Value object to json in go










2















I have a struct which contains an other struct as value object.



type User struct 
Name string `json:"name"``
Email valueobject.Email `json:"email"`



The valueobject.Email looks like this:



type Email struct 
value string

func (e *Email) Value() string
return e.Value



I want the value object as an immutable object, there is also a "factory" method in this is not necessary for my problem.



Now I want to return the User struct as json and therefor I use



response := map[string]interface"user": User
json.NewEncoder(w).Encode(response)


The result is:




"user":
"name": "John Doe",
"email":
"Email: "johndoe@example.com"





But I want something link this:




"user":
"name": "John Doe",
"email": "johndoe@example.com"











share|improve this question


























    2















    I have a struct which contains an other struct as value object.



    type User struct 
    Name string `json:"name"``
    Email valueobject.Email `json:"email"`



    The valueobject.Email looks like this:



    type Email struct 
    value string

    func (e *Email) Value() string
    return e.Value



    I want the value object as an immutable object, there is also a "factory" method in this is not necessary for my problem.



    Now I want to return the User struct as json and therefor I use



    response := map[string]interface"user": User
    json.NewEncoder(w).Encode(response)


    The result is:




    "user":
    "name": "John Doe",
    "email":
    "Email: "johndoe@example.com"





    But I want something link this:




    "user":
    "name": "John Doe",
    "email": "johndoe@example.com"











    share|improve this question
























      2












      2








      2








      I have a struct which contains an other struct as value object.



      type User struct 
      Name string `json:"name"``
      Email valueobject.Email `json:"email"`



      The valueobject.Email looks like this:



      type Email struct 
      value string

      func (e *Email) Value() string
      return e.Value



      I want the value object as an immutable object, there is also a "factory" method in this is not necessary for my problem.



      Now I want to return the User struct as json and therefor I use



      response := map[string]interface"user": User
      json.NewEncoder(w).Encode(response)


      The result is:




      "user":
      "name": "John Doe",
      "email":
      "Email: "johndoe@example.com"





      But I want something link this:




      "user":
      "name": "John Doe",
      "email": "johndoe@example.com"











      share|improve this question














      I have a struct which contains an other struct as value object.



      type User struct 
      Name string `json:"name"``
      Email valueobject.Email `json:"email"`



      The valueobject.Email looks like this:



      type Email struct 
      value string

      func (e *Email) Value() string
      return e.Value



      I want the value object as an immutable object, there is also a "factory" method in this is not necessary for my problem.



      Now I want to return the User struct as json and therefor I use



      response := map[string]interface"user": User
      json.NewEncoder(w).Encode(response)


      The result is:




      "user":
      "name": "John Doe",
      "email":
      "Email: "johndoe@example.com"





      But I want something link this:




      "user":
      "name": "John Doe",
      "email": "johndoe@example.com"








      json go






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 14 '18 at 7:06









      Marvin CasparMarvin Caspar

      359317




      359317






















          2 Answers
          2






          active

          oldest

          votes


















          6














          It sounds like you need valueobject.Email to implement the json.Marshaler interface:



          func (e *Email) MarshalJSON() (byte, error) 
          return json.Marshal(e.Value())



          That is the bare-minimum to implement what you are asking for. By implementing the json.Marshaler interface, it allows you to customize how json.Marshal renders your value.



          Another option is to simplify Email into just a wrapper for string, instead of a struct:



          type Email string

          func (e Email) Value() string
          return e



          Since strings are already handled by json.Marshal, it should just work.






          share|improve this answer























          • Thanks, the MarshalJSON methods solves my problem

            – Marvin Caspar
            Nov 14 '18 at 7:47


















          0














          To make your Email type marshal the way you'd like, you'll need to make it implement the json.marshaler interface. GopherAcademy uses the following example:



          func (d Dog) MarshalJSON() (byte, error) 
          return json.Marshal(NewJSONDog(d))





          share|improve this answer
























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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            6














            It sounds like you need valueobject.Email to implement the json.Marshaler interface:



            func (e *Email) MarshalJSON() (byte, error) 
            return json.Marshal(e.Value())



            That is the bare-minimum to implement what you are asking for. By implementing the json.Marshaler interface, it allows you to customize how json.Marshal renders your value.



