What's with error 1241 Operand should contain 1 column?










-1















I have a class project and I want to rank my data according to their score
but every time I run this query on mysql it always gives me error 1241.



Any thoughts on what's causing these?



here is my query:



SELECT
(SELECT gen_cityname,
SUM(scc_bgyscoretotal) as score,
@curRank := @curRank + 1 AS rank
FROM bgyprofile b, (SELECT @curRank := 0) r
WHERE gen_provname = bgyprofile.gen_provname
GROUP BY gen_incomeyr, gen_cityname
ORDER BY score asc) AS provranks
FROM bgyprofile
GROUP BY bgyprofile.gen_incomeyr, bgyprofile.gen_cityname









share|improve this question
























  • I'm trying to rank the score column

    – Yuuki
    Nov 16 '18 at 8:01











  • please provide some sample data for all the relevant tables and expected output. It would be best if you could setup db-fiddle.com

    – Madhur Bhaiya
    Nov 16 '18 at 8:02











  • Subquery in SELECT can only return a scalar value. Your subquery returns a table. Google some subquery tutorial.

    – Eric
    Nov 27 '18 at 17:52















-1















I have a class project and I want to rank my data according to their score
but every time I run this query on mysql it always gives me error 1241.



Any thoughts on what's causing these?



here is my query:



SELECT
(SELECT gen_cityname,
SUM(scc_bgyscoretotal) as score,
@curRank := @curRank + 1 AS rank
FROM bgyprofile b, (SELECT @curRank := 0) r
WHERE gen_provname = bgyprofile.gen_provname
GROUP BY gen_incomeyr, gen_cityname
ORDER BY score asc) AS provranks
FROM bgyprofile
GROUP BY bgyprofile.gen_incomeyr, bgyprofile.gen_cityname









share|improve this question
























  • I'm trying to rank the score column

    – Yuuki
    Nov 16 '18 at 8:01











  • please provide some sample data for all the relevant tables and expected output. It would be best if you could setup db-fiddle.com

    – Madhur Bhaiya
    Nov 16 '18 at 8:02











  • Subquery in SELECT can only return a scalar value. Your subquery returns a table. Google some subquery tutorial.

    – Eric
    Nov 27 '18 at 17:52













-1












-1








-1








I have a class project and I want to rank my data according to their score
but every time I run this query on mysql it always gives me error 1241.



Any thoughts on what's causing these?



here is my query:



SELECT
(SELECT gen_cityname,
SUM(scc_bgyscoretotal) as score,
@curRank := @curRank + 1 AS rank
FROM bgyprofile b, (SELECT @curRank := 0) r
WHERE gen_provname = bgyprofile.gen_provname
GROUP BY gen_incomeyr, gen_cityname
ORDER BY score asc) AS provranks
FROM bgyprofile
GROUP BY bgyprofile.gen_incomeyr, bgyprofile.gen_cityname









share|improve this question
















I have a class project and I want to rank my data according to their score
but every time I run this query on mysql it always gives me error 1241.



Any thoughts on what's causing these?



here is my query:



SELECT
(SELECT gen_cityname,
SUM(scc_bgyscoretotal) as score,
@curRank := @curRank + 1 AS rank
FROM bgyprofile b, (SELECT @curRank := 0) r
WHERE gen_provname = bgyprofile.gen_provname
GROUP BY gen_incomeyr, gen_cityname
ORDER BY score asc) AS provranks
FROM bgyprofile
GROUP BY bgyprofile.gen_incomeyr, bgyprofile.gen_cityname






mysql






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 16 '18 at 7:57









Madhur Bhaiya

19.6k62336




19.6k62336










asked Nov 16 '18 at 7:56









YuukiYuuki

145




145












  • I'm trying to rank the score column

    – Yuuki
    Nov 16 '18 at 8:01











  • please provide some sample data for all the relevant tables and expected output. It would be best if you could setup db-fiddle.com

    – Madhur Bhaiya
    Nov 16 '18 at 8:02











  • Subquery in SELECT can only return a scalar value. Your subquery returns a table. Google some subquery tutorial.

    – Eric
    Nov 27 '18 at 17:52

















  • I'm trying to rank the score column

    – Yuuki
    Nov 16 '18 at 8:01











  • please provide some sample data for all the relevant tables and expected output. It would be best if you could setup db-fiddle.com

    – Madhur Bhaiya
    Nov 16 '18 at 8:02











  • Subquery in SELECT can only return a scalar value. Your subquery returns a table. Google some subquery tutorial.

    – Eric
    Nov 27 '18 at 17:52
















I'm trying to rank the score column

– Yuuki
Nov 16 '18 at 8:01





I'm trying to rank the score column

– Yuuki
Nov 16 '18 at 8:01













please provide some sample data for all the relevant tables and expected output. It would be best if you could setup db-fiddle.com

– Madhur Bhaiya
Nov 16 '18 at 8:02





please provide some sample data for all the relevant tables and expected output. It would be best if you could setup db-fiddle.com

– Madhur Bhaiya
Nov 16 '18 at 8:02













Subquery in SELECT can only return a scalar value. Your subquery returns a table. Google some subquery tutorial.

– Eric
Nov 27 '18 at 17:52





Subquery in SELECT can only return a scalar value. Your subquery returns a table. Google some subquery tutorial.

– Eric
Nov 27 '18 at 17:52












1 Answer
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it gives error 1241 because your query has the form



SELECT (SELECT column1, column2 FROM t2) FROM t1;


(https://dev.mysql.com/doc/refman/8.0/en/subquery-errors.html)



As they say in comments sample data and an explenation of what you expect would be very useful. Maybe the first step is to change the query starting with SELECT * and moving the SELECT between brackets after the FROM, but, I repeat, I need some more information to understand the right way.






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    1 Answer
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    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    it gives error 1241 because your query has the form



    SELECT (SELECT column1, column2 FROM t2) FROM t1;


    (https://dev.mysql.com/doc/refman/8.0/en/subquery-errors.html)



    As they say in comments sample data and an explenation of what you expect would be very useful. Maybe the first step is to change the query starting with SELECT * and moving the SELECT between brackets after the FROM, but, I repeat, I need some more information to understand the right way.






    share|improve this answer





























      0














      it gives error 1241 because your query has the form



      SELECT (SELECT column1, column2 FROM t2) FROM t1;


      (https://dev.mysql.com/doc/refman/8.0/en/subquery-errors.html)



      As they say in comments sample data and an explenation of what you expect would be very useful. Maybe the first step is to change the query starting with SELECT * and moving the SELECT between brackets after the FROM, but, I repeat, I need some more information to understand the right way.






      share|improve this answer



























        0












        0








        0







        it gives error 1241 because your query has the form



        SELECT (SELECT column1, column2 FROM t2) FROM t1;


        (https://dev.mysql.com/doc/refman/8.0/en/subquery-errors.html)



        As they say in comments sample data and an explenation of what you expect would be very useful. Maybe the first step is to change the query starting with SELECT * and moving the SELECT between brackets after the FROM, but, I repeat, I need some more information to understand the right way.






        share|improve this answer















        it gives error 1241 because your query has the form



        SELECT (SELECT column1, column2 FROM t2) FROM t1;


        (https://dev.mysql.com/doc/refman/8.0/en/subquery-errors.html)



        As they say in comments sample data and an explenation of what you expect would be very useful. Maybe the first step is to change the query starting with SELECT * and moving the SELECT between brackets after the FROM, but, I repeat, I need some more information to understand the right way.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 29 '18 at 20:54

























        answered Nov 27 '18 at 17:48









        GufusGufus

        138119




        138119





























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