A method or function that returns a list of pairs of numbers which would sum up to 5










-2















I am trying to implement a function in JAVA which would give me a List of Pairs of Numbers.



This pair of numbers which would add up to 5, so ultimate goal is to print this list of pair of numbers



I have this code to determine pair but not sure how to return from method.
Please Note: I have used void as I have no clue of how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....?



public void setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);













share|improve this question



















  • 2





    Welcome to SO. Please post the code you already have and specify where you are having trouble. Stop by the help center and read How to Ask. Thanks.

    – Johnny Mopp
    Nov 13 '18 at 18:27











  • I'm guessing there must also be other limits, otherwise this question has an infinite number of solutions. -23 + 28, as just one example.

    – KevinO
    Nov 13 '18 at 18:31











  • You have the numbers in your lists numberA and numberB. Please edit your question with the problem you have right now, you have not asked any question.

    – Progman
    Nov 13 '18 at 19:27











  • how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....

    – BVK 0118
    Nov 13 '18 at 19:30











  • @BVK0118 You can change the return type to Set<List<Integer>>. And return a Set with lists of numbers (which will have only 2 elements each) which sum results in your search number 5.

    – Progman
    Nov 13 '18 at 19:36















-2















I am trying to implement a function in JAVA which would give me a List of Pairs of Numbers.



This pair of numbers which would add up to 5, so ultimate goal is to print this list of pair of numbers



I have this code to determine pair but not sure how to return from method.
Please Note: I have used void as I have no clue of how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....?



public void setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);













share|improve this question



















  • 2





    Welcome to SO. Please post the code you already have and specify where you are having trouble. Stop by the help center and read How to Ask. Thanks.

    – Johnny Mopp
    Nov 13 '18 at 18:27











  • I'm guessing there must also be other limits, otherwise this question has an infinite number of solutions. -23 + 28, as just one example.

    – KevinO
    Nov 13 '18 at 18:31











  • You have the numbers in your lists numberA and numberB. Please edit your question with the problem you have right now, you have not asked any question.

    – Progman
    Nov 13 '18 at 19:27











  • how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....

    – BVK 0118
    Nov 13 '18 at 19:30











  • @BVK0118 You can change the return type to Set<List<Integer>>. And return a Set with lists of numbers (which will have only 2 elements each) which sum results in your search number 5.

    – Progman
    Nov 13 '18 at 19:36













-2












-2








-2








I am trying to implement a function in JAVA which would give me a List of Pairs of Numbers.



This pair of numbers which would add up to 5, so ultimate goal is to print this list of pair of numbers



I have this code to determine pair but not sure how to return from method.
Please Note: I have used void as I have no clue of how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....?



public void setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);













share|improve this question
















I am trying to implement a function in JAVA which would give me a List of Pairs of Numbers.



This pair of numbers which would add up to 5, so ultimate goal is to print this list of pair of numbers



I have this code to determine pair but not sure how to return from method.
Please Note: I have used void as I have no clue of how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....?



public void setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);










java






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 13 '18 at 19:31







BVK 0118

















asked Nov 13 '18 at 18:24









BVK 0118BVK 0118

43




43







  • 2





    Welcome to SO. Please post the code you already have and specify where you are having trouble. Stop by the help center and read How to Ask. Thanks.

    – Johnny Mopp
    Nov 13 '18 at 18:27











  • I'm guessing there must also be other limits, otherwise this question has an infinite number of solutions. -23 + 28, as just one example.

    – KevinO
    Nov 13 '18 at 18:31











  • You have the numbers in your lists numberA and numberB. Please edit your question with the problem you have right now, you have not asked any question.

    – Progman
    Nov 13 '18 at 19:27











  • how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....

    – BVK 0118
    Nov 13 '18 at 19:30











  • @BVK0118 You can change the return type to Set<List<Integer>>. And return a Set with lists of numbers (which will have only 2 elements each) which sum results in your search number 5.

    – Progman
    Nov 13 '18 at 19:36












  • 2





    Welcome to SO. Please post the code you already have and specify where you are having trouble. Stop by the help center and read How to Ask. Thanks.

    – Johnny Mopp
    Nov 13 '18 at 18:27











  • I'm guessing there must also be other limits, otherwise this question has an infinite number of solutions. -23 + 28, as just one example.

    – KevinO
    Nov 13 '18 at 18:31











  • You have the numbers in your lists numberA and numberB. Please edit your question with the problem you have right now, you have not asked any question.

    – Progman
    Nov 13 '18 at 19:27











  • how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....

    – BVK 0118
    Nov 13 '18 at 19:30











  • @BVK0118 You can change the return type to Set<List<Integer>>. And return a Set with lists of numbers (which will have only 2 elements each) which sum results in your search number 5.

    – Progman
    Nov 13 '18 at 19:36







2




2





Welcome to SO. Please post the code you already have and specify where you are having trouble. Stop by the help center and read How to Ask. Thanks.

– Johnny Mopp
Nov 13 '18 at 18:27





Welcome to SO. Please post the code you already have and specify where you are having trouble. Stop by the help center and read How to Ask. Thanks.

