Logic Level Conventer for UART 5V / 3.3V with high transmission speed (115200)
I need to connect ESP32 (3.3 V) and Arduino UNO (5 V) on the UART bus. I used to connect two devices through a 1k resistor and it worked. I want to make a reliable connection.
On the Internet, I found a matching circuit for UART levels based on a BSS138 transistor.
Will this scheme work reliably at a transfer rate of 115200 BOD? If it were not, would you advise me a more reliable option?
arduino
edited 14 hours ago
Harry Svensson
6,40032346
asked 15 hours ago
ÃÂûõúѠÓðрøÑÂþý
225
add a comment |Â
I need to connect ESP32 (3.3 V) and Arduino UNO (5 V) on the UART bus. I used to connect two devices through a 1k resistor and it worked. I want to make a reliable connection.
On the Internet, I found a matching circuit for UART levels based on a BSS138 transistor.
Will this scheme work reliably at a transfer rate of 115200 BOD? If it were not, would you advise me a more reliable option?
arduino
edited 14 hours ago
Harry Svensson
6,40032346
asked 15 hours ago
ÃÂûõúѠÓðрøÑÂþý
225
1
115.2 kBaud is not really high speed. Here someone simulated the same circuit and found that it works comfortably even at 2 MHz: electronics.stackexchange.com/a/367055/31091 The link also contains a detailed explanation of the circuit and its frequency-limiting factors.
– Geier
13 hours ago
2
One resistor is not really a proper solution except when you have a current rating for the protection diodes. But two resistors forming a voltage divider can be a fine solution - more definitive than your proposal except for things that need to run for a long time on battery. But a 5v Arduino wouldn't be suitable for that to begin with.
– Chris Stratton
13 hours ago
add a comment |Â
I need to connect ESP32 (3.3 V) and Arduino UNO (5 V) on the UART bus. I used to connect two devices through a 1k resistor and it worked. I want to make a reliable connection.
On the Internet, I found a matching circuit for UART levels based on a BSS138 transistor.
Will this scheme work reliably at a transfer rate of 115200 BOD? If it were not, would you advise me a more reliable option?
arduino
edited 14 hours ago
Harry Svensson
6,40032346
asked 15 hours ago
ÃÂûõúѠÓðрøÑÂþý
225
I need to connect ESP32 (3.3 V) and Arduino UNO (5 V) on the UART bus. I used to connect two devices through a 1k resistor and it worked. I want to make a reliable connection.
On the Internet, I found a matching circuit for UART levels based on a BSS138 transistor.
Will this scheme work reliably at a transfer rate of 115200 BOD? If it were not, would you advise me a more reliable option?
arduino
arduino
edited 14 hours ago
Harry Svensson
6,40032346
asked 15 hours ago
ÃÂûõúѠÓðрøÑÂþý
225
edited 14 hours ago
Harry Svensson
6,40032346
asked 15 hours ago
ÃÂûõúѠÓðрøÑÂþý
225
edited 14 hours ago
Harry Svensson
6,40032346
edited 14 hours ago
Harry Svensson
6,40032346
edited 14 hours ago
Harry Svensson
6,40032346
6,40032346
asked 15 hours ago
ÃÂûõúѠÓðрøÑÂþý
225
asked 15 hours ago
ÃÂûõúѠÓðрøÑÂþý
225
asked 15 hours ago
ÃÂûõúѠÓðрøÑÂþý
225
225
1
115.2 kBaud is not really high speed. Here someone simulated the same circuit and found that it works comfortably even at 2 MHz: electronics.stackexchange.com/a/367055/31091 The link also contains a detailed explanation of the circuit and its frequency-limiting factors.
– Geier
13 hours ago
2
One resistor is not really a proper solution except when you have a current rating for the protection diodes. But two resistors forming a voltage divider can be a fine solution - more definitive than your proposal except for things that need to run for a long time on battery. But a 5v Arduino wouldn't be suitable for that to begin with.
