How to log call graph in Elm?
Please help, this is driving me absolutely insane!
How do I make Elm log a call graph?
Sounds simple, doesn't it? The Debug.log
function should make this quiet easy. But no, try as I might, I just cannot force Elm to log the events in the correct order. I'm losing my mind here...
Let's take a trivial function like this:
factorial : Int -> Int
factorial n = if n < 2 then 1 else n * factorial (n-1)
What I want to do is write a custom trace
function so I can do something similar to
factorial n = trace ("factorial " + toString n) (if n < 2 ...)
and it will log something like
factorial 3: ENTER
factorial 2: ENTER
factorial 1: ENTER
factorial 1: 1
factorial 2: 2
factorial 3: 6
So you can see it enter each function, and you can see it return from each function (and what value it actually returned).
What doesn't work:
Obvious first attempt is to do something like
trace : String -> x -> x
trace label x =
let
_ = Debug.log label "ENTER"
_ = Debug.log label x
in xBut I don't think that can ever work. Since Elm is strict (?),
x
was evaluated before you ever even calledtrace
. So all the traces print out backwards.Alright, let's make the input a function then:
trace : String -> (() -> x) -> x
trace label fx =
let
_ = Debug.log label "ENTER"
x = fx ()
_ = Debug.log label x
in xThat really, really looks like it should work perfectly. But somehow, this manages to print the entry and exit together, followed by all of the subordinate calls afterwards, which is obviously wrong.
I'm particularly disturbed by the fact that
let
_ = Debug.log label "ENTER"
x = fx ()
in xprints all the enters forwards, yet the identical expression
let
_ = Debug.log label "ENTER"
in fx ()prints all the enters backwards. (??!) I guess that's what I get for trying to control order of side-effects in a pure-functional programming language...
Alright, let's make it a case-block then:
trace label fx =
case Debug.log label "ENTER" of
_ -> case Debug.log label (fx ()) of
x -> xNope, that prints everything backwards. Well that's weird. What if I just swap both of the case expressions? ...Nope, that prints enter+exit together followed by the child calls.
OK, let's get hard-core. Lambdas FTW!
trace label fx = Debug.log label (( _ -> fx ()) (Debug.log label "ENTER"))
That lots all the exits followed by all the enters. I'll just swap the expressions:
trace label fx = ( x -> ( _ -> x) (Debug.log label "ENTER")) (Debug.log label (fx ()))
No dice. That prints enter+exit for each call groups together again.
Umm...
Seriously, there must be a way to get this to work! >_<
Plz help... :'{
logging elm
add a comment |
Please help, this is driving me absolutely insane!
How do I make Elm log a call graph?
Sounds simple, doesn't it? The Debug.log
function should make this quiet easy. But no, try as I might, I just cannot force Elm to log the events in the correct order. I'm losing my mind here...
Let's take a trivial function like this:
factorial : Int -> Int
factorial n = if n < 2 then 1 else n * factorial (n-1)
What I want to do is write a custom trace
function so I can do something similar to
factorial n = trace ("factorial " + toString n) (if n < 2 ...)
and it will log something like
factorial 3: ENTER
factorial 2: ENTER
factorial 1: ENTER
factorial 1: 1
factorial 2: 2
factorial 3: 6
So you can see it enter each function, and you can see it return from each function (and what value it actually returned).
What doesn't work:
Obvious first attempt is to do something like
trace : String -> x -> x
trace label x =
let
_ = Debug.log label "ENTER"
_ = Debug.log label x
in xBut I don't think that can ever work. Since Elm is strict (?),
x
was evaluated before you ever even calledtrace
. So all the traces print out backwards.Alright, let's make the input a function then:
trace : String -> (() -> x) -> x
trace label fx =
let
_ = Debug.log label "ENTER"
x = fx ()
_ = Debug.log label x
in xThat really, really looks like it should work perfectly. But somehow, this manages to print the entry and exit together, followed by all of the subordinate calls afterwards, which is obviously wrong.
I'm particularly disturbed by the fact that
let
_ = Debug.log label "ENTER"
x = fx ()
in xprints all the enters forwards, yet the identical expression
let
_ = Debug.log label "ENTER"
in fx ()prints all the enters backwards. (??!) I guess that's what I get for trying to control order of side-effects in a pure-functional programming language...
