Identify which element is currently processed
I would like to know how can I identify which element in the array is currently being processed. for example
I would like to print the following:
e
1
Element1 consumed
e
2
Element2 consumed
e
3
Element2 consumed
how can i modify the below code to achieve the given results please.
code:
public static void main(String args)
Observable<String> stringObservable = Observable.just("e1", "e2", "e3");
stringObservable
.map(x->x.split(""))//return non-observable
.flatMap(y->Observable.fromArray(y)//return observable
.map(n->n))
.observeOn(Schedulers.io())
.blockingSubscribe(getObserver());
java java-8 observable rx-java2
asked Nov 12 at 14:41
LetsamrIt
1,23231940
add a comment |
I would like to know how can I identify which element in the array is currently being processed. for example
I would like to print the following:
e
1
Element1 consumed
e
2
Element2 consumed
e
3
Element2 consumed
how can i modify the below code to achieve the given results please.
code:
public static void main(String args)
Observable<String> stringObservable = Observable.just("e1", "e2", "e3");
stringObservable
.map(x->x.split(""))//return non-observable
.flatMap(y->Observable.fromArray(y)//return observable
.map(n->n))
.observeOn(Schedulers.io())
.blockingSubscribe(getObserver());
java java-8 observable rx-java2
asked Nov 12 at 14:41
LetsamrIt
1,23231940
add a comment |
I would like to know how can I identify which element in the array is currently being processed. for example
I would like to print the following:
e
1
Element1 consumed
e
2
Element2 consumed
e
3
Element2 consumed
how can i modify the below code to achieve the given results please.
code:
public static void main(String args)
Observable<String> stringObservable = Observable.just("e1", "e2", "e3");
stringObservable
.map(x->x.split(""))//return non-observable
.flatMap(y->Observable.fromArray(y)//return observable
.map(n->n))
.observeOn(Schedulers.io())
.blockingSubscribe(getObserver());
java java-8 observable rx-java2
asked Nov 12 at 14:41
LetsamrIt
1,23231940
I would like to know how can I identify which element in the array is currently being processed. for example
I would like to print the following:
e
1
Element1 consumed
e
2
Element2 consumed
e
3
Element2 consumed
how can i modify the below code to achieve the given results please.
code:
public static void main(String args)
Observable<String> stringObservable = Observable.just("e1", "e2", "e3");
stringObservable
.map(x->x.split(""))//return non-observable
.flatMap(y->Observable.fromArray(y)//return observable
.map(n->n))
.observeOn(Schedulers.io())
.blockingSubscribe(getObserver());
java java-8 observable rx-java2
java java-8 observable rx-java2
asked Nov 12 at 14:41
LetsamrIt
1,23231940
asked Nov 12 at 14:41
LetsamrIt
1,23231940
edited Nov 12 at 22:31
asked Nov 12 at 14:41
LetsamrIt
1,23231940
asked Nov 12 at 14:41
LetsamrIt
1,23231940
asked Nov 12 at 14:41
LetsamrIt
1,23231940
1,23231940
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Use doOnNext and doOnComplete on the inner sequence that splits your source item:
public static void main(String args)
Observable<String> stringObservable = Observable.just("e1", "e2", "e3");
stringObservable
.flatMap(x ->
Observable.fromArray(x.split(""))
.doOnNext(n ->
System.out.println(n)) // <-------------------- prints each split item
.map(n->n)
.doOnComplete(() ->
System.out.println(
"Element " + x + " consumed")) // <--------- end of processing of x
)
.observeOn(Schedulers.io())
.blockingSubscribe(getObserver());
answered Nov 13 at 9:31
akarnokd
48.7k998147
add a comment |
you might want to take a look at the doOnEach operator, you can do they printing there
