am using reader to read from file.
In the above string ',' represents the data delimeter while '#' represents EOL of the file.
myString = myString.TrimEnd('#'); //Removing extra # in the end.
//Result of above 1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,
I want to convert the above into multidimentional array, loop through it reading value of each row data and create my own json.
So I started with the below code. This would result me with row and column count.
int rowCount = result.TrimEnd('#').Split('#').Count();
int colCount = result.TrimEnd('#').Split('#')[0].TrimEnd(',').Split(',').Length;
//Defining my object which I want to fill.
JObject myObject = new JObject();
Below I want to loop through row and column getting data value from each row and column
for (int row = o ; row <= rowCount; row++)
for (int col = 0; col <= colCount; col++)
//So here I want to do something like:
var rowValue = multiArray[row][col];
//After getting the row value below is the logic to add to my object
if(col == 0)
myObject.Add("first", rowValue);
else if(col == colCount)
myObject.Add("last", rowValue);
else
myObject.Add(col, rowValue);
So my question is how can I create the multidimentional array "multiArray" in my code.
Example of my json:
"first": 1
"1": a,
"2": b,
"last": C1
,
"first": 2
"1": c,
"2": d,
"last": C2
c#
I have an comma separated string like this:
string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#";
This is basically the data from an csv file where I am using reader to read from file.
In the above string ',' represents the data delimeter while '#' represents EOL of the file.
myString = myString.TrimEnd('#'); //Removing extra # in the end.
//Result of above 1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,
I want to convert the above into multidimentional array, loop through it reading value of each row data and create my own json.
So I started with the below code. This would result me with row and column count.
int rowCount = result.TrimEnd('#').Split('#').Count();
int colCount = result.TrimEnd('#').Split('#')[0].TrimEnd(',').Split(',').Length;
//Defining my object which I want to fill.
JObject myObject = new JObject();
Below I want to loop through row and column getting data value from each row and column
for (int row = o ; row <= rowCount; row++)
for (int col = 0; col <= colCount; col++)
//So here I want to do something like:
var rowValue = multiArray[row][col];
//After getting the row value below is the logic to add to my object
if(col == 0)
myObject.Add("first", rowValue);
else if(col == colCount)
myObject.Add("last", rowValue);
else
myObject.Add(col, rowValue);
So my question is how can I create the multidimentional array "multiArray" in my code.
Example of my json:
"first": 1
"1": a,
"2": b,
"last": C1
,
"first": 2
"1": c,
"2": d,
"last": C2
c#
c#
edited Nov 15 '18 at 19:23
user1563677
asked Nov 15 '18 at 19:09
user1563677user1563677
153217
153217
It would be helpful if you included what you want your final JSON to look like given the starting string"1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#"
– Matt Burland
Nov 15 '18 at 19:12
So where are you stuck?
– Ole EH Dufour
Nov 15 '18 at 19:15
@MattBurland my final json would depend upon the rows and columns of the file ie the string. I would take care of creating the json its just that I dont know to create the multi array "multiArray" in my code above from which I can loop through. I have updated my post with json.
– user1563677
Nov 15 '18 at 19:19
@OleEHDufour as mentioned in my post, I dont know how to create the "multiarray" so that I can loop through it.
– user1563677
Nov 15 '18 at 19:20
@user1563677 - you have an example input, what's the example output for that?
– Matt Burland
Nov 15 '18 at 21:10
add a comment |
It would be helpful if you included what you want your final JSON to look like given the starting string"1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#"
– Matt Burland
Nov 15 '18 at 19:12
So where are you stuck?
– Ole EH Dufour
Nov 15 '18 at 19:15
@MattBurland my final json would depend upon the rows and columns of the file ie the string. I would take care of creating the json its just that I dont know to create the multi array "multiArray" in my code above from which I can loop through. I have updated my post with json.
– user1563677
Nov 15 '18 at 19:19
@OleEHDufour as mentioned in my post, I dont know how to create the "multiarray" so that I can loop through it.
– user1563677
Nov 15 '18 at 19:20
@user1563677 - you have an example input, what's the example output for that?
