Is it possible to disable bool operator<(float,int)
Can I, in C++, disable or force an explicit cast in operator<
when comparing integer and floating types? Using operator<
between integer and float types can easily lead to bugs in quantitative code. I tried bool operator<(double, int) = delete;
but it expects one of the types to be a class or enum. How do I make the below fail to compile with a type error?
int main()
if (3.0 < 4)
std::cout << "X" << std::endl;
else
std::cout << "Y" << std::endl;
return 0;
c++
add a comment |
Can I, in C++, disable or force an explicit cast in operator<
when comparing integer and floating types? Using operator<
between integer and float types can easily lead to bugs in quantitative code. I tried bool operator<(double, int) = delete;
but it expects one of the types to be a class or enum. How do I make the below fail to compile with a type error?
int main()
if (3.0 < 4)
std::cout << "X" << std::endl;
else
std::cout << "Y" << std::endl;
return 0;
c++
It cannot be done natively. But you can look into various external tests.
– Mooing Duck
Nov 13 '18 at 21:43
Nuts. Do you mean taking a static analysis approach?
– Carbon
Nov 13 '18 at 21:43
I don't see the applicability of being able to do this. It's really a contract between the programmer and the compiler to not do stupid things. The end-client can't touch this.
– DeiDei
Nov 13 '18 at 21:59
In quant finance it's very common to have business users doing dev. I clean up.
– Carbon
Nov 13 '18 at 22:37
add a comment |
Can I, in C++, disable or force an explicit cast in operator<
when comparing integer and floating types? Using operator<
between integer and float types can easily lead to bugs in quantitative code. I tried bool operator<(double, int) = delete;
but it expects one of the types to be a class or enum. How do I make the below fail to compile with a type error?
int main()
if (3.0 < 4)
std::cout << "X" << std::endl;
else
std::cout << "Y" << std::endl;
return 0;
c++
Can I, in C++, disable or force an explicit cast in operator<
when comparing integer and floating types? Using operator<
between integer and float types can easily lead to bugs in quantitative code. I tried bool operator<(double, int) = delete;
but it expects one of the types to be a class or enum. How do I make the below fail to compile with a type error?
int main()
if (3.0 < 4)
std::cout << "X" << std::endl;
else
std::cout << "Y" << std::endl;
return 0;
c++
c++
asked Nov 13 '18 at 21:41
CarbonCarbon
1,4211926
1,4211926
It cannot be done natively. But you can look into various external tests.
– Mooing Duck
Nov 13 '18 at 21:43
Nuts. Do you mean taking a static analysis approach?
– Carbon
Nov 13 '18 at 21:43
I don't see the applicability of being able to do this. It's really a contract between the programmer and the compiler to not do stupid things. The end-client can't touch this.
– DeiDei
Nov 13 '18 at 21:59
In quant finance it's very common to have business users doing dev. I clean up.
– Carbon
Nov 13 '18 at 22:37
add a comment |
It cannot be done natively. But you can look into various external tests.
– Mooing Duck
Nov 13 '18 at 21:43
Nuts. Do you mean taking a static analysis approach?
– Carbon
Nov 13 '18 at 21:43
I don't see the applicability of being able to do this. It's really a contract between the programmer and the compiler to not do stupid things. The end-client can't touch this.
– DeiDei
Nov 13 '18 at 21:59
In quant finance it's very common to have business users doing dev. I clean up.
– Carbon
Nov 13 '18 at 22:37
It cannot be done natively. But you can look into various external tests.
– Mooing Duck
Nov 13 '18 at 21:43
It cannot be done natively. But you can look into various external tests.
– Mooing Duck
Nov 13 '18 at 21:43
Nuts. Do you mean taking a static analysis approach?
– Carbon
Nov 13 '18 at 21:43
Nuts. Do you mean taking a static analysis approach?
– Carbon
Nov 13 '18 at 21:43
I don't see the applicability of being able to do this. It's really a contract between the programmer and the compiler to not do stupid things. The end-client can't touch this.
– DeiDei
Nov 13 '18 at 21:59
I don't see the applicability of being able to do this. It's really a contract between the programmer and the compiler to not do stupid things. The end-client can't touch this.
– DeiDei
Nov 13 '18 at 21:59
In quant finance it's very common to have business users doing dev. I clean up.
– Carbon
Nov 13 '18 at 22:37
In quant finance it's very common to have business users doing dev. I clean up.
– Carbon
Nov 13 '18 at 22:37
add a comment |
1 Answer
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It's not possible to change the behaviour of built-in operators. You will have to detect this situation via compiler warnings or other code analysis tools.
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
It's not possible to change the behaviour of built-in operators. You will have to detect this situation via compiler warnings or other code analysis tools.
add a comment |
It's not possible to change the behaviour of built-in operators. You will have to detect this situation via compiler warnings or other code analysis tools.
add a comment |
It's not possible to change the behaviour of built-in operators. You will have to detect this situation via compiler warnings or other code analysis tools.
It's not possible to change the behaviour of built-in operators. You will have to detect this situation via compiler warnings or other code analysis tools.
answered Nov 13 '18 at 21:44
M.MM.M
105k11116237
105k11116237
add a comment |
add a comment |
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It cannot be done natively. But you can look into various external tests.
– Mooing Duck
Nov 13 '18 at 21:43
Nuts. Do you mean taking a static analysis approach?
– Carbon
Nov 13 '18 at 21:43
I don't see the applicability of being able to do this. It's really a contract between the programmer and the compiler to not do stupid things. The end-client can't touch this.
– DeiDei
Nov 13 '18 at 21:59
In quant finance it's very common to have business users doing dev. I clean up.
– Carbon
Nov 13 '18 at 22:37