Filter repeated keys
1
Please I'm new to this. I have searched, what I saw left me confused.
How can I reduce duplicated items in an array and add the values of the duplicated key to the unique one like below.
I want to have it like arrayA
let arrayA = [
name: "temperature", data: "2000-09-26": 82 ,
name: "temperature", data: "1997-03-08": 71 ,
name: "current", data: "1993-08-11": 79 ,
name: "frequency", data: "2004-01-17": 16 ,
name: "current", data: "1997-02-14": 65
]
let arrayB = [
name: "temperature", data: "2000-09-26": 82, "1997-03-08": 71 ,
name: "current", data: "1993-08-11": 79, "1997-02-14": 65 ,
name: "frequency", data: "2004-01-17": 16
]
javascript arrays
asked Nov 16 '18 at 8:42
obi patrickobi patrick
214
add a comment |
1
Please I'm new to this. I have searched, what I saw left me confused.
How can I reduce duplicated items in an array and add the values of the duplicated key to the unique one like below.
I want to have it like arrayA
let arrayA = [
name: "temperature", data: "2000-09-26": 82 ,
name: "temperature", data: "1997-03-08": 71 ,
name: "current", data: "1993-08-11": 79 ,
name: "frequency", data: "2004-01-17": 16 ,
name: "current", data: "1997-02-14": 65
]
let arrayB = [
name: "temperature", data: "2000-09-26": 82, "1997-03-08": 71 ,
name: "current", data: "1993-08-11": 79, "1997-02-14": 65 ,
name: "frequency", data: "2004-01-17": 16
]
javascript arrays
asked Nov 16 '18 at 8:42
obi patrickobi patrick
214
1
would you like to go from a to b or from b to a? btw, what have you tried?
– Nina Scholz
Nov 16 '18 at 8:44
I want to go from a to b
– obi patrick
Nov 16 '18 at 8:47
What I tried was using variable as the key
– obi patrick
Nov 16 '18 at 8:49
add a comment |
1
1
1
Please I'm new to this. I have searched, what I saw left me confused.
How can I reduce duplicated items in an array and add the values of the duplicated key to the unique one like below.
I want to have it like arrayA
let arrayA = [
name: "temperature", data: "2000-09-26": 82 ,
name: "temperature", data: "1997-03-08": 71 ,
name: "current", data: "1993-08-11": 79 ,
name: "frequency", data: "2004-01-17": 16 ,
name: "current", data: "1997-02-14": 65
]
let arrayB = [
name: "temperature", data: "2000-09-26": 82, "1997-03-08": 71 ,
name: "current", data: "1993-08-11": 79, "1997-02-14": 65 ,
name: "frequency", data: "2004-01-17": 16
]
javascript arrays
asked Nov 16 '18 at 8:42
obi patrickobi patrick
214
Please I'm new to this. I have searched, what I saw left me confused.
How can I reduce duplicated items in an array and add the values of the duplicated key to the unique one like below.
I want to have it like arrayA
let arrayA = [
name: "temperature", data: "2000-09-26": 82 ,
name: "temperature", data: "1997-03-08": 71 ,
name: "current", data: "1993-08-11": 79 ,
name: "frequency", data: "2004-01-17": 16 ,
name: "current", data: "1997-02-14": 65
]
let arrayB = [
name: "temperature", data: "2000-09-26": 82, "1997-03-08": 71 ,
name: "current", data: "1993-08-11": 79, "1997-02-14": 65 ,
name: "frequency", data: "2004-01-17": 16
]
javascript arrays
javascript arrays
asked Nov 16 '18 at 8:42
obi patrickobi patrick
214
asked Nov 16 '18 at 8:42
obi patrickobi patrick
214
asked Nov 16 '18 at 8:42
obi patrickobi patrick
214
asked Nov 16 '18 at 8:42
obi patrickobi patrick
214
asked Nov 16 '18 at 8:42
obi patrickobi patrick
214
214
1
would you like to go from a to b or from b to a? btw, what have you tried?
– Nina Scholz
Nov 16 '18 at 8:44
I want to go from a to b
– obi patrick
Nov 16 '18 at 8:47
What I tried was using variable as the key
– obi patrick
Nov 16 '18 at 8:49
add a comment |
1
would you like to go from a to b or from b to a? btw, what have you tried?
