jq filter objects with specific values and get Id of parent object
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
Hi I'm playing a bit with jq and have a problem.
This is my data:
"auctionInfo": [
"tradeId": 229143000306,
"itemData":
"id": 320854114832,
"rating": 82
,
"tradeId": 229143000307,
"itemData":
"id": 320854114833,
"rating": 84
,
"tradeId": 229143000308,
"itemData":
"id": 320854114834,
"rating": 84
]
What I now want are alle tradeIds where the rating is 84.
So I tried it with this filter:
| jq -r .auctionInfo.itemData | select(.rating==84)
But with this filter I'm inside the itemData and have no access to the tradeId which I'm interested for. I'm not really familiar with jq so might be a basic question but how can I reach the tradeId from where I'm standing with this filter?
json filter jq
add a comment |
Hi I'm playing a bit with jq and have a problem.
This is my data:
"auctionInfo": [
"tradeId": 229143000306,
"itemData":
"id": 320854114832,
"rating": 82
,
"tradeId": 229143000307,
"itemData":
"id": 320854114833,
"rating": 84
,
"tradeId": 229143000308,
"itemData":
"id": 320854114834,
"rating": 84
]
What I now want are alle tradeIds where the rating is 84.
So I tried it with this filter:
| jq -r .auctionInfo.itemData | select(.rating==84)
But with this filter I'm inside the itemData and have no access to the tradeId which I'm interested for. I'm not really familiar with jq so might be a basic question but how can I reach the tradeId from where I'm standing with this filter?
json filter jq
add a comment |
Hi I'm playing a bit with jq and have a problem.
This is my data:
"auctionInfo": [
"tradeId": 229143000306,
"itemData":
"id": 320854114832,
"rating": 82
,
"tradeId": 229143000307,
"itemData":
"id": 320854114833,
"rating": 84
,
"tradeId": 229143000308,
"itemData":
"id": 320854114834,
"rating": 84
]
What I now want are alle tradeIds where the rating is 84.
So I tried it with this filter:
| jq -r .auctionInfo.itemData | select(.rating==84)
But with this filter I'm inside the itemData and have no access to the tradeId which I'm interested for. I'm not really familiar with jq so might be a basic question but how can I reach the tradeId from where I'm standing with this filter?
json filter jq
Hi I'm playing a bit with jq and have a problem.
This is my data:
"auctionInfo": [
"tradeId": 229143000306,
"itemData":
"id": 320854114832,
"rating": 82
,
"tradeId": 229143000307,
"itemData":
"id": 320854114833,
"rating": 84
,
"tradeId": 229143000308,
"itemData":
"id": 320854114834,
"rating": 84
]
What I now want are alle tradeIds where the rating is 84.
So I tried it with this filter:
| jq -r .auctionInfo.itemData | select(.rating==84)
But with this filter I'm inside the itemData and have no access to the tradeId which I'm interested for. I'm not really familiar with jq so might be a basic question but how can I reach the tradeId from where I'm standing with this filter?
json filter jq
json filter jq
asked Nov 16 '18 at 11:50
KingalioneKingalione
2,16312966
2,16312966
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I think all you need to do is below. The logic is you need to list all array objects, filter on the rating value to get the subset and print the tradeId
for those objects
jq '.auctionInfo | select(.itemData.rating == 84).tradeId'
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53337311%2fjq-filter-objects-with-specific-values-and-get-id-of-parent-object%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I think all you need to do is below. The logic is you need to list all array objects, filter on the rating value to get the subset and print the tradeId
for those objects
jq '.auctionInfo | select(.itemData.rating == 84).tradeId'
add a comment |
I think all you need to do is below. The logic is you need to list all array objects, filter on the rating value to get the subset and print the tradeId
for those objects
jq '.auctionInfo | select(.itemData.rating == 84).tradeId'
add a comment |
I think all you need to do is below. The logic is you need to list all array objects, filter on the rating value to get the subset and print the tradeId
for those objects
jq '.auctionInfo | select(.itemData.rating == 84).tradeId'
I think all you need to do is below. The logic is you need to list all array objects, filter on the rating value to get the subset and print the tradeId
for those objects
jq '.auctionInfo | select(.itemData.rating == 84).tradeId'
answered Nov 16 '18 at 12:04
InianInian
41.5k64374
41.5k64374
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53337311%2fjq-filter-objects-with-specific-values-and-get-id-of-parent-object%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown