Return rows that have a negative equivalent
I have a non-normalized table with several columns. I would like to return all columns that have a positive number along with a negative number of the same value.
Example:
ID | Value
-------------
1 | 10
1 | -10
3 | 15
3 | 15
4 | -1
5 | 4
Current Output:
ID | Values
-------------
1 | 10
1 | -10
3 | 15
3 | 15
Desired Output:
ID | Value
-------------
1 | 10
1 | -10
I have made a windows function as seen below that will select absolute values that are the same, but this includes pairs where there are a positive number.
select Count(*) Over (Partition By DVN, [Tran Date], [Reference Number],Description,Vendor, Abs([Maintenance Expense])) As cnt , *
From WorkTemp.dbo.Customer2700Combine
Where [Maintenance Expense] Is Not Null
Order By 1 Desc,DVN, [Tran Date], [Reference Number],Description,Vendor, Abs([NonRental Total])
sql-server
add a comment |
I have a non-normalized table with several columns. I would like to return all columns that have a positive number along with a negative number of the same value.
Example:
ID | Value
-------------
1 | 10
1 | -10
3 | 15
3 | 15
4 | -1
5 | 4
Current Output:
ID | Values
-------------
1 | 10
1 | -10
3 | 15
3 | 15
Desired Output:
ID | Value
-------------
1 | 10
1 | -10
I have made a windows function as seen below that will select absolute values that are the same, but this includes pairs where there are a positive number.
select Count(*) Over (Partition By DVN, [Tran Date], [Reference Number],Description,Vendor, Abs([Maintenance Expense])) As cnt , *
From WorkTemp.dbo.Customer2700Combine
Where [Maintenance Expense] Is Not Null
Order By 1 Desc,DVN, [Tran Date], [Reference Number],Description,Vendor, Abs([NonRental Total])
sql-server
2
Hi and welcome to SO. Here is a great place to start.
– Sean Lange
Nov 12 '18 at 22:37
In your example above, do you care about these values being part of the same ID? or any value regardless of the ID?
– Saul Cruz
Nov 12 '18 at 23:19
add a comment |
I have a non-normalized table with several columns. I would like to return all columns that have a positive number along with a negative number of the same value.
Example:
ID | Value
-------------
1 | 10
1 | -10
3 | 15
3 | 15
4 | -1
5 | 4
Current Output:
ID | Values
-------------
1 | 10
1 | -10
3 | 15
3 | 15
Desired Output:
ID | Value
-------------
1 | 10
1 | -10
I have made a windows function as seen below that will select absolute values that are the same, but this includes pairs where there are a positive number.
select Count(*) Over (Partition By DVN, [Tran Date], [Reference Number],Description,Vendor, Abs([Maintenance Expense])) As cnt , *
From WorkTemp.dbo.Customer2700Combine
Where [Maintenance Expense] Is Not Null
Order By 1 Desc,DVN, [Tran Date], [Reference Number],Description,Vendor, Abs([NonRental Total])
sql-server
I have a non-normalized table with several columns. I would like to return all columns that have a positive number along with a negative number of the same value.
Example:
ID | Value
-------------
1 | 10
1 | -10
3 | 15
3 | 15
4 | -1
5 | 4
Current Output:
ID | Values
-------------
1 | 10
1 | -10
3 | 15
3 | 15
Desired Output:
ID | Value
-------------
1 | 10
1 | -10
I have made a windows function as seen below that will select absolute values that are the same, but this includes pairs where there are a positive number.
select Count(*) Over (Partition By DVN, [Tran Date], [Reference Number],Description,Vendor, Abs([Maintenance Expense])) As cnt , *
From WorkTemp.dbo.Customer2700Combine
Where [Maintenance Expense] Is Not Null
Order By 1 Desc,DVN, [Tran Date], [Reference Number],Description,Vendor, Abs([NonRental Total])
sql-server
sql-server
edited Nov 13 '18 at 0:40
Alejandro
4,24322136
4,24322136
asked Nov 12 '18 at 22:32
Jowy
31
31
2
Hi and welcome to SO. Here is a great place to start.