Alright, let's make it a case-block then:
trace label fx =
case Debug.log label "ENTER" of
_ -> case Debug.log label (fx ()) of
x -> xNope, that prints everything backwards. Well that's weird. What if I just swap both of the case expressions? ...Nope, that prints enter+exit together followed by the child calls.
OK, let's get hard-core. Lambdas FTW!
trace label fx = Debug.log label (( _ -> fx ()) (Debug.log label "ENTER"))
That lots all the exits followed by all the enters. I'll just swap the expressions:
trace label fx = ( x -> ( _ -> x) (Debug.log label "ENTER")) (Debug.log label (fx ()))
No dice. That prints enter+exit for each call groups together again.
Umm...
Seriously, there must be a way to get this to work! >_<
Plz help... :'{
logging elm
add a comment |
Please help, this is driving me absolutely insane!
How do I make Elm log a call graph?
Sounds simple, doesn't it? The Debug.log
function should make this quiet easy. But no, try as I might, I just cannot force Elm to log the events in the correct order. I'm losing my mind here...
Let's take a trivial function like this:
factorial : Int -> Int
factorial n = if n < 2 then 1 else n * factorial (n-1)
What I want to do is write a custom trace
function so I can do something similar to
factorial n = trace ("factorial " + toString n) (if n < 2 ...)
and it will log something like
factorial 3: ENTER
factorial 2: ENTER
factorial 1: ENTER
factorial 1: 1
factorial 2: 2
factorial 3: 6
So you can see it enter each function, and you can see it return from each function (and what value it actually returned).
What doesn't work:
Obvious first attempt is to do something like
trace : String -> x -> x
trace label x =
let
_ = Debug.log label "ENTER"
_ = Debug.log label x
in xBut I don't think that can ever work. Since Elm is strict (?),
x
was evaluated before you ever even calledtrace
. So all the traces print out backwards.Alright, let's make the input a function then:
trace : String -> (() -> x) -> x
trace label fx =
let
_ = Debug.log label "ENTER"
x = fx ()
_ = Debug.log label x
in xThat really, really looks like it should work perfectly. But somehow, this manages to print the entry and exit together, followed by all of the subordinate calls afterwards, which is obviously wrong.
I'm particularly disturbed by the fact that
let
_ = Debug.log label "ENTER"
x = fx ()
in xprints all the enters forwards, yet the identical expression
let
_ = Debug.log label "ENTER"
in fx ()prints all the enters backwards. (??!) I guess that's what I get for trying to control order of side-effects in a pure-functional programming language...
Alright, let's make it a case-block then:
trace label fx =
case Debug.log label "ENTER" of
_ -> case Debug.log label (fx ()) of
x -> xNope, that prints everything backwards. Well that's weird. What if I just swap both of the case expressions? ...Nope, that prints enter+exit together followed by the child calls.
OK, let's get hard-core. Lambdas FTW!
trace label fx = Debug.log label (( _ -> fx ()) (Debug.log label "ENTER"))
That lots all the exits followed by all the enters. I'll just swap the expressions:
trace label fx = ( x -> ( _ -> x) (Debug.log label "ENTER")) (Debug.log label (fx ()))
No dice. That prints enter+exit for each call groups together again.
Umm...
Seriously, there must be a way to get this to work! >_<
Plz help... :'{
logging elm
Please help, this is driving me absolutely insane!
How do I make Elm log a call graph?
Sounds simple, doesn't it? The Debug.log
function should make this quiet easy. But no, try as I might, I just cannot force Elm to log the events in the correct order. I'm losing my mind here...
Let's take a trivial function like this:
factorial : Int -> Int
factorial n = if n < 2 then 1 else n * factorial (n-1)
What I want to do is write a custom trace
function so I can do something similar to
factorial n = trace ("factorial " + toString n) (if n < 2 ...)
and it will log something like
factorial 3: ENTER
factorial 2: ENTER
factorial 1: ENTER
factorial 1: 1
factorial 2: 2
factorial 3: 6
So you can see it enter each function, and you can see it return from each function (and what value it actually returned).
