What's with error 1241 Operand should contain 1 column?
I have a class project and I want to rank my data according to their score
but every time I run this query on mysql it always gives me error 1241.
Any thoughts on what's causing these?
here is my query:
SELECT
(SELECT gen_cityname,
SUM(scc_bgyscoretotal) as score,
@curRank := @curRank + 1 AS rank
FROM bgyprofile b, (SELECT @curRank := 0) r
WHERE gen_provname = bgyprofile.gen_provname
GROUP BY gen_incomeyr, gen_cityname
ORDER BY score asc) AS provranks
FROM bgyprofile
GROUP BY bgyprofile.gen_incomeyr, bgyprofile.gen_cityname
mysql
add a comment |
I have a class project and I want to rank my data according to their score
but every time I run this query on mysql it always gives me error 1241.
Any thoughts on what's causing these?
here is my query:
SELECT
(SELECT gen_cityname,
SUM(scc_bgyscoretotal) as score,
@curRank := @curRank + 1 AS rank
FROM bgyprofile b, (SELECT @curRank := 0) r
WHERE gen_provname = bgyprofile.gen_provname
GROUP BY gen_incomeyr, gen_cityname
ORDER BY score asc) AS provranks
FROM bgyprofile
GROUP BY bgyprofile.gen_incomeyr, bgyprofile.gen_cityname
mysql
I'm trying to rank the score column
– Yuuki
Nov 16 '18 at 8:01
please provide some sample data for all the relevant tables and expected output. It would be best if you could setup db-fiddle.com
– Madhur Bhaiya
Nov 16 '18 at 8:02
Subquery inSELECT
can only return a scalar value. Your subquery returns a table. Google some subquery tutorial.
– Eric
Nov 27 '18 at 17:52
add a comment |
I have a class project and I want to rank my data according to their score
but every time I run this query on mysql it always gives me error 1241.
Any thoughts on what's causing these?
here is my query:
SELECT
(SELECT gen_cityname,
SUM(scc_bgyscoretotal) as score,
@curRank := @curRank + 1 AS rank
FROM bgyprofile b, (SELECT @curRank := 0) r
WHERE gen_provname = bgyprofile.gen_provname
GROUP BY gen_incomeyr, gen_cityname
ORDER BY score asc) AS provranks
FROM bgyprofile
GROUP BY bgyprofile.gen_incomeyr, bgyprofile.gen_cityname
mysql
I have a class project and I want to rank my data according to their score
but every time I run this query on mysql it always gives me error 1241.
Any thoughts on what's causing these?
here is my query:
SELECT
(SELECT gen_cityname,
SUM(scc_bgyscoretotal) as score,
@curRank := @curRank + 1 AS rank
FROM bgyprofile b, (SELECT @curRank := 0) r
WHERE gen_provname = bgyprofile.gen_provname
GROUP BY gen_incomeyr, gen_cityname
ORDER BY score asc) AS provranks
FROM bgyprofile
GROUP BY bgyprofile.gen_incomeyr, bgyprofile.gen_cityname
mysql
mysql
edited Nov 16 '18 at 7:57
Madhur Bhaiya
19.6k62336
19.6k62336
asked Nov 16 '18 at 7:56
YuukiYuuki
145
145
I'm trying to rank the score column
– Yuuki
Nov 16 '18 at 8:01
please provide some sample data for all the relevant tables and expected output. It would be best if you could setup db-fiddle.com
– Madhur Bhaiya
Nov 16 '18 at 8:02
Subquery inSELECT
can only return a scalar value. Your subquery returns a table. Google some subquery tutorial.
– Eric
Nov 27 '18 at 17:52
add a comment |
I'm trying to rank the score column
– Yuuki
Nov 16 '18 at 8:01
please provide some sample data for all the relevant tables and expected output. It would be best if you could setup db-fiddle.com
– Madhur Bhaiya
Nov 16 '18 at 8:02
Subquery inSELECT
can only return a scalar value. Your subquery returns a table. Google some subquery tutorial.
– Eric
Nov 27 '18 at 17:52
I'm trying to rank the score column
– Yuuki
Nov 16 '18 at 8:01
I'm trying to rank the score column
– Yuuki
Nov 16 '18 at 8:01
please provide some sample data for all the relevant tables and expected output. It would be best if you could setup db-fiddle.com
– Madhur Bhaiya
Nov 16 '18 at 8:02
please provide some sample data for all the relevant tables and expected output. It would be best if you could setup db-fiddle.com
– Madhur Bhaiya
Nov 16 '18 at 8:02
Subquery in
SELECT
can only return a scalar value. Your subquery returns a table. Google some subquery tutorial.– Eric
Nov 27 '18 at 17:52
Subquery in
SELECT
can only return a scalar value. Your subquery returns a table. Google some subquery tutorial.– Eric
Nov 27 '18 at 17:52
add a comment |
1 Answer
1
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oldest
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it gives error 1241 because your query has the form
SELECT (SELECT column1, column2 FROM t2) FROM t1;
(https://dev.mysql.com/doc/refman/8.0/en/subquery-errors.html)
As they say in comments sample data and an explenation of what you expect would be very useful. Maybe the first step is to change the query starting with SELECT * and moving the SELECT between brackets after the FROM, but, I repeat, I need some more information to understand the right way.
add a comment |
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1 Answer
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active
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votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
it gives error 1241 because your query has the form
SELECT (SELECT column1, column2 FROM t2) FROM t1;
(https://dev.mysql.com/doc/refman/8.0/en/subquery-errors.html)
As they say in comments sample data and an explenation of what you expect would be very useful. Maybe the first step is to change the query starting with SELECT * and moving the SELECT between brackets after the FROM, but, I repeat, I need some more information to understand the right way.
add a comment |
it gives error 1241 because your query has the form
SELECT (SELECT column1, column2 FROM t2) FROM t1;
(https://dev.mysql.com/doc/refman/8.0/en/subquery-errors.html)
As they say in comments sample data and an explenation of what you expect would be very useful. Maybe the first step is to change the query starting with SELECT * and moving the SELECT between brackets after the FROM, but, I repeat, I need some more information to understand the right way.
add a comment |
it gives error 1241 because your query has the form
SELECT (SELECT column1, column2 FROM t2) FROM t1;
(https://dev.mysql.com/doc/refman/8.0/en/subquery-errors.html)
As they say in comments sample data and an explenation of what you expect would be very useful. Maybe the first step is to change the query starting with SELECT * and moving the SELECT between brackets after the FROM, but, I repeat, I need some more information to understand the right way.
it gives error 1241 because your query has the form
SELECT (SELECT column1, column2 FROM t2) FROM t1;
(https://dev.mysql.com/doc/refman/8.0/en/subquery-errors.html)
As they say in comments sample data and an explenation of what you expect would be very useful. Maybe the first step is to change the query starting with SELECT * and moving the SELECT between brackets after the FROM, but, I repeat, I need some more information to understand the right way.
edited Nov 29 '18 at 20:54
answered Nov 27 '18 at 17:48
GufusGufus
138119
138119
add a comment |
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I'm trying to rank the score column
– Yuuki
Nov 16 '18 at 8:01
please provide some sample data for all the relevant tables and expected output. It would be best if you could setup db-fiddle.com
– Madhur Bhaiya
Nov 16 '18 at 8:02
Subquery in
SELECT
can only return a scalar value. Your subquery returns a table. Google some subquery tutorial.– Eric
Nov 27 '18 at 17:52