Count of unique words in multiple text files in a folder using awk in windows
I have multiple files in a folder (d:text).
Using gawk (in windows), I want to generate a list of words and their occurence count in the format below:
a 12145
the 22483
but 754
etc.
awk
add a comment |
I have multiple files in a folder (d:text).
Using gawk (in windows), I want to generate a list of words and their occurence count in the format below:
a 12145
the 22483
but 754
etc.
awk
7
Cool - what have you tried so far?
– Mark Setchell
Nov 15 '18 at 15:58
add a comment |
I have multiple files in a folder (d:text).
Using gawk (in windows), I want to generate a list of words and their occurence count in the format below:
a 12145
the 22483
but 754
etc.
awk
I have multiple files in a folder (d:text).
Using gawk (in windows), I want to generate a list of words and their occurence count in the format below:
a 12145
the 22483
but 754
etc.
awk
awk
asked Nov 15 '18 at 15:47
user1955215user1955215
3102616
3102616
7
Cool - what have you tried so far?
– Mark Setchell
Nov 15 '18 at 15:58
add a comment |
7
Cool - what have you tried so far?
– Mark Setchell
Nov 15 '18 at 15:58
7
7
Cool - what have you tried so far?
– Mark Setchell
Nov 15 '18 at 15:58
Cool - what have you tried so far?
– Mark Setchell
Nov 15 '18 at 15:58
add a comment |
1 Answer
1
active
oldest
votes
Considering inputs:
$ ls ./in*
./in1.txt ./in2.txt
$ cat in*
What's up Buddy. How are you doin Buddy?
What's up Man. I am happy and good and awesome.
AWK counting words with associative array, words treated as alpha characters (You will need to tune up and also create logic for upper/lower cases etc.). Note there is also added count 4 for empty string:
$ gawk 'BEGIN RS="[^A-Za-z]"; words[$0]++; END for ( i in words ) print(i " " words[i]); ' ./in*
happy 1
are 1
4
What 2
awesome 1
How 1
Buddy 2
and 2
I 1
up 2
good 1
doin 1
am 1
Man 1
you 1
s 2
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Considering inputs:
$ ls ./in*
./in1.txt ./in2.txt
$ cat in*
What's up Buddy. How are you doin Buddy?
What's up Man. I am happy and good and awesome.
AWK counting words with associative array, words treated as alpha characters (You will need to tune up and also create logic for upper/lower cases etc.). Note there is also added count 4 for empty string:
$ gawk 'BEGIN RS="[^A-Za-z]"; words[$0]++; END for ( i in words ) print(i " " words[i]); ' ./in*
happy 1
are 1
4
What 2
awesome 1
How 1
Buddy 2
and 2
I 1
up 2
good 1
doin 1
am 1
Man 1
you 1
s 2
add a comment |
Considering inputs:
$ ls ./in*
./in1.txt ./in2.txt
$ cat in*
What's up Buddy. How are you doin Buddy?
What's up Man. I am happy and good and awesome.
AWK counting words with associative array, words treated as alpha characters (You will need to tune up and also create logic for upper/lower cases etc.). Note there is also added count 4 for empty string:
$ gawk 'BEGIN RS="[^A-Za-z]"; words[$0]++; END for ( i in words ) print(i " " words[i]); ' ./in*
happy 1
are 1
4
What 2
awesome 1
How 1
Buddy 2
and 2
I 1
up 2
good 1
doin 1
am 1
Man 1
you 1
s 2
add a comment |
Considering inputs:
$ ls ./in*
./in1.txt ./in2.txt
$ cat in*
What's up Buddy. How are you doin Buddy?
What's up Man. I am happy and good and awesome.
AWK counting words with associative array, words treated as alpha characters (You will need to tune up and also create logic for upper/lower cases etc.). Note there is also added count 4 for empty string:
$ gawk 'BEGIN RS="[^A-Za-z]"; words[$0]++; END for ( i in words ) print(i " " words[i]); ' ./in*
happy 1
are 1
4
What 2
awesome 1
How 1
Buddy 2
and 2
I 1
up 2
good 1
doin 1
am 1
Man 1
you 1
s 2
Considering inputs:
$ ls ./in*
./in1.txt ./in2.txt
$ cat in*
What's up Buddy. How are you doin Buddy?
What's up Man. I am happy and good and awesome.
AWK counting words with associative array, words treated as alpha characters (You will need to tune up and also create logic for upper/lower cases etc.). Note there is also added count 4 for empty string:
$ gawk 'BEGIN RS="[^A-Za-z]"; words[$0]++; END for ( i in words ) print(i " " words[i]); ' ./in*
happy 1
are 1
4
What 2
awesome 1
How 1
Buddy 2
and 2
I 1
up 2
good 1
doin 1
am 1
Man 1
you 1
s 2
edited Nov 20 '18 at 12:22
answered Nov 20 '18 at 9:26
KubatorKubator
74911
74911
add a comment |
add a comment |
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7
Cool - what have you tried so far?
– Mark Setchell
Nov 15 '18 at 15:58