– Johnny Mopp
Nov 13 '18 at 18:27













I'm guessing there must also be other limits, otherwise this question has an infinite number of solutions. -23 + 28, as just one example.

– KevinO
Nov 13 '18 at 18:31





I'm guessing there must also be other limits, otherwise this question has an infinite number of solutions. -23 + 28, as just one example.

– KevinO
Nov 13 '18 at 18:31













You have the numbers in your lists numberA and numberB. Please edit your question with the problem you have right now, you have not asked any question.

– Progman
Nov 13 '18 at 19:27





You have the numbers in your lists numberA and numberB. Please edit your question with the problem you have right now, you have not asked any question.

– Progman
Nov 13 '18 at 19:27













how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....

– BVK 0118
Nov 13 '18 at 19:30





how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....

– BVK 0118
Nov 13 '18 at 19:30













@BVK0118 You can change the return type to Set<List<Integer>>. And return a Set with lists of numbers (which will have only 2 elements each) which sum results in your search number 5.

– Progman
Nov 13 '18 at 19:36





@BVK0118 You can change the return type to Set<List<Integer>>. And return a Set with lists of numbers (which will have only 2 elements each) which sum results in your search number 5.

– Progman
Nov 13 '18 at 19:36












1 Answer
1






active

oldest

votes


















0














You can change the return type of your method to Set<List<Integer>>. The Set will contain lists of numbers, where the numbers in each list will sum up to your target number 5. The method will look like this:



public static Set<List<Integer>> setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);



Set<List<Integer>> result = new HashSet<List<Integer>>();
for (int i=0; i<numberA.size(); i++)
int n1 = numberA.get(i);
int n2 = numberB.get(i);
List<Integer> numbersToAdd = Arrays.asList(n1, n2);
result.add(numbersToAdd);

return result;






share|improve this answer























  • Thank you so much for your help! It works!

    – BVK 0118
    Nov 14 '18 at 22:08










Your Answer






StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);













draft saved

draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53287325%2fa-method-or-function-that-returns-a-list-of-pairs-of-numbers-which-would-sum-up%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














You can change the return type of your method to Set<List<Integer>>. The Set will contain lists of numbers, where the numbers in each list will sum up to your target number 5. The method will look like this:



public static Set<List<Integer>> setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);



Set<List<Integer>> result = new HashSet<List<Integer>>();
for (int i=0; i<numberA.size(); i++)
int n1 = numberA.get(i);
int n2 = numberB.get(i);
List<Integer> numbersToAdd = Arrays.asList(n1, n2);
result.add(numbersToAdd);

return result;






share|improve this answer























  • Thank you so much for your help! It works!

    – BVK 0118
    Nov 14 '18 at 22:08















0














You can change the return type of your method to Set<List<Integer>>. The Set will contain lists of numbers, where the numbers in each list will sum up to your target number 5. The method will look like this:



public static Set<List<Integer>> setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);



Set<List<Integer>> result = new HashSet<List<Integer>>();
for (int i=0; i<numberA.size(); i++)
int n1 = numberA.get(i);
int n2 = numberB.get(i);
List<Integer> numbersToAdd = Arrays.asList(n1, n2);
result.add(numbersToAdd);

return result;






share|improve this answer























  • Thank you so much for your help! It works!

    – BVK 0118
    Nov 14 '18 at 22:08













0












0








0







You can change the return type of your method to Set<List<Integer>>. The Set will contain lists of numbers, where the numbers in each list will sum up to your target number 5. The method will look like this:



public static Set<List<Integer>> setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);



Set<List<Integer>> result = new HashSet<List<Integer>>();
for (int i=0; i<numberA.size(); i++)
int n1 = numberA.get(i);
int n2 = numberB.get(i);
List<Integer> numbersToAdd = Arrays.asList(n1, n2);
result.add(numbersToAdd);

return result;






share|improve this answer













You can change the return type of your method to Set<List<Integer>>. The Set will contain lists of numbers, where the numbers in each list will sum up to your target number 5. The method will look like this:



public static Set<List<Integer>> setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);



Set<List<Integer>> result = new HashSet<List<Integer>>();
for (int i=0; i<numberA.size(); i++)
int n1 = numberA.get(i);
int n2 = numberB.get(i);
List<Integer> numbersToAdd = Arrays.asList(n1, n2);
result.add(numbersToAdd);

return result;







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 14 '18 at 9:55









ProgmanProgman

6,35331936




6,35331936












  • Thank you so much for your help! It works!

    – BVK 0118
    Nov 14 '18 at 22:08

















  • Thank you so much for your help! It works!

    – BVK 0118
    Nov 14 '18 at 22:08
















Thank you so much for your help! It works!

– BVK 0118
Nov 14 '18 at 22:08





Thank you so much for your help! It works!

– BVK 0118
Nov 14 '18 at 22:08

















draft saved

draft discarded
















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid


  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53287325%2fa-method-or-function-that-returns-a-list-of-pairs-of-numbers-which-would-sum-up%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Top Tejano songwriter Luis Silva dead of heart attack at 64

政党

天津地下鉄3号線