What doesn't work:
Obvious first attempt is to do something like
trace : String -> x -> x
trace label x =
let
_ = Debug.log label "ENTER"
_ = Debug.log label x
in xBut I don't think that can ever work. Since Elm is strict (?),
x
was evaluated before you ever even calledtrace
. So all the traces print out backwards.Alright, let's make the input a function then:
trace : String -> (() -> x) -> x
trace label fx =
let
_ = Debug.log label "ENTER"
x = fx ()
_ = Debug.log label x
in xThat really, really looks like it should work perfectly. But somehow, this manages to print the entry and exit together, followed by all of the subordinate calls afterwards, which is obviously wrong.
I'm particularly disturbed by the fact that
let
_ = Debug.log label "ENTER"
x = fx ()
in xprints all the enters forwards, yet the identical expression
let
_ = Debug.log label "ENTER"
in fx ()prints all the enters backwards. (??!) I guess that's what I get for trying to control order of side-effects in a pure-functional programming language...
Alright, let's make it a case-block then:
trace label fx =
case Debug.log label "ENTER" of
_ -> case Debug.log label (fx ()) of
x -> xNope, that prints everything backwards. Well that's weird. What if I just swap both of the case expressions? ...Nope, that prints enter+exit together followed by the child calls.
OK, let's get hard-core. Lambdas FTW!
trace label fx = Debug.log label (( _ -> fx ()) (Debug.log label "ENTER"))
That lots all the exits followed by all the enters. I'll just swap the expressions:
trace label fx = ( x -> ( _ -> x) (Debug.log label "ENTER")) (Debug.log label (fx ()))
No dice. That prints enter+exit for each call groups together again.
Umm...
Seriously, there must be a way to get this to work! >_<
Plz help... :'{
logging elm
logging elm
asked Nov 15 '18 at 20:27
MathematicalOrchidMathematicalOrchid
40.2k1598188
40.2k1598188
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
By using Debug.log
, you're trying to do something impure in a pure language. Even if you do get it to a point where it's working, as @Luke Woodward pointed out, I would hesitate relying on that because the log output could very well shift between compiler versions.
Instead, we could build a slimmed down Writer monad to keep a stateful representation of logs in the order they occur.
type Writer w a = Writer (a, List w)
runWriter : Writer w a -> (a, List w)
runWriter (Writer x) = x
pure : a -> Writer w a
pure x = Writer (x, )
andThen : (a -> Writer w b) -> Writer w a -> Writer w b
andThen f (Writer (x, v)) =
let (Writer (y, v_)) = f x
in Writer (y, v ++ v_)
log : String -> a -> Writer String a
log label x = Writer (x, [label ++ ": " ++ Debug.toString x])
You could then sprinkle it in your factorial function, which means the function would now have to return a Writer String Int
instead of just an Int
:
factorial : Int -> Writer String Int
factorial n =
let logic =
if n < 2 then
pure 1
else
factorial (n-1)
|> andThen (z -> pure (n * z))
in
log ("factorial " ++ Debug.toString n) "ENTER"
|> andThen (_ -> logic)
|> andThen (result -> log ("factorial " ++ Debug.toString n) result)
Though this looks more cumbersome and intrusive (Elm syntax is not as monad-friendly as Haskell), this will give you predictable results every time rather than having to depend upon unreliable side-effects.
The result of running factorial 3 |> runWriter |> Tuple.second
is:
[ "factorial 3: "ENTER""
, "factorial 2: "ENTER""
, "factorial 1: "ENTER""
, "factorial 1: 1"
, "factorial 2: 2"
, "factorial 3: 6"
]
Note that this writer is not optimized (it concatenates lists, yuck!) but the idea is tried and true
Yeah, trying to order side-effects in pure functions seems like it's fairly doomed to failure. I'm really just trying to do some quick and dirty debugging to find out why my (already very complicated) code doesn't produce the right answer...
– MathematicalOrchid
Nov 16 '18 at 13:01
Sadly, it seems this just isn't stable between compiler versions. Oh well... Maybe one day they'll add real debugging capabilities. (I did try using a JS debugger, but the generated code is just too incomprehensible.)