– Matt Burland
Nov 15 '18 at 21:10
It would be helpful if you included what you want your final JSON to look like given the starting string
"1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#"
– Matt Burland
Nov 15 '18 at 19:12
It would be helpful if you included what you want your final JSON to look like given the starting string
"1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#"
– Matt Burland
Nov 15 '18 at 19:12
So where are you stuck?
– Ole EH Dufour
Nov 15 '18 at 19:15
So where are you stuck?
– Ole EH Dufour
Nov 15 '18 at 19:15
@MattBurland my final json would depend upon the rows and columns of the file ie the string. I would take care of creating the json its just that I dont know to create the multi array "multiArray" in my code above from which I can loop through. I have updated my post with json.
– user1563677
Nov 15 '18 at 19:19
@MattBurland my final json would depend upon the rows and columns of the file ie the string. I would take care of creating the json its just that I dont know to create the multi array "multiArray" in my code above from which I can loop through. I have updated my post with json.
– user1563677
Nov 15 '18 at 19:19
@OleEHDufour as mentioned in my post, I dont know how to create the "multiarray" so that I can loop through it.
– user1563677
Nov 15 '18 at 19:20
@OleEHDufour as mentioned in my post, I dont know how to create the "multiarray" so that I can loop through it.
– user1563677
Nov 15 '18 at 19:20
@user1563677 - you have an example input, what's the example output for that?
– Matt Burland
Nov 15 '18 at 21:10
@user1563677 - you have an example input, what's the example output for that?
– Matt Burland
Nov 15 '18 at 21:10
add a comment |
2 Answers
2
active
oldest
votes
The following code creates and fills your multi-dimensional array, but there is a problem with your data. Because of the extra commas your json will not look like your sample json.
string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".TrimEnd('#');
var rows = myString.Split('#');
var rowCount = rows.Length;
var columnCount = rows[0].Split(',').Length;
string[,] multiArray = new string[rowCount, columnCount];
for (int i = 0; i < rowCount; i ++)
var values = rows[i].Split(',');
for (int j = 0; j < columnCount && j < values.Length; j++)
multiArray[i,j] = values[j];
The results I get from this are that there is a 4x6 array with only 4 values in each row.
Thanks will check and get back
– user1563677
Nov 15 '18 at 20:11
I had to adjust a little bit with my code but this works fine.
– user1563677
Nov 16 '18 at 15:08
add a comment |
The below code does the trick for me and spits out the following json:
[
"first": 1,
"one": "a",
"two": "b",
"last": "C1"
,
"first": 2,
"one": "d",
"two": "e",
"last": "C2"
,
"first": 3,
"one": "f",
"two": "g",
"last": "C3"
,
"first": 4,
"one": "h",
"two": "i",
"last": "C4"
]
You will need to install Newtonsoft.Json via your package manager.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
using Newtonsoft.Json;
namespace ConsoleApp2
class Program
class WahEvah
public int first;
public string one;
public string two;
public string last;
static void Main(string args)
List<string> myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".Split('#').ToList();
List<List<string>> myString2 = myString.Select(x => x.Split(',').ToList()).ToList();
List<WahEvah> l = new List<WahEvah>();
int counter = 0;
for (int i = 0; i < myString2.Count - 1; i++)
WahEvah wd = NewMethod(myString2[i], counter);
l.Add(wd);
string json = JsonConvert.SerializeObject(l, Formatting.Indented);
Console.Write(json);
Console.ReadLine();
private static WahEvah NewMethod(List<string> myString, int counter)
counter = 0;
WahEvah w = null; w = new WahEvah();
foreach (string s2 in myString)
if (counter == 0)
w.first = Convert.ToInt32(s2.Trim()); counter++; continue;
if (counter == 1)
w.one = s2.Trim(); counter++; continue;
if (counter == 2)
w.two = s2.Trim(); counter++; continue;
if (counter == 3)
w.last = s2.Trim(); counter++; continue;
return w;
Thanks for the inputs but I dont have a static list so cant create a fixed model as you have created.
– user1563677
Nov 16 '18 at 15:09
It's just an example. It should work with any string that follows your pattern.
