Code splitting and dynamic loading in Webpack 4 with react loadable
So I have a webpack 4 react app that has 2 parts:
- Login component
- Rest of the app
My routes.js looks like this:
import React from 'react';
import Home from 'Home';
....
const LoadableLoginComponent = Loadable(
loader: () => import('LoginComponent'),
loading()
return <div>Loading...</div>
);
.....
render()
if (!this.loggedIn)
return (
<LoadableLoginComponent />
);
return (
<Home />
);
My webpack generates 2 js files bundle.min.js and 0.min.js
My assumption was that by default if the user is not logged in only the login component will load with 0.min.js and if user is logged in, the rest of the app will load
but I see both bundle.min.js and 0.min.js being loaded.
reactjs webpack webpack-4 code-splitting react-loadable
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So I have a webpack 4 react app that has 2 parts:
- Login component
- Rest of the app
My routes.js looks like this:
import React from 'react';
import Home from 'Home';
....
const LoadableLoginComponent = Loadable(
loader: () => import('LoginComponent'),
loading()
return <div>Loading...</div>
);
.....
render()
if (!this.loggedIn)
return (
<LoadableLoginComponent />
);
return (
<Home />
);
My webpack generates 2 js files bundle.min.js and 0.min.js
My assumption was that by default if the user is not logged in only the login component will load with 0.min.js and if user is logged in, the rest of the app will load
but I see both bundle.min.js and 0.min.js being loaded.
reactjs webpack webpack-4 code-splitting react-loadable
add a comment |
So I have a webpack 4 react app that has 2 parts:
- Login component
- Rest of the app
My routes.js looks like this:
import React from 'react';
import Home from 'Home';
....
const LoadableLoginComponent = Loadable(
loader: () => import('LoginComponent'),
loading()
return <div>Loading...</div>
);
.....
render()
if (!this.loggedIn)
return (
<LoadableLoginComponent />
);
return (
<Home />
);
My webpack generates 2 js files bundle.min.js and 0.min.js
My assumption was that by default if the user is not logged in only the login component will load with 0.min.js and if user is logged in, the rest of the app will load
but I see both bundle.min.js and 0.min.js being loaded.
reactjs webpack webpack-4 code-splitting react-loadable
So I have a webpack 4 react app that has 2 parts:
- Login component
- Rest of the app
My routes.js looks like this:
import React from 'react';
import Home from 'Home';
....
const LoadableLoginComponent = Loadable(
loader: () => import('LoginComponent'),
loading()
return <div>Loading...</div>
);
.....
render()
if (!this.loggedIn)
return (
<LoadableLoginComponent />
);
return (
<Home />
);
My webpack generates 2 js files bundle.min.js and 0.min.js
My assumption was that by default if the user is not logged in only the login component will load with 0.min.js and if user is logged in, the rest of the app will load
but I see both bundle.min.js and 0.min.js being loaded.
reactjs webpack webpack-4 code-splitting react-loadable
reactjs webpack webpack-4 code-splitting react-loadable
asked Nov 14 '18 at 23:54
prgrmrprgrmr
4002519
4002519
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1 Answer
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If you have an if statement (!this.loggedIn) in the non-login bundle that has the possibility of rendering the login component, then the login component will be included in your non-login bundle. This is because the entry point for your non-login bundle searches all the possible code paths and files it might need to use and bundles them together, even if your if statement always fails and never uses the Login component.
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you have an if statement (!this.loggedIn) in the non-login bundle that has the possibility of rendering the login component, then the login component will be included in your non-login bundle. This is because the entry point for your non-login bundle searches all the possible code paths and files it might need to use and bundles them together, even if your if statement always fails and never uses the Login component.
add a comment |
If you have an if statement (!this.loggedIn) in the non-login bundle that has the possibility of rendering the login component, then the login component will be included in your non-login bundle. This is because the entry point for your non-login bundle searches all the possible code paths and files it might need to use and bundles them together, even if your if statement always fails and never uses the Login component.
add a comment |
If you have an if statement (!this.loggedIn) in the non-login bundle that has the possibility of rendering the login component, then the login component will be included in your non-login bundle. This is because the entry point for your non-login bundle searches all the possible code paths and files it might need to use and bundles them together, even if your if statement always fails and never uses the Login component.
If you have an if statement (!this.loggedIn) in the non-login bundle that has the possibility of rendering the login component, then the login component will be included in your non-login bundle. This is because the entry point for your non-login bundle searches all the possible code paths and files it might need to use and bundles them together, even if your if statement always fails and never uses the Login component.
answered Nov 15 '18 at 0:45
Shawn AndrewsShawn Andrews
965617
965617
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