How to union to immutable.js list of objects (with id prop)









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I want to replace / add new values in an immutable list like:



const old = [
id: 1, value: 'foo' ,
id: 3, value: 'bar' ,
id: 2, value: 'baz' ,
]

const new = [
id: 1, value: 'quux' , // update
id: 4, value: 'asd' , // push

]

union == [
id: 1, value: 'quux' , // updated
id: 3, value: 'bar' ,
id: 2, value: 'baz' ,
id: 4, value: 'asd' , // new
]


I can use any data type if lists don't have this functionality but something has



If this isn't built in immutable.js just say that, i already wrote a script for this, i'm just missing the built in method










share|improve this question

























    up vote
    0
    down vote

    favorite












    I want to replace / add new values in an immutable list like:



    const old = [
    id: 1, value: 'foo' ,
    id: 3, value: 'bar' ,
    id: 2, value: 'baz' ,
    ]

    const new = [
    id: 1, value: 'quux' , // update
    id: 4, value: 'asd' , // push

    ]

    union == [
    id: 1, value: 'quux' , // updated
    id: 3, value: 'bar' ,
    id: 2, value: 'baz' ,
    id: 4, value: 'asd' , // new
    ]


    I can use any data type if lists don't have this functionality but something has



    If this isn't built in immutable.js just say that, i already wrote a script for this, i'm just missing the built in method










    share|improve this question























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I want to replace / add new values in an immutable list like:



      const old = [
      id: 1, value: 'foo' ,
      id: 3, value: 'bar' ,
      id: 2, value: 'baz' ,
      ]

      const new = [
      id: 1, value: 'quux' , // update
      id: 4, value: 'asd' , // push

      ]

      union == [
      id: 1, value: 'quux' , // updated
      id: 3, value: 'bar' ,
      id: 2, value: 'baz' ,
      id: 4, value: 'asd' , // new
      ]


      I can use any data type if lists don't have this functionality but something has



      If this isn't built in immutable.js just say that, i already wrote a script for this, i'm just missing the built in method










      share|improve this question













      I want to replace / add new values in an immutable list like:



      const old = [
      id: 1, value: 'foo' ,
      id: 3, value: 'bar' ,
      id: 2, value: 'baz' ,
      ]

      const new = [
      id: 1, value: 'quux' , // update
      id: 4, value: 'asd' , // push

      ]

      union == [
      id: 1, value: 'quux' , // updated
      id: 3, value: 'bar' ,
      id: 2, value: 'baz' ,
      id: 4, value: 'asd' , // new
      ]


      I can use any data type if lists don't have this functionality but something has



      If this isn't built in immutable.js just say that, i already wrote a script for this, i'm just missing the built in method







      javascript immutable.js






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 10 at 13:14









      tomitheninja

      63




      63






















          1 Answer
          1






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          up vote
          0
          down vote













          Algorithms for union



          First you have to maintain two map with key as id and value as object then check for length of array which is of bigger size and pass the bigger size array with small size map to merged function there you can iterate over the array and check if it's exists in the map if yes then update the object and delete that row from map otherwise add the object into output. After the for loop complete check if map has element present then push all the values from map into output array and return;



          index.js



          const old = [
          id: 1, value: 'foo' ,
          id: 3, value: 'bar' ,
          id: 2, value: 'baz' ,
          ];

          const newa = [
          id: 1, value: 'quux' , // update
          id: 4, value: 'asd' , // push

          ];

          function merged(input,filterMap)
          var output = ;
          input.forEach(function(eachRow)
          if(filterMap.hasOwnProperty(eachRow.id))
          output.push(Object.assign(eachRow,filterMap[eachRow.id]));
          delete filterMap[eachRow.id];
          else
          output.push(eachRow);

          );

          if(Object.keys(filterMap).length > 0)
          output = output.concat(Object.values(filterMap));

          return output;


          function parseData(first,second)
          var mapFirst = ,
          mapSecond = ;
          var output = ;
          first.forEach(function(eachRow)
          mapFirst[eachRow.id] = eachRow;
          );

          second.forEach(function(eachRow)
          mapSecond[eachRow.id] = eachRow;
          );

          if(first.length > second.length)
          return merged(first,mapSecond);
          else
          return merged(second,mapFirst);



          console.log(parseData(old,newa));


          Working jsFiddle demo - https://jsfiddle.net/qz25hnmf/






          share|improve this answer




















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            1 Answer
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            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            0
            down vote













            Algorithms for union



            First you have to maintain two map with key as id and value as object then check for length of array which is of bigger size and pass the bigger size array with small size map to merged function there you can iterate over the array and check if it's exists in the map if yes then update the object and delete that row from map otherwise add the object into output. After the for loop complete check if map has element present then push all the values from map into output array and return;



            index.js



            const old = [
            id: 1, value: 'foo' ,
            id: 3, value: 'bar' ,
            id: 2, value: 'baz' ,
            ];

            const newa = [
            id: 1, value: 'quux' , // update
            id: 4, value: 'asd' , // push

            ];

            function merged(input,filterMap)
            var output = ;
            input.forEach(function(eachRow)
            if(filterMap.hasOwnProperty(eachRow.id))
            output.push(Object.assign(eachRow,filterMap[eachRow.id]));
            delete filterMap[eachRow.id];
            else
            output.push(eachRow);

