using Ajax to insert and fetch the data insert is working but fetch function is not working



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0















I'm using ajax insert and fetch the data from the database, insert is working perfectly but fetching part is not working give a feedback to fix this issues.



<script>
$(document).ready(function()
$("#button").click(function(e)
e.preventDefault();
var postId=$("#postId").val();
var userId=$("#userId").val();
var postComm=$("#postComments").val();

$.ajax(
url:'../validate/inserPostComm.php',
method:'POST',
data:
poId:postId,
usId:userId,
poco:postComm
,
success:function(data)
//alert(data);
displayFromDatabase();
$("#postComments").val('');

);
);
);

function displayFromDatabase()
var postId=$("#postId").val();
alert(postId);
$.ajax(
url: "../validate/getComments.php",
type: "POST",
async: false,
data:
poId:postId,
,
success: function(data)
('#display_area').html(data);

);

</script>


and this my html code to retrieve the fetching details from database.



<li>
<div id="display_area">

</div>
</li>
<button type="button" id="button"><i class="fa fa-paper-plane"></i></button>


and also i attached my php code through the ajax i'm passing the id and i'm get the details according to the id.



$postId=$_POST["poId"];

$getPostCom=$postComments->getPostComm($postId,"../");

while($PostComments=mysqli_fetch_assoc($getPostCom))


?>


<div class="comet-avatar">
<img src="<?php echo $PostComments["u_image"]; ?>" alt="">
</div>
<div class="we-comment">
<div class="coment-head">
<h5><a href="user-profile.php?user_id=<?php echo $PostComments["u_id"]; ?>" title=""><?php echo $PostComments["u_fname"]; ?> <?php echo $PostComments["u_lname"]; ?></a></h5>
</div>
<p><?php echo $PostComments["p_comments"]; ?></p>
</div>

<?php

exit();
?>









share|improve this question



















  • 2





    There is no element with the id button in your code. Provide a Minimal, Complete, and Verifiable example

    – Quentin
    Nov 16 '18 at 12:02






  • 1





    You missed $ in the success block

    – Akshit Ahuja
    Nov 16 '18 at 12:10











  • Did you look at the error in your developer console?

    – epascarello
    Nov 16 '18 at 14:32


















0















I'm using ajax insert and fetch the data from the database, insert is working perfectly but fetching part is not working give a feedback to fix this issues.



<script>
$(document).ready(function()
$("#button").click(function(e)
e.preventDefault();
var postId=$("#postId").val();
var userId=$("#userId").val();
var postComm=$("#postComments").val();

$.ajax(
url:'../validate/inserPostComm.php',
method:'POST',
data:
poId:postId,
usId:userId,
poco:postComm
,
success:function(data)
//alert(data);
displayFromDatabase();
$("#postComments").val('');

);
);
);

function displayFromDatabase()
var postId=$("#postId").val();
alert(postId);
$.ajax(
url: "../validate/getComments.php",
type: "POST",
async: false,
data:
poId:postId,
,
success: function(data)
('#display_area').html(data);

);

</script>


and this my html code to retrieve the fetching details from database.



<li>
<div id="display_area">

</div>
</li>
<button type="button" id="button"><i class="fa fa-paper-plane"></i></button>


and also i attached my php code through the ajax i'm passing the id and i'm get the details according to the id.



$postId=$_POST["poId"];

$getPostCom=$postComments->getPostComm($postId,"../");

while($PostComments=mysqli_fetch_assoc($getPostCom))


?>


<div class="comet-avatar">
<img src="<?php echo $PostComments["u_image"]; ?>" alt="">
</div>
<div class="we-comment">
<div class="coment-head">
<h5><a href="user-profile.php?user_id=<?php echo $PostComments["u_id"]; ?>" title=""><?php echo $PostComments["u_fname"]; ?> <?php echo $PostComments["u_lname"]; ?></a></h5>
</div>
<p><?php echo $PostComments["p_comments"]; ?></p>
</div>

<?php

exit();
?>









share|improve this question



















  • 2





    There is no element with the id button in your code. Provide a Minimal, Complete, and Verifiable example

    – Quentin
    Nov 16 '18 at 12:02






  • 1





    You missed $ in the success block

    – Akshit Ahuja
    Nov 16 '18 at 12:10











  • Did you look at the error in your developer console?

    – epascarello
    Nov 16 '18 at 14:32














0












0








0








I'm using ajax insert and fetch the data from the database, insert is working perfectly but fetching part is not working give a feedback to fix this issues.



