Creating a multidimensional array from a string with delimiter










0















I have an comma separated string like this:



string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#";


This is basically the data from an csv file where I am using reader to read from file.



In the above string ',' represents the data delimeter while '#' represents EOL of the file.



myString = myString.TrimEnd('#'); //Removing extra # in the end.
//Result of above 1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,


I want to convert the above into multidimentional array, loop through it reading value of each row data and create my own json.



So I started with the below code. This would result me with row and column count.



int rowCount = result.TrimEnd('#').Split('#').Count();
int colCount = result.TrimEnd('#').Split('#')[0].TrimEnd(',').Split(',').Length;

//Defining my object which I want to fill.
JObject myObject = new JObject();


Below I want to loop through row and column getting data value from each row and column



for (int row = o ; row <= rowCount; row++)

for (int col = 0; col <= colCount; col++)

//So here I want to do something like:
var rowValue = multiArray[row][col];

//After getting the row value below is the logic to add to my object
if(col == 0)

myObject.Add("first", rowValue);

else if(col == colCount)

myObject.Add("last", rowValue);

else

myObject.Add(col, rowValue);





So my question is how can I create the multidimentional array "multiArray" in my code.



Example of my json:




"first": 1
"1": a,
"2": b,
"last": C1
,

"first": 2
"1": c,
"2": d,
"last": C2










share|improve this question
























  • It would be helpful if you included what you want your final JSON to look like given the starting string "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#"

    – Matt Burland
    Nov 15 '18 at 19:12











  • So where are you stuck?

    – Ole EH Dufour
    Nov 15 '18 at 19:15











  • @MattBurland my final json would depend upon the rows and columns of the file ie the string. I would take care of creating the json its just that I dont know to create the multi array "multiArray" in my code above from which I can loop through. I have updated my post with json.

    – user1563677
    Nov 15 '18 at 19:19












  • @OleEHDufour as mentioned in my post, I dont know how to create the "multiarray" so that I can loop through it.

    – user1563677
    Nov 15 '18 at 19:20











  • @user1563677 - you have an example input, what's the example output for that?

    – Matt Burland
    Nov 15 '18 at 21:10















0















I have an comma separated string like this:



string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#";


This is basically the data from an csv file where I am using reader to read from file.



In the above string ',' represents the data delimeter while '#' represents EOL of the file.



myString = myString.TrimEnd('#'); //Removing extra # in the end.
//Result of above 1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,


I want to convert the above into multidimentional array, loop through it reading value of each row data and create my own json.



So I started with the below code. This would result me with row and column count.



int rowCount = result.TrimEnd('#').Split('#').Count();
int colCount = result.TrimEnd('#').Split('#')[0].TrimEnd(',').Split(',').Length;

//Defining my object which I want to fill.
JObject myObject = new JObject();


Below I want to loop through row and column getting data value from each row and column



for (int row = o ; row <= rowCount; row++)

for (int col = 0; col <= colCount; col++)

//So here I want to do something like:
var rowValue = multiArray[row][col];

//After getting the row value below is the logic to add to my object
if(col == 0)

myObject.Add("first", rowValue);

else if(col == colCount)

myObject.Add("last", rowValue);

else

myObject.Add(col, rowValue);





So my question is how can I create the multidimentional array "multiArray" in my code.



Example of my json:




"first": 1
"1": a,
"2": b,
"last": C1
,

"first": 2
"1": c,
"2": d,
"last": C2










share|improve this question
























  • It would be helpful if you included what you want your final JSON to look like given the starting string "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#"

    – Matt Burland
    Nov 15 '18 at 19:12











  • So where are you stuck?

    – Ole EH Dufour
    Nov 15 '18 at 19:15











  • @MattBurland my final json would depend upon the rows and columns of the file ie the string. I would take care of creating the json its just that I dont know to create the multi array "multiArray" in my code above from which I can loop through. I have updated my post with json.

    – user1563677
    Nov 15 '18 at 19:19












  • @OleEHDufour as mentioned in my post, I dont know how to create the "multiarray" so that I can loop through it.