– MathematicalOrchid
Nov 16 '18 at 20:38
add a comment |
Try this:
trace : String -> (() -> x) -> x
trace label fx =
let
_ = Debug.log label "ENTER"
in
let
x = fx ()
_ = Debug.log label x
in
x
This appears to give your desired output.
Alternatively, since Debug.log
returns its second argument, you could also write the following, which is slightly shorter:
trace : String -> (() -> x) -> x
trace label fx =
let
_ = Debug.log label "ENTER"
in
let
x = fx ()
in
Debug.log label x
Taking a look at the generated code it seems the compiler was reordering the declarations within let
blocks. Using a nested let
block seems to persuade the compiler to not reorder the declarations.
If the declarations within the let
block don't have any dependencies then the compiler is free to reorder them as it doesn't change the value returned by the function. Also, if variables are declared out-of-order within a let
block, the compiler will sort them into the correct order. Take for example the following function:
silly : Int -> Int
silly x =
let
c = b
b = a
a = x
in
c * c
The Elm compiler cannot generate the three assignments in the let
block in the same order that they are declared: it cannot calculate c
without first knowing what b
is. Looking at the generated code for this function I can see that the assignments are sorted into order so that the output value is calculated correctly. What would you expect to happen if you put Debug.log
calls in the middle of this function?
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
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active
oldest
votes
By using Debug.log
, you're trying to do something impure in a pure language. Even if you do get it to a point where it's working, as @Luke Woodward pointed out, I would hesitate relying on that because the log output could very well shift between compiler versions.
Instead, we could build a slimmed down Writer monad to keep a stateful representation of logs in the order they occur.
type Writer w a = Writer (a, List w)
runWriter : Writer w a -> (a, List w)
runWriter (Writer x) = x
pure : a -> Writer w a
pure x = Writer (x, )
andThen : (a -> Writer w b) -> Writer w a -> Writer w b
andThen f (Writer (x, v)) =
let (Writer (y, v_)) = f x
in Writer (y, v ++ v_)
log : String -> a -> Writer String a
log label x = Writer (x, [label ++ ": " ++ Debug.toString x])
You could then sprinkle it in your factorial function, which means the function would now have to return a Writer String Int
instead of just an Int
:
factorial : Int -> Writer String Int
factorial n =
let logic =
if n < 2 then
pure 1
else
factorial (n-1)
|> andThen (z -> pure (n * z))
in
log ("factorial " ++ Debug.toString n) "ENTER"
|> andThen (_ -> logic)
|> andThen (result -> log ("factorial " ++ Debug.toString n) result)
Though this looks more cumbersome and intrusive (Elm syntax is not as monad-friendly as Haskell), this will give you predictable results every time rather than having to depend upon unreliable side-effects.
The result of running factorial 3 |> runWriter |> Tuple.second
is:
[ "factorial 3: "ENTER""
, "factorial 2: "ENTER""
, "factorial 1: "ENTER""
, "factorial 1: 1"
, "factorial 2: 2"
, "factorial 3: 6"
]
Note that this writer is not optimized (it concatenates lists, yuck!) but the idea is tried and true
Yeah, trying to order side-effects in pure functions seems like it's fairly doomed to failure. I'm really just trying to do some quick and dirty debugging to find out why my (already very complicated) code doesn't produce the right answer...
– MathematicalOrchid
Nov 16 '18 at 13:01
Sadly, it seems this just isn't stable between compiler versions. Oh well... Maybe one day they'll add real debugging capabilities. (I did try using a JS debugger, but the generated code is just too incomprehensible.)
– MathematicalOrchid
Nov 16 '18 at 20:38
add a comment |
By using Debug.log
, you're trying to do something impure in a pure language. Even if you do get it to a point where it's working, as @Luke Woodward pointed out, I would hesitate relying on that because the log output could very well shift between compiler versions.