            Another option is to simplify Email into just a wrapper for string, instead of a struct:



            type Email string

            func (e Email) Value() string
            return e



            Since strings are already handled by json.Marshal, it should just work.






            share|improve this answer























            • Thanks, the MarshalJSON methods solves my problem

              – Marvin Caspar
              Nov 14 '18 at 7:47















            6














            It sounds like you need valueobject.Email to implement the json.Marshaler interface:



            func (e *Email) MarshalJSON() (byte, error) 
            return json.Marshal(e.Value())



            That is the bare-minimum to implement what you are asking for. By implementing the json.Marshaler interface, it allows you to customize how json.Marshal renders your value.



            Another option is to simplify Email into just a wrapper for string, instead of a struct:



            type Email string

            func (e Email) Value() string
            return e



            Since strings are already handled by json.Marshal, it should just work.






            share|improve this answer























            • Thanks, the MarshalJSON methods solves my problem

              – Marvin Caspar
              Nov 14 '18 at 7:47













            6












            6








            6







            It sounds like you need valueobject.Email to implement the json.Marshaler interface:



            func (e *Email) MarshalJSON() (byte, error) 
            return json.Marshal(e.Value())



            That is the bare-minimum to implement what you are asking for. By implementing the json.Marshaler interface, it allows you to customize how json.Marshal renders your value.



            Another option is to simplify Email into just a wrapper for string, instead of a struct:



            type Email string

            func (e Email) Value() string
            return e



            Since strings are already handled by json.Marshal, it should just work.






            share|improve this answer













            It sounds like you need valueobject.Email to implement the json.Marshaler interface:



            func (e *Email) MarshalJSON() (byte, error) 
            return json.Marshal(e.Value())



            That is the bare-minimum to implement what you are asking for. By implementing the json.Marshaler interface, it allows you to customize how json.Marshal renders your value.



            Another option is to simplify Email into just a wrapper for string, instead of a struct:



            type Email string

            func (e Email) Value() string
            return e



            Since strings are already handled by json.Marshal, it should just work.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 14 '18 at 7:25









            Dominic BarnesDominic Barnes

            23.7k75482




            23.7k75482












            • Thanks, the MarshalJSON methods solves my problem

              – Marvin Caspar
              Nov 14 '18 at 7:47

















            • Thanks, the MarshalJSON methods solves my problem

              – Marvin Caspar
              Nov 14 '18 at 7:47
















            Thanks, the MarshalJSON methods solves my problem

            – Marvin Caspar
            Nov 14 '18 at 7:47





            Thanks, the MarshalJSON methods solves my problem

            – Marvin Caspar
            Nov 14 '18 at 7:47













            0














            To make your Email type marshal the way you'd like, you'll need to make it implement the json.marshaler interface. GopherAcademy uses the following example:



            func (d Dog) MarshalJSON() (byte, error) 
            return json.Marshal(NewJSONDog(d))





            share|improve this answer





























              0














              To make your Email type marshal the way you'd like, you'll need to make it implement the json.marshaler interface. GopherAcademy uses the following example:



              func (d Dog) MarshalJSON() (byte, error) 
              return json.Marshal(NewJSONDog(d))





              share|improve this answer



























                0












                0








                0







                To make your Email type marshal the way you'd like, you'll need to make it implement the json.marshaler interface. GopherAcademy uses the following example:



                func (d Dog) MarshalJSON() (byte, error) 
                return json.Marshal(NewJSONDog(d))





                share|improve this answer















                To make your Email type marshal the way you'd like, you'll need to make it implement the json.marshaler interface. GopherAcademy uses the following example:



                func (d Dog) MarshalJSON() (byte, error) 
                return json.Marshal(NewJSONDog(d))






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 14 '18 at 7:43

























                answered Nov 14 '18 at 7:32









                Snake14Snake14

                28917




                28917



























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