how to detect logical and string index in sub-list and delete it

up vote
1
down vote

favorite

I have a list like this:

A = [[1,2,3,4],[1,1,2,4],[1,2,3,False],[1,False,2,3],[1,2,3,4],[1,2,3,'word'],[5,6,7,8],[1,4,3,4],[True,1,2,4],[0,1,0,1],[0,0,0,0],[False,False,False,False]]

and I want as output a list like this:

A = [[1,2,3,4],[1,1,2,4],[1,2,3,4],[5,6,7,8],[1,4,3,4],[0,1,0,1],[0,0,0,0]]

I just want to delete or remove a any list. it have member of string or logical.
how i can do it.

edited Nov 10 at 18:20

Daniel Mesejo

7,9741922

asked Nov 10 at 18:12

lyca

112

So you want to remove any lists that have False in them?
– Ayxan
Nov 10 at 18:16

yeap, I want to remove any type is not int or float from list.
– lyca
Nov 10 at 18:18

add a comment |

up vote
1
down vote

favorite

I have a list like this:

A = [[1,2,3,4],[1,1,2,4],[1,2,3,False],[1,False,2,3],[1,2,3,4],[1,2,3,'word'],[5,6,7,8],[1,4,3,4],[True,1,2,4],[0,1,0,1],[0,0,0,0],[False,False,False,False]]

and I want as output a list like this:

A = [[1,2,3,4],[1,1,2,4],[1,2,3,4],[5,6,7,8],[1,4,3,4],[0,1,0,1],[0,0,0,0]]

I just want to delete or remove a any list. it have member of string or logical.
how i can do it.

edited Nov 10 at 18:20

Daniel Mesejo

7,9741922

asked Nov 10 at 18:12

lyca

112

So you want to remove any lists that have False in them?
– Ayxan
Nov 10 at 18:16

yeap, I want to remove any type is not int or float from list.
– lyca
Nov 10 at 18:18

add a comment |

up vote
1
down vote

favorite

I have a list like this:

A = [[1,2,3,4],[1,1,2,4],[1,2,3,False],[1,False,2,3],[1,2,3,4],[1,2,3,'word'],[5,6,7,8],[1,4,3,4],[True,1,2,4],[0,1,0,1],[0,0,0,0],[False,False,False,False]]

and I want as output a list like this:

A = [[1,2,3,4],[1,1,2,4],[1,2,3,4],[5,6,7,8],[1,4,3,4],[0,1,0,1],[0,0,0,0]]

I just want to delete or remove a any list. it have member of string or logical.
how i can do it.

edited Nov 10 at 18:20

Daniel Mesejo

7,9741922

asked Nov 10 at 18:12

lyca

112

I have a list like this:

A = [[1,2,3,4],[1,1,2,4],[1,2,3,False],[1,False,2,3],[1,2,3,4],[1,2,3,'word'],[5,6,7,8],[1,4,3,4],[True,1,2,4],[0,1,0,1],[0,0,0,0],[False,False,False,False]]

and I want as output a list like this:

A = [[1,2,3,4],[1,1,2,4],[1,2,3,4],[5,6,7,8],[1,4,3,4],[0,1,0,1],[0,0,0,0]]

I just want to delete or remove a any list. it have member of string or logical.
how i can do it.

python python-3.x algorithm list types

edited Nov 10 at 18:20

Daniel Mesejo

7,9741922

asked Nov 10 at 18:12

lyca

112

edited Nov 10 at 18:20

Daniel Mesejo

7,9741922

asked Nov 10 at 18:12

lyca

112

edited Nov 10 at 18:20

Daniel Mesejo

7,9741922

edited Nov 10 at 18:20

Daniel Mesejo

7,9741922

edited Nov 10 at 18:20

Daniel Mesejo

7,9741922

asked Nov 10 at 18:12

lyca

112

asked Nov 10 at 18:12

lyca

112

asked Nov 10 at 18:12

lyca

112

So you want to remove any lists that have False in them?
– Ayxan
Nov 10 at 18:16

yeap, I want to remove any type is not int or float from list.
– lyca
Nov 10 at 18:18

add a comment |

So you want to remove any lists that have False in them?
– Ayxan
Nov 10 at 18:16

yeap, I want to remove any type is not int or float from list.
– lyca
Nov 10 at 18:18

