Firebase query results are mistaken
up vote
1
down vote
favorite
This is my database design.
foodie-ab2b4
Foods
0
FoodName: "Baked Beans In Tomato Sauce"
FoodRecipe:
FoodUri:
Image:
1
FoodName: "Another bean
I'm working on an ios project and this is how my firebase json structured.
let ref = Database.database().reference()
func searchFoodByName(FoodName: String)
let foodsRef = ref.child("Foods")
let input = FoodName
let query = foodsRef.child(key).queryOrdered(byChild: "FoodName").queryEnding(atValue: input)
query.observeSingleEvent(of: .value, with: snapshot in
print(snapshot)
for child in snapshot.children
let snap = child as! DataSnapshot
let dict = snap.value as! [String: Any]
let fName = dict["FoodName"] as! String
let fIngredients = dict["Ingredients"] as! [String]
print(fName)
print(fIngredients)
let key = snapshot.key
print(key)
)
I'm trying to filter my food objects by their names. I have 10 objects in my database. In most cases this search return true objects. But there is one example i can not solve.
When i query the "tomato" word i need to get 1 object. But there is two. Although there is no tomato word in my second object.
The two object is in my json file.
If it is necessary i can upload my whole JSON file to here.
ios swift firebase firebase-realtime-database
add a comment |
up vote
1
down vote
favorite
This is my database design.
foodie-ab2b4
Foods
0
FoodName: "Baked Beans In Tomato Sauce"
FoodRecipe:
FoodUri:
Image:
1
FoodName: "Another bean
I'm working on an ios project and this is how my firebase json structured.
let ref = Database.database().reference()
func searchFoodByName(FoodName: String)
let foodsRef = ref.child("Foods")
let input = FoodName
let query = foodsRef.child(key).queryOrdered(byChild: "FoodName").queryEnding(atValue: input)
query.observeSingleEvent(of: .value, with: snapshot in
print(snapshot)
for child in snapshot.children
let snap = child as! DataSnapshot
let dict = snap.value as! [String: Any]
let fName = dict["FoodName"] as! String
let fIngredients = dict["Ingredients"] as! [String]
print(fName)
print(fIngredients)
let key = snapshot.key
print(key)
)
I'm trying to filter my food objects by their names. I have 10 objects in my database. In most cases this search return true objects. But there is one example i can not solve.
When i query the "tomato" word i need to get 1 object. But there is two. Although there is no tomato word in my second object.
The two object is in my json file.
If it is necessary i can upload my whole JSON file to here.
ios swift firebase firebase-realtime-database
What is the value ofkey
?
– Frank van Puffelen
Nov 10 at 17:47
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
This is my database design.
foodie-ab2b4
Foods
0
FoodName: "Baked Beans In Tomato Sauce"
FoodRecipe:
FoodUri:
Image:
1
FoodName: "Another bean
I'm working on an ios project and this is how my firebase json structured.
let ref = Database.database().reference()
func searchFoodByName(FoodName: String)
let foodsRef = ref.child("Foods")
let input = FoodName
let query = foodsRef.child(key).queryOrdered(byChild: "FoodName").queryEnding(atValue: input)
query.observeSingleEvent(of: .value, with: snapshot in
print(snapshot)
for child in snapshot.children
let snap = child as! DataSnapshot
let dict = snap.value as! [String: Any]
let fName = dict["FoodName"] as! String
let fIngredients = dict["Ingredients"] as! [String]
print(fName)
print(fIngredients)
let key = snapshot.key
print(key)
)
I'm trying to filter my food objects by their names. I have 10 objects in my database. In most cases this search return true objects. But there is one example i can not solve.
When i query the "tomato" word i need to get 1 object. But there is two. Although there is no tomato word in my second object.
The two object is in my json file.
