While loop over numbers doesn't seem to be working [duplicate]

This question already has an answer here:

Reading in integer from stdin in Python

4 answers

I am new to python and I am trying run this piece of code, however, the while loop doesn't seem to be working. Any ideas?

def whilelooper(loop):
 i = 0
 numbers = 


 while i < loop:
 print "At the top i is %d" %i
 numbers.append(i)

 i += 1
 print "numbers now:",numbers
 print "At the bottom i is %d" %i

 print "the numbers:",

 for num in numbers:
 print num


print "Enter a number for loop"
b = raw_input(">")

whilelooper(b)

edited Nov 16 '18 at 9:43

cricket_007

83.8k1147118

asked Nov 16 '18 at 9:35

Priyanka Yadav

132

marked as duplicate by cricket_007, tripleee, Community♦ Nov 16 '18 at 9:52

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

1

What do you hope for the code to do and what actual behavior do you observe? Also, please edit the code to fix the indentation.

– tripleee
Nov 16 '18 at 9:41

2

raw_input returns a string... you need whilelooper(int(b))

– cricket_007
Nov 16 '18 at 9:44

1

By the way, for i in range(loop) would be "safer" than a while loop

– cricket_007
Nov 16 '18 at 9:45

1

@PriyankaYadav that was me but you're welcome :D

– Ben Jones
Nov 16 '18 at 9:53

1

You may use the checkmark next to the answer below to accept it

– cricket_007
Nov 16 '18 at 9:53

|
show 4 more comments

This question already has an answer here:

Reading in integer from stdin in Python

4 answers

I am new to python and I am trying run this piece of code, however, the while loop doesn't seem to be working. Any ideas?

def whilelooper(loop):
 i = 0
 numbers = 


 while i < loop:
 print "At the top i is %d" %i
 numbers.append(i)

 i += 1
 print "numbers now:",numbers
 print "At the bottom i is %d" %i

 print "the numbers:",

 for num in numbers:
 print num


print "Enter a number for loop"
b = raw_input(">")

whilelooper(b)

edited Nov 16 '18 at 9:43

cricket_007

83.8k1147118

asked Nov 16 '18 at 9:35

Priyanka Yadav

132

marked as duplicate by cricket_007, tripleee, Community♦ Nov 16 '18 at 9:52

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

1

What do you hope for the code to do and what actual behavior do you observe? Also, please edit the code to fix the indentation.

– tripleee
Nov 16 '18 at 9:41

2

raw_input returns a string... you need whilelooper(int(b))

– cricket_007
Nov 16 '18 at 9:44

1

By the way, for i in range(loop) would be "safer" than a while loop

– cricket_007
Nov 16 '18 at 9:45

1

@PriyankaYadav that was me but you're welcome :D

– Ben Jones
Nov 16 '18 at 9:53

1

You may use the checkmark next to the answer below to accept it

– cricket_007
Nov 16 '18 at 9:53

|
show 4 more comments

This question already has an answer here:

Reading in integer from stdin in Python

4 answers

I am new to python and I am trying run this piece of code, however, the while loop doesn't seem to be working. Any ideas?

def whilelooper(loop):
 i = 0
 numbers = 


 while i < loop:
 print "At the top i is %d" %i
 numbers.append(i)

 i += 1
 print "numbers now:",numbers
 print "At the bottom i is %d" %i

 print "the numbers:",

 for num in numbers:
 print num


print "Enter a number for loop"
b = raw_input(">")

whilelooper(b)

edited Nov 16 '18 at 9:43

cricket_007

83.8k1147118

asked Nov 16 '18 at 9:35

Priyanka Yadav

132

This question already has an answer here:

Reading in integer from stdin in Python

4 answers

I am new to python and I am trying run this piece of code, however, the while loop doesn't seem to be working. Any ideas?

def whilelooper(loop):
 i = 0
 numbers = 


 while i < loop:
 print "At the top i is %d" %i
 numbers.append(i)

 i += 1
 print "numbers now:",numbers
 print "At the bottom i is %d" %i

 print "the numbers:",

 for num in numbers:
 print num


print "Enter a number for loop"
b = raw_input(">")

whilelooper(b)

This question already has an answer here:

Reading in integer from stdin in Python

4 answers

python python-2.x

edited Nov 16 '18 at 9:43

cricket_007

83.8k1147118

asked Nov 16 '18 at 9:35

Priyanka Yadav

132

edited Nov 16 '18 at 9:43

cricket_007

83.8k1147118

asked Nov 16 '18 at 9:35

Priyanka Yadav

132

edited Nov 16 '18 at 9:43

cricket_007

83.8k1147118

edited Nov 16 '18 at 9:43

cricket_007

83.8k1147118

edited Nov 16 '18 at 9:43

cricket_007

83.8k1147118

asked Nov 16 '18 at 9:35

Priyanka Yadav

132

asked Nov 16 '18 at 9:35

Priyanka Yadav

132

asked Nov 16 '18 at 9:35

Priyanka Yadav

132

marked as duplicate by cricket_007, tripleee, Community♦ Nov 16 '18 at 9:52

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

marked as duplicate by cricket_007, tripleee, Community♦ Nov 16 '18 at 9:52

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

1

What do you hope for the code to do and what actual behavior do you observe? Also, please edit the code to fix the indentation.