    – user1563677
    Nov 15 '18 at 19:20











  • @user1563677 - you have an example input, what's the example output for that?

    – Matt Burland
    Nov 15 '18 at 21:10













0












0








0








I have an comma separated string like this:



string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#";


This is basically the data from an csv file where I am using reader to read from file.



In the above string ',' represents the data delimeter while '#' represents EOL of the file.



myString = myString.TrimEnd('#'); //Removing extra # in the end.
//Result of above 1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,


I want to convert the above into multidimentional array, loop through it reading value of each row data and create my own json.



So I started with the below code. This would result me with row and column count.



int rowCount = result.TrimEnd('#').Split('#').Count();
int colCount = result.TrimEnd('#').Split('#')[0].TrimEnd(',').Split(',').Length;

//Defining my object which I want to fill.
JObject myObject = new JObject();


Below I want to loop through row and column getting data value from each row and column



for (int row = o ; row <= rowCount; row++)

for (int col = 0; col <= colCount; col++)

//So here I want to do something like:
var rowValue = multiArray[row][col];

//After getting the row value below is the logic to add to my object
if(col == 0)

myObject.Add("first", rowValue);

else if(col == colCount)

myObject.Add("last", rowValue);

else

myObject.Add(col, rowValue);





So my question is how can I create the multidimentional array "multiArray" in my code.



Example of my json:




"first": 1
"1": a,
"2": b,
"last": C1
,

"first": 2
"1": c,
"2": d,
"last": C2










share|improve this question
















I have an comma separated string like this:



string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#";


This is basically the data from an csv file where I am using reader to read from file.



In the above string ',' represents the data delimeter while '#' represents EOL of the file.



myString = myString.TrimEnd('#'); //Removing extra # in the end.
//Result of above 1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,


I want to convert the above into multidimentional array, loop through it reading value of each row data and create my own json.



So I started with the below code. This would result me with row and column count.



int rowCount = result.TrimEnd('#').Split('#').Count();
int colCount = result.TrimEnd('#').Split('#')[0].TrimEnd(',').Split(',').Length;

//Defining my object which I want to fill.
JObject myObject = new JObject();


Below I want to loop through row and column getting data value from each row and column



for (int row = o ; row <= rowCount; row++)

for (int col = 0; col <= colCount; col++)

//So here I want to do something like:
var rowValue = multiArray[row][col];

//After getting the row value below is the logic to add to my object
if(col == 0)

myObject.Add("first", rowValue);

else if(col == colCount)

myObject.Add("last", rowValue);

else

myObject.Add(col, rowValue);





So my question is how can I create the multidimentional array "multiArray" in my code.



Example of my json:




"first": 1
"1": a,
"2": b,
"last": C1
,

"first": 2
"1": c,
"2": d,
"last": C2







c#






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 15 '18 at 19:23







user1563677

















asked Nov 15 '18 at 19:09









user1563677user1563677

153217




153217












  • It would be helpful if you included what you want your final JSON to look like given the starting string "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#"

    – Matt Burland
    Nov 15 '18 at 19:12











  • So where are you stuck?

    – Ole EH Dufour
    Nov 15 '18 at 19:15











  • @MattBurland my final json would depend upon the rows and columns of the file ie the string. I would take care of creating the json its just that I dont know to create the multi array "multiArray" in my code above from which I can loop through. I have updated my post with json.

    – user1563677
    Nov 15 '18 at 19:19












  • @OleEHDufour as mentioned in my post, I dont know how to create the "multiarray" so that I can loop through it.

    – user1563677
    Nov 15 '18 at 19:20











  • @user1563677 - you have an example input, what's the example output for that?

    – Matt Burland
    Nov 15 '18 at 21:10

















  • It would be helpful if you included what you want your final JSON to look like given the starting string "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#"

    – Matt Burland
    Nov 15 '18 at 19:12











  • So where are you stuck?

    – Ole EH Dufour
    Nov 15 '18 at 19:15











  • @MattBurland my final json would depend upon the rows and columns of the file ie the string. I would take care of creating the json its just that I dont know to create the multi array "multiArray" in my code above from which I can loop through. I have updated my post with json.

