Is there an iOS accelerate methods for doing elementwise maximum (np.maximum)?
I am investigating using iOS Accelerate to perform some fast math on a mobile device. I would need the equivalent of np.maximum in numpy. This is an element wise maximum between 2 ndarray.
I have been searching documentations related to Apple Accelerate Framework, and I found nothing within it that can directly perform this.
Note: The Q was answered correctly below and tested with:
let a: [Float] = [2, 4, 3, 8, 1, 10]
let b: [Float] = [1, 5, 2, 1, 9, 1]
var c: [Float] = [0.0, 0.0, 0.0, 0.0, 0.0, 0.0]
vDSP_vmax(a, 1, b, 1, &c, 1, 6)
c
in a Xcode Playground.
ios frameworks max lapack accelerate
asked Nov 16 '18 at 0:48
kawingkelvinkawingkelvin
550416
add a comment |
I am investigating using iOS Accelerate to perform some fast math on a mobile device. I would need the equivalent of np.maximum in numpy. This is an element wise maximum between 2 ndarray.
I have been searching documentations related to Apple Accelerate Framework, and I found nothing within it that can directly perform this.
Note: The Q was answered correctly below and tested with:
let a: [Float] = [2, 4, 3, 8, 1, 10]
let b: [Float] = [1, 5, 2, 1, 9, 1]
var c: [Float] = [0.0, 0.0, 0.0, 0.0, 0.0, 0.0]
vDSP_vmax(a, 1, b, 1, &c, 1, 6)
c
in a Xcode Playground.
ios frameworks max lapack accelerate
asked Nov 16 '18 at 0:48
kawingkelvinkawingkelvin
550416
add a comment |
I am investigating using iOS Accelerate to perform some fast math on a mobile device. I would need the equivalent of np.maximum in numpy. This is an element wise maximum between 2 ndarray.
I have been searching documentations related to Apple Accelerate Framework, and I found nothing within it that can directly perform this.
Note: The Q was answered correctly below and tested with:
let a: [Float] = [2, 4, 3, 8, 1, 10]
let b: [Float] = [1, 5, 2, 1, 9, 1]
var c: [Float] = [0.0, 0.0, 0.0, 0.0, 0.0, 0.0]
vDSP_vmax(a, 1, b, 1, &c, 1, 6)
c
in a Xcode Playground.
ios frameworks max lapack accelerate
asked Nov 16 '18 at 0:48
kawingkelvinkawingkelvin
550416
I am investigating using iOS Accelerate to perform some fast math on a mobile device. I would need the equivalent of np.maximum in numpy. This is an element wise maximum between 2 ndarray.
I have been searching documentations related to Apple Accelerate Framework, and I found nothing within it that can directly perform this.
Note: The Q was answered correctly below and tested with:
let a: [Float] = [2, 4, 3, 8, 1, 10]
let b: [Float] = [1, 5, 2, 1, 9, 1]
var c: [Float] = [0.0, 0.0, 0.0, 0.0, 0.0, 0.0]
vDSP_vmax(a, 1, b, 1, &c, 1, 6)
c
in a Xcode Playground.
ios frameworks max lapack accelerate
ios frameworks max lapack accelerate
asked Nov 16 '18 at 0:48
kawingkelvinkawingkelvin
550416
asked Nov 16 '18 at 0:48
kawingkelvinkawingkelvin
550416
edited Nov 16 '18 at 1:53
kawingkelvin
asked Nov 16 '18 at 0:48
kawingkelvinkawingkelvin
550416
asked Nov 16 '18 at 0:48
kawingkelvinkawingkelvin
550416
asked Nov 16 '18 at 0:48
kawingkelvinkawingkelvin
550416
550416
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Check vDSP_vmaxD(). It's what you want.
answered Nov 16 '18 at 1:41
E.ComsE.Coms
2,8682415
This looks like what I wanted. I noticed this isn't under Accelerate Framework documentation, it is actually under Kernel. I wonder why they organized it this way. Let me give this a try, and will upvote if i get to work.
– kawingkelvin
Nov 16 '18 at 1:45
Yes, this is exactly what i wanted. I tried: let a: [Float] = [2, 4, 3, 8, 1, 10] let b: [Float] = [1, 5, 2, 1, 9, 1] var c: [Float] = [0.0, 0.0, 0.0, 0.0, 0.0, 0.0] vDSP_vmax(a, 1, b, 1, &c, 1, 6)
– kawingkelvin
Nov 16 '18 at 1:50
add a comment |
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1 Answer
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1 Answer
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active
oldest
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votes
Check vDSP_vmaxD(). It's what you want.
answered Nov 16 '18 at 1:41
E.ComsE.Coms
2,8682415
This looks like what I wanted. I noticed this isn't under Accelerate Framework documentation, it is actually under Kernel. I wonder why they organized it this way. Let me give this a try, and will upvote if i get to work.