– Ole EH Dufour
Nov 16 '18 at 15:42
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The following code creates and fills your multi-dimensional array, but there is a problem with your data. Because of the extra commas your json will not look like your sample json.
string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".TrimEnd('#');
var rows = myString.Split('#');
var rowCount = rows.Length;
var columnCount = rows[0].Split(',').Length;
string[,] multiArray = new string[rowCount, columnCount];
for (int i = 0; i < rowCount; i ++)
var values = rows[i].Split(',');
for (int j = 0; j < columnCount && j < values.Length; j++)
multiArray[i,j] = values[j];
The results I get from this are that there is a 4x6 array with only 4 values in each row.
Thanks will check and get back
– user1563677
Nov 15 '18 at 20:11
I had to adjust a little bit with my code but this works fine.
– user1563677
Nov 16 '18 at 15:08
add a comment |
The following code creates and fills your multi-dimensional array, but there is a problem with your data. Because of the extra commas your json will not look like your sample json.
string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".TrimEnd('#');
var rows = myString.Split('#');
var rowCount = rows.Length;
var columnCount = rows[0].Split(',').Length;
string[,] multiArray = new string[rowCount, columnCount];
for (int i = 0; i < rowCount; i ++)
var values = rows[i].Split(',');
for (int j = 0; j < columnCount && j < values.Length; j++)
multiArray[i,j] = values[j];
The results I get from this are that there is a 4x6 array with only 4 values in each row.
Thanks will check and get back
– user1563677
Nov 15 '18 at 20:11
I had to adjust a little bit with my code but this works fine.
– user1563677
Nov 16 '18 at 15:08
add a comment |
The following code creates and fills your multi-dimensional array, but there is a problem with your data. Because of the extra commas your json will not look like your sample json.
string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".TrimEnd('#');
var rows = myString.Split('#');
var rowCount = rows.Length;
var columnCount = rows[0].Split(',').Length;
string[,] multiArray = new string[rowCount, columnCount];
for (int i = 0; i < rowCount; i ++)
var values = rows[i].Split(',');
for (int j = 0; j < columnCount && j < values.Length; j++)
multiArray[i,j] = values[j];
The results I get from this are that there is a 4x6 array with only 4 values in each row.
The following code creates and fills your multi-dimensional array, but there is a problem with your data. Because of the extra commas your json will not look like your sample json.
string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".TrimEnd('#');
var rows = myString.Split('#');
var rowCount = rows.Length;
var columnCount = rows[0].Split(',').Length;
string[,] multiArray = new string[rowCount, columnCount];
for (int i = 0; i < rowCount; i ++)
var values = rows[i].Split(',');
for (int j = 0; j < columnCount && j < values.Length; j++)
multiArray[i,j] = values[j];
The results I get from this are that there is a 4x6 array with only 4 values in each row.
answered Nov 15 '18 at 19:49
JamesJames
936
936
Thanks will check and get back
– user1563677
Nov 15 '18 at 20:11
I had to adjust a little bit with my code but this works fine.
– user1563677
Nov 16 '18 at 15:08
add a comment |
Thanks will check and get back
– user1563677
Nov 15 '18 at 20:11
I had to adjust a little bit with my code but this works fine.
– user1563677
Nov 16 '18 at 15:08
Thanks will check and get back
– user1563677
Nov 15 '18 at 20:11
Thanks will check and get back
– user1563677
Nov 15 '18 at 20:11
I had to adjust a little bit with my code but this works fine.
– user1563677
Nov 16 '18 at 15:08
I had to adjust a little bit with my code but this works fine.
