Converting into range in Python










-2















I want to convert a list into range.



a = ['Eth1/1', 'Eth1/2', 'Eth1/3', 'Eth1/4', 'Eth1/5', 'Eth1/6', 'Eth1/7', 'Eth1/8', 'Eth1/9', 'Eth1/10','Eth2/1', 'Eth2/2', 'Eth2/3', 'Eth2/4', 'Eth2/5', 'Eth2/6','Eth3/1', 'Eth3/2', 'Eth3/3', 'Eth3/4', 'Eth3/5', 'Eth3/6','Eth4/1', 'Eth4/2', 'Eth4/3', 'Eth4/4', 'Eth4/5', 'Eth4/6']


what i am trying :



fp = open('mode.txt' , 'w+')
for i in a:
fp.write('confi ' + i + 'n mode n')


what i am looking for :



confi Eth1/1-5
mode
confi Eth1/6-10
mode
confi Eth2/1-6
mode
confi Eth3/1-6
mode
confi Eth4/1-6
mode


Any idea how to do this ?










share|improve this question



















  • 1





    So, why does the range divided in 1-5 and 6-10? Any criteria for that?

    – Andreas
    Nov 13 '18 at 7:03











  • @Andreas looking for group of 5

    – Jinni
    Nov 13 '18 at 7:08











  • Let 'a" be like that ..

    – Jinni
    Nov 13 '18 at 7:15











  • @Andreas i updaed the question ..can we get the output i mentioned ? Logic :divide line in chunk of 5 where Eth1 exist and for line consist Eth2 , take everything ?

    – Jinni
    Nov 15 '18 at 6:24











  • @Andreas what if i have to do thing for Eth3 same to what we do for Eth2..

    – Jinni
    Nov 15 '18 at 7:11















-2















I want to convert a list into range.



a = ['Eth1/1', 'Eth1/2', 'Eth1/3', 'Eth1/4', 'Eth1/5', 'Eth1/6', 'Eth1/7', 'Eth1/8', 'Eth1/9', 'Eth1/10','Eth2/1', 'Eth2/2', 'Eth2/3', 'Eth2/4', 'Eth2/5', 'Eth2/6','Eth3/1', 'Eth3/2', 'Eth3/3', 'Eth3/4', 'Eth3/5', 'Eth3/6','Eth4/1', 'Eth4/2', 'Eth4/3', 'Eth4/4', 'Eth4/5', 'Eth4/6']


what i am trying :



fp = open('mode.txt' , 'w+')
for i in a:
fp.write('confi ' + i + 'n mode n')


what i am looking for :



confi Eth1/1-5
mode
confi Eth1/6-10
mode
confi Eth2/1-6
mode
confi Eth3/1-6
mode
confi Eth4/1-6
mode


Any idea how to do this ?










share|improve this question



















  • 1





    So, why does the range divided in 1-5 and 6-10? Any criteria for that?

    – Andreas
    Nov 13 '18 at 7:03











  • @Andreas looking for group of 5

    – Jinni
    Nov 13 '18 at 7:08











  • Let 'a" be like that ..

    – Jinni
    Nov 13 '18 at 7:15











  • @Andreas i updaed the question ..can we get the output i mentioned ? Logic :divide line in chunk of 5 where Eth1 exist and for line consist Eth2 , take everything ?

    – Jinni
    Nov 15 '18 at 6:24











  • @Andreas what if i have to do thing for Eth3 same to what we do for Eth2..

    – Jinni
    Nov 15 '18 at 7:11













-2












-2








-2








I want to convert a list into range.



a = ['Eth1/1', 'Eth1/2', 'Eth1/3', 'Eth1/4', 'Eth1/5', 'Eth1/6', 'Eth1/7', 'Eth1/8', 'Eth1/9', 'Eth1/10','Eth2/1', 'Eth2/2', 'Eth2/3', 'Eth2/4', 'Eth2/5', 'Eth2/6','Eth3/1', 'Eth3/2', 'Eth3/3', 'Eth3/4', 'Eth3/5', 'Eth3/6','Eth4/1', 'Eth4/2', 'Eth4/3', 'Eth4/4', 'Eth4/5', 'Eth4/6']


what i am trying :



fp = open('mode.txt' , 'w+')
for i in a:
fp.write('confi ' + i + 'n mode n')


what i am looking for :



confi Eth1/1-5
mode
confi Eth1/6-10
mode
confi Eth2/1-6
mode
confi Eth3/1-6
mode
confi Eth4/1-6
mode


Any idea how to do this ?










share|improve this question
















I want to convert a list into range.



