A method or function that returns a list of pairs of numbers which would sum up to 5










-2















I am trying to implement a function in JAVA which would give me a List of Pairs of Numbers.



This pair of numbers which would add up to 5, so ultimate goal is to print this list of pair of numbers



I have this code to determine pair but not sure how to return from method.
Please Note: I have used void as I have no clue of how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....?



public void setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);













share|improve this question



















  • 2





    Welcome to SO. Please post the code you already have and specify where you are having trouble. Stop by the help center and read How to Ask. Thanks.

    – Johnny Mopp
    Nov 13 '18 at 18:27











  • I'm guessing there must also be other limits, otherwise this question has an infinite number of solutions. -23 + 28, as just one example.

    – KevinO
    Nov 13 '18 at 18:31











  • You have the numbers in your lists numberA and numberB. Please edit your question with the problem you have right now, you have not asked any question.

    – Progman
    Nov 13 '18 at 19:27











  • how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....

    – BVK 0118
    Nov 13 '18 at 19:30











  • @BVK0118 You can change the return type to Set<List<Integer>>. And return a Set with lists of numbers (which will have only 2 elements each) which sum results in your search number 5.

    – Progman
    Nov 13 '18 at 19:36















-2















I am trying to implement a function in JAVA which would give me a List of Pairs of Numbers.



This pair of numbers which would add up to 5, so ultimate goal is to print this list of pair of numbers



I have this code to determine pair but not sure how to return from method.
Please Note: I have used void as I have no clue of how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....?



public void setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);













share|improve this question



















  • 2





    Welcome to SO. Please post the code you already have and specify where you are having trouble. Stop by the help center and read How to Ask. Thanks.

    – Johnny Mopp
    Nov 13 '18 at 18:27











  • I'm guessing there must also be other limits, otherwise this question has an infinite number of solutions. -23 + 28, as just one example.

    – KevinO
    Nov 13 '18 at 18:31











  • You have the numbers in your lists numberA and numberB. Please edit your question with the problem you have right now, you have not asked any question.

    – Progman
    Nov 13 '18 at 19:27











  • how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....

    – BVK 0118
    Nov 13 '18 at 19:30











  • @BVK0118 You can change the return type to Set<List<Integer>>. And return a Set with lists of numbers (which will have only 2 elements each) which sum results in your search number 5.

    – Progman
    Nov 13 '18 at 19:36













-2












-2








-2








I am trying to implement a function in JAVA which would give me a List of Pairs of Numbers.



This pair of numbers which would add up to 5, so ultimate goal is to print this list of pair of numbers



I have this code to determine pair but not sure how to return from method.
Please Note: I have used void as I have no clue of how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....?



public void setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);













share|improve this question
















I am trying to implement a function in JAVA which would give me a List of Pairs of Numbers.



This pair of numbers which would add up to 5, so ultimate goal is to print this list of pair of numbers



I have this code to determine pair but not sure how to return from method.
Please Note: I have used void as I have no clue of how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....?



public void setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);










java






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 13 '18 at 19:31







BVK 0118

















asked Nov 13 '18 at 18:24









BVK 0118BVK 0118

43




43







  • 2





    Welcome to SO. Please post the code you already have and specify where you are having trouble. Stop by the help center and read How to Ask. Thanks.

    – Johnny Mopp
    Nov 13 '18 at 18:27











  • I'm guessing there must also be other limits, otherwise this question has an infinite number of solutions. -23 + 28, as just one example.

    – KevinO
    Nov 13 '18 at 18:31











  • You have the numbers in your lists numberA and numberB. Please edit your question with the problem you have right now, you have not asked any question.

    – Progman
    Nov 13 '18 at 19:27











  • how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....

    – BVK 0118
    Nov 13 '18 at 19:30











  • @BVK0118 You can change the return type to Set<List<Integer>>. And return a Set with lists of numbers (which will have only 2 elements each) which sum results in your search number 5.

    – Progman
    Nov 13 '18 at 19:36












  • 2





    Welcome to SO. Please post the code you already have and specify where you are having trouble. Stop by the help center and read How to Ask. Thanks.

    – Johnny Mopp
    Nov 13 '18 at 18:27











  • I'm guessing there must also be other limits, otherwise this question has an infinite number of solutions. -23 + 28, as just one example.

    – KevinO
    Nov 13 '18 at 18:31











  • You have the numbers in your lists numberA and numberB. Please edit your question with the problem you have right now, you have not asked any question.

    – Progman
    Nov 13 '18 at 19:27











  • how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....

    – BVK 0118
    Nov 13 '18 at 19:30











  • @BVK0118 You can change the return type to Set<List<Integer>>. And return a Set with lists of numbers (which will have only 2 elements each) which sum results in your search number 5.

    – Progman
    Nov 13 '18 at 19:36







2




2





Welcome to SO. Please post the code you already have and specify where you are having trouble. Stop by the help center and read How to Ask. Thanks.

– Johnny Mopp
Nov 13 '18 at 18:27





Welcome to SO. Please post the code you already have and specify where you are having trouble. Stop by the help center and read How to Ask. Thanks.