– Nina Scholz
Nov 16 '18 at 8:44
I want to go from a to b
– obi patrick
Nov 16 '18 at 8:47
What I tried was using variable as the key
– obi patrick
Nov 16 '18 at 8:49
1
1
would you like to go from a to b or from b to a? btw, what have you tried?
– Nina Scholz
Nov 16 '18 at 8:44
would you like to go from a to b or from b to a? btw, what have you tried?
– Nina Scholz
Nov 16 '18 at 8:44
I want to go from a to b
– obi patrick
Nov 16 '18 at 8:47
I want to go from a to b
– obi patrick
Nov 16 '18 at 8:47
What I tried was using variable as the key
– obi patrick
Nov 16 '18 at 8:49
What I tried was using variable as the key
– obi patrick
Nov 16 '18 at 8:49
add a comment |
3 Answers
3
active
oldest
votes
2
You can use array#reduce and Object.values(). Create a hash of name and add the data value for a given name. Then get the values from the object using Object.values().
let arrayA = [ name: "temperature", data: "2000-09-26": 82 , name: "temperature", data: "1997-03-08": 71 , name: "current", data: "1993-08-11": 79 , name: "frequency", data: "2004-01-17": 16 , name: "current", data: "1997-02-14":
65 ],
result = Object.values(arrayA.reduce((r,name, data) => ,));
console.log(result);answered Nov 16 '18 at 8:49
Hassan ImamHassan Imam
12k31532
add a comment |
0
Here you are
let arrayB = arrayA.reduce((acc, curr) =>
const found = acc.find(i => i.name === curr.name)
if (found)
// If this object is already there, merge their `data` property
Object.assign(found.data, curr.data)
else
// Otherwise add to the accumulator (`acc`)
acc.push(curr)
return acc
, )
Reference to the reduce function:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/reduce
answered Nov 16 '18 at 8:53
Nurbol AlpysbayevNurbol Alpysbayev
4,8091533
add a comment |
0
var arrayA = [ name: "temperature", data: "2000-09-26": 82 , name: "temperature", data: "1997-03-08": 71 , name: "current", data: "1993-08-11": 79 , name: "frequency", data: "2004-01-17": 16 , name: "current", data: "1997-02-14": 65 ]
var arrayB=_.map(_.groupBy(arrayA, 'name'),function(list)
return _.reduce(list,function(nObj,obj)
if(nObj.data && _.difference(_.keys(nObj.data),_.keys(obj.data)))
nObj.data=_.assign(nObj.data,obj.data)
else
nObj=obj
return nObj
,)
)
console.log(arrayB)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.5.1/lodash.js"></script>answered Nov 16 '18 at 9:35
Pritam JanaPritam Jana
10913
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
You can use array#reduce and Object.values(). Create a hash of name and add the data value for a given name. Then get the values from the object using Object.values().
let arrayA = [ name: "temperature", data: "2000-09-26": 82 , name: "temperature", data: "1997-03-08": 71 , name: "current", data: "1993-08-11": 79 , name: "frequency", data: "2004-01-17": 16 , name: "current", data: "1997-02-14":
65 ],
result = Object.values(arrayA.reduce((r,name, data) => ,));
console.log(result);answered Nov 16 '18 at 8:49
Hassan ImamHassan Imam
12k31532
add a comment |
2
You can use array#reduce and Object.values(). Create a hash of name and add the data value for a given name. Then get the values from the object using Object.values().
let arrayA = [ name: "temperature", data: "2000-09-26": 82 , name: "temperature", data: "1997-03-08": 71 , name: "current", data: "1993-08-11": 79 , name: "frequency", data: "2004-01-17": 16 , name: "current", data: "1997-02-14":
65 ],
result = Object.values(arrayA.reduce((r,name, data) => ,));
console.log(result);answered Nov 16 '18 at 8:49
Hassan ImamHassan Imam
12k31532
add a comment |
2
2
2
You can use array#reduce and Object.values(). Create a hash of name and add the data value for a given name. Then get the values from the object using Object.values().
let arrayA = [ name: "temperature", data: "2000-09-26": 82 , name: "temperature", data: "1997-03-08": 71 , name: "current", data: "1993-08-11": 79 , name: "frequency", data: "2004-01-17": 16 , name: "current", data: "1997-02-14":
65 ],
result = Object.values(arrayA.reduce((r,name, data) => ,));
console.log(result);answered Nov 16 '18 at 8:49
Hassan ImamHassan Imam
12k31532
You can use array#reduce and Object.values(). Create a hash of name and add the data value for a given name. Then get the values from the object using Object.values().
