A Discordjs Chat Filter
0
I'm making a discord.js bot and I was curious how to add a chat filter to it. As in a user says f*** and it will auto-delete.
json discord discord.js
asked Oct 29 '18 at 22:21
pausepause
82
add a comment |
0
I'm making a discord.js bot and I was curious how to add a chat filter to it. As in a user says f*** and it will auto-delete.
json discord discord.js
asked Oct 29 '18 at 22:21
pausepause
82
See this answer.
– Obsidian Age
Oct 29 '18 at 22:24
1
Possible duplicate of "bad words" filter
– Wesam
Oct 29 '18 at 22:27
1
npmjs.com/package/bad-words
– Frustrated programmer
Oct 29 '18 at 23:17
add a comment |
0
0
0
I'm making a discord.js bot and I was curious how to add a chat filter to it. As in a user says f*** and it will auto-delete.
json discord discord.js
asked Oct 29 '18 at 22:21
pausepause
82
I'm making a discord.js bot and I was curious how to add a chat filter to it. As in a user says f*** and it will auto-delete.
json discord discord.js
json discord discord.js
asked Oct 29 '18 at 22:21
pausepause
82
asked Oct 29 '18 at 22:21
pausepause
82
asked Oct 29 '18 at 22:21
pausepause
82
asked Oct 29 '18 at 22:21
pausepause
82
asked Oct 29 '18 at 22:21
pausepause
82
82
See this answer.
– Obsidian Age
Oct 29 '18 at 22:24
1
Possible duplicate of "bad words" filter
– Wesam
Oct 29 '18 at 22:27
1
npmjs.com/package/bad-words
– Frustrated programmer
Oct 29 '18 at 23:17
add a comment |
See this answer.
– Obsidian Age
Oct 29 '18 at 22:24
1
Possible duplicate of "bad words" filter
– Wesam
Oct 29 '18 at 22:27
1
npmjs.com/package/bad-words
– Frustrated programmer
Oct 29 '18 at 23:17
See this answer.
– Obsidian Age
Oct 29 '18 at 22:24
See this answer.
– Obsidian Age
Oct 29 '18 at 22:24
1
1
Possible duplicate of "bad words" filter
– Wesam
Oct 29 '18 at 22:27
Possible duplicate of "bad words" filter
– Wesam
Oct 29 '18 at 22:27
1
1
npmjs.com/package/bad-words
– Frustrated programmer
Oct 29 '18 at 23:17
npmjs.com/package/bad-words
– Frustrated programmer
Oct 29 '18 at 23:17
add a comment |
2 Answers
2
active
oldest
votes
0
You can do this with an array of words,
var profanities = ["test1", "test2", "..."];
then in your bot.on message handler, or how you use to handle messages,
bot.on('message', async message =>
let msg = message.content.toLowerCase();
let Admin = message.guild.roles.find('name', "Admin"); // Change this to meet what you want
let General = message.guild.channels.find(`name`, "general"); // All text channels are lowecase. Change this to meet what you want
for (x = 0; x < profanities.length; x++) message.channel.id === General.id) return; // if you changed the name of the variables above, change these too.
if (msg.includes(profanities[x]))
await message.reply("You cannot say that here!")
message.delete()
// Your code here
return;
);
EDIT:
This is very basic, it won't look for substitute letters such as $, @ or numbers/spaces unless you code those directly in, which you can have a list of words then have a console log every word with substitute letters.
answered Nov 2 '18 at 1:37
Steven WebsterSteven Webster
467
Thanks! One more question, is there any way to make it to where Administrators bypass that? Or is there a way too make it ignore a certain channel?
– pause
Nov 12 '18 at 22:55
Yes, you can check if the sender has a certain role with this code, add it right under "let msg = ..." let role = message.guild.roles.find('name', "Case sensitive role name") message.member.roles.has(role.id), for your convience, I've updated the post
– Steven Webster
Nov 15 '18 at 16:45
I also forgot to say, you can check the channel as well! Both have been implemented in the code above, the 2 new variables are what you change. If you change the names of them make sure to do so in the new if statement too
– Steven Webster
Nov 15 '18 at 17:28
Thanks so much!
– pause
Nov 15 '18 at 21:07
add a comment |
-1
client.on('message', message =>
message.delete(message.content.replace(/asshole/gi))
.catch(console.error);
);
This is just a example you can make it, with a text array too.
edited Oct 29 '18 at 23:53
Nisse Engström
4,16292135
answered Oct 29 '18 at 23:36
Esdese EsdeathEsdese Esdeath
35
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53054737%2fa-discordjs-chat-filter%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
You can do this with an array of words,
var profanities = ["test1", "test2", "..."];
then in your bot.on message handler, or how you use to handle messages,
bot.on('message', async message =>
let msg = message.content.toLowerCase();
let Admin = message.guild.roles.find('name', "Admin"); // Change this to meet what you want
let General = message.guild.channels.find(`name`, "general"); // All text channels are lowecase. Change this to meet what you want
for (x = 0; x < profanities.length; x++) message.channel.id === General.id) return; // if you changed the name of the variables above, change these too.
if (msg.includes(profanities[x]))
await message.reply("You cannot say that here!")
message.delete()
// Your code here
return;
);
EDIT:
This is very basic, it won't look for substitute letters such as $, @ or numbers/spaces unless you code those directly in, which you can have a list of words then have a console log every word with substitute letters.
answered Nov 2 '18 at 1:37
Steven WebsterSteven Webster
467
Thanks! One more question, is there any way to make it to where Administrators bypass that? Or is there a way too make it ignore a certain channel?