– user1563677
Nov 16 '18 at 15:08
add a comment |
The below code does the trick for me and spits out the following json:
[
"first": 1,
"one": "a",
"two": "b",
"last": "C1"
,
"first": 2,
"one": "d",
"two": "e",
"last": "C2"
,
"first": 3,
"one": "f",
"two": "g",
"last": "C3"
,
"first": 4,
"one": "h",
"two": "i",
"last": "C4"
]
You will need to install Newtonsoft.Json via your package manager.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
using Newtonsoft.Json;
namespace ConsoleApp2
class Program
class WahEvah
public int first;
public string one;
public string two;
public string last;
static void Main(string args)
List<string> myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".Split('#').ToList();
List<List<string>> myString2 = myString.Select(x => x.Split(',').ToList()).ToList();
List<WahEvah> l = new List<WahEvah>();
int counter = 0;
for (int i = 0; i < myString2.Count - 1; i++)
WahEvah wd = NewMethod(myString2[i], counter);
l.Add(wd);
string json = JsonConvert.SerializeObject(l, Formatting.Indented);
Console.Write(json);
Console.ReadLine();
private static WahEvah NewMethod(List<string> myString, int counter)
counter = 0;
WahEvah w = null; w = new WahEvah();
foreach (string s2 in myString)
if (counter == 0)
w.first = Convert.ToInt32(s2.Trim()); counter++; continue;
if (counter == 1)
w.one = s2.Trim(); counter++; continue;
if (counter == 2)
w.two = s2.Trim(); counter++; continue;
if (counter == 3)
w.last = s2.Trim(); counter++; continue;
return w;
Thanks for the inputs but I dont have a static list so cant create a fixed model as you have created.
– user1563677
Nov 16 '18 at 15:09
It's just an example. It should work with any string that follows your pattern.
– Ole EH Dufour
Nov 16 '18 at 15:42
add a comment |
The below code does the trick for me and spits out the following json:
[
"first": 1,
"one": "a",
"two": "b",
"last": "C1"
,
"first": 2,
"one": "d",
"two": "e",
"last": "C2"
,
"first": 3,
"one": "f",
"two": "g",
"last": "C3"
,
"first": 4,
"one": "h",
"two": "i",
"last": "C4"
]
You will need to install Newtonsoft.Json via your package manager.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
using Newtonsoft.Json;
namespace ConsoleApp2
class Program
class WahEvah
public int first;
public string one;
public string two;
public string last;
static void Main(string args)
List<string> myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".Split('#').ToList();
List<List<string>> myString2 = myString.Select(x => x.Split(',').ToList()).ToList();
List<WahEvah> l = new List<WahEvah>();
int counter = 0;
for (int i = 0; i < myString2.Count - 1; i++)
WahEvah wd = NewMethod(myString2[i], counter);
l.Add(wd);
string json = JsonConvert.SerializeObject(l, Formatting.Indented);
Console.Write(json);
Console.ReadLine();
private static WahEvah NewMethod(List<string> myString, int counter)
counter = 0;
WahEvah w = null; w = new WahEvah();
foreach (string s2 in myString)
if (counter == 0)
w.first = Convert.ToInt32(s2.Trim()); counter++; continue;
if (counter == 1)
w.one = s2.Trim(); counter++; continue;
if (counter == 2)
w.two = s2.Trim(); counter++; continue;
if (counter == 3)
w.last = s2.Trim(); counter++; continue;
return w;
Thanks for the inputs but I dont have a static list so cant create a fixed model as you have created.
– user1563677
Nov 16 '18 at 15:09
It's just an example. It should work with any string that follows your pattern.