            );

            if(Object.keys(filterMap).length > 0)
            output = output.concat(Object.values(filterMap));

            return output;


            function parseData(first,second)
            var mapFirst = ,
            mapSecond = ;
            var output = ;
            first.forEach(function(eachRow)
            mapFirst[eachRow.id] = eachRow;
            );

            second.forEach(function(eachRow)
            mapSecond[eachRow.id] = eachRow;
            );

            if(first.length > second.length)
            return merged(first,mapSecond);
            else
            return merged(second,mapFirst);



            console.log(parseData(old,newa));


            Working jsFiddle demo - https://jsfiddle.net/qz25hnmf/






            share|improve this answer
























              up vote
              0
              down vote













              Algorithms for union



              First you have to maintain two map with key as id and value as object then check for length of array which is of bigger size and pass the bigger size array with small size map to merged function there you can iterate over the array and check if it's exists in the map if yes then update the object and delete that row from map otherwise add the object into output. After the for loop complete check if map has element present then push all the values from map into output array and return;



              index.js



              const old = [
              id: 1, value: 'foo' ,
              id: 3, value: 'bar' ,
              id: 2, value: 'baz' ,
              ];

              const newa = [
              id: 1, value: 'quux' , // update
              id: 4, value: 'asd' , // push

              ];

              function merged(input,filterMap)
              var output = ;
              input.forEach(function(eachRow)
              if(filterMap.hasOwnProperty(eachRow.id))
              output.push(Object.assign(eachRow,filterMap[eachRow.id]));
              delete filterMap[eachRow.id];
              else
              output.push(eachRow);

              );

              if(Object.keys(filterMap).length > 0)
              output = output.concat(Object.values(filterMap));

              return output;


              function parseData(first,second)
              var mapFirst = ,
              mapSecond = ;
              var output = ;
              first.forEach(function(eachRow)
              mapFirst[eachRow.id] = eachRow;
              );

              second.forEach(function(eachRow)
              mapSecond[eachRow.id] = eachRow;
              );

              if(first.length > second.length)
              return merged(first,mapSecond);
              else
              return merged(second,mapFirst);



              console.log(parseData(old,newa));


              Working jsFiddle demo - https://jsfiddle.net/qz25hnmf/






              share|improve this answer






















                up vote
                0
                down vote










                up vote
                0
                down vote









                Algorithms for union



                First you have to maintain two map with key as id and value as object then check for length of array which is of bigger size and pass the bigger size array with small size map to merged function there you can iterate over the array and check if it's exists in the map if yes then update the object and delete that row from map otherwise add the object into output. After the for loop complete check if map has element present then push all the values from map into output array and return;



                index.js



                const old = [
                id: 1, value: 'foo' ,
                id: 3, value: 'bar' ,
                id: 2, value: 'baz' ,
                ];

                const newa = [
                id: 1, value: 'quux' , // update
                id: 4, value: 'asd' , // push

                ];

                function merged(input,filterMap)
                var output = ;
                input.forEach(function(eachRow)
                if(filterMap.hasOwnProperty(eachRow.id))
                output.push(Object.assign(eachRow,filterMap[eachRow.id]));
                delete filterMap[eachRow.id];
                else
                output.push(eachRow);

                );

                if(Object.keys(filterMap).length > 0)
                output = output.concat(Object.values(filterMap));

                return output;


                function parseData(first,second)
                var mapFirst = ,
                mapSecond = ;
                var output = ;
                first.forEach(function(eachRow)
                mapFirst[eachRow.id] = eachRow;
                );

                second.forEach(function(eachRow)
                mapSecond[eachRow.id] = eachRow;
                );

                if(first.length > second.length)
                return merged(first,mapSecond);
                else
                return merged(second,mapFirst);



                console.log(parseData(old,newa));


                Working jsFiddle demo - https://jsfiddle.net/qz25hnmf/






                share|improve this answer












                Algorithms for union



                First you have to maintain two map with key as id and value as object then check for length of array which is of bigger size and pass the bigger size array with small size map to merged function there you can iterate over the array and check if it's exists in the map if yes then update the object and delete that row from map otherwise add the object into output. After the for loop complete check if map has element present then push all the values from map into output array and return;



                index.js



                const old = [
                id: 1, value: 'foo' ,
                id: 3, value: 'bar' ,
                id: 2, value: 'baz' ,
                ];

                const newa = [
                id: 1, value: 'quux' , // update
                id: 4, value: 'asd' , // push

                ];

                function merged(input,filterMap)
                var output = ;
                input.forEach(function(eachRow)
                if(filterMap.hasOwnProperty(eachRow.id))
                output.push(Object.assign(eachRow,filterMap[eachRow.id]));
                delete filterMap[eachRow.id];
                else
                output.push(eachRow);

                );

                if(Object.keys(filterMap).length > 0)
                output = output.concat(Object.values(filterMap));

                return output;


                function parseData(first,second)
                var mapFirst = ,
                mapSecond = ;
                var output = ;
                first.forEach(function(eachRow)
                mapFirst[eachRow.id] = eachRow;
                );

                second.forEach(function(eachRow)
                mapSecond[eachRow.id] = eachRow;
                );

                if(first.length > second.length)
                return merged(first,mapSecond);
                else
                return merged(second,mapFirst);



                console.log(parseData(old,newa));


                Working jsFiddle demo - https://jsfiddle.net/qz25hnmf/







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 10 at 14:06









                front_end_dev

                1,310411




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