<script>
$(document).ready(function()
$("#button").click(function(e)
e.preventDefault();
var postId=$("#postId").val();
var userId=$("#userId").val();
var postComm=$("#postComments").val();

$.ajax(
url:'../validate/inserPostComm.php',
method:'POST',
data:
poId:postId,
usId:userId,
poco:postComm
,
success:function(data)
//alert(data);
displayFromDatabase();
$("#postComments").val('');

);
);
);

function displayFromDatabase()
var postId=$("#postId").val();
alert(postId);
$.ajax(
url: "../validate/getComments.php",
type: "POST",
async: false,
data:
poId:postId,
,
success: function(data)
('#display_area').html(data);

);

</script>


and this my html code to retrieve the fetching details from database.



<li>
<div id="display_area">

</div>
</li>
<button type="button" id="button"><i class="fa fa-paper-plane"></i></button>


and also i attached my php code through the ajax i'm passing the id and i'm get the details according to the id.



$postId=$_POST["poId"];

$getPostCom=$postComments->getPostComm($postId,"../");

while($PostComments=mysqli_fetch_assoc($getPostCom))


?>


<div class="comet-avatar">
<img src="<?php echo $PostComments["u_image"]; ?>" alt="">
</div>
<div class="we-comment">
<div class="coment-head">
<h5><a href="user-profile.php?user_id=<?php echo $PostComments["u_id"]; ?>" title=""><?php echo $PostComments["u_fname"]; ?> <?php echo $PostComments["u_lname"]; ?></a></h5>
</div>
<p><?php echo $PostComments["p_comments"]; ?></p>
</div>

<?php

exit();
?>









share|improve this question
















I'm using ajax insert and fetch the data from the database, insert is working perfectly but fetching part is not working give a feedback to fix this issues.



<script>
$(document).ready(function()
$("#button").click(function(e)
e.preventDefault();
var postId=$("#postId").val();
var userId=$("#userId").val();
var postComm=$("#postComments").val();

$.ajax(
url:'../validate/inserPostComm.php',
method:'POST',
data:
poId:postId,
usId:userId,
poco:postComm
,
success:function(data)
//alert(data);
displayFromDatabase();
$("#postComments").val('');

);
);
);

function displayFromDatabase()
var postId=$("#postId").val();
alert(postId);
$.ajax(
url: "../validate/getComments.php",
type: "POST",
async: false,
data:
poId:postId,
,
success: function(data)
('#display_area').html(data);

);

</script>


and this my html code to retrieve the fetching details from database.



<li>
<div id="display_area">

</div>
</li>
<button type="button" id="button"><i class="fa fa-paper-plane"></i></button>


and also i attached my php code through the ajax i'm passing the id and i'm get the details according to the id.



$postId=$_POST["poId"];

$getPostCom=$postComments->getPostComm($postId,"../");

while($PostComments=mysqli_fetch_assoc($getPostCom))


?>


<div class="comet-avatar">
<img src="<?php echo $PostComments["u_image"]; ?>" alt="">
</div>
<div class="we-comment">
<div class="coment-head">
<h5><a href="user-profile.php?user_id=<?php echo $PostComments["u_id"]; ?>" title=""><?php echo $PostComments["u_fname"]; ?> <?php echo $PostComments["u_lname"]; ?></a></h5>
</div>
<p><?php echo $PostComments["p_comments"]; ?></p>
</div>

<?php

exit();
?>






javascript php jquery ajax






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 16 '18 at 12:04







Jerad

















asked Nov 16 '18 at 11:58









JeradJerad

829




829







  • 2





    There is no element with the id button in your code. Provide a Minimal, Complete, and Verifiable example

    – Quentin
    Nov 16 '18 at 12:02






  • 1





    You missed $ in the success block

    – Akshit Ahuja
    Nov 16 '18 at 12:10











  • Did you look at the error in your developer console?

    – epascarello
    Nov 16 '18 at 14:32













  • 2





    There is no element with the id button in your code. Provide a Minimal, Complete, and Verifiable example

    – Quentin
    Nov 16 '18 at 12:02






  • 1





    You missed $ in the success block

    – Akshit Ahuja
    Nov 16 '18 at 12:10











  • Did you look at the error in your developer console?

    – epascarello
    Nov 16 '18 at 14:32








2




2





There is no element with the id button in your code. Provide a Minimal, Complete, and Verifiable example

– Quentin
Nov 16 '18 at 12:02





There is no element with the id button in your code. Provide a Minimal, Complete, and Verifiable example

– Quentin
Nov 16 '18 at 12:02




1




1





You missed $ in the success block

– Akshit Ahuja
Nov 16 '18 at 12:10





You missed $ in the success block

– Akshit Ahuja
Nov 16 '18 at 12:10













Did you look at the error in your developer console?