– Sean Lange
Nov 12 '18 at 22:37
In your example above, do you care about these values being part of the same ID? or any value regardless of the ID?
– Saul Cruz
Nov 12 '18 at 23:19
add a comment |
2
Hi and welcome to SO. Here is a great place to start.
– Sean Lange
Nov 12 '18 at 22:37
In your example above, do you care about these values being part of the same ID? or any value regardless of the ID?
– Saul Cruz
Nov 12 '18 at 23:19
2
2
Hi and welcome to SO. Here is a great place to start.
– Sean Lange
Nov 12 '18 at 22:37
Hi and welcome to SO. Here is a great place to start.
– Sean Lange
Nov 12 '18 at 22:37
In your example above, do you care about these values being part of the same ID? or any value regardless of the ID?
– Saul Cruz
Nov 12 '18 at 23:19
In your example above, do you care about these values being part of the same ID? or any value regardless of the ID?
– Saul Cruz
Nov 12 '18 at 23:19
add a comment |
1 Answer
1
active
oldest
votes
Not sure if your requirement is by [ID], looking at your example, description and desired output, this is how I would do it:
DROP TABLE IF EXISTS #sopg;
SELECT [ID],
[VALUE]
INTO #sopg
FROM
(
SELECT 1 AS ID,
10 AS VALUE
UNION
SELECT 1 AS ID,
-10 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 4 AS ID,
-1 AS VALUE
UNION
SELECT 5 AS ID,
4 AS VALUE
) x;
-- Assuming that one ID can only have maximum 2 rows (like your example above) and want this by ID
SELECT s.[ID],
s.[VALUE]
FROM #sopg s
INNER JOIN
(
SELECT ID,
SUM(VALUE) SumZero
FROM #sopg
GROUP BY ID
HAVING SUM(VALUE) = 0
) SumZero ON SumZero.ID = s.ID
-- Another way, assuming that ID can have more than 2 rows and different values
DROP TABLE IF EXISTS #sopg2;
SELECT [ID],
[VALUE]
INTO #sopg2
FROM
(
SELECT 1 AS ID,
10 AS VALUE
UNION
SELECT 1 AS ID,
-10 AS VALUE
UNION
SELECT 1 AS ID,
-9 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 4 AS ID,
-1 AS VALUE
UNION
SELECT 5 AS ID,
4 AS VALUE
) x
SELECT a.[ID],
a.[VALUE]
FROM #sopg2 a
INNER JOIN #sopg b ON b.ID = a.ID AND a.VALUE = -b.VALUE
1
Thank you so much! The second solution works perfectly, matching on a reversed value is very clever, I had no idea you could do that!
– Jowy
Nov 13 '18 at 20:38
Yeah, you can basically do every conversion/transformation on the '=' part, by the way, if you copy and paste the test data that I put in my answer as part of your input test data in your question, people might upvote your answer as it will be easier to understand and reproduce. Cheers
– Saul Cruz
Nov 13 '18 at 21:11
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Not sure if your requirement is by [ID], looking at your example, description and desired output, this is how I would do it:
DROP TABLE IF EXISTS #sopg;
SELECT [ID],
[VALUE]
INTO #sopg
FROM
(
SELECT 1 AS ID,
10 AS VALUE
UNION
SELECT 1 AS ID,
-10 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 4 AS ID,
-1 AS VALUE
UNION
SELECT 5 AS ID,
4 AS VALUE
) x;
-- Assuming that one ID can only have maximum 2 rows (like your example above) and want this by ID
SELECT s.[ID],
s.[VALUE]
FROM #sopg s
INNER JOIN
(
SELECT ID,
SUM(VALUE) SumZero
FROM #sopg
GROUP BY ID
HAVING SUM(VALUE) = 0
) SumZero ON SumZero.ID = s.ID
-- Another way, assuming that ID can have more than 2 rows and different values
DROP TABLE IF EXISTS #sopg2;
SELECT [ID],
[VALUE]
INTO #sopg2
FROM
(
SELECT 1 AS ID,
10 AS VALUE
UNION
SELECT 1 AS ID,
-10 AS VALUE
UNION
SELECT 1 AS ID,
-9 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 4 AS ID,
-1 AS VALUE
UNION
SELECT 5 AS ID,
4 AS VALUE
) x
SELECT a.[ID],
a.[VALUE]
FROM #sopg2 a
INNER JOIN #sopg b ON b.ID = a.ID AND a.VALUE = -b.VALUE
1
Thank you so much! The second solution works perfectly, matching on a reversed value is very clever, I had no idea you could do that!