Instead, we could build a slimmed down Writer monad to keep a stateful representation of logs in the order they occur.
type Writer w a = Writer (a, List w)
runWriter : Writer w a -> (a, List w)
runWriter (Writer x) = x
pure : a -> Writer w a
pure x = Writer (x, )
andThen : (a -> Writer w b) -> Writer w a -> Writer w b
andThen f (Writer (x, v)) =
let (Writer (y, v_)) = f x
in Writer (y, v ++ v_)
log : String -> a -> Writer String a
log label x = Writer (x, [label ++ ": " ++ Debug.toString x])
You could then sprinkle it in your factorial function, which means the function would now have to return a Writer String Int
instead of just an Int
:
factorial : Int -> Writer String Int
factorial n =
let logic =
if n < 2 then
pure 1
else
factorial (n-1)
|> andThen (z -> pure (n * z))
in
log ("factorial " ++ Debug.toString n) "ENTER"
|> andThen (_ -> logic)
|> andThen (result -> log ("factorial " ++ Debug.toString n) result)
Though this looks more cumbersome and intrusive (Elm syntax is not as monad-friendly as Haskell), this will give you predictable results every time rather than having to depend upon unreliable side-effects.
The result of running factorial 3 |> runWriter |> Tuple.second
is:
[ "factorial 3: "ENTER""
, "factorial 2: "ENTER""
, "factorial 1: "ENTER""
, "factorial 1: 1"
, "factorial 2: 2"
, "factorial 3: 6"
]
Note that this writer is not optimized (it concatenates lists, yuck!) but the idea is tried and true
Yeah, trying to order side-effects in pure functions seems like it's fairly doomed to failure. I'm really just trying to do some quick and dirty debugging to find out why my (already very complicated) code doesn't produce the right answer...
– MathematicalOrchid
Nov 16 '18 at 13:01
Sadly, it seems this just isn't stable between compiler versions. Oh well... Maybe one day they'll add real debugging capabilities. (I did try using a JS debugger, but the generated code is just too incomprehensible.)
– MathematicalOrchid
Nov 16 '18 at 20:38
add a comment |
By using Debug.log
, you're trying to do something impure in a pure language. Even if you do get it to a point where it's working, as @Luke Woodward pointed out, I would hesitate relying on that because the log output could very well shift between compiler versions.
Instead, we could build a slimmed down Writer monad to keep a stateful representation of logs in the order they occur.
type Writer w a = Writer (a, List w)
runWriter : Writer w a -> (a, List w)
runWriter (Writer x) = x
pure : a -> Writer w a
pure x = Writer (x, )
andThen : (a -> Writer w b) -> Writer w a -> Writer w b
andThen f (Writer (x, v)) =
let (Writer (y, v_)) = f x
in Writer (y, v ++ v_)
log : String -> a -> Writer String a
log label x = Writer (x, [label ++ ": " ++ Debug.toString x])
You could then sprinkle it in your factorial function, which means the function would now have to return a Writer String Int
instead of just an Int
:
factorial : Int -> Writer String Int
factorial n =
let logic =
if n < 2 then
pure 1
else
factorial (n-1)
|> andThen (z -> pure (n * z))
in
log ("factorial " ++ Debug.toString n) "ENTER"
|> andThen (_ -> logic)
|> andThen (result -> log ("factorial " ++ Debug.toString n) result)
Though this looks more cumbersome and intrusive (Elm syntax is not as monad-friendly as Haskell), this will give you predictable results every time rather than having to depend upon unreliable side-effects.
The result of running factorial 3 |> runWriter |> Tuple.second
is:
[ "factorial 3: "ENTER""
, "factorial 2: "ENTER""
, "factorial 1: "ENTER""
, "factorial 1: 1"
, "factorial 2: 2"
, "factorial 3: 6"
]
Note that this writer is not optimized (it concatenates lists, yuck!) but the idea is tried and true
By using Debug.log
, you're trying to do something impure in a pure language. Even if you do get it to a point where it's working, as @Luke Woodward pointed out, I would hesitate relying on that because the log output could very well shift between compiler versions.
