double.ToString truncates last 2 digits while I can still see them while debugging

How to I get double.ToString to not sometimes truncate last digits.

If I show a double in Visualstudio Immediate window or Quickwatch I see 17 decimals. When I convert it to a string I see 15.

There is probably a good reason for this but my problem is how to get around it.

? 0.87912328514094507
0.87912328514094507
? 0.87912328514094507.ToString()
"0,879123285140945"

Dotnet 4.6.2 on a Win7 fwiw.

edited Nov 16 '18 at 12:16

asked Nov 16 '18 at 6:53

LosManos

3,51452767

2

0.87912328514094507.ToString("R") - round trip formatting - docs.microsoft.com/en-us/dotnet/standard/base-types/…

– Dmitry Bychenko
Nov 16 '18 at 6:54

1

Note that technically, both representations are truncating the underlying double. If your goal is to get an exact representation, you may want to consider using Jon Skeet's DoubleConverter class. See stackoverflow.com/a/1658420/18192 for discussion. Note that usually using the exact representation is inappropriate, since it displays more precision than a double can actually represent.

– Brian
Nov 16 '18 at 14:15

add a comment |

How to I get double.ToString to not sometimes truncate last digits.

? 0.87912328514094507
0.87912328514094507
? 0.87912328514094507.ToString()
"0,879123285140945"

Dotnet 4.6.2 on a Win7 fwiw.

edited Nov 16 '18 at 12:16

asked Nov 16 '18 at 6:53

LosManos

3,51452767

2

0.87912328514094507.ToString("R") - round trip formatting - docs.microsoft.com/en-us/dotnet/standard/base-types/…

– Dmitry Bychenko
Nov 16 '18 at 6:54

1

Note that technically, both representations are truncating the underlying double. If your goal is to get an exact representation, you may want to consider using Jon Skeet's DoubleConverter class. See stackoverflow.com/a/1658420/18192 for discussion. Note that usually using the exact representation is inappropriate, since it displays more precision than a double can actually represent.

– Brian
Nov 16 '18 at 14:15

add a comment |

How to I get double.ToString to not sometimes truncate last digits.

? 0.87912328514094507
0.87912328514094507
? 0.87912328514094507.ToString()
"0,879123285140945"

Dotnet 4.6.2 on a Win7 fwiw.

edited Nov 16 '18 at 12:16

asked Nov 16 '18 at 6:53

LosManos

3,51452767

How to I get double.ToString to not sometimes truncate last digits.

? 0.87912328514094507
0.87912328514094507
? 0.87912328514094507.ToString()
"0,879123285140945"

Dotnet 4.6.2 on a Win7 fwiw.

c# .net

edited Nov 16 '18 at 12:16

asked Nov 16 '18 at 6:53

LosManos

3,51452767

edited Nov 16 '18 at 12:16

asked Nov 16 '18 at 6:53

LosManos

3,51452767

edited Nov 16 '18 at 12:16

asked Nov 16 '18 at 6:53

LosManos

3,51452767

asked Nov 16 '18 at 6:53

LosManos

3,51452767

asked Nov 16 '18 at 6:53

LosManos

3,51452767

2

0.87912328514094507.ToString("R") - round trip formatting - docs.microsoft.com/en-us/dotnet/standard/base-types/…

– Dmitry Bychenko
Nov 16 '18 at 6:54

1

Note that technically, both representations are truncating the underlying double. If your goal is to get an exact representation, you may want to consider using Jon Skeet's DoubleConverter class. See stackoverflow.com/a/1658420/18192 for discussion. Note that usually using the exact representation is inappropriate, since it displays more precision than a double can actually represent.

– Brian
Nov 16 '18 at 14:15

add a comment |

2

0.87912328514094507.ToString("R") - round trip formatting - docs.microsoft.com/en-us/dotnet/standard/base-types/…

– Dmitry Bychenko
Nov 16 '18 at 6:54

1

Note that technically, both representations are truncating the underlying double. If your goal is to get an exact representation, you may want to consider using Jon Skeet's DoubleConverter class. See stackoverflow.com/a/1658420/18192 for discussion. Note that usually using the exact representation is inappropriate, since it displays more precision than a double can actually represent.

– Brian
Nov 16 '18 at 14:15

0.87912328514094507.ToString("R") - round trip formatting - docs.microsoft.com/en-us/dotnet/standard/base-types/…

– Dmitry Bychenko
Nov 16 '18 at 6:54

Note that technically, both representations are truncating the underlying double. If your goal is to get an exact representation, you may want to consider using Jon Skeet's DoubleConverter class. See stackoverflow.com/a/1658420/18192 for discussion. Note that usually using the exact representation is inappropriate, since it displays more precision than a double can actually represent.

– Brian
Nov 16 '18 at 14:15

add a comment |

1 Answer
1

active

oldest

votes

There are two standard mechanisms for achieving that.

If you pass "R" as the argument to ToString then you get the round trip string. That is, the string where converting the double to a string, then the string back to a double always gives you the double you started with.

If you pass "G17" as the argument then you get the standard string format but extended to 17 decimal places.

You can certainly be forgiven for not knowing that! This mechanism is not particularly discoverable. I'm not a big fan of how formatting strings have failed to evolve in the last 40 years.

For more details, read the documentation: https://docs.microsoft.com/en-us/dotnet/api/system.double.tostring

answered Nov 16 '18 at 6:58

Eric Lippert

547k14610681953

1

It seems "R" does not always work for double. In docs I read "For Double values, the "R" format specifier in some cases fails to successfully round-trip the original value. For both Double and Single values, it also offers relatively poor performance. Instead, we recommend that you use the "G17" format specifier for Double values and the "G9" format specifier to successfully round-trip Single values."

