Fold expression: iterate over variadic template type parameter to check compile-time conditions on the comprising types









up vote
-2
down vote

favorite












What I want to do is simple: in a variadic class template, I want to check some compile-time condition on the types. In this case, I want to find out if a certain type is in the pack or not. This is what the code might have looked like with C++17's fold expressions, but obviously that's not valid syntax. How to implement it?



#include <type_traits>

template <class... Types>
struct TypesPack

template <typename T>
static constexpr bool hasType()
;









share|improve this question



















  • 1




    Since you're using C++17, you can take advantage of the convenient _v additions to traits: std::is_same_v<T, U> == std::is_same<T, U>::value.
    – chris
    Nov 11 at 23:01














up vote
-2
down vote

favorite












What I want to do is simple: in a variadic class template, I want to check some compile-time condition on the types. In this case, I want to find out if a certain type is in the pack or not. This is what the code might have looked like with C++17's fold expressions, but obviously that's not valid syntax. How to implement it?



#include <type_traits>

template <class... Types>
struct TypesPack

template <typename T>
static constexpr bool hasType()
;









share|improve this question



















  • 1




    Since you're using C++17, you can take advantage of the convenient _v additions to traits: std::is_same_v<T, U> == std::is_same<T, U>::value.
    – chris
    Nov 11 at 23:01












up vote
-2
down vote

favorite









up vote
-2
down vote

favorite











What I want to do is simple: in a variadic class template, I want to check some compile-time condition on the types. In this case, I want to find out if a certain type is in the pack or not. This is what the code might have looked like with C++17's fold expressions, but obviously that's not valid syntax. How to implement it?



#include <type_traits>

template <class... Types>
struct TypesPack

template <typename T>
static constexpr bool hasType()
;









share|improve this question















What I want to do is simple: in a variadic class template, I want to check some compile-time condition on the types. In this case, I want to find out if a certain type is in the pack or not. This is what the code might have looked like with C++17's fold expressions, but obviously that's not valid syntax. How to implement it?



#include <type_traits>

template <class... Types>
struct TypesPack

template <typename T>
static constexpr bool hasType()
;






c++ templates c++17






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 12 at 16:06

























asked Nov 11 at 22:50









Violet Giraffe

14.3k26130240




14.3k26130240







  • 1




    Since you're using C++17, you can take advantage of the convenient _v additions to traits: std::is_same_v<T, U> == std::is_same<T, U>::value.
    – chris
    Nov 11 at 23:01












  • 1




    Since you're using C++17, you can take advantage of the convenient _v additions to traits: std::is_same_v<T, U> == std::is_same<T, U>::value.
    – chris
    Nov 11 at 23:01







1




1




Since you're using C++17, you can take advantage of the convenient _v additions to traits: std::is_same_v<T, U> == std::is_same<T, U>::value.
– chris
Nov 11 at 23:01




Since you're using C++17, you can take advantage of the convenient _v additions to traits: std::is_same_v<T, U> == std::is_same<T, U>::value.
– chris
Nov 11 at 23:01












1 Answer
1






active

oldest

votes

















up vote
5
down vote



accepted










static constexpr bool hasType() 


A fold-expression must be parenthesized, and you're allowed to omit the false when using || as the operator.






share|improve this answer




















  • Will it also work if there's only one type in the pack?
    – Violet Giraffe
    Nov 12 at 5:45










  • @VioletGiraffe Yes, it will even work if there are zero.
    – Brian
    Nov 12 at 5:59










Your Answer






StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);













draft saved

draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53254029%2ffold-expression-iterate-over-variadic-template-type-parameter-to-check-compile%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
5
down vote



accepted










static constexpr bool hasType() 


A fold-expression must be parenthesized, and you're allowed to omit the false when using || as the operator.






share|improve this answer




















  • Will it also work if there's only one type in the pack?
    – Violet Giraffe
    Nov 12 at 5:45










  • @VioletGiraffe Yes, it will even work if there are zero.
    – Brian
    Nov 12 at 5:59














up vote
5
down vote



accepted










static constexpr bool hasType() 


A fold-expression must be parenthesized, and you're allowed to omit the false when using || as the operator.






share|improve this answer




















  • Will it also work if there's only one type in the pack?
    – Violet Giraffe
    Nov 12 at 5:45










  • @VioletGiraffe Yes, it will even work if there are zero.
    – Brian
    Nov 12 at 5:59












up vote
5
down vote



accepted







up vote
5
down vote



accepted






static constexpr bool hasType() 


A fold-expression must be parenthesized, and you're allowed to omit the false when using || as the operator.






share|improve this answer












static constexpr bool hasType() 


A fold-expression must be parenthesized, and you're allowed to omit the false when using || as the operator.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 11 at 22:52









Brian

63.7k794179




63.7k794179











  • Will it also work if there's only one type in the pack?
    – Violet Giraffe
    Nov 12 at 5:45










  • @VioletGiraffe Yes, it will even work if there are zero.
    – Brian
    Nov 12 at 5:59
















  • Will it also work if there's only one type in the pack?
    – Violet Giraffe
    Nov 12 at 5:45










  • @VioletGiraffe Yes, it will even work if there are zero.
    – Brian
    Nov 12 at 5:59















Will it also work if there's only one type in the pack?
– Violet Giraffe
Nov 12 at 5:45




Will it also work if there's only one type in the pack?
– Violet Giraffe
Nov 12 at 5:45












@VioletGiraffe Yes, it will even work if there are zero.
– Brian
Nov 12 at 5:59




@VioletGiraffe Yes, it will even work if there are zero.
– Brian
Nov 12 at 5:59

















draft saved

draft discarded
















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid


  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.





Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


Please pay close attention to the following guidance:


  • Please be sure to answer the question. Provide details and share your research!

But avoid


  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53254029%2ffold-expression-iterate-over-variadic-template-type-parameter-to-check-compile%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Top Tejano songwriter Luis Silva dead of heart attack at 64

政党

天津地下鉄3号線