    – user1563677
    Nov 15 '18 at 19:19












  • @OleEHDufour as mentioned in my post, I dont know how to create the "multiarray" so that I can loop through it.

    – user1563677
    Nov 15 '18 at 19:20











  • @user1563677 - you have an example input, what's the example output for that?

    – Matt Burland
    Nov 15 '18 at 21:10
















It would be helpful if you included what you want your final JSON to look like given the starting string "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#"

– Matt Burland
Nov 15 '18 at 19:12





It would be helpful if you included what you want your final JSON to look like given the starting string "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#"

– Matt Burland
Nov 15 '18 at 19:12













So where are you stuck?

– Ole EH Dufour
Nov 15 '18 at 19:15





So where are you stuck?

– Ole EH Dufour
Nov 15 '18 at 19:15













@MattBurland my final json would depend upon the rows and columns of the file ie the string. I would take care of creating the json its just that I dont know to create the multi array "multiArray" in my code above from which I can loop through. I have updated my post with json.

– user1563677
Nov 15 '18 at 19:19






@MattBurland my final json would depend upon the rows and columns of the file ie the string. I would take care of creating the json its just that I dont know to create the multi array "multiArray" in my code above from which I can loop through. I have updated my post with json.

– user1563677
Nov 15 '18 at 19:19














@OleEHDufour as mentioned in my post, I dont know how to create the "multiarray" so that I can loop through it.

– user1563677
Nov 15 '18 at 19:20





@OleEHDufour as mentioned in my post, I dont know how to create the "multiarray" so that I can loop through it.

– user1563677
Nov 15 '18 at 19:20













@user1563677 - you have an example input, what's the example output for that?

– Matt Burland
Nov 15 '18 at 21:10





@user1563677 - you have an example input, what's the example output for that?

– Matt Burland
Nov 15 '18 at 21:10












2 Answers
2






active

oldest

votes


















1














The following code creates and fills your multi-dimensional array, but there is a problem with your data. Because of the extra commas your json will not look like your sample json.



string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".TrimEnd('#');

var rows = myString.Split('#');
var rowCount = rows.Length;
var columnCount = rows[0].Split(',').Length;

string[,] multiArray = new string[rowCount, columnCount];

for (int i = 0; i < rowCount; i ++)

var values = rows[i].Split(',');
for (int j = 0; j < columnCount && j < values.Length; j++)

multiArray[i,j] = values[j];




The results I get from this are that there is a 4x6 array with only 4 values in each row.






share|improve this answer























  • Thanks will check and get back

    – user1563677
    Nov 15 '18 at 20:11











  • I had to adjust a little bit with my code but this works fine.

    – user1563677
    Nov 16 '18 at 15:08


















0














The below code does the trick for me and spits out the following json:



[

"first": 1,
"one": "a",
"two": "b",
"last": "C1"
,

"first": 2,
"one": "d",
"two": "e",
"last": "C2"
,

"first": 3,
"one": "f",
"two": "g",
"last": "C3"
,

"first": 4,
"one": "h",
"two": "i",
"last": "C4"

]


You will need to install Newtonsoft.Json via your package manager.



using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
using Newtonsoft.Json;

namespace ConsoleApp2

class Program

class WahEvah

public int first;
public string one;
public string two;
public string last;



static void Main(string args)

List<string> myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".Split('#').ToList();
List<List<string>> myString2 = myString.Select(x => x.Split(',').ToList()).ToList();
List<WahEvah> l = new List<WahEvah>();
int counter = 0;
for (int i = 0; i < myString2.Count - 1; i++)

WahEvah wd = NewMethod(myString2[i], counter);
l.Add(wd);


string json = JsonConvert.SerializeObject(l, Formatting.Indented);
Console.Write(json);
Console.ReadLine();


private static WahEvah NewMethod(List<string> myString, int counter)

counter = 0;
WahEvah w = null; w = new WahEvah();
foreach (string s2 in myString)



if (counter == 0)

w.first = Convert.ToInt32(s2.Trim()); counter++; continue;

if (counter == 1)

w.one = s2.Trim(); counter++; continue;

if (counter == 2)

w.two = s2.Trim(); counter++; continue;

if (counter == 3)

w.last = s2.Trim(); counter++; continue;





return w;










share|improve this answer























  • Thanks for the inputs but I dont have a static list so cant create a fixed model as you have created.