So you want to remove any lists that have False in them?
– Ayxan
Nov 10 at 18:16

yeap, I want to remove any type is not int or float from list.
– lyca
Nov 10 at 18:18

add a comment |

1 Answer
1

active

oldest

votes

up vote
5
down vote

We can do this with list comprehension where we perform a filter with any(..) that checks if there is any element that is an instance of str or bool:

[sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]

this then yields:

>>> [sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]
[[1, 2, 3, 4], [1, 1, 2, 4], [1, 2, 3, 4], [5, 6, 7, 8], [1, 4, 3, 4], [0, 1, 0, 1], [0, 0, 0, 0]]

answered Nov 10 at 18:16

Willem Van Onsem

140k16131222

what is meaning of e ?
– lyca
Nov 10 at 18:21

@lyca: the element in the generator, it enumerates over sublist with ... for e in sublist.
– Willem Van Onsem
Nov 10 at 18:22

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
5
down vote

We can do this with list comprehension where we perform a filter with any(..) that checks if there is any element that is an instance of str or bool:

[sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]

this then yields:

>>> [sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]
[[1, 2, 3, 4], [1, 1, 2, 4], [1, 2, 3, 4], [5, 6, 7, 8], [1, 4, 3, 4], [0, 1, 0, 1], [0, 0, 0, 0]]

answered Nov 10 at 18:16

Willem Van Onsem

140k16131222

what is meaning of e ?
– lyca
Nov 10 at 18:21

@lyca: the element in the generator, it enumerates over sublist with ... for e in sublist.
– Willem Van Onsem
Nov 10 at 18:22

add a comment |

up vote
5
down vote

We can do this with list comprehension where we perform a filter with any(..) that checks if there is any element that is an instance of str or bool:

[sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]

this then yields:

>>> [sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]
[[1, 2, 3, 4], [1, 1, 2, 4], [1, 2, 3, 4], [5, 6, 7, 8], [1, 4, 3, 4], [0, 1, 0, 1], [0, 0, 0, 0]]

answered Nov 10 at 18:16

Willem Van Onsem

140k16131222

what is meaning of e ?
– lyca
Nov 10 at 18:21

@lyca: the element in the generator, it enumerates over sublist with ... for e in sublist.
– Willem Van Onsem
Nov 10 at 18:22

add a comment |

up vote
5
down vote

We can do this with list comprehension where we perform a filter with any(..) that checks if there is any element that is an instance of str or bool:

[sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]

this then yields:

>>> [sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]
[[1, 2, 3, 4], [1, 1, 2, 4], [1, 2, 3, 4], [5, 6, 7, 8], [1, 4, 3, 4], [0, 1, 0, 1], [0, 0, 0, 0]]

answered Nov 10 at 18:16

Willem Van Onsem

140k16131222

We can do this with list comprehension where we perform a filter with any(..) that checks if there is any element that is an instance of str or bool:

[sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]

this then yields:

>>> [sublist for sublist in A if not any(isinstance(e, (str, bool)) for e in sublist)]
[[1, 2, 3, 4], [1, 1, 2, 4], [1, 2, 3, 4], [5, 6, 7, 8], [1, 4, 3, 4], [0, 1, 0, 1], [0, 0, 0, 0]]

answered Nov 10 at 18:16

Willem Van Onsem

140k16131222

answered Nov 10 at 18:16

Willem Van Onsem

140k16131222

answered Nov 10 at 18:16

Willem Van Onsem

140k16131222

answered Nov 10 at 18:16

Willem Van Onsem

140k16131222

what is meaning of e ?
– lyca
Nov 10 at 18:21

@lyca: the element in the generator, it enumerates over sublist with ... for e in sublist.
– Willem Van Onsem
Nov 10 at 18:22

add a comment |

what is meaning of e ?
– lyca
Nov 10 at 18:21

@lyca: the element in the generator, it enumerates over sublist with ... for e in sublist.
– Willem Van Onsem
Nov 10 at 18:22

what is meaning of e ?
– lyca
Nov 10 at 18:21

@lyca: the element in the generator, it enumerates over sublist with ... for e in sublist.
– Willem Van Onsem
Nov 10 at 18:22

add a comment |

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