Extract a map from a Json interprets all numbers as BigInt
i've extracted a map from json. This works so far. As I don't know before parsing which fields are there in the json, I've been using a Map[String, Any]
. Every field only consisting of digits is interpreted as a BigInt
, which I don't want.
MyCode:
implicit val formats: DefaultFormats.type = org.json4s.DefaultFormats
json.extract[Map[String, Any]]
Any way to implicitly make the numbers interpreted as Int
or Long
?
json scala json4s
add a comment |
i've extracted a map from json. This works so far. As I don't know before parsing which fields are there in the json, I've been using a Map[String, Any]
. Every field only consisting of digits is interpreted as a BigInt
, which I don't want.
MyCode:
implicit val formats: DefaultFormats.type = org.json4s.DefaultFormats
json.extract[Map[String, Any]]
Any way to implicitly make the numbers interpreted as Int
or Long
?
json scala json4s
add a comment |
i've extracted a map from json. This works so far. As I don't know before parsing which fields are there in the json, I've been using a Map[String, Any]
. Every field only consisting of digits is interpreted as a BigInt
, which I don't want.
MyCode:
implicit val formats: DefaultFormats.type = org.json4s.DefaultFormats
json.extract[Map[String, Any]]
Any way to implicitly make the numbers interpreted as Int
or Long
?
json scala json4s
i've extracted a map from json. This works so far. As I don't know before parsing which fields are there in the json, I've been using a Map[String, Any]
. Every field only consisting of digits is interpreted as a BigInt
, which I don't want.
MyCode:
implicit val formats: DefaultFormats.type = org.json4s.DefaultFormats
json.extract[Map[String, Any]]
Any way to implicitly make the numbers interpreted as Int
or Long
?
json scala json4s
json scala json4s
asked Nov 14 '18 at 9:34
ScalaNewbieScalaNewbie
486
486
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You did not specify, how the json
value is created. If you parse it from a String
, than the useBigIntForLong
flag does the trick:
import org.json4s.DefaultFormats
import org.json4s.JsonAST._
import org.json4s.native.JsonMethods
object Main
def main(args: Array[String]): Unit =
implicit val formats: DefaultFormats = DefaultFormats
val parsedJson = JsonMethods.parse(""" "a" : 42 """, useBigIntForLong = false)
parsedJson.extract[Map[String, Any]].foreach
case (name, value) => println(s"$name = $value ($value.getClass)")
Output:
a = 42 (class java.lang.Long)
If you construct the json value programmatically, than you choose between BigInt
and Long
directly:
val constructedJson = JObject(
"alwaysBigInt" -> JInt(42),
"alwaysLong" -> JLong(55),
)
constructedJson.extract[Map[String, Any]].foreach
case (name, value) => println(s"$name = $value ($value.getClass)")
Output:
alwaysBigInt = 42 (class scala.math.BigInt)
alwaysLong = 55 (class java.lang.Long)
Example source code
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You did not specify, how the json
value is created. If you parse it from a String
, than the useBigIntForLong
flag does the trick:
import org.json4s.DefaultFormats
import org.json4s.JsonAST._
import org.json4s.native.JsonMethods
object Main
def main(args: Array[String]): Unit =
implicit val formats: DefaultFormats = DefaultFormats
val parsedJson = JsonMethods.parse(""" "a" : 42 """, useBigIntForLong = false)
parsedJson.extract[Map[String, Any]].foreach
case (name, value) => println(s"$name = $value ($value.getClass)")
Output:
a = 42 (class java.lang.Long)
If you construct the json value programmatically, than you choose between BigInt
and Long
directly:
val constructedJson = JObject(
"alwaysBigInt" -> JInt(42),
"alwaysLong" -> JLong(55),
)
constructedJson.extract[Map[String, Any]].foreach
case (name, value) => println(s"$name = $value ($value.getClass)")
Output:
alwaysBigInt = 42 (class scala.math.BigInt)
alwaysLong = 55 (class java.lang.Long)
Example source code
add a comment |
You did not specify, how the json
value is created. If you parse it from a String
, than the useBigIntForLong
flag does the trick:
import org.json4s.DefaultFormats
import org.json4s.JsonAST._
import org.json4s.native.JsonMethods
object Main
def main(args: Array[String]): Unit =
implicit val formats: DefaultFormats = DefaultFormats
val parsedJson = JsonMethods.parse(""" "a" : 42 """, useBigIntForLong = false)
parsedJson.extract[Map[String, Any]].foreach
case (name, value) => println(s"$name = $value ($value.getClass)")
Output:
a = 42 (class java.lang.Long)
If you construct the json value programmatically, than you choose between BigInt
and Long
directly:
val constructedJson = JObject(
"alwaysBigInt" -> JInt(42),
"alwaysLong" -> JLong(55),
)
constructedJson.extract[Map[String, Any]].foreach
case (name, value) => println(s"$name = $value ($value.getClass)")
Output:
alwaysBigInt = 42 (class scala.math.BigInt)
alwaysLong = 55 (class java.lang.Long)
Example source code
add a comment |
You did not specify, how the json
value is created. If you parse it from a String
, than the useBigIntForLong
flag does the trick:
import org.json4s.DefaultFormats
import org.json4s.JsonAST._
import org.json4s.native.JsonMethods
object Main
def main(args: Array[String]): Unit =
implicit val formats: DefaultFormats = DefaultFormats
val parsedJson = JsonMethods.parse(""" "a" : 42 """, useBigIntForLong = false)
parsedJson.extract[Map[String, Any]].foreach
case (name, value) => println(s"$name = $value ($value.getClass)")
Output:
a = 42 (class java.lang.Long)
If you construct the json value programmatically, than you choose between BigInt
and Long
directly:
val constructedJson = JObject(
"alwaysBigInt" -> JInt(42),
"alwaysLong" -> JLong(55),
)
constructedJson.extract[Map[String, Any]].foreach
case (name, value) => println(s"$name = $value ($value.getClass)")
Output:
alwaysBigInt = 42 (class scala.math.BigInt)
alwaysLong = 55 (class java.lang.Long)
Example source code
You did not specify, how the json
value is created. If you parse it from a String
, than the useBigIntForLong
flag does the trick:
import org.json4s.DefaultFormats
import org.json4s.JsonAST._
import org.json4s.native.JsonMethods
object Main
def main(args: Array[String]): Unit =
implicit val formats: DefaultFormats = DefaultFormats
val parsedJson = JsonMethods.parse(""" "a" : 42 """, useBigIntForLong = false)
parsedJson.extract[Map[String, Any]].foreach
case (name, value) => println(s"$name = $value ($value.getClass)")
Output:
a = 42 (class java.lang.Long)
If you construct the json value programmatically, than you choose between BigInt
and Long
directly:
val constructedJson = JObject(
"alwaysBigInt" -> JInt(42),
"alwaysLong" -> JLong(55),
)
constructedJson.extract[Map[String, Any]].foreach
case (name, value) => println(s"$name = $value ($value.getClass)")
Output:
alwaysBigInt = 42 (class scala.math.BigInt)
alwaysLong = 55 (class java.lang.Long)
Example source code
edited Nov 14 '18 at 16:34
answered Nov 14 '18 at 12:32
ygorygor
1,112615
1,112615
add a comment |
add a comment |
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