    – user1563677
    Nov 16 '18 at 15:09











  • It's just an example. It should work with any string that follows your pattern.

    – Ole EH Dufour
    Nov 16 '18 at 15:42










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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














The following code creates and fills your multi-dimensional array, but there is a problem with your data. Because of the extra commas your json will not look like your sample json.



string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".TrimEnd('#');

var rows = myString.Split('#');
var rowCount = rows.Length;
var columnCount = rows[0].Split(',').Length;

string[,] multiArray = new string[rowCount, columnCount];

for (int i = 0; i < rowCount; i ++)

var values = rows[i].Split(',');
for (int j = 0; j < columnCount && j < values.Length; j++)

multiArray[i,j] = values[j];




The results I get from this are that there is a 4x6 array with only 4 values in each row.






share|improve this answer























  • Thanks will check and get back

    – user1563677
    Nov 15 '18 at 20:11











  • I had to adjust a little bit with my code but this works fine.

    – user1563677
    Nov 16 '18 at 15:08















1














The following code creates and fills your multi-dimensional array, but there is a problem with your data. Because of the extra commas your json will not look like your sample json.



string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".TrimEnd('#');

var rows = myString.Split('#');
var rowCount = rows.Length;
var columnCount = rows[0].Split(',').Length;

string[,] multiArray = new string[rowCount, columnCount];

for (int i = 0; i < rowCount; i ++)

var values = rows[i].Split(',');
for (int j = 0; j < columnCount && j < values.Length; j++)

multiArray[i,j] = values[j];




The results I get from this are that there is a 4x6 array with only 4 values in each row.






share|improve this answer























  • Thanks will check and get back

    – user1563677
    Nov 15 '18 at 20:11











  • I had to adjust a little bit with my code but this works fine.

    – user1563677
    Nov 16 '18 at 15:08













1












1








1







The following code creates and fills your multi-dimensional array, but there is a problem with your data. Because of the extra commas your json will not look like your sample json.



string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".TrimEnd('#');

var rows = myString.Split('#');
var rowCount = rows.Length;
var columnCount = rows[0].Split(',').Length;

string[,] multiArray = new string[rowCount, columnCount];

for (int i = 0; i < rowCount; i ++)

var values = rows[i].Split(',');
for (int j = 0; j < columnCount && j < values.Length; j++)

multiArray[i,j] = values[j];




The results I get from this are that there is a 4x6 array with only 4 values in each row.






share|improve this answer













The following code creates and fills your multi-dimensional array, but there is a problem with your data. Because of the extra commas your json will not look like your sample json.



string myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".TrimEnd('#');

var rows = myString.Split('#');
var rowCount = rows.Length;
var columnCount = rows[0].Split(',').Length;

string[,] multiArray = new string[rowCount, columnCount];

for (int i = 0; i < rowCount; i ++)

var values = rows[i].Split(',');
for (int j = 0; j < columnCount && j < values.Length; j++)

multiArray[i,j] = values[j];




The results I get from this are that there is a 4x6 array with only 4 values in each row.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 15 '18 at 19:49









JamesJames

936




936












  • Thanks will check and get back

    – user1563677
    Nov 15 '18 at 20:11











  • I had to adjust a little bit with my code but this works fine.

    – user1563677
    Nov 16 '18 at 15:08

















  • Thanks will check and get back

    – user1563677
    Nov 15 '18 at 20:11











  • I had to adjust a little bit with my code but this works fine.

    – user1563677
    Nov 16 '18 at 15:08
















Thanks will check and get back

– user1563677
Nov 15 '18 at 20:11





Thanks will check and get back

– user1563677
Nov 15 '18 at 20:11













I had to adjust a little bit with my code but this works fine.

– user1563677
Nov 16 '18 at 15:08





I had to adjust a little bit with my code but this works fine.

