Extract a map from a Json interprets all numbers as BigInt










0















i've extracted a map from json. This works so far. As I don't know before parsing which fields are there in the json, I've been using a Map[String, Any]. Every field only consisting of digits is interpreted as a BigInt, which I don't want.



MyCode:



 implicit val formats: DefaultFormats.type = org.json4s.DefaultFormats
json.extract[Map[String, Any]]


Any way to implicitly make the numbers interpreted as Int or Long?










share|improve this question


























    0















    i've extracted a map from json. This works so far. As I don't know before parsing which fields are there in the json, I've been using a Map[String, Any]. Every field only consisting of digits is interpreted as a BigInt, which I don't want.



    MyCode:



     implicit val formats: DefaultFormats.type = org.json4s.DefaultFormats
    json.extract[Map[String, Any]]


    Any way to implicitly make the numbers interpreted as Int or Long?










    share|improve this question
























      0












      0








      0








      i've extracted a map from json. This works so far. As I don't know before parsing which fields are there in the json, I've been using a Map[String, Any]. Every field only consisting of digits is interpreted as a BigInt, which I don't want.



      MyCode:



       implicit val formats: DefaultFormats.type = org.json4s.DefaultFormats
      json.extract[Map[String, Any]]


      Any way to implicitly make the numbers interpreted as Int or Long?










      share|improve this question














      i've extracted a map from json. This works so far. As I don't know before parsing which fields are there in the json, I've been using a Map[String, Any]. Every field only consisting of digits is interpreted as a BigInt, which I don't want.



      MyCode:



       implicit val formats: DefaultFormats.type = org.json4s.DefaultFormats
      json.extract[Map[String, Any]]


      Any way to implicitly make the numbers interpreted as Int or Long?







      json scala json4s






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 14 '18 at 9:34









      ScalaNewbieScalaNewbie

      486




      486






















          1 Answer
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          1














          You did not specify, how the json value is created. If you parse it from a String, than the useBigIntForLong flag does the trick:



          import org.json4s.DefaultFormats
          import org.json4s.JsonAST._
          import org.json4s.native.JsonMethods

          object Main

          def main(args: Array[String]): Unit =
          implicit val formats: DefaultFormats = DefaultFormats

          val parsedJson = JsonMethods.parse(""" "a" : 42 """, useBigIntForLong = false)
          parsedJson.extract[Map[String, Any]].foreach
          case (name, value) => println(s"$name = $value ($value.getClass)")






          Output:



          a = 42 (class java.lang.Long)


          If you construct the json value programmatically, than you choose between BigInt and Long directly:



          val constructedJson = JObject(
          "alwaysBigInt" -> JInt(42),
          "alwaysLong" -> JLong(55),
          )
          constructedJson.extract[Map[String, Any]].foreach
          case (name, value) => println(s"$name = $value ($value.getClass)")



          Output:



          alwaysBigInt = 42 (class scala.math.BigInt)
          alwaysLong = 55 (class java.lang.Long)


          Example source code






          share|improve this answer
























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            1 Answer
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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1














            You did not specify, how the json value is created. If you parse it from a String, than the useBigIntForLong flag does the trick:



            import org.json4s.DefaultFormats
            import org.json4s.JsonAST._
            import org.json4s.native.JsonMethods

            object Main

            def main(args: Array[String]): Unit =
            implicit val formats: DefaultFormats = DefaultFormats

            val parsedJson = JsonMethods.parse(""" "a" : 42 """, useBigIntForLong = false)
            parsedJson.extract[Map[String, Any]].foreach
            case (name, value) => println(s"$name = $value ($value.getClass)")






            Output:



            a = 42 (class java.lang.Long)


            If you construct the json value programmatically, than you choose between BigInt and Long directly:



            val constructedJson = JObject(
            "alwaysBigInt" -> JInt(42),
            "alwaysLong" -> JLong(55),
            )
            constructedJson.extract[Map[String, Any]].foreach
            case (name, value) => println(s"$name = $value ($value.getClass)")



            Output:



            alwaysBigInt = 42 (class scala.math.BigInt)
            alwaysLong = 55 (class java.lang.Long)


            Example source code






            share|improve this answer





























              1














              You did not specify, how the json value is created. If you parse it from a String, than the useBigIntForLong flag does the trick:



              import org.json4s.DefaultFormats
              import org.json4s.JsonAST._
              import org.json4s.native.JsonMethods

              object Main

              def main(args: Array[String]): Unit =
              implicit val formats: DefaultFormats = DefaultFormats

              val parsedJson = JsonMethods.parse(""" "a" : 42 """, useBigIntForLong = false)
              parsedJson.extract[Map[String, Any]].foreach
              case (name, value) => println(s"$name = $value ($value.getClass)")






              Output:



              a = 42 (class java.lang.Long)


              If you construct the json value programmatically, than you choose between BigInt and Long directly:



              val constructedJson = JObject(
              "alwaysBigInt" -> JInt(42),
              "alwaysLong" -> JLong(55),
              )
              constructedJson.extract[Map[String, Any]].foreach
              case (name, value) => println(s"$name = $value ($value.getClass)")



              Output:



              alwaysBigInt = 42 (class scala.math.BigInt)
              alwaysLong = 55 (class java.lang.Long)


              Example source code






              share|improve this answer



























                1












                1








                1







                You did not specify, how the json value is created. If you parse it from a String, than the useBigIntForLong flag does the trick:



                import org.json4s.DefaultFormats
                import org.json4s.JsonAST._
                import org.json4s.native.JsonMethods

                object Main

                def main(args: Array[String]): Unit =
                implicit val formats: DefaultFormats = DefaultFormats

                val parsedJson = JsonMethods.parse(""" "a" : 42 """, useBigIntForLong = false)
                parsedJson.extract[Map[String, Any]].foreach
                case (name, value) => println(s"$name = $value ($value.getClass)")






                Output:



                a = 42 (class java.lang.Long)


                If you construct the json value programmatically, than you choose between BigInt and Long directly:



                val constructedJson = JObject(
                "alwaysBigInt" -> JInt(42),
                "alwaysLong" -> JLong(55),
                )
                constructedJson.extract[Map[String, Any]].foreach
                case (name, value) => println(s"$name = $value ($value.getClass)")



                Output:



                alwaysBigInt = 42 (class scala.math.BigInt)
                alwaysLong = 55 (class java.lang.Long)


                Example source code






                share|improve this answer















                You did not specify, how the json value is created. If you parse it from a String, than the useBigIntForLong flag does the trick:



                import org.json4s.DefaultFormats
                import org.json4s.JsonAST._
                import org.json4s.native.JsonMethods

                object Main

                def main(args: Array[String]): Unit =
                implicit val formats: DefaultFormats = DefaultFormats

                val parsedJson = JsonMethods.parse(""" "a" : 42 """, useBigIntForLong = false)
                parsedJson.extract[Map[String, Any]].foreach
                case (name, value) => println(s"$name = $value ($value.getClass)")






                Output:



                a = 42 (class java.lang.Long)


                If you construct the json value programmatically, than you choose between BigInt and Long directly:



                val constructedJson = JObject(
                "alwaysBigInt" -> JInt(42),
                "alwaysLong" -> JLong(55),
                )
                constructedJson.extract[Map[String, Any]].foreach
                case (name, value) => println(s"$name = $value ($value.getClass)")



                Output:



                alwaysBigInt = 42 (class scala.math.BigInt)
                alwaysLong = 55 (class java.lang.Long)


                Example source code







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 14 '18 at 16:34

























                answered Nov 14 '18 at 12:32









                ygorygor

                1,112615




                1,112615



























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