– Jowy
Nov 13 '18 at 20:38
Yeah, you can basically do every conversion/transformation on the '=' part, by the way, if you copy and paste the test data that I put in my answer as part of your input test data in your question, people might upvote your answer as it will be easier to understand and reproduce. Cheers
– Saul Cruz
Nov 13 '18 at 21:11
add a comment |
Not sure if your requirement is by [ID], looking at your example, description and desired output, this is how I would do it:
DROP TABLE IF EXISTS #sopg;
SELECT [ID],
[VALUE]
INTO #sopg
FROM
(
SELECT 1 AS ID,
10 AS VALUE
UNION
SELECT 1 AS ID,
-10 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 4 AS ID,
-1 AS VALUE
UNION
SELECT 5 AS ID,
4 AS VALUE
) x;
-- Assuming that one ID can only have maximum 2 rows (like your example above) and want this by ID
SELECT s.[ID],
s.[VALUE]
FROM #sopg s
INNER JOIN
(
SELECT ID,
SUM(VALUE) SumZero
FROM #sopg
GROUP BY ID
HAVING SUM(VALUE) = 0
) SumZero ON SumZero.ID = s.ID
-- Another way, assuming that ID can have more than 2 rows and different values
DROP TABLE IF EXISTS #sopg2;
SELECT [ID],
[VALUE]
INTO #sopg2
FROM
(
SELECT 1 AS ID,
10 AS VALUE
UNION
SELECT 1 AS ID,
-10 AS VALUE
UNION
SELECT 1 AS ID,
-9 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 4 AS ID,
-1 AS VALUE
UNION
SELECT 5 AS ID,
4 AS VALUE
) x
SELECT a.[ID],
a.[VALUE]
FROM #sopg2 a
INNER JOIN #sopg b ON b.ID = a.ID AND a.VALUE = -b.VALUE
1
Thank you so much! The second solution works perfectly, matching on a reversed value is very clever, I had no idea you could do that!
– Jowy
Nov 13 '18 at 20:38
Yeah, you can basically do every conversion/transformation on the '=' part, by the way, if you copy and paste the test data that I put in my answer as part of your input test data in your question, people might upvote your answer as it will be easier to understand and reproduce. Cheers
– Saul Cruz
Nov 13 '18 at 21:11
add a comment |
Not sure if your requirement is by [ID], looking at your example, description and desired output, this is how I would do it:
DROP TABLE IF EXISTS #sopg;
SELECT [ID],
[VALUE]
INTO #sopg
FROM
(
SELECT 1 AS ID,
10 AS VALUE
UNION
SELECT 1 AS ID,
-10 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 4 AS ID,
-1 AS VALUE
UNION
SELECT 5 AS ID,
4 AS VALUE
) x;
-- Assuming that one ID can only have maximum 2 rows (like your example above) and want this by ID
SELECT s.[ID],
s.[VALUE]
FROM #sopg s
INNER JOIN
(
SELECT ID,
SUM(VALUE) SumZero
FROM #sopg
GROUP BY ID
HAVING SUM(VALUE) = 0
) SumZero ON SumZero.ID = s.ID
-- Another way, assuming that ID can have more than 2 rows and different values
DROP TABLE IF EXISTS #sopg2;
SELECT [ID],
[VALUE]
INTO #sopg2
FROM
(
SELECT 1 AS ID,
10 AS VALUE
UNION
SELECT 1 AS ID,
-10 AS VALUE
UNION
SELECT 1 AS ID,
-9 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 4 AS ID,
-1 AS VALUE
UNION
SELECT 5 AS ID,
4 AS VALUE
) x
SELECT a.[ID],
a.[VALUE]
FROM #sopg2 a
INNER JOIN #sopg b ON b.ID = a.ID AND a.VALUE = -b.VALUE
Not sure if your requirement is by [ID], looking at your example, description and desired output, this is how I would do it:
DROP TABLE IF EXISTS #sopg;
SELECT [ID],
[VALUE]
INTO #sopg
FROM
(
SELECT 1 AS ID,
10 AS VALUE
