Powershell loop with numbers to alphabet
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I need help with the following:
Create a for loop based on the conditions that the index is initialized to 0, $test is less than 26, and the index is incremented by 1
For each iteration, print the current letter of the alphabet. Start at the letter A. Thus, for each iteration, a single letter is printed on a separate line.
I am not able to increment the char each time the loop runs
for ($test = 0; $test -lt 26; $test++)
[char]65
I have tried multiple attempts with trying to increment the char 65 through 90 with no success.
Is there an easier way to increment the alphabet to show a letter for each loop that is ran?
powershell increment alphabet
asked Sep 8 '17 at 5:37
vnavna
814
add a comment |
up vote
0
down vote
favorite
I need help with the following:
Create a for loop based on the conditions that the index is initialized to 0, $test is less than 26, and the index is incremented by 1
For each iteration, print the current letter of the alphabet. Start at the letter A. Thus, for each iteration, a single letter is printed on a separate line.
I am not able to increment the char each time the loop runs
for ($test = 0; $test -lt 26; $test++)
[char]65
I have tried multiple attempts with trying to increment the char 65 through 90 with no success.
Is there an easier way to increment the alphabet to show a letter for each loop that is ran?
powershell increment alphabet
asked Sep 8 '17 at 5:37
vnavna
814
0=A 1=B 2=C 3=D ....25=Z
– vnavna
Sep 8 '17 at 5:41
0..25 | % [char] ($_ + [byte][char] 'A')
– David Brabant
Sep 8 '17 at 6:40
if all you want it the range of uppercase letters, this will do it ...[char]('A'[0]..'Z'[0]). [grin]
– Lee_Dailey
Nov 11 at 17:13
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I need help with the following:
Create a for loop based on the conditions that the index is initialized to 0, $test is less than 26, and the index is incremented by 1
For each iteration, print the current letter of the alphabet. Start at the letter A. Thus, for each iteration, a single letter is printed on a separate line.
I am not able to increment the char each time the loop runs
for ($test = 0; $test -lt 26; $test++)
[char]65
I have tried multiple attempts with trying to increment the char 65 through 90 with no success.
Is there an easier way to increment the alphabet to show a letter for each loop that is ran?
powershell increment alphabet
asked Sep 8 '17 at 5:37
vnavna
814
I need help with the following:
Create a for loop based on the conditions that the index is initialized to 0, $test is less than 26, and the index is incremented by 1
For each iteration, print the current letter of the alphabet. Start at the letter A. Thus, for each iteration, a single letter is printed on a separate line.
I am not able to increment the char each time the loop runs
for ($test = 0; $test -lt 26; $test++)
[char]65
I have tried multiple attempts with trying to increment the char 65 through 90 with no success.
Is there an easier way to increment the alphabet to show a letter for each loop that is ran?
powershell increment alphabet
powershell increment alphabet
asked Sep 8 '17 at 5:37
vnavna
814
asked Sep 8 '17 at 5:37
vnavna
814
edited Sep 8 '17 at 5:45
asked Sep 8 '17 at 5:37
vnavna
814
asked Sep 8 '17 at 5:37
vnavna
814
asked Sep 8 '17 at 5:37
vnavna
814
814
0=A 1=B 2=C 3=D ....25=Z
– vnavna
Sep 8 '17 at 5:41
0..25 | % [char] ($_ + [byte][char] 'A')
– David Brabant
Sep 8 '17 at 6:40
if all you want it the range of uppercase letters, this will do it ...[char]('A'[0]..'Z'[0]). [grin]
– Lee_Dailey
Nov 11 at 17:13
add a comment |
0=A 1=B 2=C 3=D ....25=Z
– vnavna
Sep 8 '17 at 5:41
0..25 | % [char] ($_ + [byte][char] 'A')
– David Brabant
Sep 8 '17 at 6:40
if all you want it the range of uppercase letters, this will do it ...[char]('A'[0]..'Z'[0]). [grin]
– Lee_Dailey
Nov 11 at 17:13
0=A 1=B 2=C 3=D ....25=Z
– vnavna
Sep 8 '17 at 5:41
0=A 1=B 2=C 3=D ....25=Z
– vnavna
Sep 8 '17 at 5:41
0..25 | % [char] ($_ + [byte][char] 'A')
– David Brabant
Sep 8 '17 at 6:40
0..25 | % [char] ($_ + [byte][char] 'A')
– David Brabant
Sep 8 '17 at 6:40
if all you want it the range of uppercase letters, this will do it ...
[char]('A'[0]..'Z'[0]). [grin]– Lee_Dailey
Nov 11 at 17:13
if all you want it the range of uppercase letters, this will do it ...