– tripleee
Nov 16 '18 at 9:41

2

raw_input returns a string... you need whilelooper(int(b))

– cricket_007
Nov 16 '18 at 9:44

1

By the way, for i in range(loop) would be "safer" than a while loop

– cricket_007
Nov 16 '18 at 9:45

1

@PriyankaYadav that was me but you're welcome :D

– Ben Jones
Nov 16 '18 at 9:53

1

You may use the checkmark next to the answer below to accept it

– cricket_007
Nov 16 '18 at 9:53

|
show 4 more comments

1

What do you hope for the code to do and what actual behavior do you observe? Also, please edit the code to fix the indentation.

– tripleee
Nov 16 '18 at 9:41

2

raw_input returns a string... you need whilelooper(int(b))

– cricket_007
Nov 16 '18 at 9:44

1

By the way, for i in range(loop) would be "safer" than a while loop

– cricket_007
Nov 16 '18 at 9:45

1

@PriyankaYadav that was me but you're welcome :D

– Ben Jones
Nov 16 '18 at 9:53

1

You may use the checkmark next to the answer below to accept it

– cricket_007
Nov 16 '18 at 9:53

What do you hope for the code to do and what actual behavior do you observe? Also, please edit the code to fix the indentation.

– tripleee
Nov 16 '18 at 9:41

raw_input returns a string... you need whilelooper(int(b))

– cricket_007
Nov 16 '18 at 9:44

By the way, for i in range(loop) would be "safer" than a while loop

– cricket_007
Nov 16 '18 at 9:45

@PriyankaYadav that was me but you're welcome :D

– Ben Jones
Nov 16 '18 at 9:53

You may use the checkmark next to the answer below to accept it

– cricket_007
Nov 16 '18 at 9:53

|
show 4 more comments

1 Answer
1

active

oldest

votes

Your input is inputted as a string type, but the comparator

while i < loop:

is expecting both i and loop to be of type int (for integer), in order to be able to compare them.

You can fix this by casting loop to an int:

def whilelooper(loop):
 i = 0
 numbers = 
 loop = int(loop)
 ...

answered Nov 16 '18 at 9:41

Ben Jones

15113

1

Or whilelooper(int(b))

– cricket_007
Nov 16 '18 at 9:44

Better to do it inside the function, because it's always going to want to be an int for the function to work

– Ben Jones
Nov 16 '18 at 9:47

add a comment |

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

Your input is inputted as a string type, but the comparator

while i < loop:

is expecting both i and loop to be of type int (for integer), in order to be able to compare them.

You can fix this by casting loop to an int:

def whilelooper(loop):
 i = 0
 numbers = 
 loop = int(loop)
 ...

answered Nov 16 '18 at 9:41

Ben Jones

15113

1

Or whilelooper(int(b))

– cricket_007
Nov 16 '18 at 9:44

Better to do it inside the function, because it's always going to want to be an int for the function to work

– Ben Jones
Nov 16 '18 at 9:47

add a comment |

Your input is inputted as a string type, but the comparator

while i < loop:

is expecting both i and loop to be of type int (for integer), in order to be able to compare them.

You can fix this by casting loop to an int:

def whilelooper(loop):
 i = 0
 numbers = 
 loop = int(loop)
 ...

answered Nov 16 '18 at 9:41

Ben Jones

15113

1

Or whilelooper(int(b))

– cricket_007
Nov 16 '18 at 9:44

Better to do it inside the function, because it's always going to want to be an int for the function to work

– Ben Jones
Nov 16 '18 at 9:47

add a comment |

Your input is inputted as a string type, but the comparator

while i < loop:

is expecting both i and loop to be of type int (for integer), in order to be able to compare them.

You can fix this by casting loop to an int:

def whilelooper(loop):
 i = 0
 numbers = 
 loop = int(loop)
 ...

answered Nov 16 '18 at 9:41

Ben Jones

15113

Your input is inputted as a string type, but the comparator

while i < loop:

is expecting both i and loop to be of type int (for integer), in order to be able to compare them.

You can fix this by casting loop to an int:

def whilelooper(loop):
 i = 0
 numbers = 
 loop = int(loop)
 ...

answered Nov 16 '18 at 9:41

Ben Jones

15113

answered Nov 16 '18 at 9:41

Ben Jones

15113

answered Nov 16 '18 at 9:41

Ben Jones

15113

answered Nov 16 '18 at 9:41

Ben Jones

15113

1

Or whilelooper(int(b))

– cricket_007
Nov 16 '18 at 9:44

Better to do it inside the function, because it's always going to want to be an int for the function to work

– Ben Jones
Nov 16 '18 at 9:47

add a comment |

1

Or whilelooper(int(b))

– cricket_007
Nov 16 '18 at 9:44

Better to do it inside the function, because it's always going to want to be an int for the function to work

– Ben Jones
Nov 16 '18 at 9:47

Or whilelooper(int(b))

– cricket_007
Nov 16 '18 at 9:44

Better to do it inside the function, because it's always going to want to be an int for the function to work

– Ben Jones
Nov 16 '18 at 9:47

add a comment |

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