Instead, we could build a slimmed down Writer monad to keep a stateful representation of logs in the order they occur.
type Writer w a = Writer (a, List w)
runWriter : Writer w a -> (a, List w)
runWriter (Writer x) = x
pure : a -> Writer w a
pure x = Writer (x, )
andThen : (a -> Writer w b) -> Writer w a -> Writer w b
andThen f (Writer (x, v)) =
let (Writer (y, v_)) = f x
in Writer (y, v ++ v_)
log : String -> a -> Writer String a
log label x = Writer (x, [label ++ ": " ++ Debug.toString x])
You could then sprinkle it in your factorial function, which means the function would now have to return a Writer String Int
instead of just an Int
:
factorial : Int -> Writer String Int
factorial n =
let logic =
if n < 2 then
pure 1
else
factorial (n-1)
|> andThen (z -> pure (n * z))
in
log ("factorial " ++ Debug.toString n) "ENTER"
|> andThen (_ -> logic)
|> andThen (result -> log ("factorial " ++ Debug.toString n) result)
Though this looks more cumbersome and intrusive (Elm syntax is not as monad-friendly as Haskell), this will give you predictable results every time rather than having to depend upon unreliable side-effects.
The result of running factorial 3 |> runWriter |> Tuple.second
is:
[ "factorial 3: "ENTER""
, "factorial 2: "ENTER""
, "factorial 1: "ENTER""
, "factorial 1: 1"
, "factorial 2: 2"
, "factorial 3: 6"
]
Note that this writer is not optimized (it concatenates lists, yuck!) but the idea is tried and true
answered Nov 16 '18 at 12:42
Chad GilbertChad Gilbert
31k35977
31k35977
Yeah, trying to order side-effects in pure functions seems like it's fairly doomed to failure. I'm really just trying to do some quick and dirty debugging to find out why my (already very complicated) code doesn't produce the right answer...
– MathematicalOrchid
Nov 16 '18 at 13:01
Sadly, it seems this just isn't stable between compiler versions. Oh well... Maybe one day they'll add real debugging capabilities. (I did try using a JS debugger, but the generated code is just too incomprehensible.)
– MathematicalOrchid
Nov 16 '18 at 20:38
add a comment |
Yeah, trying to order side-effects in pure functions seems like it's fairly doomed to failure. I'm really just trying to do some quick and dirty debugging to find out why my (already very complicated) code doesn't produce the right answer...
– MathematicalOrchid
Nov 16 '18 at 13:01
Sadly, it seems this just isn't stable between compiler versions. Oh well... Maybe one day they'll add real debugging capabilities. (I did try using a JS debugger, but the generated code is just too incomprehensible.)
– MathematicalOrchid
Nov 16 '18 at 20:38
Yeah, trying to order side-effects in pure functions seems like it's fairly doomed to failure. I'm really just trying to do some quick and dirty debugging to find out why my (already very complicated) code doesn't produce the right answer...
– MathematicalOrchid
Nov 16 '18 at 13:01
Yeah, trying to order side-effects in pure functions seems like it's fairly doomed to failure. I'm really just trying to do some quick and dirty debugging to find out why my (already very complicated) code doesn't produce the right answer...
– MathematicalOrchid
Nov 16 '18 at 13:01
Sadly, it seems this just isn't stable between compiler versions. Oh well... Maybe one day they'll add real debugging capabilities. (I did try using a JS debugger, but the generated code is just too incomprehensible.)
– MathematicalOrchid
Nov 16 '18 at 20:38
Sadly, it seems this just isn't stable between compiler versions. Oh well... Maybe one day they'll add real debugging capabilities. (I did try using a JS debugger, but the generated code is just too incomprehensible.)
– MathematicalOrchid
Nov 16 '18 at 20:38
add a comment |
Try this:
trace : String -> (() -> x) -> x
trace label fx =
let
_ = Debug.log label "ENTER"
in
let
x = fx ()
_ = Debug.log label x
in
x
This appears to give your desired output.
Alternatively, since Debug.log
returns its second argument, you could also write the following, which is slightly shorter:
trace : String -> (() -> x) -> x
trace label fx =
let
_ = Debug.log label "ENTER"
in
let
x = fx ()
in
Debug.log label x
Taking a look at the generated code it seems the compiler was reordering the declarations within let
blocks. Using a nested let
block seems to persuade the compiler to not reorder the declarations.