If it is necessary i can upload my whole JSON file to here.
ios swift firebase firebase-realtime-database
This is my database design.
foodie-ab2b4
Foods
0
FoodName: "Baked Beans In Tomato Sauce"
FoodRecipe:
FoodUri:
Image:
1
FoodName: "Another bean
I'm working on an ios project and this is how my firebase json structured.
let ref = Database.database().reference()
func searchFoodByName(FoodName: String)
let foodsRef = ref.child("Foods")
let input = FoodName
let query = foodsRef.child(key).queryOrdered(byChild: "FoodName").queryEnding(atValue: input)
query.observeSingleEvent(of: .value, with: snapshot in
print(snapshot)
for child in snapshot.children
let snap = child as! DataSnapshot
let dict = snap.value as! [String: Any]
let fName = dict["FoodName"] as! String
let fIngredients = dict["Ingredients"] as! [String]
print(fName)
print(fIngredients)
let key = snapshot.key
print(key)
)
I'm trying to filter my food objects by their names. I have 10 objects in my database. In most cases this search return true objects. But there is one example i can not solve.
When i query the "tomato" word i need to get 1 object. But there is two. Although there is no tomato word in my second object.
The two object is in my json file.
If it is necessary i can upload my whole JSON file to here.
ios swift firebase firebase-realtime-database
ios swift firebase firebase-realtime-database
edited Nov 10 at 17:46
Frank van Puffelen
219k25361387
219k25361387
asked Nov 10 at 15:46
Asgencer
62
62
What is the value ofkey
?
– Frank van Puffelen
Nov 10 at 17:47
add a comment |
What is the value ofkey
?
– Frank van Puffelen
Nov 10 at 17:47
What is the value of
key
?– Frank van Puffelen
Nov 10 at 17:47
What is the value of
key
?– Frank van Puffelen
Nov 10 at 17:47
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
You seem to assume that Firebase can filter based on strings that contain a value, but it can't. See Firebase query - Find item with child that contains string (and the many links from there).
What Firebase can do is search for string values that start with a certain value. You do that by using a combination of queyStarting(atValue:)
and queryEnding(atValue:)
:
let query = foodsRef
.queryOrdered(byChild: "FoodName")
.queryStarting(atValue: input)
.queryEnding(atValue: input+"\uf8ff")
If you use this query, and input
is ``Baked`, it will only match the first food from your JSON.
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
You seem to assume that Firebase can filter based on strings that contain a value, but it can't. See Firebase query - Find item with child that contains string (and the many links from there).
What Firebase can do is search for string values that start with a certain value. You do that by using a combination of queyStarting(atValue:)
and queryEnding(atValue:)
:
let query = foodsRef
.queryOrdered(byChild: "FoodName")
.queryStarting(atValue: input)
.queryEnding(atValue: input+"\uf8ff")
If you use this query, and input
is ``Baked`, it will only match the first food from your JSON.
add a comment |
up vote
0
down vote
You seem to assume that Firebase can filter based on strings that contain a value, but it can't. See Firebase query - Find item with child that contains string (and the many links from there).
What Firebase can do is search for string values that start with a certain value. You do that by using a combination of queyStarting(atValue:)
and queryEnding(atValue:)
:
let query = foodsRef
.queryOrdered(byChild: "FoodName")
.queryStarting(atValue: input)
.queryEnding(atValue: input+"\uf8ff")
If you use this query, and input
is ``Baked`, it will only match the first food from your JSON.
add a comment |
up vote
0
down vote
up vote
0
down vote
You seem to assume that Firebase can filter based on strings that contain a value, but it can't. See Firebase query - Find item with child that contains string (and the many links from there).
What Firebase can do is search for string values that start with a certain value. You do that by using a combination of queyStarting(atValue:)
and queryEnding(atValue:)
:
let query = foodsRef
.queryOrdered(byChild: "FoodName")
.queryStarting(atValue: input)
.queryEnding(atValue: input+"\uf8ff")
If you use this query, and input
is ``Baked`, it will only match the first food from your JSON.
You seem to assume that Firebase can filter based on strings that contain a value, but it can't. See Firebase query - Find item with child that contains string (and the many links from there).
What Firebase can do is search for string values that start with a certain value. You do that by using a combination of queyStarting(atValue:)
and queryEnding(atValue:)
:
let query = foodsRef
.queryOrdered(byChild: "FoodName")
.queryStarting(atValue: input)
.queryEnding(atValue: input+"\uf8ff")
If you use this query, and input
is ``Baked`, it will only match the first food from your JSON.
answered Nov 10 at 17:54
Frank van Puffelen
219k25361387
219k25361387
add a comment |
add a comment |
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What is the value of
key
?– Frank van Puffelen
Nov 10 at 17:47