Code splitting and dynamic loading in Webpack 4 with react loadable










1















So I have a webpack 4 react app that has 2 parts:



  • Login component

  • Rest of the app

My routes.js looks like this:



import React from 'react';
import Home from 'Home';

....

const LoadableLoginComponent = Loadable(
loader: () => import('LoginComponent'),
loading()
return <div>Loading...</div>

);

.....

render()
if (!this.loggedIn)
return (
<LoadableLoginComponent />
);


return (
<Home />
);



My webpack generates 2 js files bundle.min.js and 0.min.js



My assumption was that by default if the user is not logged in only the login component will load with 0.min.js and if user is logged in, the rest of the app will load
but I see both bundle.min.js and 0.min.js being loaded.










share|improve this question


























    1















    So I have a webpack 4 react app that has 2 parts:



    • Login component

    • Rest of the app

    My routes.js looks like this:



    import React from 'react';
    import Home from 'Home';

    ....

    const LoadableLoginComponent = Loadable(
    loader: () => import('LoginComponent'),
    loading()
    return <div>Loading...</div>

    );

    .....

    render()
    if (!this.loggedIn)
    return (
    <LoadableLoginComponent />
    );


    return (
    <Home />
    );



    My webpack generates 2 js files bundle.min.js and 0.min.js



    My assumption was that by default if the user is not logged in only the login component will load with 0.min.js and if user is logged in, the rest of the app will load
    but I see both bundle.min.js and 0.min.js being loaded.










    share|improve this question
























      1












      1








      1








      So I have a webpack 4 react app that has 2 parts:



      • Login component

      • Rest of the app

      My routes.js looks like this:



      import React from 'react';
      import Home from 'Home';

      ....

      const LoadableLoginComponent = Loadable(
      loader: () => import('LoginComponent'),
      loading()
      return <div>Loading...</div>

      );

      .....

      render()
      if (!this.loggedIn)
      return (
      <LoadableLoginComponent />
      );


      return (
      <Home />
      );



      My webpack generates 2 js files bundle.min.js and 0.min.js



      My assumption was that by default if the user is not logged in only the login component will load with 0.min.js and if user is logged in, the rest of the app will load
      but I see both bundle.min.js and 0.min.js being loaded.










      share|improve this question














      So I have a webpack 4 react app that has 2 parts:



      • Login component

      • Rest of the app

      My routes.js looks like this:



      import React from 'react';
      import Home from 'Home';

      ....

      const LoadableLoginComponent = Loadable(
      loader: () => import('LoginComponent'),
      loading()
      return <div>Loading...</div>

      );

      .....

      render()
      if (!this.loggedIn)
      return (
      <LoadableLoginComponent />
      );


      return (
      <Home />
      );



      My webpack generates 2 js files bundle.min.js and 0.min.js



      My assumption was that by default if the user is not logged in only the login component will load with 0.min.js and if user is logged in, the rest of the app will load
      but I see both bundle.min.js and 0.min.js being loaded.







      reactjs webpack webpack-4 code-splitting react-loadable






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      asked Nov 14 '18 at 23:54









      prgrmrprgrmr

      4002519




      4002519






















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          If you have an if statement (!this.loggedIn) in the non-login bundle that has the possibility of rendering the login component, then the login component will be included in your non-login bundle. This is because the entry point for your non-login bundle searches all the possible code paths and files it might need to use and bundles them together, even if your if statement always fails and never uses the Login component.






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            1 Answer
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            If you have an if statement (!this.loggedIn) in the non-login bundle that has the possibility of rendering the login component, then the login component will be included in your non-login bundle. This is because the entry point for your non-login bundle searches all the possible code paths and files it might need to use and bundles them together, even if your if statement always fails and never uses the Login component.






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              If you have an if statement (!this.loggedIn) in the non-login bundle that has the possibility of rendering the login component, then the login component will be included in your non-login bundle. This is because the entry point for your non-login bundle searches all the possible code paths and files it might need to use and bundles them together, even if your if statement always fails and never uses the Login component.






              share|improve this answer

























                1












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                1







                If you have an if statement (!this.loggedIn) in the non-login bundle that has the possibility of rendering the login component, then the login component will be included in your non-login bundle. This is because the entry point for your non-login bundle searches all the possible code paths and files it might need to use and bundles them together, even if your if statement always fails and never uses the Login component.






                share|improve this answer













                If you have an if statement (!this.loggedIn) in the non-login bundle that has the possibility of rendering the login component, then the login component will be included in your non-login bundle. This is because the entry point for your non-login bundle searches all the possible code paths and files it might need to use and bundles them together, even if your if statement always fails and never uses the Login component.







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                answered Nov 15 '18 at 0:45









                Shawn AndrewsShawn Andrews

                965617




                965617





























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