– Chris Stratton
13 hours ago
add a comment |Â
1
115.2 kBaud is not really high speed. Here someone simulated the same circuit and found that it works comfortably even at 2 MHz: electronics.stackexchange.com/a/367055/31091 The link also contains a detailed explanation of the circuit and its frequency-limiting factors.
– Geier
13 hours ago
2
One resistor is not really a proper solution except when you have a current rating for the protection diodes. But two resistors forming a voltage divider can be a fine solution - more definitive than your proposal except for things that need to run for a long time on battery. But a 5v Arduino wouldn't be suitable for that to begin with.
– Chris Stratton
13 hours ago
1
1
115.2 kBaud is not really high speed. Here someone simulated the same circuit and found that it works comfortably even at 2 MHz: electronics.stackexchange.com/a/367055/31091 The link also contains a detailed explanation of the circuit and its frequency-limiting factors.
– Geier
13 hours ago
115.2 kBaud is not really high speed. Here someone simulated the same circuit and found that it works comfortably even at 2 MHz: electronics.stackexchange.com/a/367055/31091 The link also contains a detailed explanation of the circuit and its frequency-limiting factors.
– Geier
13 hours ago
2
2
One resistor is not really a proper solution except when you have a current rating for the protection diodes. But two resistors forming a voltage divider can be a fine solution - more definitive than your proposal except for things that need to run for a long time on battery. But a 5v Arduino wouldn't be suitable for that to begin with.
– Chris Stratton
13 hours ago
One resistor is not really a proper solution except when you have a current rating for the protection diodes. But two resistors forming a voltage divider can be a fine solution - more definitive than your proposal except for things that need to run for a long time on battery. But a 5v Arduino wouldn't be suitable for that to begin with.
– Chris Stratton
13 hours ago
add a comment |Â
1 Answer
1
active
oldest
votes
According to a quick simulation, the answer is yes. Note that I have not added any parasitics, but the outputs look ok.
There is an error in your schematic incidentally; the gate of the MOSFET needs to be pulled directly to 3.3V
Driving from the 3.3V side, 5V side output:
3.3V output when driven from the 5V side has some overshoot (but nothing serious):
Timings set for 115200 bit times. The overshoot on the 3.3V side is due to the body diode of the MOSFET which is involved in down shifting but not in up shifting.
answered 14 hours ago
Peter Smith
13.4k11237
Peter, Thank you very much!
– ÃÂûõúѠÓðрøÑÂþý
13 hours ago
While it may work, it's worth noting that this will be weaker than a voltage divider solution on the high side, and not meaningfully better on the low side.
– Chris Stratton
13 hours ago
I had problems using a voltage divider. For some reason I could not exchange data through it.
– ÃÂûõúѠÓðрøÑÂþý
12 hours ago
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
According to a quick simulation, the answer is yes. Note that I have not added any parasitics, but the outputs look ok.
There is an error in your schematic incidentally; the gate of the MOSFET needs to be pulled directly to 3.3V
Driving from the 3.3V side, 5V side output:
3.3V output when driven from the 5V side has some overshoot (but nothing serious):
Timings set for 115200 bit times. The overshoot on the 3.3V side is due to the body diode of the MOSFET which is involved in down shifting but not in up shifting.
answered 14 hours ago
Peter Smith
13.4k11237
Peter, Thank you very much!
– ÃÂûõúѠÓðрøÑÂþý
13 hours ago
While it may work, it's worth noting that this will be weaker than a voltage divider solution on the high side, and not meaningfully better on the low side.
– Chris Stratton
13 hours ago
I had problems using a voltage divider. For some reason I could not exchange data through it.
– ÃÂûõúѠÓðрøÑÂþý
12 hours ago
add a comment |Â
According to a quick simulation, the answer is yes. Note that I have not added any parasitics, but the outputs look ok.
There is an error in your schematic incidentally; the gate of the MOSFET needs to be pulled directly to 3.3V
Driving from the 3.3V side, 5V side output:
3.3V output when driven from the 5V side has some overshoot (but nothing serious):
Timings set for 115200 bit times. The overshoot on the 3.3V side is due to the body diode of the MOSFET which is involved in down shifting but not in up shifting.
answered 14 hours ago
Peter Smith
13.4k11237
Peter, Thank you very much!