– kawingkelvin
Nov 16 '18 at 1:45
Yes, this is exactly what i wanted. I tried: let a: [Float] = [2, 4, 3, 8, 1, 10] let b: [Float] = [1, 5, 2, 1, 9, 1] var c: [Float] = [0.0, 0.0, 0.0, 0.0, 0.0, 0.0] vDSP_vmax(a, 1, b, 1, &c, 1, 6)
– kawingkelvin
Nov 16 '18 at 1:50
add a comment |
Check vDSP_vmaxD(). It's what you want.
answered Nov 16 '18 at 1:41
E.ComsE.Coms
2,8682415
This looks like what I wanted. I noticed this isn't under Accelerate Framework documentation, it is actually under Kernel. I wonder why they organized it this way. Let me give this a try, and will upvote if i get to work.
– kawingkelvin
Nov 16 '18 at 1:45
Yes, this is exactly what i wanted. I tried: let a: [Float] = [2, 4, 3, 8, 1, 10] let b: [Float] = [1, 5, 2, 1, 9, 1] var c: [Float] = [0.0, 0.0, 0.0, 0.0, 0.0, 0.0] vDSP_vmax(a, 1, b, 1, &c, 1, 6)
– kawingkelvin
Nov 16 '18 at 1:50
add a comment |
Check vDSP_vmaxD(). It's what you want.
answered Nov 16 '18 at 1:41
E.ComsE.Coms
2,8682415
Check vDSP_vmaxD(). It's what you want.
answered Nov 16 '18 at 1:41
E.ComsE.Coms
2,8682415
answered Nov 16 '18 at 1:41
E.ComsE.Coms
2,8682415
answered Nov 16 '18 at 1:41
E.ComsE.Coms
2,8682415
answered Nov 16 '18 at 1:41
E.ComsE.Coms
2,8682415
2,8682415
This looks like what I wanted. I noticed this isn't under Accelerate Framework documentation, it is actually under Kernel. I wonder why they organized it this way. Let me give this a try, and will upvote if i get to work.
– kawingkelvin
Nov 16 '18 at 1:45
Yes, this is exactly what i wanted. I tried: let a: [Float] = [2, 4, 3, 8, 1, 10] let b: [Float] = [1, 5, 2, 1, 9, 1] var c: [Float] = [0.0, 0.0, 0.0, 0.0, 0.0, 0.0] vDSP_vmax(a, 1, b, 1, &c, 1, 6)
– kawingkelvin
Nov 16 '18 at 1:50
add a comment |
This looks like what I wanted. I noticed this isn't under Accelerate Framework documentation, it is actually under Kernel. I wonder why they organized it this way. Let me give this a try, and will upvote if i get to work.
– kawingkelvin
Nov 16 '18 at 1:45
Yes, this is exactly what i wanted. I tried: let a: [Float] = [2, 4, 3, 8, 1, 10] let b: [Float] = [1, 5, 2, 1, 9, 1] var c: [Float] = [0.0, 0.0, 0.0, 0.0, 0.0, 0.0] vDSP_vmax(a, 1, b, 1, &c, 1, 6)
– kawingkelvin
Nov 16 '18 at 1:50
This looks like what I wanted. I noticed this isn't under Accelerate Framework documentation, it is actually under Kernel. I wonder why they organized it this way. Let me give this a try, and will upvote if i get to work.
– kawingkelvin
Nov 16 '18 at 1:45
This looks like what I wanted. I noticed this isn't under Accelerate Framework documentation, it is actually under Kernel. I wonder why they organized it this way. Let me give this a try, and will upvote if i get to work.
– kawingkelvin
Nov 16 '18 at 1:45
Yes, this is exactly what i wanted. I tried: let a: [Float] = [2, 4, 3, 8, 1, 10] let b: [Float] = [1, 5, 2, 1, 9, 1] var c: [Float] = [0.0, 0.0, 0.0, 0.0, 0.0, 0.0] vDSP_vmax(a, 1, b, 1, &c, 1, 6)
– kawingkelvin
Nov 16 '18 at 1:50
Yes, this is exactly what i wanted. I tried: let a: [Float] = [2, 4, 3, 8, 1, 10] let b: [Float] = [1, 5, 2, 1, 9, 1] var c: [Float] = [0.0, 0.0, 0.0, 0.0, 0.0, 0.0] vDSP_vmax(a, 1, b, 1, &c, 1, 6)
– kawingkelvin
Nov 16 '18 at 1:50
add a comment |
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