– pause
Nov 12 '18 at 22:55
Yes, you can check if the sender has a certain role with this code, add it right under "let msg = ..." let role = message.guild.roles.find('name', "Case sensitive role name") message.member.roles.has(role.id), for your convience, I've updated the post
– Steven Webster
Nov 15 '18 at 16:45
I also forgot to say, you can check the channel as well! Both have been implemented in the code above, the 2 new variables are what you change. If you change the names of them make sure to do so in the new if statement too
– Steven Webster
Nov 15 '18 at 17:28
Thanks so much!
– pause
Nov 15 '18 at 21:07
add a comment |
0
You can do this with an array of words,
var profanities = ["test1", "test2", "..."];
then in your bot.on message handler, or how you use to handle messages,
bot.on('message', async message =>
let msg = message.content.toLowerCase();
let Admin = message.guild.roles.find('name', "Admin"); // Change this to meet what you want
let General = message.guild.channels.find(`name`, "general"); // All text channels are lowecase. Change this to meet what you want
for (x = 0; x < profanities.length; x++) message.channel.id === General.id) return; // if you changed the name of the variables above, change these too.
if (msg.includes(profanities[x]))
await message.reply("You cannot say that here!")
message.delete()
// Your code here
return;
);
EDIT:
This is very basic, it won't look for substitute letters such as $, @ or numbers/spaces unless you code those directly in, which you can have a list of words then have a console log every word with substitute letters.
answered Nov 2 '18 at 1:37
Steven WebsterSteven Webster
467
Thanks! One more question, is there any way to make it to where Administrators bypass that? Or is there a way too make it ignore a certain channel?
– pause
Nov 12 '18 at 22:55
Yes, you can check if the sender has a certain role with this code, add it right under "let msg = ..." let role = message.guild.roles.find('name', "Case sensitive role name") message.member.roles.has(role.id), for your convience, I've updated the post
– Steven Webster
Nov 15 '18 at 16:45
I also forgot to say, you can check the channel as well! Both have been implemented in the code above, the 2 new variables are what you change. If you change the names of them make sure to do so in the new if statement too
– Steven Webster
Nov 15 '18 at 17:28
Thanks so much!
– pause
Nov 15 '18 at 21:07
add a comment |
0
0
0
You can do this with an array of words,
var profanities = ["test1", "test2", "..."];
then in your bot.on message handler, or how you use to handle messages,
bot.on('message', async message =>
let msg = message.content.toLowerCase();
let Admin = message.guild.roles.find('name', "Admin"); // Change this to meet what you want
let General = message.guild.channels.find(`name`, "general"); // All text channels are lowecase. Change this to meet what you want
for (x = 0; x < profanities.length; x++) message.channel.id === General.id) return; // if you changed the name of the variables above, change these too.
if (msg.includes(profanities[x]))
await message.reply("You cannot say that here!")
message.delete()
// Your code here
return;
);
EDIT:
This is very basic, it won't look for substitute letters such as $, @ or numbers/spaces unless you code those directly in, which you can have a list of words then have a console log every word with substitute letters.
answered Nov 2 '18 at 1:37
Steven WebsterSteven Webster
467
You can do this with an array of words,
var profanities = ["test1", "test2", "..."];
then in your bot.on message handler, or how you use to handle messages,
bot.on('message', async message =>
let msg = message.content.toLowerCase();
let Admin = message.guild.roles.find('name', "Admin"); // Change this to meet what you want
let General = message.guild.channels.find(`name`, "general"); // All text channels are lowecase. Change this to meet what you want
for (x = 0; x < profanities.length; x++) message.channel.id === General.id) return; // if you changed the name of the variables above, change these too.
if (msg.includes(profanities[x]))
await message.reply("You cannot say that here!")
message.delete()
// Your code here
return;
);
EDIT:
This is very basic, it won't look for substitute letters such as $, @ or numbers/spaces unless you code those directly in, which you can have a list of words then have a console log every word with substitute letters.
answered Nov 2 '18 at 1:37
Steven WebsterSteven Webster
467
edited Nov 15 '18 at 17:26
answered Nov 2 '18 at 1:37
Steven WebsterSteven Webster
467
answered Nov 2 '18 at 1:37
Steven WebsterSteven Webster
467
answered Nov 2 '18 at 1:37
Steven WebsterSteven Webster
467
467
Thanks! One more question, is there any way to make it to where Administrators bypass that? Or is there a way too make it ignore a certain channel?