– LosManos
Nov 16 '18 at 7:30

Future readers: According to my comment @ericlippert 's comment was incorrect. As I understand ToString("G17") should be the correct answer. Should I remove the tick marking this answer as correct?

– LosManos
Nov 16 '18 at 12:18

add a comment |

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There are two standard mechanisms for achieving that.

If you pass "G17" as the argument then you get the standard string format but extended to 17 decimal places.

You can certainly be forgiven for not knowing that! This mechanism is not particularly discoverable. I'm not a big fan of how formatting strings have failed to evolve in the last 40 years.

For more details, read the documentation: https://docs.microsoft.com/en-us/dotnet/api/system.double.tostring

answered Nov 16 '18 at 6:58

Eric Lippert

547k14610681953

1

It seems "R" does not always work for double. In docs I read "For Double values, the "R" format specifier in some cases fails to successfully round-trip the original value. For both Double and Single values, it also offers relatively poor performance. Instead, we recommend that you use the "G17" format specifier for Double values and the "G9" format specifier to successfully round-trip Single values."

– LosManos
Nov 16 '18 at 7:30

Future readers: According to my comment @ericlippert 's comment was incorrect. As I understand ToString("G17") should be the correct answer. Should I remove the tick marking this answer as correct?

– LosManos
Nov 16 '18 at 12:18

add a comment |

There are two standard mechanisms for achieving that.

If you pass "G17" as the argument then you get the standard string format but extended to 17 decimal places.

You can certainly be forgiven for not knowing that! This mechanism is not particularly discoverable. I'm not a big fan of how formatting strings have failed to evolve in the last 40 years.

For more details, read the documentation: https://docs.microsoft.com/en-us/dotnet/api/system.double.tostring

answered Nov 16 '18 at 6:58

Eric Lippert

547k14610681953

1

It seems "R" does not always work for double. In docs I read "For Double values, the "R" format specifier in some cases fails to successfully round-trip the original value. For both Double and Single values, it also offers relatively poor performance. Instead, we recommend that you use the "G17" format specifier for Double values and the "G9" format specifier to successfully round-trip Single values."

– LosManos
Nov 16 '18 at 7:30

Future readers: According to my comment @ericlippert 's comment was incorrect. As I understand ToString("G17") should be the correct answer. Should I remove the tick marking this answer as correct?

– LosManos
Nov 16 '18 at 12:18

add a comment |

There are two standard mechanisms for achieving that.

If you pass "G17" as the argument then you get the standard string format but extended to 17 decimal places.

You can certainly be forgiven for not knowing that! This mechanism is not particularly discoverable. I'm not a big fan of how formatting strings have failed to evolve in the last 40 years.

For more details, read the documentation: https://docs.microsoft.com/en-us/dotnet/api/system.double.tostring

answered Nov 16 '18 at 6:58

Eric Lippert

547k14610681953

There are two standard mechanisms for achieving that.

If you pass "G17" as the argument then you get the standard string format but extended to 17 decimal places.

You can certainly be forgiven for not knowing that! This mechanism is not particularly discoverable. I'm not a big fan of how formatting strings have failed to evolve in the last 40 years.

For more details, read the documentation: https://docs.microsoft.com/en-us/dotnet/api/system.double.tostring

answered Nov 16 '18 at 6:58

Eric Lippert

547k14610681953

answered Nov 16 '18 at 6:58

Eric Lippert

547k14610681953

answered Nov 16 '18 at 6:58

Eric Lippert

547k14610681953

answered Nov 16 '18 at 6:58

Eric Lippert

547k14610681953

1

It seems "R" does not always work for double. In docs I read "For Double values, the "R" format specifier in some cases fails to successfully round-trip the original value. For both Double and Single values, it also offers relatively poor performance. Instead, we recommend that you use the "G17" format specifier for Double values and the "G9" format specifier to successfully round-trip Single values."

– LosManos
Nov 16 '18 at 7:30

Future readers: According to my comment @ericlippert 's comment was incorrect. As I understand ToString("G17") should be the correct answer. Should I remove the tick marking this answer as correct?

– LosManos
Nov 16 '18 at 12:18

add a comment |

1

It seems "R" does not always work for double. In docs I read "For Double values, the "R" format specifier in some cases fails to successfully round-trip the original value. For both Double and Single values, it also offers relatively poor performance. Instead, we recommend that you use the "G17" format specifier for Double values and the "G9" format specifier to successfully round-trip Single values."

– LosManos
Nov 16 '18 at 7:30

Future readers: According to my comment @ericlippert 's comment was incorrect. As I understand ToString("G17") should be the correct answer. Should I remove the tick marking this answer as correct?

– LosManos
Nov 16 '18 at 12:18

It seems "R" does not always work for double. In docs I read "For Double values, the "R" format specifier in some cases fails to successfully round-trip the original value. For both Double and Single values, it also offers relatively poor performance. Instead, we recommend that you use the "G17" format specifier for Double values and the "G9" format specifier to successfully round-trip Single values."

– LosManos
Nov 16 '18 at 7:30

Future readers: According to my comment @ericlippert 's comment was incorrect. As I understand ToString("G17") should be the correct answer. Should I remove the tick marking this answer as correct?

– LosManos
Nov 16 '18 at 12:18

add a comment |

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