a = ['Eth1/1', 'Eth1/2', 'Eth1/3', 'Eth1/4', 'Eth1/5', 'Eth1/6', 'Eth1/7', 'Eth1/8', 'Eth1/9', 'Eth1/10','Eth2/1', 'Eth2/2', 'Eth2/3', 'Eth2/4', 'Eth2/5', 'Eth2/6','Eth3/1', 'Eth3/2', 'Eth3/3', 'Eth3/4', 'Eth3/5', 'Eth3/6','Eth4/1', 'Eth4/2', 'Eth4/3', 'Eth4/4', 'Eth4/5', 'Eth4/6']


what i am trying :



fp = open('mode.txt' , 'w+')
for i in a:
fp.write('confi ' + i + 'n mode n')


what i am looking for :



confi Eth1/1-5
mode
confi Eth1/6-10
mode
confi Eth2/1-6
mode
confi Eth3/1-6
mode
confi Eth4/1-6
mode


Any idea how to do this ?







list python-2.6






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 15 '18 at 7:32







Jinni

















asked Nov 13 '18 at 6:59









JinniJinni

166




166







  • 1





    So, why does the range divided in 1-5 and 6-10? Any criteria for that?

    – Andreas
    Nov 13 '18 at 7:03











  • @Andreas looking for group of 5

    – Jinni
    Nov 13 '18 at 7:08











  • Let 'a" be like that ..

    – Jinni
    Nov 13 '18 at 7:15











  • @Andreas i updaed the question ..can we get the output i mentioned ? Logic :divide line in chunk of 5 where Eth1 exist and for line consist Eth2 , take everything ?

    – Jinni
    Nov 15 '18 at 6:24











  • @Andreas what if i have to do thing for Eth3 same to what we do for Eth2..

    – Jinni
    Nov 15 '18 at 7:11












  • 1





    So, why does the range divided in 1-5 and 6-10? Any criteria for that?

    – Andreas
    Nov 13 '18 at 7:03











  • @Andreas looking for group of 5

    – Jinni
    Nov 13 '18 at 7:08











  • Let 'a" be like that ..

    – Jinni
    Nov 13 '18 at 7:15











  • @Andreas i updaed the question ..can we get the output i mentioned ? Logic :divide line in chunk of 5 where Eth1 exist and for line consist Eth2 , take everything ?

    – Jinni
    Nov 15 '18 at 6:24











  • @Andreas what if i have to do thing for Eth3 same to what we do for Eth2..

    – Jinni
    Nov 15 '18 at 7:11







1




1





So, why does the range divided in 1-5 and 6-10? Any criteria for that?

– Andreas
Nov 13 '18 at 7:03





So, why does the range divided in 1-5 and 6-10? Any criteria for that?

– Andreas
Nov 13 '18 at 7:03













@Andreas looking for group of 5

– Jinni
Nov 13 '18 at 7:08





@Andreas looking for group of 5

– Jinni
Nov 13 '18 at 7:08













Let 'a" be like that ..

– Jinni
Nov 13 '18 at 7:15





Let 'a" be like that ..

– Jinni
Nov 13 '18 at 7:15













@Andreas i updaed the question ..can we get the output i mentioned ? Logic :divide line in chunk of 5 where Eth1 exist and for line consist Eth2 , take everything ?

– Jinni
Nov 15 '18 at 6:24





@Andreas i updaed the question ..can we get the output i mentioned ? Logic :divide line in chunk of 5 where Eth1 exist and for line consist Eth2 , take everything ?

– Jinni
Nov 15 '18 at 6:24













@Andreas what if i have to do thing for Eth3 same to what we do for Eth2..

– Jinni
Nov 15 '18 at 7:11





@Andreas what if i have to do thing for Eth3 same to what we do for Eth2..

– Jinni
Nov 15 '18 at 7:11












1 Answer
1






active

oldest

votes


















0














You could create a loop that checks the current element as the start. If it starts with Eth1 then get the 4th element after as the end. Otherwise, keep the starting Eth_, iterate through the list until you get the last Eth_ element or until the list end. Assign the last element as the end.



a = ['Eth1/1', 'Eth1/2', 'Eth1/3', 'Eth1/4', 'Eth1/5', 'Eth1/6', 'Eth1/7', 'Eth1/8', 'Eth1/9', 'Eth1/10','Eth2/1', 'Eth2/2', 'Eth2/3', 'Eth2/4', 'Eth2/5', 'Eth2/6','Eth3/1', 'Eth3/2', 'Eth3/3', 'Eth3/4', 'Eth3/5', 'Eth3/6','Eth4/1', 'Eth4/2', 'Eth4/3', 'Eth4/4', 'Eth4/5', 'Eth4/6']
i = 0

while i < len(a):
start = a[i].split('/')
if (start[0] == 'Eth1'):
i += 5
else:
key = start[0]
i += 1
while i < len(a) and a[i].split('/')[0] == key:
i += 1
end = a[i-1].split('/')
print('confi ' + start[0] + '/' + start[1] + '-' + end[1] + 'n moden')





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    1 Answer
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    You could create a loop that checks the current element as the start. If it starts with Eth1 then get the 4th element after as the end. Otherwise, keep the starting Eth_, iterate through the list until you get the last Eth_ element or until the list end. Assign the last element as the end.