If the declarations within the let
block don't have any dependencies then the compiler is free to reorder them as it doesn't change the value returned by the function. Also, if variables are declared out-of-order within a let
block, the compiler will sort them into the correct order. Take for example the following function:
silly : Int -> Int
silly x =
let
c = b
b = a
a = x
in
c * c
The Elm compiler cannot generate the three assignments in the let
block in the same order that they are declared: it cannot calculate c
without first knowing what b
is. Looking at the generated code for this function I can see that the assignments are sorted into order so that the output value is calculated correctly. What would you expect to happen if you put Debug.log
calls in the middle of this function?
add a comment |
Try this:
trace : String -> (() -> x) -> x
trace label fx =
let
_ = Debug.log label "ENTER"
in
let
x = fx ()
_ = Debug.log label x
in
x
This appears to give your desired output.
Alternatively, since Debug.log
returns its second argument, you could also write the following, which is slightly shorter:
trace : String -> (() -> x) -> x
trace label fx =
let
_ = Debug.log label "ENTER"
in
let
x = fx ()
in
Debug.log label x
Taking a look at the generated code it seems the compiler was reordering the declarations within let
blocks. Using a nested let
block seems to persuade the compiler to not reorder the declarations.
If the declarations within the let
block don't have any dependencies then the compiler is free to reorder them as it doesn't change the value returned by the function. Also, if variables are declared out-of-order within a let
block, the compiler will sort them into the correct order. Take for example the following function:
silly : Int -> Int
silly x =
let
c = b
b = a
a = x
in
c * c
The Elm compiler cannot generate the three assignments in the let
block in the same order that they are declared: it cannot calculate c
without first knowing what b
is. Looking at the generated code for this function I can see that the assignments are sorted into order so that the output value is calculated correctly. What would you expect to happen if you put Debug.log
calls in the middle of this function?
add a comment |
Try this:
trace : String -> (() -> x) -> x
trace label fx =
let
_ = Debug.log label "ENTER"
in
let
x = fx ()
_ = Debug.log label x
in
x
This appears to give your desired output.
Alternatively, since Debug.log
returns its second argument, you could also write the following, which is slightly shorter:
trace : String -> (() -> x) -> x
trace label fx =
let
_ = Debug.log label "ENTER"
in
let
x = fx ()
in
Debug.log label x
Taking a look at the generated code it seems the compiler was reordering the declarations within let
blocks. Using a nested let
block seems to persuade the compiler to not reorder the declarations.
If the declarations within the let
block don't have any dependencies then the compiler is free to reorder them as it doesn't change the value returned by the function. Also, if variables are declared out-of-order within a let
block, the compiler will sort them into the correct order. Take for example the following function:
silly : Int -> Int
silly x =
let
c = b
b = a
a = x
in
c * c
The Elm compiler cannot generate the three assignments in the let
block in the same order that they are declared: it cannot calculate c
without first knowing what b
is. Looking at the generated code for this function I can see that the assignments are sorted into order so that the output value is calculated correctly. What would you expect to happen if you put Debug.log
calls in the middle of this function?
Try this:
trace : String -> (() -> x) -> x
trace label fx =
let
_ = Debug.log label "ENTER"
in
let
x = fx ()
_ = Debug.log label x
in
x
This appears to give your desired output.
Alternatively, since Debug.log
returns its second argument, you could also write the following, which is slightly shorter:
trace : String -> (() -> x) -> x
trace label fx =
let
_ = Debug.log label "ENTER"
in
let
x = fx ()
in
Debug.log label x
Taking a look at the generated code it seems the compiler was reordering the declarations within let
blocks. Using a nested let
block seems to persuade the compiler to not reorder the declarations.
If the declarations within the let
block don't have any dependencies then the compiler is free to reorder them as it doesn't change the value returned by the function. Also, if variables are declared out-of-order within a let
block, the compiler will sort them into the correct order. Take for example the following function:
silly : Int -> Int
silly x =
let
c = b
b = a
a = x
in
c * c
The Elm compiler cannot generate the three assignments in the let
block in the same order that they are declared: it cannot calculate c
without first knowing what b
is. Looking at the generated code for this function I can see that the assignments are sorted into order so that the output value is calculated correctly. What would you expect to happen if you put Debug.log
calls in the middle of this function?
answered Nov 16 '18 at 10:34
Luke WoodwardLuke Woodward
45.5k126688
45.5k126688
add a comment |
add a comment |
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