let arrayA = [ name: "temperature", data: "2000-09-26": 82 , name: "temperature", data: "1997-03-08": 71 , name: "current", data: "1993-08-11": 79 , name: "frequency", data: "2004-01-17": 16 , name: "current", data: "1997-02-14":
65 ],
result = Object.values(arrayA.reduce((r,name, data) => ,));
console.log(result);let arrayA = [ name: "temperature", data: "2000-09-26": 82 , name: "temperature", data: "1997-03-08": 71 , name: "current", data: "1993-08-11": 79 , name: "frequency", data: "2004-01-17": 16 , name: "current", data: "1997-02-14":
65 ],
result = Object.values(arrayA.reduce((r,name, data) => ,));
console.log(result);let arrayA = [ name: "temperature", data: "2000-09-26": 82 , name: "temperature", data: "1997-03-08": 71 , name: "current", data: "1993-08-11": 79 , name: "frequency", data: "2004-01-17": 16 , name: "current", data: "1997-02-14":
65 ],
result = Object.values(arrayA.reduce((r,name, data) => ,));
console.log(result);answered Nov 16 '18 at 8:49
Hassan ImamHassan Imam
12k31532
answered Nov 16 '18 at 8:49
Hassan ImamHassan Imam
12k31532
answered Nov 16 '18 at 8:49
Hassan ImamHassan Imam
12k31532
answered Nov 16 '18 at 8:49
Hassan ImamHassan Imam
12k31532
12k31532
add a comment |
add a comment |
0
Here you are
let arrayB = arrayA.reduce((acc, curr) =>
const found = acc.find(i => i.name === curr.name)
if (found)
// If this object is already there, merge their `data` property
Object.assign(found.data, curr.data)
else
// Otherwise add to the accumulator (`acc`)
acc.push(curr)
return acc
, )
Reference to the reduce function:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/reduce
answered Nov 16 '18 at 8:53
Nurbol AlpysbayevNurbol Alpysbayev
4,8091533
add a comment |
0
Here you are
let arrayB = arrayA.reduce((acc, curr) =>
const found = acc.find(i => i.name === curr.name)
if (found)
// If this object is already there, merge their `data` property
Object.assign(found.data, curr.data)
else
// Otherwise add to the accumulator (`acc`)
acc.push(curr)
return acc
, )
Reference to the reduce function:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/reduce
answered Nov 16 '18 at 8:53
Nurbol AlpysbayevNurbol Alpysbayev
4,8091533
add a comment |
0
0
0
Here you are
let arrayB = arrayA.reduce((acc, curr) =>
const found = acc.find(i => i.name === curr.name)
if (found)
// If this object is already there, merge their `data` property
Object.assign(found.data, curr.data)
else
// Otherwise add to the accumulator (`acc`)
acc.push(curr)
return acc
, )
Reference to the reduce function:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/reduce
answered Nov 16 '18 at 8:53
Nurbol AlpysbayevNurbol Alpysbayev
4,8091533
Here you are
let arrayB = arrayA.reduce((acc, curr) =>
const found = acc.find(i => i.name === curr.name)
if (found)
// If this object is already there, merge their `data` property
Object.assign(found.data, curr.data)
else
// Otherwise add to the accumulator (`acc`)
acc.push(curr)
return acc
, )
Reference to the reduce function:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/reduce
answered Nov 16 '18 at 8:53
Nurbol AlpysbayevNurbol Alpysbayev
4,8091533
answered Nov 16 '18 at 8:53
Nurbol AlpysbayevNurbol Alpysbayev
4,8091533
answered Nov 16 '18 at 8:53
Nurbol AlpysbayevNurbol Alpysbayev
4,8091533
answered Nov 16 '18 at 8:53
Nurbol AlpysbayevNurbol Alpysbayev
4,8091533
4,8091533
add a comment |
add a comment |
0
var arrayA = [ name: "temperature", data: "2000-09-26": 82 , name: "temperature", data: "1997-03-08": 71 , name: "current", data: "1993-08-11": 79 , name: "frequency", data: "2004-01-17": 16 , name: "current", data: "1997-02-14": 65 ]
var arrayB=_.map(_.groupBy(arrayA, 'name'),function(list)
return _.reduce(list,function(nObj,obj)
if(nObj.data && _.difference(_.keys(nObj.data),_.keys(obj.data)))