– Ole EH Dufour
Nov 16 '18 at 15:42
add a comment |
The below code does the trick for me and spits out the following json:
[
"first": 1,
"one": "a",
"two": "b",
"last": "C1"
,
"first": 2,
"one": "d",
"two": "e",
"last": "C2"
,
"first": 3,
"one": "f",
"two": "g",
"last": "C3"
,
"first": 4,
"one": "h",
"two": "i",
"last": "C4"
]
You will need to install Newtonsoft.Json via your package manager.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
using Newtonsoft.Json;
namespace ConsoleApp2
class Program
class WahEvah
public int first;
public string one;
public string two;
public string last;
static void Main(string args)
List<string> myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".Split('#').ToList();
List<List<string>> myString2 = myString.Select(x => x.Split(',').ToList()).ToList();
List<WahEvah> l = new List<WahEvah>();
int counter = 0;
for (int i = 0; i < myString2.Count - 1; i++)
WahEvah wd = NewMethod(myString2[i], counter);
l.Add(wd);
string json = JsonConvert.SerializeObject(l, Formatting.Indented);
Console.Write(json);
Console.ReadLine();
private static WahEvah NewMethod(List<string> myString, int counter)
counter = 0;
WahEvah w = null; w = new WahEvah();
foreach (string s2 in myString)
if (counter == 0)
w.first = Convert.ToInt32(s2.Trim()); counter++; continue;
if (counter == 1)
w.one = s2.Trim(); counter++; continue;
if (counter == 2)
w.two = s2.Trim(); counter++; continue;
if (counter == 3)
w.last = s2.Trim(); counter++; continue;
return w;
The below code does the trick for me and spits out the following json:
[
"first": 1,
"one": "a",
"two": "b",
"last": "C1"
,
"first": 2,
"one": "d",
"two": "e",
"last": "C2"
,
"first": 3,
"one": "f",
"two": "g",
"last": "C3"
,
"first": 4,
"one": "h",
"two": "i",
"last": "C4"
]
You will need to install Newtonsoft.Json via your package manager.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
using Newtonsoft.Json;
namespace ConsoleApp2
class Program
class WahEvah
public int first;
public string one;
public string two;
public string last;
static void Main(string args)
List<string> myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".Split('#').ToList();
List<List<string>> myString2 = myString.Select(x => x.Split(',').ToList()).ToList();
List<WahEvah> l = new List<WahEvah>();
int counter = 0;
for (int i = 0; i < myString2.Count - 1; i++)
WahEvah wd = NewMethod(myString2[i], counter);
l.Add(wd);
string json = JsonConvert.SerializeObject(l, Formatting.Indented);
Console.Write(json);
Console.ReadLine();
private static WahEvah NewMethod(List<string> myString, int counter)
counter = 0;
WahEvah w = null; w = new WahEvah();
foreach (string s2 in myString)
if (counter == 0)
w.first = Convert.ToInt32(s2.Trim()); counter++; continue;
if (counter == 1)
w.one = s2.Trim(); counter++; continue;
if (counter == 2)
w.two = s2.Trim(); counter++; continue;
if (counter == 3)
w.last = s2.Trim(); counter++; continue;
return w;
answered Nov 15 '18 at 20:16
Ole EH DufourOle EH Dufour
1,10911121
1,10911121
Thanks for the inputs but I dont have a static list so cant create a fixed model as you have created.
– user1563677
Nov 16 '18 at 15:09
It's just an example. It should work with any string that follows your pattern.
– Ole EH Dufour
Nov 16 '18 at 15:42
add a comment |
Thanks for the inputs but I dont have a static list so cant create a fixed model as you have created.
– user1563677
Nov 16 '18 at 15:09
It's just an example. It should work with any string that follows your pattern.
– Ole EH Dufour
Nov 16 '18 at 15:42
Thanks for the inputs but I dont have a static list so cant create a fixed model as you have created.
– user1563677
Nov 16 '18 at 15:09
Thanks for the inputs but I dont have a static list so cant create a fixed model as you have created.
– user1563677
Nov 16 '18 at 15:09
It's just an example. It should work with any string that follows your pattern.
– Ole EH Dufour
Nov 16 '18 at 15:42
It's just an example. It should work with any string that follows your pattern.
– Ole EH Dufour
Nov 16 '18 at 15:42
add a comment |
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It would be helpful if you included what you want your final JSON to look like given the starting string
"1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#"
– Matt Burland
Nov 15 '18 at 19:12
So where are you stuck?
– Ole EH Dufour
Nov 15 '18 at 19:15
@MattBurland my final json would depend upon the rows and columns of the file ie the string. I would take care of creating the json its just that I dont know to create the multi array "multiArray" in my code above from which I can loop through. I have updated my post with json.
– user1563677
Nov 15 '18 at 19:19
@OleEHDufour as mentioned in my post, I dont know how to create the "multiarray" so that I can loop through it.
– user1563677
Nov 15 '18 at 19:20
@user1563677 - you have an example input, what's the example output for that?
– Matt Burland
Nov 15 '18 at 21:10