– Johnny Mopp
Nov 13 '18 at 18:27













I'm guessing there must also be other limits, otherwise this question has an infinite number of solutions. -23 + 28, as just one example.

– KevinO
Nov 13 '18 at 18:31





I'm guessing there must also be other limits, otherwise this question has an infinite number of solutions. -23 + 28, as just one example.

– KevinO
Nov 13 '18 at 18:31













You have the numbers in your lists numberA and numberB. Please edit your question with the problem you have right now, you have not asked any question.

– Progman
Nov 13 '18 at 19:27





You have the numbers in your lists numberA and numberB. Please edit your question with the problem you have right now, you have not asked any question.

– Progman
Nov 13 '18 at 19:27













how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....

– BVK 0118
Nov 13 '18 at 19:30





how to return values from method in the form (numberA[0], numberB[0]), (numberA[1], numberB[1]), ....

– BVK 0118
Nov 13 '18 at 19:30













@BVK0118 You can change the return type to Set<List<Integer>>. And return a Set with lists of numbers (which will have only 2 elements each) which sum results in your search number 5.

– Progman
Nov 13 '18 at 19:36





@BVK0118 You can change the return type to Set<List<Integer>>. And return a Set with lists of numbers (which will have only 2 elements each) which sum results in your search number 5.

– Progman
Nov 13 '18 at 19:36












1 Answer
1






active

oldest

votes


















0














You can change the return type of your method to Set<List<Integer>>. The Set will contain lists of numbers, where the numbers in each list will sum up to your target number 5. The method will look like this:



public static Set<List<Integer>> setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);



Set<List<Integer>> result = new HashSet<List<Integer>>();
for (int i=0; i<numberA.size(); i++)
int n1 = numberA.get(i);
int n2 = numberB.get(i);
List<Integer> numbersToAdd = Arrays.asList(n1, n2);
result.add(numbersToAdd);

return result;






share|improve this answer























  • Thank you so much for your help! It works!

    – BVK 0118
    Nov 14 '18 at 22:08










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














You can change the return type of your method to Set<List<Integer>>. The Set will contain lists of numbers, where the numbers in each list will sum up to your target number 5. The method will look like this:



public static Set<List<Integer>> setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);



Set<List<Integer>> result = new HashSet<List<Integer>>();
for (int i=0; i<numberA.size(); i++)
int n1 = numberA.get(i);
int n2 = numberB.get(i);
List<Integer> numbersToAdd = Arrays.asList(n1, n2);
result.add(numbersToAdd);

return result;






share|improve this answer























  • Thank you so much for your help! It works!

    – BVK 0118
    Nov 14 '18 at 22:08















0














You can change the return type of your method to Set<List<Integer>>. The Set will contain lists of numbers, where the numbers in each list will sum up to your target number 5. The method will look like this:



public static Set<List<Integer>> setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);



Set<List<Integer>> result = new HashSet<List<Integer>>();
for (int i=0; i<numberA.size(); i++)
int n1 = numberA.get(i);
int n2 = numberB.get(i);
List<Integer> numbersToAdd = Arrays.asList(n1, n2);
result.add(numbersToAdd);

return result;






share|improve this answer























  • Thank you so much for your help! It works!

    – BVK 0118
    Nov 14 '18 at 22:08













0












0








0







You can change the return type of your method to Set<List<Integer>>. The Set will contain lists of numbers, where the numbers in each list will sum up to your target number 5. The method will look like this:



public static Set<List<Integer>> setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);



Set<List<Integer>> result = new HashSet<List<Integer>>();
for (int i=0; i<numberA.size(); i++)
int n1 = numberA.get(i);
int n2 = numberB.get(i);
List<Integer> numbersToAdd = Arrays.asList(n1, n2);
result.add(numbersToAdd);

return result;






share|improve this answer













You can change the return type of your method to Set<List<Integer>>. The Set will contain lists of numbers, where the numbers in each list will sum up to your target number 5. The method will look like this:



public static Set<List<Integer>> setNumberList(int numberList) 

ArrayList<Integer> numberA = new ArrayList<Integer>();
ArrayList<Integer> numberB = new ArrayList<Integer>();

for (int i = 0; i < numberList.length; i++)

int first = numberList[i];

for (int j = i + 1; j < numberList.length; j++)

int second = numberList[j];

if ((first + second) == 5)

numberA.add(first);
numberB.add(second);



Set<List<Integer>> result = new HashSet<List<Integer>>();
for (int i=0; i<numberA.size(); i++)
int n1 = numberA.get(i);
int n2 = numberB.get(i);
List<Integer> numbersToAdd = Arrays.asList(n1, n2);
result.add(numbersToAdd);

return result;







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 14 '18 at 9:55









ProgmanProgman

6,35331936




6,35331936












  • Thank you so much for your help! It works!

    – BVK 0118
    Nov 14 '18 at 22:08

















  • Thank you so much for your help! It works!

    – BVK 0118
    Nov 14 '18 at 22:08
















Thank you so much for your help! It works!

– BVK 0118
Nov 14 '18 at 22:08





Thank you so much for your help! It works!

– BVK 0118
Nov 14 '18 at 22:08

















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