– ÃÂûõúѠÓðрøÑÂþý
13 hours ago
While it may work, it's worth noting that this will be weaker than a voltage divider solution on the high side, and not meaningfully better on the low side.
– Chris Stratton
13 hours ago
I had problems using a voltage divider. For some reason I could not exchange data through it.
– ÃÂûõúѠÓðрøÑÂþý
12 hours ago
add a comment |Â
According to a quick simulation, the answer is yes. Note that I have not added any parasitics, but the outputs look ok.
There is an error in your schematic incidentally; the gate of the MOSFET needs to be pulled directly to 3.3V
Driving from the 3.3V side, 5V side output:
3.3V output when driven from the 5V side has some overshoot (but nothing serious):
Timings set for 115200 bit times. The overshoot on the 3.3V side is due to the body diode of the MOSFET which is involved in down shifting but not in up shifting.
answered 14 hours ago
Peter Smith
13.4k11237
According to a quick simulation, the answer is yes. Note that I have not added any parasitics, but the outputs look ok.
There is an error in your schematic incidentally; the gate of the MOSFET needs to be pulled directly to 3.3V
Driving from the 3.3V side, 5V side output:
3.3V output when driven from the 5V side has some overshoot (but nothing serious):
Timings set for 115200 bit times. The overshoot on the 3.3V side is due to the body diode of the MOSFET which is involved in down shifting but not in up shifting.
answered 14 hours ago
Peter Smith
13.4k11237
edited 13 hours ago
answered 14 hours ago
Peter Smith
13.4k11237
answered 14 hours ago
Peter Smith
13.4k11237
answered 14 hours ago
Peter Smith
13.4k11237
13.4k11237
Peter, Thank you very much!
– ÃÂûõúѠÓðрøÑÂþý
13 hours ago
While it may work, it's worth noting that this will be weaker than a voltage divider solution on the high side, and not meaningfully better on the low side.
– Chris Stratton
13 hours ago
I had problems using a voltage divider. For some reason I could not exchange data through it.
– ÃÂûõúѠÓðрøÑÂþý
12 hours ago
add a comment |Â
Peter, Thank you very much!
– ÃÂûõúѠÓðрøÑÂþý
13 hours ago
While it may work, it's worth noting that this will be weaker than a voltage divider solution on the high side, and not meaningfully better on the low side.
– Chris Stratton
13 hours ago
I had problems using a voltage divider. For some reason I could not exchange data through it.
– ÃÂûõúѠÓðрøÑÂþý
12 hours ago
Peter, Thank you very much!
– ÃÂûõúѠÓðрøÑÂþý
13 hours ago
Peter, Thank you very much!
– ÃÂûõúѠÓðрøÑÂþý
13 hours ago
While it may work, it's worth noting that this will be weaker than a voltage divider solution on the high side, and not meaningfully better on the low side.
– Chris Stratton
13 hours ago
While it may work, it's worth noting that this will be weaker than a voltage divider solution on the high side, and not meaningfully better on the low side.
– Chris Stratton
13 hours ago
I had problems using a voltage divider. For some reason I could not exchange data through it.
– ÃÂûõúѠÓðрøÑÂþý
12 hours ago
I had problems using a voltage divider. For some reason I could not exchange data through it.
– ÃÂûõúѠÓðрøÑÂþý
12 hours ago
add a comment |Â
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1
115.2 kBaud is not really high speed. Here someone simulated the same circuit and found that it works comfortably even at 2 MHz: electronics.stackexchange.com/a/367055/31091 The link also contains a detailed explanation of the circuit and its frequency-limiting factors.
– Geier
13 hours ago
2
One resistor is not really a proper solution except when you have a current rating for the protection diodes. But two resistors forming a voltage divider can be a fine solution - more definitive than your proposal except for things that need to run for a long time on battery. But a 5v Arduino wouldn't be suitable for that to begin with.
– Chris Stratton
13 hours ago