http://reactivex.io/RxJava/javadoc/rx/Observable.html#doOnEach(rx.functions.Action1)
answered Nov 13 at 2:48
Kun
1,1232916
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use doOnNext and doOnComplete on the inner sequence that splits your source item:
public static void main(String args)
Observable<String> stringObservable = Observable.just("e1", "e2", "e3");
stringObservable
.flatMap(x ->
Observable.fromArray(x.split(""))
.doOnNext(n ->
System.out.println(n)) // <-------------------- prints each split item
.map(n->n)
.doOnComplete(() ->
System.out.println(
"Element " + x + " consumed")) // <--------- end of processing of x
)
.observeOn(Schedulers.io())
.blockingSubscribe(getObserver());
answered Nov 13 at 9:31
akarnokd
48.7k998147
add a comment |
Use doOnNext and doOnComplete on the inner sequence that splits your source item:
public static void main(String args)
Observable<String> stringObservable = Observable.just("e1", "e2", "e3");
stringObservable
.flatMap(x ->
Observable.fromArray(x.split(""))
.doOnNext(n ->
System.out.println(n)) // <-------------------- prints each split item
.map(n->n)
.doOnComplete(() ->
System.out.println(
"Element " + x + " consumed")) // <--------- end of processing of x
)
.observeOn(Schedulers.io())
.blockingSubscribe(getObserver());
answered Nov 13 at 9:31
akarnokd
48.7k998147
add a comment |
Use doOnNext and doOnComplete on the inner sequence that splits your source item:
public static void main(String args)
Observable<String> stringObservable = Observable.just("e1", "e2", "e3");
stringObservable
.flatMap(x ->
Observable.fromArray(x.split(""))
.doOnNext(n ->
System.out.println(n)) // <-------------------- prints each split item
.map(n->n)
.doOnComplete(() ->
System.out.println(
"Element " + x + " consumed")) // <--------- end of processing of x
)
.observeOn(Schedulers.io())
.blockingSubscribe(getObserver());
answered Nov 13 at 9:31
akarnokd
48.7k998147
Use doOnNext and doOnComplete on the inner sequence that splits your source item:
public static void main(String args)
Observable<String> stringObservable = Observable.just("e1", "e2", "e3");
stringObservable
.flatMap(x ->
Observable.fromArray(x.split(""))
.doOnNext(n ->
System.out.println(n)) // <-------------------- prints each split item
.map(n->n)
.doOnComplete(() ->
System.out.println(
"Element " + x + " consumed")) // <--------- end of processing of x
)
.observeOn(Schedulers.io())
.blockingSubscribe(getObserver());
answered Nov 13 at 9:31
akarnokd
48.7k998147
answered Nov 13 at 9:31
akarnokd
48.7k998147
answered Nov 13 at 9:31
akarnokd
48.7k998147
answered Nov 13 at 9:31
akarnokd
48.7k998147
48.7k998147
add a comment |
add a comment |
you might want to take a look at the doOnEach operator, you can do they printing there
http://reactivex.io/RxJava/javadoc/rx/Observable.html#doOnEach(rx.functions.Action1)
answered Nov 13 at 2:48
Kun
1,1232916
add a comment |
you might want to take a look at the doOnEach operator, you can do they printing there
http://reactivex.io/RxJava/javadoc/rx/Observable.html#doOnEach(rx.functions.Action1)
answered Nov 13 at 2:48
Kun
1,1232916
add a comment |
you might want to take a look at the doOnEach operator, you can do they printing there
http://reactivex.io/RxJava/javadoc/rx/Observable.html#doOnEach(rx.functions.Action1)
answered Nov 13 at 2:48
Kun
1,1232916
you might want to take a look at the doOnEach operator, you can do they printing there
http://reactivex.io/RxJava/javadoc/rx/Observable.html#doOnEach(rx.functions.Action1)
answered Nov 13 at 2:48
Kun
1,1232916
answered Nov 13 at 2:48
Kun
1,1232916
answered Nov 13 at 2:48
Kun
1,1232916
answered Nov 13 at 2:48
Kun
1,1232916
1,1232916
add a comment |
add a comment |
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