– user1563677
Nov 16 '18 at 15:08













0














The below code does the trick for me and spits out the following json:



[

"first": 1,
"one": "a",
"two": "b",
"last": "C1"
,

"first": 2,
"one": "d",
"two": "e",
"last": "C2"
,

"first": 3,
"one": "f",
"two": "g",
"last": "C3"
,

"first": 4,
"one": "h",
"two": "i",
"last": "C4"

]


You will need to install Newtonsoft.Json via your package manager.



using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
using Newtonsoft.Json;

namespace ConsoleApp2

class Program

class WahEvah

public int first;
public string one;
public string two;
public string last;



static void Main(string args)

List<string> myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".Split('#').ToList();
List<List<string>> myString2 = myString.Select(x => x.Split(',').ToList()).ToList();
List<WahEvah> l = new List<WahEvah>();
int counter = 0;
for (int i = 0; i < myString2.Count - 1; i++)

WahEvah wd = NewMethod(myString2[i], counter);
l.Add(wd);


string json = JsonConvert.SerializeObject(l, Formatting.Indented);
Console.Write(json);
Console.ReadLine();


private static WahEvah NewMethod(List<string> myString, int counter)

counter = 0;
WahEvah w = null; w = new WahEvah();
foreach (string s2 in myString)



if (counter == 0)

w.first = Convert.ToInt32(s2.Trim()); counter++; continue;

if (counter == 1)

w.one = s2.Trim(); counter++; continue;

if (counter == 2)

w.two = s2.Trim(); counter++; continue;

if (counter == 3)

w.last = s2.Trim(); counter++; continue;





return w;










share|improve this answer























  • Thanks for the inputs but I dont have a static list so cant create a fixed model as you have created.

    – user1563677
    Nov 16 '18 at 15:09











  • It's just an example. It should work with any string that follows your pattern.

    – Ole EH Dufour
    Nov 16 '18 at 15:42















0














The below code does the trick for me and spits out the following json:



[

"first": 1,
"one": "a",
"two": "b",
"last": "C1"
,

"first": 2,
"one": "d",
"two": "e",
"last": "C2"
,

"first": 3,
"one": "f",
"two": "g",
"last": "C3"
,

"first": 4,
"one": "h",
"two": "i",
"last": "C4"

]


You will need to install Newtonsoft.Json via your package manager.



using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
using Newtonsoft.Json;

namespace ConsoleApp2

class Program

class WahEvah

public int first;
public string one;
public string two;
public string last;



static void Main(string args)

List<string> myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".Split('#').ToList();
List<List<string>> myString2 = myString.Select(x => x.Split(',').ToList()).ToList();
List<WahEvah> l = new List<WahEvah>();
int counter = 0;
for (int i = 0; i < myString2.Count - 1; i++)

WahEvah wd = NewMethod(myString2[i], counter);
l.Add(wd);


string json = JsonConvert.SerializeObject(l, Formatting.Indented);
Console.Write(json);
Console.ReadLine();


private static WahEvah NewMethod(List<string> myString, int counter)

counter = 0;
WahEvah w = null; w = new WahEvah();
foreach (string s2 in myString)



if (counter == 0)

w.first = Convert.ToInt32(s2.Trim()); counter++; continue;

if (counter == 1)

w.one = s2.Trim(); counter++; continue;

if (counter == 2)

w.two = s2.Trim(); counter++; continue;

if (counter == 3)

w.last = s2.Trim(); counter++; continue;





return w;










share|improve this answer























  • Thanks for the inputs but I dont have a static list so cant create a fixed model as you have created.

    – user1563677
    Nov 16 '18 at 15:09











  • It's just an example. It should work with any string that follows your pattern.