UNION
SELECT 1 AS ID,
-10 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 4 AS ID,
-1 AS VALUE
UNION
SELECT 5 AS ID,
4 AS VALUE
) x;
-- Assuming that one ID can only have maximum 2 rows (like your example above) and want this by ID
SELECT s.[ID],
s.[VALUE]
FROM #sopg s
INNER JOIN
(
SELECT ID,
SUM(VALUE) SumZero
FROM #sopg
GROUP BY ID
HAVING SUM(VALUE) = 0
) SumZero ON SumZero.ID = s.ID
-- Another way, assuming that ID can have more than 2 rows and different values
DROP TABLE IF EXISTS #sopg2;
SELECT [ID],
[VALUE]
INTO #sopg2
FROM
(
SELECT 1 AS ID,
10 AS VALUE
UNION
SELECT 1 AS ID,
-10 AS VALUE
UNION
SELECT 1 AS ID,
-9 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 3 AS ID,
15 AS VALUE
UNION
SELECT 4 AS ID,
-1 AS VALUE
UNION
SELECT 5 AS ID,
4 AS VALUE
) x
SELECT a.[ID],
a.[VALUE]
FROM #sopg2 a
INNER JOIN #sopg b ON b.ID = a.ID AND a.VALUE = -b.VALUE
edited Nov 13 '18 at 0:19
answered Nov 12 '18 at 23:26
Saul Cruz
33229
33229
1
Thank you so much! The second solution works perfectly, matching on a reversed value is very clever, I had no idea you could do that!
– Jowy
Nov 13 '18 at 20:38
Yeah, you can basically do every conversion/transformation on the '=' part, by the way, if you copy and paste the test data that I put in my answer as part of your input test data in your question, people might upvote your answer as it will be easier to understand and reproduce. Cheers
– Saul Cruz
Nov 13 '18 at 21:11
add a comment |
1
Thank you so much! The second solution works perfectly, matching on a reversed value is very clever, I had no idea you could do that!
– Jowy
Nov 13 '18 at 20:38
Yeah, you can basically do every conversion/transformation on the '=' part, by the way, if you copy and paste the test data that I put in my answer as part of your input test data in your question, people might upvote your answer as it will be easier to understand and reproduce. Cheers
– Saul Cruz
Nov 13 '18 at 21:11
1
1
Thank you so much! The second solution works perfectly, matching on a reversed value is very clever, I had no idea you could do that!
– Jowy
Nov 13 '18 at 20:38
Thank you so much! The second solution works perfectly, matching on a reversed value is very clever, I had no idea you could do that!
– Jowy
Nov 13 '18 at 20:38
Yeah, you can basically do every conversion/transformation on the '=' part, by the way, if you copy and paste the test data that I put in my answer as part of your input test data in your question, people might upvote your answer as it will be easier to understand and reproduce. Cheers
– Saul Cruz
Nov 13 '18 at 21:11
Yeah, you can basically do every conversion/transformation on the '=' part, by the way, if you copy and paste the test data that I put in my answer as part of your input test data in your question, people might upvote your answer as it will be easier to understand and reproduce. Cheers
– Saul Cruz
Nov 13 '18 at 21:11
add a comment |
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2
Hi and welcome to SO. Here is a great place to start.
– Sean Lange
Nov 12 '18 at 22:37
In your example above, do you care about these values being part of the same ID? or any value regardless of the ID?
– Saul Cruz
Nov 12 '18 at 23:19