Canot interfer type: TreeSet with lambda Comparator









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I have tried a few things and i don't understand why it is not working.



I'm creating a SortedSet and like to use a TreeSet as the implementation with an lambda expression comparator:



SortedSet<int> all = new TreeSet<>(
(int a, int b) -> return (a[0] == b[0]) ? a[1] >= b[1] : a[0] >= b[0];
);


SortedSet<int> all = new TreeSet<>(
(a, b) -> (a[0] == b[0]) ? a[1] >= b[1] : a[0] >= b[0]
);


Whatever version i tried, it just doesn't work and i don't understand why it doesn't.



If a int is allowed, it should be able to understand what the type is, right?










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  • 2




    A Comparator's compare method is supposed to return an integer. Your lambda returns a boolean.
    – JB Nizet
    Nov 11 at 12:24











  • Tx! Looked at it way too long already :-)
    – sigi
    Nov 11 at 12:30














up vote
0
down vote

favorite












I have tried a few things and i don't understand why it is not working.



I'm creating a SortedSet and like to use a TreeSet as the implementation with an lambda expression comparator:



SortedSet<int> all = new TreeSet<>(
(int a, int b) -> return (a[0] == b[0]) ? a[1] >= b[1] : a[0] >= b[0];
);


SortedSet<int> all = new TreeSet<>(
(a, b) -> (a[0] == b[0]) ? a[1] >= b[1] : a[0] >= b[0]
);


Whatever version i tried, it just doesn't work and i don't understand why it doesn't.



If a int is allowed, it should be able to understand what the type is, right?










share|improve this question

















  • 2




    A Comparator's compare method is supposed to return an integer. Your lambda returns a boolean.
    – JB Nizet
    Nov 11 at 12:24











  • Tx! Looked at it way too long already :-)
    – sigi
    Nov 11 at 12:30












up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have tried a few things and i don't understand why it is not working.



I'm creating a SortedSet and like to use a TreeSet as the implementation with an lambda expression comparator:



SortedSet<int> all = new TreeSet<>(
(int a, int b) -> return (a[0] == b[0]) ? a[1] >= b[1] : a[0] >= b[0];
);


SortedSet<int> all = new TreeSet<>(
(a, b) -> (a[0] == b[0]) ? a[1] >= b[1] : a[0] >= b[0]
);


Whatever version i tried, it just doesn't work and i don't understand why it doesn't.



If a int is allowed, it should be able to understand what the type is, right?










share|improve this question













I have tried a few things and i don't understand why it is not working.



I'm creating a SortedSet and like to use a TreeSet as the implementation with an lambda expression comparator:



SortedSet<int> all = new TreeSet<>(
(int a, int b) -> return (a[0] == b[0]) ? a[1] >= b[1] : a[0] >= b[0];
);


SortedSet<int> all = new TreeSet<>(
(a, b) -> (a[0] == b[0]) ? a[1] >= b[1] : a[0] >= b[0]
);


Whatever version i tried, it just doesn't work and i don't understand why it doesn't.



If a int is allowed, it should be able to understand what the type is, right?







java arrays int






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 11 at 12:22









sigi

8910




8910







  • 2




    A Comparator's compare method is supposed to return an integer. Your lambda returns a boolean.
    – JB Nizet
    Nov 11 at 12:24











  • Tx! Looked at it way too long already :-)
    – sigi
    Nov 11 at 12:30












  • 2




    A Comparator's compare method is supposed to return an integer. Your lambda returns a boolean.
    – JB Nizet
    Nov 11 at 12:24











  • Tx! Looked at it way too long already :-)
    – sigi
    Nov 11 at 12:30







2




2




A Comparator's compare method is supposed to return an integer. Your lambda returns a boolean.
– JB Nizet
Nov 11 at 12:24





A Comparator's compare method is supposed to return an integer. Your lambda returns a boolean.
– JB Nizet
Nov 11 at 12:24













Tx! Looked at it way too long already :-)
– sigi
Nov 11 at 12:30




Tx! Looked at it way too long already :-)
– sigi
Nov 11 at 12:30

















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