    – Ole EH Dufour
    Nov 16 '18 at 15:42













0












0








0







The below code does the trick for me and spits out the following json:



[

"first": 1,
"one": "a",
"two": "b",
"last": "C1"
,

"first": 2,
"one": "d",
"two": "e",
"last": "C2"
,

"first": 3,
"one": "f",
"two": "g",
"last": "C3"
,

"first": 4,
"one": "h",
"two": "i",
"last": "C4"

]


You will need to install Newtonsoft.Json via your package manager.



using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
using Newtonsoft.Json;

namespace ConsoleApp2

class Program

class WahEvah

public int first;
public string one;
public string two;
public string last;



static void Main(string args)

List<string> myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".Split('#').ToList();
List<List<string>> myString2 = myString.Select(x => x.Split(',').ToList()).ToList();
List<WahEvah> l = new List<WahEvah>();
int counter = 0;
for (int i = 0; i < myString2.Count - 1; i++)

WahEvah wd = NewMethod(myString2[i], counter);
l.Add(wd);


string json = JsonConvert.SerializeObject(l, Formatting.Indented);
Console.Write(json);
Console.ReadLine();


private static WahEvah NewMethod(List<string> myString, int counter)

counter = 0;
WahEvah w = null; w = new WahEvah();
foreach (string s2 in myString)



if (counter == 0)

w.first = Convert.ToInt32(s2.Trim()); counter++; continue;

if (counter == 1)

w.one = s2.Trim(); counter++; continue;

if (counter == 2)

w.two = s2.Trim(); counter++; continue;

if (counter == 3)

w.last = s2.Trim(); counter++; continue;





return w;










share|improve this answer













The below code does the trick for me and spits out the following json:



[

"first": 1,
"one": "a",
"two": "b",
"last": "C1"
,

"first": 2,
"one": "d",
"two": "e",
"last": "C2"
,

"first": 3,
"one": "f",
"two": "g",
"last": "C3"
,

"first": 4,
"one": "h",
"two": "i",
"last": "C4"

]


You will need to install Newtonsoft.Json via your package manager.



using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;
using Newtonsoft.Json;

namespace ConsoleApp2

class Program

class WahEvah

public int first;
public string one;
public string two;
public string last;



static void Main(string args)

List<string> myString = "1,a,b,C1,,#2,d,e,C2,,#3,f,g,C3,,#4,h,i,C4,,#".Split('#').ToList();
List<List<string>> myString2 = myString.Select(x => x.Split(',').ToList()).ToList();
List<WahEvah> l = new List<WahEvah>();
int counter = 0;
for (int i = 0; i < myString2.Count - 1; i++)

WahEvah wd = NewMethod(myString2[i], counter);
l.Add(wd);


string json = JsonConvert.SerializeObject(l, Formatting.Indented);
Console.Write(json);
Console.ReadLine();


private static WahEvah NewMethod(List<string> myString, int counter)

counter = 0;
WahEvah w = null; w = new WahEvah();
foreach (string s2 in myString)



if (counter == 0)

w.first = Convert.ToInt32(s2.Trim()); counter++; continue;

if (counter == 1)

w.one = s2.Trim(); counter++; continue;

if (counter == 2)

w.two = s2.Trim(); counter++; continue;

if (counter == 3)

w.last = s2.Trim(); counter++; continue;





return w;











share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 15 '18 at 20:16









Ole EH DufourOle EH Dufour

1,10911121




1,10911121












  • Thanks for the inputs but I dont have a static list so cant create a fixed model as you have created.

    – user1563677
    Nov 16 '18 at 15:09











  • It's just an example. It should work with any string that follows your pattern.

    – Ole EH Dufour
    Nov 16 '18 at 15:42

















  • Thanks for the inputs but I dont have a static list so cant create a fixed model as you have created.

    – user1563677
    Nov 16 '18 at 15:09











  • It's just an example. It should work with any string that follows your pattern.

    – Ole EH Dufour
    Nov 16 '18 at 15:42
















Thanks for the inputs but I dont have a static list so cant create a fixed model as you have created.

– user1563677
Nov 16 '18 at 15:09





Thanks for the inputs but I dont have a static list so cant create a fixed model as you have created.

– user1563677
Nov 16 '18 at 15:09













It's just an example. It should work with any string that follows your pattern.

– Ole EH Dufour
Nov 16 '18 at 15:42





It's just an example. It should work with any string that follows your pattern.

– Ole EH Dufour
Nov 16 '18 at 15:42

















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