– pause
Nov 12 '18 at 22:55
Yes, you can check if the sender has a certain role with this code, add it right under "let msg = ..." let role = message.guild.roles.find('name', "Case sensitive role name") message.member.roles.has(role.id), for your convience, I've updated the post
– Steven Webster
Nov 15 '18 at 16:45
I also forgot to say, you can check the channel as well! Both have been implemented in the code above, the 2 new variables are what you change. If you change the names of them make sure to do so in the new if statement too
– Steven Webster
Nov 15 '18 at 17:28
Thanks so much!
– pause
Nov 15 '18 at 21:07
add a comment |
Thanks! One more question, is there any way to make it to where Administrators bypass that? Or is there a way too make it ignore a certain channel?
– pause
Nov 12 '18 at 22:55
Yes, you can check if the sender has a certain role with this code, add it right under "let msg = ..." let role = message.guild.roles.find('name', "Case sensitive role name") message.member.roles.has(role.id), for your convience, I've updated the post
– Steven Webster
Nov 15 '18 at 16:45
I also forgot to say, you can check the channel as well! Both have been implemented in the code above, the 2 new variables are what you change. If you change the names of them make sure to do so in the new if statement too
– Steven Webster
Nov 15 '18 at 17:28
Thanks so much!
– pause
Nov 15 '18 at 21:07
Thanks! One more question, is there any way to make it to where Administrators bypass that? Or is there a way too make it ignore a certain channel?
– pause
Nov 12 '18 at 22:55
Thanks! One more question, is there any way to make it to where Administrators bypass that? Or is there a way too make it ignore a certain channel?
– pause
Nov 12 '18 at 22:55
Yes, you can check if the sender has a certain role with this code, add it right under "let msg = ..." let role = message.guild.roles.find('name', "Case sensitive role name") message.member.roles.has(role.id), for your convience, I've updated the post
– Steven Webster
Nov 15 '18 at 16:45
Yes, you can check if the sender has a certain role with this code, add it right under "let msg = ..." let role = message.guild.roles.find('name', "Case sensitive role name") message.member.roles.has(role.id), for your convience, I've updated the post
– Steven Webster
Nov 15 '18 at 16:45
I also forgot to say, you can check the channel as well! Both have been implemented in the code above, the 2 new variables are what you change. If you change the names of them make sure to do so in the new if statement too
– Steven Webster
Nov 15 '18 at 17:28
I also forgot to say, you can check the channel as well! Both have been implemented in the code above, the 2 new variables are what you change. If you change the names of them make sure to do so in the new if statement too
– Steven Webster
Nov 15 '18 at 17:28
Thanks so much!
– pause
Nov 15 '18 at 21:07
Thanks so much!
– pause
Nov 15 '18 at 21:07
add a comment |
-1
client.on('message', message =>
message.delete(message.content.replace(/asshole/gi))
.catch(console.error);
);
This is just a example you can make it, with a text array too.
edited Oct 29 '18 at 23:53
Nisse Engström
4,16292135
answered Oct 29 '18 at 23:36
Esdese EsdeathEsdese Esdeath
35
add a comment |
-1
client.on('message', message =>
message.delete(message.content.replace(/asshole/gi))
.catch(console.error);
);
This is just a example you can make it, with a text array too.
edited Oct 29 '18 at 23:53
Nisse Engström
4,16292135
answered Oct 29 '18 at 23:36
Esdese EsdeathEsdese Esdeath
35
add a comment |
-1
-1
-1
client.on('message', message =>
message.delete(message.content.replace(/asshole/gi))
.catch(console.error);
);
This is just a example you can make it, with a text array too.
edited Oct 29 '18 at 23:53
Nisse Engström
4,16292135
answered Oct 29 '18 at 23:36
Esdese EsdeathEsdese Esdeath
35
client.on('message', message =>
message.delete(message.content.replace(/asshole/gi))
.catch(console.error);
);
This is just a example you can make it, with a text array too.
edited Oct 29 '18 at 23:53
Nisse Engström
4,16292135
answered Oct 29 '18 at 23:36
Esdese EsdeathEsdese Esdeath
35
edited Oct 29 '18 at 23:53
Nisse Engström
4,16292135
edited Oct 29 '18 at 23:53
Nisse Engström
4,16292135
edited Oct 29 '18 at 23:53
Nisse Engström
4,16292135
4,16292135
answered Oct 29 '18 at 23:36
Esdese EsdeathEsdese Esdeath
35
answered Oct 29 '18 at 23:36
Esdese EsdeathEsdese Esdeath
35
answered Oct 29 '18 at 23:36
Esdese EsdeathEsdese Esdeath
35
35
add a comment |
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53054737%2fa-discordjs-chat-filter%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
See this answer.
– Obsidian Age
Oct 29 '18 at 22:24
1
Possible duplicate of "bad words" filter
– Wesam
Oct 29 '18 at 22:27
1
npmjs.com/package/bad-words
– Frustrated programmer
Oct 29 '18 at 23:17