[char]('A'[0]..'Z'[0]). [grin]– Lee_Dailey
Nov 11 at 17:13
add a comment |
2 Answers
2
active
oldest
votes
up vote
5
down vote
accepted
You can sum your loop index with 65. So, it'll be: 0 + 65 = A, 1 + 65 = B ...
for ($test = 0; $test -lt 26; $test++)
[char](65 + $test)
answered Sep 8 '17 at 5:53
Cassio Farias Machado
664
for ($test = 0; $test -lt 26; $test++) $char = [char](65 +$test) Write-Host $char Your suggestion worked out great. Thank you
– vnavna
Sep 8 '17 at 14:33
add a comment |
up vote
1
down vote
PS2 to PS5:
97..(97+25) | % [char]$_
Faster:
(97..(97+25)).ForEach( [char]$_ )
PS6+:
'a'..'z' | % $_
Faster:
('a'..'z').ForEach( $_ )
answered Nov 11 at 14:56
Daniel Ferreira
112
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
5
down vote
accepted
You can sum your loop index with 65. So, it'll be: 0 + 65 = A, 1 + 65 = B ...
for ($test = 0; $test -lt 26; $test++)
[char](65 + $test)
answered Sep 8 '17 at 5:53
Cassio Farias Machado
664
for ($test = 0; $test -lt 26; $test++) $char = [char](65 +$test) Write-Host $char Your suggestion worked out great. Thank you
– vnavna
Sep 8 '17 at 14:33
add a comment |
up vote
5
down vote
accepted
You can sum your loop index with 65. So, it'll be: 0 + 65 = A, 1 + 65 = B ...
for ($test = 0; $test -lt 26; $test++)
[char](65 + $test)
answered Sep 8 '17 at 5:53
Cassio Farias Machado
664
for ($test = 0; $test -lt 26; $test++) $char = [char](65 +$test) Write-Host $char Your suggestion worked out great. Thank you
– vnavna
Sep 8 '17 at 14:33
add a comment |
up vote
5
down vote
accepted
up vote
5
down vote
accepted
You can sum your loop index with 65. So, it'll be: 0 + 65 = A, 1 + 65 = B ...
for ($test = 0; $test -lt 26; $test++)
[char](65 + $test)
answered Sep 8 '17 at 5:53
Cassio Farias Machado
664
You can sum your loop index with 65. So, it'll be: 0 + 65 = A, 1 + 65 = B ...
for ($test = 0; $test -lt 26; $test++)
[char](65 + $test)
answered Sep 8 '17 at 5:53
Cassio Farias Machado
664
edited Sep 8 '17 at 5:59
answered Sep 8 '17 at 5:53
Cassio Farias Machado
664
answered Sep 8 '17 at 5:53
Cassio Farias Machado
664
answered Sep 8 '17 at 5:53
Cassio Farias Machado
664
664
for ($test = 0; $test -lt 26; $test++) $char = [char](65 +$test) Write-Host $char Your suggestion worked out great. Thank you
– vnavna
Sep 8 '17 at 14:33
add a comment |
for ($test = 0; $test -lt 26; $test++) $char = [char](65 +$test) Write-Host $char Your suggestion worked out great. Thank you
– vnavna
Sep 8 '17 at 14:33
for ($test = 0; $test -lt 26; $test++) $char = [char](65 +$test) Write-Host $char Your suggestion worked out great. Thank you
– vnavna
Sep 8 '17 at 14:33
for ($test = 0; $test -lt 26; $test++) $char = [char](65 +$test) Write-Host $char Your suggestion worked out great. Thank you
– vnavna
Sep 8 '17 at 14:33
add a comment |
up vote
1
down vote
PS2 to PS5:
97..(97+25) | % [char]$_
Faster:
(97..(97+25)).ForEach( [char]$_ )
PS6+:
'a'..'z' | % $_
Faster:
('a'..'z').ForEach( $_ )
answered Nov 11 at 14:56
Daniel Ferreira
112
add a comment |
up vote
1
down vote
PS2 to PS5:
97..(97+25) | % [char]$_
Faster:
(97..(97+25)).ForEach( [char]$_ )
PS6+:
'a'..'z' | % $_
Faster:
('a'..'z').ForEach( $_ )
answered Nov 11 at 14:56
Daniel Ferreira
112
add a comment |
up vote
1
down vote
up vote
1
down vote
PS2 to PS5:
97..(97+25) | % [char]$_
Faster:
(97..(97+25)).ForEach( [char]$_ )
PS6+:
'a'..'z' | % $_
Faster:
('a'..'z').ForEach( $_ )
answered Nov 11 at 14:56
Daniel Ferreira
112
PS2 to PS5:
97..(97+25) | % [char]$_
Faster:
(97..(97+25)).ForEach( [char]$_ )
PS6+:
'a'..'z' | % $_
Faster:
('a'..'z').ForEach( $_ )
answered Nov 11 at 14:56
Daniel Ferreira
112
answered Nov 11 at 14:56
Daniel Ferreira
112
answered Nov 11 at 14:56
Daniel Ferreira
112
answered Nov 11 at 14:56
Daniel Ferreira
112
112
add a comment |
add a comment |
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0=A 1=B 2=C 3=D ....25=Z
– vnavna
Sep 8 '17 at 5:41
0..25 | % [char] ($_ + [byte][char] 'A')
– David Brabant
Sep 8 '17 at 6:40
if all you want it the range of uppercase letters, this will do it ...
[char]('A'[0]..'Z'[0]). [grin]– Lee_Dailey
Nov 11 at 17:13