    a = ['Eth1/1', 'Eth1/2', 'Eth1/3', 'Eth1/4', 'Eth1/5', 'Eth1/6', 'Eth1/7', 'Eth1/8', 'Eth1/9', 'Eth1/10','Eth2/1', 'Eth2/2', 'Eth2/3', 'Eth2/4', 'Eth2/5', 'Eth2/6','Eth3/1', 'Eth3/2', 'Eth3/3', 'Eth3/4', 'Eth3/5', 'Eth3/6','Eth4/1', 'Eth4/2', 'Eth4/3', 'Eth4/4', 'Eth4/5', 'Eth4/6']
    i = 0

    while i < len(a):
    start = a[i].split('/')
    if (start[0] == 'Eth1'):
    i += 5
    else:
    key = start[0]
    i += 1
    while i < len(a) and a[i].split('/')[0] == key:
    i += 1
    end = a[i-1].split('/')
    print('confi ' + start[0] + '/' + start[1] + '-' + end[1] + 'n moden')





    share|improve this answer





























      0














      You could create a loop that checks the current element as the start. If it starts with Eth1 then get the 4th element after as the end. Otherwise, keep the starting Eth_, iterate through the list until you get the last Eth_ element or until the list end. Assign the last element as the end.



      a = ['Eth1/1', 'Eth1/2', 'Eth1/3', 'Eth1/4', 'Eth1/5', 'Eth1/6', 'Eth1/7', 'Eth1/8', 'Eth1/9', 'Eth1/10','Eth2/1', 'Eth2/2', 'Eth2/3', 'Eth2/4', 'Eth2/5', 'Eth2/6','Eth3/1', 'Eth3/2', 'Eth3/3', 'Eth3/4', 'Eth3/5', 'Eth3/6','Eth4/1', 'Eth4/2', 'Eth4/3', 'Eth4/4', 'Eth4/5', 'Eth4/6']
      i = 0

      while i < len(a):
      start = a[i].split('/')
      if (start[0] == 'Eth1'):
      i += 5
      else:
      key = start[0]
      i += 1
      while i < len(a) and a[i].split('/')[0] == key:
      i += 1
      end = a[i-1].split('/')
      print('confi ' + start[0] + '/' + start[1] + '-' + end[1] + 'n moden')





      share|improve this answer



























        0












        0








        0







        You could create a loop that checks the current element as the start. If it starts with Eth1 then get the 4th element after as the end. Otherwise, keep the starting Eth_, iterate through the list until you get the last Eth_ element or until the list end. Assign the last element as the end.



        a = ['Eth1/1', 'Eth1/2', 'Eth1/3', 'Eth1/4', 'Eth1/5', 'Eth1/6', 'Eth1/7', 'Eth1/8', 'Eth1/9', 'Eth1/10','Eth2/1', 'Eth2/2', 'Eth2/3', 'Eth2/4', 'Eth2/5', 'Eth2/6','Eth3/1', 'Eth3/2', 'Eth3/3', 'Eth3/4', 'Eth3/5', 'Eth3/6','Eth4/1', 'Eth4/2', 'Eth4/3', 'Eth4/4', 'Eth4/5', 'Eth4/6']
        i = 0

        while i < len(a):
        start = a[i].split('/')
        if (start[0] == 'Eth1'):
        i += 5
        else:
        key = start[0]
        i += 1
        while i < len(a) and a[i].split('/')[0] == key:
        i += 1
        end = a[i-1].split('/')
        print('confi ' + start[0] + '/' + start[1] + '-' + end[1] + 'n moden')





        share|improve this answer















        You could create a loop that checks the current element as the start. If it starts with Eth1 then get the 4th element after as the end. Otherwise, keep the starting Eth_, iterate through the list until you get the last Eth_ element or until the list end. Assign the last element as the end.



        a = ['Eth1/1', 'Eth1/2', 'Eth1/3', 'Eth1/4', 'Eth1/5', 'Eth1/6', 'Eth1/7', 'Eth1/8', 'Eth1/9', 'Eth1/10','Eth2/1', 'Eth2/2', 'Eth2/3', 'Eth2/4', 'Eth2/5', 'Eth2/6','Eth3/1', 'Eth3/2', 'Eth3/3', 'Eth3/4', 'Eth3/5', 'Eth3/6','Eth4/1', 'Eth4/2', 'Eth4/3', 'Eth4/4', 'Eth4/5', 'Eth4/6']
        i = 0

        while i < len(a):
        start = a[i].split('/')
        if (start[0] == 'Eth1'):
        i += 5
        else:
        key = start[0]
        i += 1
        while i < len(a) and a[i].split('/')[0] == key:
        i += 1
        end = a[i-1].split('/')
        print('confi ' + start[0] + '/' + start[1] + '-' + end[1] + 'n moden')






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 16 '18 at 5:59

























        answered Nov 13 '18 at 7:13









        AndreasAndreas

        1,97631018




        1,97631018





























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