nObj.data=_.assign(nObj.data,obj.data)
else
nObj=obj
return nObj
,)
)
console.log(arrayB)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.5.1/lodash.js"></script>answered Nov 16 '18 at 9:35
Pritam JanaPritam Jana
10913
add a comment |
0
var arrayA = [ name: "temperature", data: "2000-09-26": 82 , name: "temperature", data: "1997-03-08": 71 , name: "current", data: "1993-08-11": 79 , name: "frequency", data: "2004-01-17": 16 , name: "current", data: "1997-02-14": 65 ]
var arrayB=_.map(_.groupBy(arrayA, 'name'),function(list)
return _.reduce(list,function(nObj,obj)
if(nObj.data && _.difference(_.keys(nObj.data),_.keys(obj.data)))
nObj.data=_.assign(nObj.data,obj.data)
else
nObj=obj
return nObj
,)
)
console.log(arrayB)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.5.1/lodash.js"></script>answered Nov 16 '18 at 9:35
Pritam JanaPritam Jana
10913
add a comment |
0
0
0
var arrayA = [ name: "temperature", data: "2000-09-26": 82 , name: "temperature", data: "1997-03-08": 71 , name: "current", data: "1993-08-11": 79 , name: "frequency", data: "2004-01-17": 16 , name: "current", data: "1997-02-14": 65 ]
var arrayB=_.map(_.groupBy(arrayA, 'name'),function(list)
return _.reduce(list,function(nObj,obj)
if(nObj.data && _.difference(_.keys(nObj.data),_.keys(obj.data)))
nObj.data=_.assign(nObj.data,obj.data)
else
nObj=obj
return nObj
,)
)
console.log(arrayB)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.5.1/lodash.js"></script>answered Nov 16 '18 at 9:35
Pritam JanaPritam Jana
10913
var arrayA = [ name: "temperature", data: "2000-09-26": 82 , name: "temperature", data: "1997-03-08": 71 , name: "current", data: "1993-08-11": 79 , name: "frequency", data: "2004-01-17": 16 , name: "current", data: "1997-02-14": 65 ]
var arrayB=_.map(_.groupBy(arrayA, 'name'),function(list)
return _.reduce(list,function(nObj,obj)
if(nObj.data && _.difference(_.keys(nObj.data),_.keys(obj.data)))
nObj.data=_.assign(nObj.data,obj.data)
else
nObj=obj
return nObj
,)
)
console.log(arrayB)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.5.1/lodash.js"></script>var arrayA = [ name: "temperature", data: "2000-09-26": 82 , name: "temperature", data: "1997-03-08": 71 , name: "current", data: "1993-08-11": 79 , name: "frequency", data: "2004-01-17": 16 , name: "current", data: "1997-02-14": 65 ]
var arrayB=_.map(_.groupBy(arrayA, 'name'),function(list)
return _.reduce(list,function(nObj,obj)
if(nObj.data && _.difference(_.keys(nObj.data),_.keys(obj.data)))
nObj.data=_.assign(nObj.data,obj.data)
else
nObj=obj
return nObj
,)
)
console.log(arrayB)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.5.1/lodash.js"></script>var arrayA = [ name: "temperature", data: "2000-09-26": 82 , name: "temperature", data: "1997-03-08": 71 , name: "current", data: "1993-08-11": 79 , name: "frequency", data: "2004-01-17": 16 , name: "current", data: "1997-02-14": 65 ]
var arrayB=_.map(_.groupBy(arrayA, 'name'),function(list)
return _.reduce(list,function(nObj,obj)
if(nObj.data && _.difference(_.keys(nObj.data),_.keys(obj.data)))
nObj.data=_.assign(nObj.data,obj.data)
else
nObj=obj
return nObj
,)
)
console.log(arrayB)<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.5.1/lodash.js"></script>answered Nov 16 '18 at 9:35
Pritam JanaPritam Jana
10913
answered Nov 16 '18 at 9:35
Pritam JanaPritam Jana
10913
answered Nov 16 '18 at 9:35
Pritam JanaPritam Jana
10913
answered Nov 16 '18 at 9:35
Pritam JanaPritam Jana
10913
10913
add a comment |
add a comment |
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1
would you like to go from a to b or from b to a? btw, what have you tried?
– Nina Scholz
Nov 16 '18 at 8:44
I want to go from a to b
– obi patrick
Nov 16 '18 at 8:47
What I tried was using variable as the key
– obi patrick
Nov 16 '18 at 8:49