– epascarello
Nov 16 '18 at 14:32






Did you look at the error in your developer console?

– epascarello
Nov 16 '18 at 14:32













1 Answer
1






active

oldest

votes


















0














Yes this code working perfectly but i missed the $ in the success block.



<script>
$(document).ready(function()
$("#button").click(function(e)
e.preventDefault();
var postId=$("#postId").val();
var userId=$("#userId").val();
var postComm=$("#postComments").val();

$.ajax(
url:'../validate/inserPostComm.php',
method:'POST',
data:
poId:postId,
usId:userId,
poco:postComm
,
success:function(data)
//alert(data);
displayFromDatabase();
$("#postComments").val('');

);
);
);

function displayFromDatabase()
var postId=$("#postId").val();
alert(postId);
$.ajax(
url: "../validate/getComments.php",
type: "POST",
async: false,
data:
poId:postId,
,
success: function(data)
$('#display_area').html(data);

);

</script>





share|improve this answer























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    oldest

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    active

    oldest

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    0














    Yes this code working perfectly but i missed the $ in the success block.



    <script>
    $(document).ready(function()
    $("#button").click(function(e)
    e.preventDefault();
    var postId=$("#postId").val();
    var userId=$("#userId").val();
    var postComm=$("#postComments").val();

    $.ajax(
    url:'../validate/inserPostComm.php',
    method:'POST',
    data:
    poId:postId,
    usId:userId,
    poco:postComm
    ,
    success:function(data)
    //alert(data);
    displayFromDatabase();
    $("#postComments").val('');

    );
    );
    );

    function displayFromDatabase()
    var postId=$("#postId").val();
    alert(postId);
    $.ajax(
    url: "../validate/getComments.php",
    type: "POST",
    async: false,
    data:
    poId:postId,
    ,
    success: function(data)
    $('#display_area').html(data);

    );

    </script>





    share|improve this answer



























      0














      Yes this code working perfectly but i missed the $ in the success block.



      <script>
      $(document).ready(function()
      $("#button").click(function(e)
      e.preventDefault();
      var postId=$("#postId").val();
      var userId=$("#userId").val();
      var postComm=$("#postComments").val();

      $.ajax(
      url:'../validate/inserPostComm.php',
      method:'POST',
      data:
      poId:postId,
      usId:userId,
      poco:postComm
      ,
      success:function(data)
      //alert(data);
      displayFromDatabase();
      $("#postComments").val('');

      );
      );
      );

      function displayFromDatabase()
      var postId=$("#postId").val();
      alert(postId);
      $.ajax(
      url: "../validate/getComments.php",
      type: "POST",
      async: false,
      data:
      poId:postId,
      ,
      success: function(data)
      $('#display_area').html(data);

      );

      </script>





      share|improve this answer

























        0












        0








        0







        Yes this code working perfectly but i missed the $ in the success block.



        <script>
        $(document).ready(function()
        $("#button").click(function(e)
        e.preventDefault();
        var postId=$("#postId").val();
        var userId=$("#userId").val();
        var postComm=$("#postComments").val();

        $.ajax(
        url:'../validate/inserPostComm.php',
        method:'POST',
        data:
        poId:postId,
        usId:userId,
        poco:postComm
        ,
        success:function(data)
        //alert(data);
        displayFromDatabase();
        $("#postComments").val('');

        );
        );
        );

        function displayFromDatabase()
        var postId=$("#postId").val();
        alert(postId);
        $.ajax(
        url: "../validate/getComments.php",
        type: "POST",
        async: false,
        data:
        poId:postId,
        ,
        success: function(data)
        $('#display_area').html(data);

        );

        </script>





        share|improve this answer













        Yes this code working perfectly but i missed the $ in the success block.



        <script>
        $(document).ready(function()
        $("#button").click(function(e)
        e.preventDefault();
        var postId=$("#postId").val();
        var userId=$("#userId").val();
        var postComm=$("#postComments").val();

        $.ajax(
        url:'../validate/inserPostComm.php',
        method:'POST',
        data:
        poId:postId,
        usId:userId,
        poco:postComm
        ,
        success:function(data)
        //alert(data);
        displayFromDatabase();
        $("#postComments").val('');

        );
        );
        );

        function displayFromDatabase()
        var postId=$("#postId").val();
        alert(postId);
        $.ajax(
        url: "../validate/getComments.php",
        type: "POST",
        async: false,
        data:
        poId:postId,
        ,
        success: function(data)
        $('#display_area').html(data);

        );

        </script>






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 18 '18 at 5:26









        JeradJerad

        829




        829





























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